Review of Algebraic Expressions
Three tools, one toolbox — collect like terms, substitute values, and apply BIDMAS. You'll lean on these in every lesson this unit.
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Before you read on — if $a = 3$ and $b = 5$, what is the value of $2a + 3b - a$? Try it in your head, then note which order you did the operations in.
Algebra is shorthand for "do this with a number — whatever the number turns out to be." When you write $3x$ you're saying "three of whatever $x$ is." The rest of the lesson is just three small tools — see below.
Every problem in this unit is just three small moves: combine like terms, substitute letters with numbers, and follow BIDMAS for order.
Know
- What an expression is vs an equation
- Term, coefficient, variable, constant
- The BIDMAS order of operations
Understand
- Why only like terms can combine
- Why $(-3)^2 = 9$, not $-9$
- Why brackets matter in substitution
Can Do
- Simplify by collecting like terms
- Substitute values, including negatives
- Evaluate with correct BIDMAS order
Wrong: "$3x + 5y$ simplifies to $8xy$."
Right: $3x$ and $5y$ are NOT like terms. They stay separate: $3x + 5y$ is already in simplest form.
Wrong: "If $x = -3$, then $x^2 = -9$."
Right: $(-3)^2 = (-3) \times (-3) = +9$. A negative times a negative is positive.
Every algebraic expression is built from terms, joined by $+$ or $-$ signs. Each term has up to three parts you need to recognise on sight.
An expression is a math phrase with no equals sign. It describes a value rather than asserting one. Each term is a block. Each block has a coefficient, a variable, or is a plain constant.
EXPRESSION
Knowing the parts by name makes everything easier. When a question says "find the coefficient of $x$" or "substitute $x = 4$", you'll know exactly where to look.
Two terms are like terms when they share exactly the same letters raised to exactly the same powers. Coefficients don't have to match — only the letter-and-power signature does. Sort the like terms together, then sum.
Sort terms into letter groups. Inside each group, add (or subtract) the coefficients. Groups with different letters stay apart — they're already in simplest form.
- $3x$ and $7x$ — like ✓ (both $x^1$)
- $5a^2$ and $-2a^2$ — like ✓ (both $a^2$)
- $3x$ and $3y$ — not like ✗ (different letters)
- $4x$ and $4x^2$ — not like ✗ (different powers)
When collecting, simply add or subtract the coefficients and keep the letter-part the same:
$$3x + 7x = 10x \qquad 5a - 2a = 3a \qquad 4x + 3y + 2x = 6x + 3y$$
Substitution means replacing each variable with a given number, then evaluating. Golden rule: always use brackets when substituting, especially around negatives.
Wherever you see a letter, write its number in brackets. Then evaluate the resulting number-only expression using BIDMAS. Brackets are your insurance policy against sign errors.
Worked example: if $x = 4$ and $y = -2$, find the value of $3x + 2y$.
When an expression has more than one operation, the answer depends on which one you do first. BIDMAS is the order — and when two operations share a priority, work left to right.
Climb the ladder from the top: Brackets, then Indices, then Div/Mult, then Add/Sub. Same priority? Left to right. Most mistakes come from forgetting that.
The full ladder — same as the mini above, with the example operations spelt out:
Example: evaluate $2 + 3 \times 4^2$.
$$2 + 3 \times 4^2 = 2 + 3 \times 16 \;\text{(indices)} = 2 + 48 \;\text{(mult)} = 50$$
Watch Me Solve It · 3 examples
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1Group like terms$(5a - 2a) + (3b + 7b)$Bring the $a$-terms together and the $b$-terms together — never mix letters when combining.
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2Combine coefficients$= 3a + 10b$$5 - 2 = 3$ and $3 + 7 = 10$. Keep the letter part the same.
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3Check it's simplest form$3a + 10b$ ✓Each letter appears once — nothing left to combine.
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1Substitute with brackets$2(5)^2 - 3(-3)$Brackets around $-3$ save you from sign errors.
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2Apply indices (BIDMAS)$2(25) - 3(-3)$Indices come before multiplication, so $5^2$ first.
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3Multiply then add$= 50 - (-9) = 50 + 9 = 59$Subtracting a negative becomes adding.
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1Set up perimeter formula$P = 2(3x + 2) + 2(2x - 1)$Perimeter = 2 × length + 2 × width.
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2Expand brackets$P = 6x + 4 + 4x - 2$Multiply each term inside by the 2 outside.
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3Collect like terms$P = 10x + 2$$x$-terms together: $6x + 4x = 10x$. Constants: $4 - 2 = 2$.
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4Substitute $x = 4$$P = 10(4) + 2 = 42$ cmNow we have a number-only expression, evaluate it.
Definitions
- Expression — math phrase, no equals sign
- Term — block separated by + or −
- Coefficient — number multiplying the variable
- Constant — plain number, no variable
Like Terms Rule
- Same letter AND same power → combine
- $3x + 7x = 10x$
- $5a^2 - 2a^2 = 3a^2$
- $3x + 5y$ stays as $3x + 5y$
Substitution
- Use brackets around negatives
- $(-3)^2 = 9$, not $-9$
- Replace every instance of each letter
BIDMAS Order
- Brackets → Indices → ×÷ → +−
- Same priority = left to right
- $10 - 5 + 2 = 7$, not $3$
How are you completing this lesson?
Brain Trainer · 4 problems
Four problems mixing all three tools. Work each one, then reveal the answer to check.
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1 Simplify $7a + 4b - 3a + 6b - 2a$.
Group $a$-terms and $b$-terms: $(7a - 3a - 2a) + (4b + 6b)$$= 2a + 10b$ -
2 If $x = -2$ and $y = 5$, evaluate $x^2 - 2y$.
Substitute with brackets: $(-2)^2 - 2(5)$$= 4 - 10 = -6$ -
3 Evaluate $20 - 6 \div 2 + 3 \times 4$.
Division and multiplication first (left to right): $20 - 3 + 12$$= 17 + 12 = 29$ -
4 If $m = 3$ and $n = -4$, find $2m^2 + 3mn$.
$2(3)^2 + 3(3)(-4) = 2(9) + (-36)$$= 18 - 36 = -18$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Simplify $9p - 2q + 4p + 7q - 5p$.
Q7. If $m = 5$ and $n = -2$, evaluate: (a) $m^2 + n^2$ (b) $3mn - 2m$.
Q8. A rectangle has length $(3x + 2)$ cm and width $(2x - 1)$ cm. (a) Write a simplified expression for the perimeter. (b) Find the perimeter when $x = 4$.
Multiple Choice
1. C — $7m$ and $-2m$ share variable $m$ to the same power.
2. A — $(8x-5x)+(3y+2y) = 3x + 5y$.
3. B — $3(4) - 2(-2) = 12 + 4 = 16$. Subtracting a negative adds.
4. A — $(2x^2 - 3x^2) + (5x + 2x) = -x^2 + 7x$.
5. A — $(-3)^2 - 2(-3)(2) = 9 + 12 = 21$.
Short Answer Model Answers
Q6 (2 marks): $(9p + 4p - 5p) + (-2q + 7q) = 8p + 5q$. [1 grouping, 1 answer]
Q7 (3 marks): (a) $5^2 + (-2)^2 = 25 + 4 = 29$ [1]. (b) $3(5)(-2) - 2(5)$ [1] $= -30 - 10 = -40$ [1].
Q8 (3 marks): (a) $P = 2(3x+2) + 2(2x-1) = 6x+4+4x-2$ [1] $= 10x + 2$ [1]. (b) $P = 10(4) + 2 = 42$ cm [1].
The Hidden Substitution
The identity $a^2 + 2ab + b^2 = (a + b)^2$ is worth memorising. Use it to evaluate $97^2$ without a calculator. Hint: let $a = 100$ and $b = -3$.
Reveal solution
$97^2 = (100 - 3)^2 = 100^2 + 2(100)(-3) + (-3)^2 = 10\,000 - 600 + 9 = 9409$.
Like Terms
Same letter, same power
Collecting
Add/subtract coefficients only
Substitute
Brackets around negatives
$(-x)^2$
Always positive
BIDMAS
B · I · DM · AS, left to right
Same priority
Work L → R
Interactive: Expression Simplifier
Practise collecting like terms and substituting values until it's automatic.
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