← Unit 4 Introduction to Probability
MA5-PRO-C-01

Introduction to Probability

⏱ 25 min📚 Year 9📈
Think First

A bag has 3 red, 5 blue, and 2 green marbles. What is the probability of drawing a blue marble?

💡 Revision: Ensure you understand fractions and basic set theory (union, intersection).

Learning Intentions

Know

  • Sample space
  • Event
  • Probability scale
  • Complementary events

Understand

  • Why probabilities sum to 1
  • The difference between theoretical and experimental probability

Can Do

  • List a sample space
  • Calculate simple probabilities
  • Find complementary probabilities
Sample spaceEventOutcomeComplementFair
Learn Phase
1

Probability Basics

Measuring likelihood

Probability measures how likely an event is to occur.

Probability Formula

$P(E) = dfrac{ ext{number of favourable outcomes}}{ ext{total number of outcomes}}$

Probabilities range from 0 (impossible) to 1 (certain).

Example: Rolling a fair die, P(rolling a 4) = 1/6.

2

Sample Space

All possible outcomes

The sample space is the set of all possible outcomes of an experiment.

Example: Tossing a coin twice:

Sample space = {HH, HT, TH, TT}

Each outcome is equally likely if the coin is fair.

For a standard die: Sample space = {1, 2, 3, 4, 5, 6}

3

Complementary Events

Not the event

The complement of event $E$ (written $E'$ or $E^c$) is the event that $E$ does not occur.

Complement Rule

$P(E') = 1 - P(E)$

Example: P(rolling a 6) = 1/6, so P(not rolling a 6) = 5/6.

This is useful when $P(E)$ is easier to find than $P(E')$.

Check Understanding

Try it yourself

A card is drawn from a standard 52-card deck. Find P(heart), P(king), and P(not a king).

Worked Example

Basic Probability

1

A bag has 4 red, 6 blue, and 10 green marbles. Find P(red), P(blue), P(green).

Total = 20

P(red) = 4/20 = 1/5

P(blue) = 6/20 = 3/10

P(green) = 10/20 = 1/2

2

A fair die is rolled. Find P(even number) and P(number greater than 4).

Even = {2, 4, 6}: P(even) = 3/6 = 1/2

Greater than 4 = {5, 6}: P(>4) = 2/6 = 1/3

3

Two coins are tossed. Find P(two heads) and P(at least one tail).

Sample space = {HH, HT, TH, TT}

P(two heads) = 1/4

P(at least one tail) = 1 - P(HH) = 1 - 1/4 = 3/4

Common Misconceptions

Add probabilities for all events to get more than 1. The sum of probabilities of all possible outcomes must equal 1. If your total exceeds 1, you have double-counted.

Assume all outcomes are equally likely. Only true for fair dice, coins, etc. Real-world situations often have unequal probabilities.

P(A) + P(B) = P(A or B) always. No — this only works for mutually exclusive events. If A and B can both occur, use the addition rule: P(A or B) = P(A) + P(B) − P(A and B).

Your Turn

Practice — Probability Basics

Work through each question in your book or digitally. Answers are in the Questions phase.

1A spinner has 8 equal sections: 3 red, 3 blue, 2 green. Find P(red) and P(not green).
2A letter is chosen from PROBABILITY. Find P(vowel) and P(consonant).
3Two dice are rolled. Find P(sum = 7) and P(sum > 9).
Real-World Anchor

Gambling and Insurance

Insurance companies use probability to calculate premiums. The probability of car accidents for different age groups informs premium pricing. Australian lottery odds (e.g., Oz Lotto) are calculated using combinatorial probability — the chance of winning Division 1 is about 1 in 45 million.

📓 Copy Into Your Books

Probability

  • $P(E) = ext{favourable}/ ext{total}$
  • Range: 0 to 1

Sample space

  • List all outcomes
  • Check equally likely

Complement

  • $P(E') = 1 - P(E)$
  • Use when complement is easier
Questions Phase
Check Your Understanding
Answer all questions correctly to unlock the Game phase.
P(impossible event) =
A fair die. P(rolling 7) =
P(A) + P(A') =
Bag: 3 red, 7 blue. P(red) =
Two coins. P(at least one head) =
P(not rolling a 6 on fair die) =
Sample space of rolling a die:
If P(rain) = 0.3, P(no rain) =
1A bag has 5 red, 3 blue, 2 green marbles. Find P(red), P(blue), and P(not green).
2A card is drawn from a deck. Find P(ace) and P(not a face card).
3Explain why P(A) + P(B) does not always equal P(A or B).

Comprehensive Answers

1Bag 5R, 3B, 2G.
P(red)=5/10=1/2, P(blue)=3/10, P(not green)=8/10=4/5.
2Card: P(ace) and P(not face).
P(ace)=4/52=1/13. Face cards=12, P(not face)=40/52=10/13.
3Why P(A)+P(B) != P(A or B).
Only for mutually exclusive events. If overlap exists, subtract P(A and B).
MC 1P(impossible).
0. Answer: A
MC 2P(rolling 7).
0. Answer: B
MC 3P(A)+P(A').
1. Answer: C
MC 4P(red) from bag.
3/10. Answer: B
MC 5P(at least one head).
3/4. Answer: C
MC 6P(not 6).
5/6. Answer: B
MC 7Sample space of die.
{1,2,3,4,5,6}. Answer: B
MC 8P(no rain).
0.7. Answer: C
SA 1Bag probabilities.
P(red)=1/2, P(blue)=3/10, P(not green)=4/5.
SA 2Card probabilities.
P(ace)=1/13, P(not face)=10/13.
SA 3P(A)+P(B) vs P(A or B).
Must subtract overlap for non-mutually exclusive events.
Game Phase
🎲
Game Unlocked!
You have mastered the Check Your Understanding questions. Choose a game mode below.
📦
Classify & Sort
Sort mathematical objects by their properties.
Speed Challenge
Answer questions against the clock.
📈
Match Maker
Match problems to their solutions.