Expanding Brackets
One simple law turns $3(x + 2)$ into $3x + 6$. Master it and you unlock half of algebra — solving equations, factorising, and beyond.
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Before you read on — quickly: expand $4(x + 5)$. What does the 4 multiply? Try it, then check your reasoning as you go.
The whole lesson is one rule, called the distributive law. It says: if you're multiplying a bracket by something, that something multiplies every term inside the bracket. No exceptions, no shortcuts.
An expansion takes a bracketed expression and rewrites it without the brackets, by multiplying the multiplier through each inner term.
Think of it as an area model: a rectangle of width $a$ and length $(b + c)$ has area $a \cdot b + a \cdot c$.
Know
- The distributive law $a(b+c) = ab+ac$
- What "expanding" / "distributing" means
- The area-model interpretation
Understand
- Why the multiplier hits every term
- Why a negative multiplier flips every sign
- Why brackets must come off before like terms can be combined
Can Do
- Expand $a(b+c)$ with positive or negative multipliers
- Expand and then collect like terms
- Use brackets to write area / perimeter expressions
Wrong: "$3(x + 2) = 3x + 2$" — the 3 only multiplied the first term.
Right: $3(x + 2) = 3x + 6$. The 3 multiplies BOTH the $x$ AND the $2$.
Wrong: "$-2(x - 3) = -2x - 6$" — kept the minus on the 6 by accident.
Right: $-2(x - 3) = -2x + 6$. A negative times a negative is positive.
Before you can expand, learn to read what's in front of you. Every bracketed expression has three parts you must spot at a glance.
The multiplier sits outside the bracket. The inner terms sit inside the bracket and each carries its own sign. Your job: multiply the multiplier by every inner term, keeping signs intact.
Here's the move in slow motion. Picture two arrows leaving the multiplier and landing on each inner term.
To expand $5(2x - 3)$: the 5 multiplies the $2x$ to give $10x$, and the 5 multiplies the $-3$ (keeping its minus sign) to give $-15$. Add them: $10x - 15$.
A negative multiplier flips the sign of every inner term. This is the #1 place students lose marks. Slow down — write the bracket out as a multiplication first if you need to.
For $-2(x - 3)$: the $-2$ multiplies the $x$ (giving $-2x$) and the $-2$ multiplies the $-3$ (giving $+6$, because negative × negative = positive).
So $-2(x - 3) = -2x + 6$ — not $-2x - 6$.
When two brackets sit in the same expression, expand each one first, then collect like terms. Don't try to combine while brackets are still up — that's how mistakes sneak in.
The recipe is always the same: (1) expand each bracket separately, (2) collect like terms. Don't skip step 1 — like-term collection only works once everything is bracket-free.
Watch Me Solve It · 3 examples
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1Identify the multipliermultiplier = 4, inner terms: $2x$ and $+5$Spot the 4 outside the bracket and the two terms inside.
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2Multiply through each inner term$4 \times 2x = 8x$ and $4 \times 5 = 20$
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3Drop the brackets and join$= 8x + 20$No like terms to collect — these are unlike (one $x$, one constant).
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1Note the negative multipliermultiplier = $-2$A negative multiplier will flip the sign of every inner term.
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2Multiply each inner term$-2 \times 3y = -6y$ and $-2 \times (-4) = +8$Negative × negative = positive.
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3Combine$= -6y + 8$
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1Expand the first bracket$3(x + 2) = 3x + 6$
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2Expand the second bracket$-2(x - 4) = -2x + 8$$-2 \times -4 = +8$. Flip both inner signs.
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3Bring together$3x + 6 - 2x + 8$
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4Collect like terms$(3x - 2x) + (6 + 8) = x + 14$
The Rule
- $a(b + c) = ab + ac$
- $a(b - c) = ab - ac$
- Multiplier hits every inner term
With Negatives
- $-a(b + c) = -ab - ac$
- $-a(b - c) = -ab + ac$
- Two negatives → positive
Two Brackets
- Expand BOTH first
- Then collect like terms
- Never combine over a bracket
Area Model
- $a(b+c)$ = rectangle $a \times (b+c)$
- Splits into $a \cdot b$ and $a \cdot c$
- Useful for sanity-checking
How are you completing this lesson?
Brain Trainer · 4 problems
Four problems mixing positive and negative multipliers. Work each, then reveal the answer.
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1 Expand $3(x + 7)$.
$3 \times x = 3x$ and $3 \times 7 = 21$$= 3x + 21$ -
2 Expand $-5(2a - 1)$.
$-5 \times 2a = -10a$ and $-5 \times -1 = +5$$= -10a + 5$ -
3 Expand and simplify $4(x + 2) + 3(x - 1)$.
$4(x+2) = 4x + 8$, $3(x-1) = 3x - 3$. Sum: $4x + 3x + 8 - 3$$= 7x + 5$ -
4 Expand and simplify $5(2y - 3) - 2(y + 4)$.
$5(2y-3) = 10y - 15$, $-2(y+4) = -2y - 8$. Sum: $10y - 2y - 15 - 8$$= 8y - 23$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Expand and simplify $2(x + 4) + 5(x - 1)$.
Q7. A rectangle has length $(2x + 3)$ cm and width $4$ cm. Write and simplify an expression for the area.
Q8. Simplify $3(2a - 5) - 4(a + 1)$.
Quick Check
1. B — $3(x+4) = 3x + 12$.
2. C — $-2 \times -5 = +10$, so $-2(y-5) = -2y + 10$.
3. A — $5(2x-3) = 10x - 15$, plus the lone $x$: $11x - 15$.
4. D — $-3(x-2)$ should give $-3x + 6$, not $-3x - 6$ (two negatives → positive).
5. A — $4(x+1) - 3(x-2) = 4x + 4 - 3x + 6 = x + 10$.
Show Your Working Model Answers
Q6 (2 marks): $2(x+4) + 5(x-1) = 2x + 8 + 5x - 5$ [1 expanding] $= 7x + 3$ [1 collecting].
Q7 (2 marks): Area $= 4(2x + 3)$ [1 setup] $= 8x + 12$ cm² [1 expansion].
Q8 (3 marks): $3(2a-5) = 6a - 15$ [1]. $-4(a+1) = -4a - 4$ [1]. Sum: $6a - 4a - 15 - 4 = 2a - 19$ [1].
Two Brackets, One Trick
Expand $(x + 2)(x + 3)$ by treating it as $x(x + 3) + 2(x + 3)$ — the distributive law applied twice. Show every step.
Reveal solution
$(x+2)(x+3) = x(x+3) + 2(x+3) = x^2 + 3x + 2x + 6 = x^2 + 5x + 6$.
The Law
$a(b + c) = ab + ac$
Every term
Multiplier hits all inner terms
Keep signs
Sign of each term comes along
Neg × neg
Result is positive
Two brackets
Expand both, then collect
Area model
$a(b+c)$ = split rectangle
Interactive: Expansion Visualiser
See the distributive law as an area model — adjust the multiplier and inner terms and watch the rectangle change.
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