Graphing Non-Linear Relationships
Systematic graphing: identify the family, build a table of values, choose a sensible scale, plot points, connect smoothly. One reliable method for parabolas, hyperbolas and exponentials.
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Graphing a non-linear curve from scratch needs four decisions: which $x$-values to choose, what scale to use, what shape to expect, how smoothly to join the points. Take $y = x^2 - 4$. Which integer $x$-values would you pick? What's the $y$-range you'd need to show?
Every non-linear graph follows the same five-step recipe: identify family $\to$ choose $x$-values $\to$ build a table $\to$ choose scale $\to$ plot and join smoothly. Same recipe, different shape.
The table of values is the bridge from equation to grid. Pick clever $x$-values: symmetric about any vertex or asymptote, including $0$ where possible, both sides of every interesting feature. Then plot and join with a smooth curve — never straight segments.
Know
- The 5-step graphing recipe applied to all non-linear families
- How to choose $x$-values for parabolas, hyperbolas and exponentials
- How to choose a sensible scale based on the $y$-range
Understand
- Why hyperbolas need values close to AND far from the asymptote
- Why exponentials need both small AND large $x$ to show growth
- Why a parabola needs values symmetric about its axis
Can Do
- Build a tidy table of values from any non-linear equation
- Plot the points on a number plane with appropriate scale
- Join points with a smooth, family-appropriate curve
Wrong: Using only $x = 1, 2, 3$ to plot $y = x^2$ — only get half the parabola.
Right: Use $x = -3, -2, -1, 0, 1, 2, 3$ so both arms appear.
Wrong: Substituting $x = 0$ into $y = \dfrac{6}{x}$ and writing $y = 0$ or $y = \infty$.
Right: $x = 0$ is excluded from the domain. Write "undefined" or skip the row entirely.
Use these five steps in this order for every non-linear graph:
- Identify the family (parabola / hyperbola / exponential / circle) from the equation form.
- Choose $x$-values based on the family (see below).
- Build the table: compute $y$ for each $x$. Use exact fractions where possible.
- Choose the scale: look at the $y$-range; pick units-per-square so the curve fits.
- Plot and join smoothly: dot each $(x, y)$, then connect with a flowing curve.
Always label axes, key intercepts and asymptotes.
Different families need different $x$-value strategies:
Parabola: 5–7 integer values symmetric about the axis (e.g. $x = -3, -2, -1, 0, 1, 2, 3$).
Hyperbola $y = \dfrac{k}{x}$: use $x = \pm 1, \pm 2, \pm 3, \pm 6$ — small and large, both sides — SKIP $x = 0$.
Exponential $y = a^x$: use $x = -2, -1, 0, 1, 2, 3$ — negatives show the asymptote, positives show growth.
Circle: can't use $y = f(x)$ form — instead use compass at centre with radius $r$, or solve $y = \pm\sqrt{r^2 - x^2}$.
Watch Me Solve It · 3 examples
- 1Identify and tableFamily: parabola, vertex $(0, -4)$, opens up. Table: $x = -3, -2, -1, 0, 1, 2, 3$ gives $y = 5, 0, -3, -4, -3, 0, 5$.
- 2Choose scale$x$ range $-3$ to $3$: $1$ unit per square. $y$ range $-4$ to $5$: $1$ unit per square works. Both scales match here.
- 3Plot and joinPlot all $7$ points. Join with a smooth U-shape through them. Label $y$-int $(0, -4)$, $x$-ints $(-2, 0)$ and $(2, 0)$.Seven points with symmetry — the curve is well constrained.
- 1Choose $x$-values and build table$x = -6, -3, -2, -1, 1, 2, 3, 6$ (factors of $6$). Then $y = -1, -2, -3, -6, 6, 3, 2, 1$. Skip $x = 0$ (undefined).
- 2Scale and plot$x$ range $-6$ to $6$, $y$ range $-6$ to $6$: $1$ unit per square fits a standard grid. Plot all eight points.
- 3Join smoothly — TWO branchesConnect the four points in quadrant 1 with one smooth branch; the four in quadrant 3 with another. NEVER cross the axes.$k = 6 > 0$ $\Rightarrow$ branches in Q1 and Q3, asymptotes $x = 0$, $y = 0$.
- 1Build table$y = 2^{-3}, 2^{-2}, 2^{-1}, 2^0, 2^1, 2^2, 2^3 = \tfrac{1}{8}, \tfrac{1}{4}, \tfrac{1}{2}, 1, 2, 4, 8$.
- 2Choose scales$x$: $1$ unit per square. $y$: $1$ unit per square (max $y = 8$ fits well). For neg $x$, $y$ is fractional — tiny near the axis but never touches.
- 3Plot and asymptotePlot all $7$ points. Smooth curve rising steeply on the right. Left arm hugs the $x$-axis but never touches — label $y = 0$ as the horizontal asymptote.Asymptote labelling is required — the visual look alone isn't enough.
Common Pitfalls
5-step recipe
- Identify family
- Choose $x$-values
- Build table
- Choose scale
- Plot & join smoothly
$x$-values by family
- Parabola: symmetric integers
- Hyperbola: factors of $k$
- Exponential: $-2$ to $3$
- Circle: compass & radius
Scale tips
- Check $y$-range first
- $x$ and $y$ can differ
- Aim to fill the grid
Plotting rules
- Smooth, never straight
- Label intercepts
- Label asymptotes
- State the equation
How are you completing this lesson?
Brain Trainer · 4 problems
Four quick problems building tables and choosing scales.
1 Complete the table for $y = x^2 + 1$: $x = -2, -1, 0, 1, 2$.
$y = (-2)^2 + 1, (-1)^2 + 1, 0+1, 1+1, 4+1$.$y = 5, 2, 1, 2, 5$2 List the best $x$-values for $y = \dfrac{8}{x}$ from $-8$ to $8$.
Factors of $8$, both signs, exclude $0$.$x = \pm 1, \pm 2, \pm 4, \pm 8$3 Complete the table for $y = 3^x$ at $x = -1, 0, 1, 2$.
$y = 3^{-1}, 3^0, 3^1, 3^2$.$y = \tfrac{1}{3}, 1, 3, 9$4 The table for $y = 4^x$ gives $y$-values up to $64$. Suggest a $y$-scale (units per square).
$64$ on a standard grid needs big squares per unit.$10$ units per square (so $7$ squares fits $0$–$70$)
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Build a table of values for $y = x^2 - 2x$ at $x = -1, 0, 1, 2, 3$. Then state the vertex by inspection.
Q7. Build a table of values for $y = \dfrac{4}{x}$ at $x = -4, -2, -1, 1, 2, 4$. Sketch the graph and label the asymptotes.
Q8. A student wants to graph $y = 3^x$ for $x = -3$ to $x = 4$. (a) Build the table. (b) The $y$-values range from $\tfrac{1}{27}$ to $81$ — explain why a $y$-scale of "$1$ unit per square" is unsuitable, and suggest a better one. (c) State the equation of the asymptote.
Quick Check
1. B — $(-2)^2 - 3 = 1$.
2. D — $\dfrac{12}{0}$ is undefined.
3. A — $2^{-2} = \dfrac{1}{4}$.
4. C — symmetric integers capture both arms.
5. B — always smooth curve, never straight.
Show Your Working Model Answers
Q6 (3 marks): $y = 3, 0, -1, 0, 3$ at $x = -1, 0, 1, 2, 3$ [1]. Minimum $y$-value in the table is $-1$ at $x = 1$ [1]. So vertex appears to be $(1, -1)$ [1].
Q7 (3 marks): $y = -1, -2, -4, 4, 2, 1$ at $x = -4, -2, -1, 1, 2, 4$ [1]. Plot $6$ points; smooth Q1 branch and Q3 branch [1]. Asymptotes: $x = 0$ (vertical) and $y = 0$ (horizontal) [1].
Q8 (3 marks): (a) $y = \tfrac{1}{27}, \tfrac{1}{9}, \tfrac{1}{3}, 1, 3, 9, 27, 81$ at $x = -3, -2, -1, 0, 1, 2, 3, 4$ [1]. (b) $1$ unit per square would need $81$ squares vertically — off the page. Use $\sim 10$ units per square (about $9$ squares fits $0$–$90$) [1]. (c) Asymptote $y = 0$ [1].
Mixed Graphing on One Set of Axes
On the same set of axes, you must plot $y = x^2$, $y = \dfrac{6}{x}$ (positive branch only), and $y = 2^x$ for $x = 1, 2, 3$. (a) Build the table for all three. (b) Which curve passes through the highest point at $x = 3$? (c) At $x = 2$, list the three points in order from lowest $y$ to highest $y$. (d) Suggest a $y$-scale that fits all three curves on the same grid.
Reveal solution
(a) $x = 1$: $1, 6, 2$. $\;x = 2$: $4, 3, 4$. $\;x = 3$: $9, 2, 8$. (b) At $x = 3$: parabola $y = 9$ is highest (just above exponential $y = 8$, hyperbola $y = 2$). (c) At $x = 2$: hyperbola $3$ < parabola $4 =$ exponential $4$ (tie). So order: $\dfrac{6}{x} (3)$, $x^2 = 2^x (4)$. (d) $y$-range $1$–$9$, so $1$ unit per square works fine on a standard grid.
Step 1
Identify family
Step 2
Choose $x$-values
Step 3
Build table
Step 4
Choose scale
Step 5
Plot + smooth curve
Reminder
Never straight segments
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