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hscscience Ext 1 · Y12
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Module 5 · L20 of 20 ~40 min ⚡ +90 XP available

Mixed Proofs & Exam Technique

You know direct proof, induction, strong induction, and contradiction. Now the exam won't tell you which to use. This final lesson gives you a decision framework, two worked mixed proofs, and the exam habits that separate Band 6 answers from the rest. No new techniques — just sharper execution.

Today's hook — Before reading the decision framework, try this: given "Prove $n^3 - n$ is divisible by $6$ for all integers $n$", which technique would you reach for first — direct, induction, or contradiction? Write your instinct and why.
0/5QUESTS
01
Recall — which technique?
+5 XP warm-up

For each statement below, without looking anything up, write which proof technique you would use and briefly why.

(a) "Prove $n^3 - n$ is divisible by $6$ for all integers $n$."

(b) "Prove $\sum_{k=1}^{n} k^2 = \frac{n(n+1)(2n+1)}{6}$ for all $n \geq 1$."

(c) "Prove $\sqrt{5}$ is irrational."

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02
The decision framework
+5 XP to read

In the HSC, proof questions often do not name the technique. Read the statement structure first, then select.

Ask these questions in order:

1. Does the statement say "for all $n \geq 1$" (or a similar integer index)? → Induction

2. Does the inductive step require earlier cases (not just $k$)?  → Strong induction

3. Is the claim a negative — irrational, impossible, infinite, unique? → Contradiction

4. Is it a direct algebraic or logical consequence? → Direct proof

Note: "for all $n$" does not always require induction — sometimes direct algebraic factoring is simpler. Choose the technique that keeps the proof shortest and clearest.

Read statement for all n? YES Induction NO negative? YES Contradiction NO Direct
statement → structure → technique
Direct when possible
Not every "for all $n$" needs induction. If algebraic factoring solves it in two lines, do that. $n^3 - n = (n-1)n(n+1)$ is direct and elegant.
Strong for recurrences
If $P(k+1)$ needs $P(k-1)$ as well as $P(k)$ (e.g. Fibonacci), switch to strong induction. The hypothesis is "assume $P(j)$ is true for all $j \leq k$".
Time management
Proof questions carry 3–5 marks. If stuck on technique selection, write the base case for induction — it often reveals which approach is natural.
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What you'll master
Know

Key facts

  • The four techniques: direct, induction, strong induction, contradiction
  • When each technique is the most efficient choice
  • The trigger phrases that signal each technique in an HSC question
Understand

Concepts

  • Why "for all $n$" does not automatically mean induction
  • The relationship between the statement structure and the proof method
  • How examiners mark proof questions (structure, working, conclusion)
Can do

Skills

  • Identify the correct technique for any Module 5 HSC question
  • Carry out direct, induction, and contradiction proofs exam-ready
  • Write proofs that earn full marks: assumptions stated, working shown, conclusion explicit
04
Key terms
Direct proofA proof that follows by algebraic or logical deduction from definitions and established results, without assuming the negation or using an integer index.
Mathematical inductionA proof for statements indexed by positive integers: prove the base case, assume $P(k)$, then prove $P(k+1)$.
Strong inductionA variant of induction where the hypothesis is "assume $P(j)$ is true for all $j \leq k$", used when the inductive step depends on multiple earlier cases.
Proof by contradictionAssume the negation of the statement, then derive a logical impossibility to conclude the original statement is true.
Exam strategyIdentify the statement structure, select the technique, state assumptions explicitly, show all working, and conclude clearly.
Band 6 habitExplicitly naming the technique used and writing a closing conclusion: "Hence, by mathematical induction…" or "This is a contradiction, therefore…"
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Trigger words & technique selection
core concept

Train yourself to read these trigger phrases and automatically map them to a technique.

"Prove for all positive integers $n$…"
Trigger: integer index. Default: try direct first; if not obvious, use induction.

"Prove the following identity for all $n \geq 1$…"
Trigger: identity + integer index. Default: mathematical induction.

"Prove $f_n$ satisfies the recurrence… for all $n$"
Trigger: recurrence, depends on earlier cases. Default: strong induction.

"Prove that $\sqrt{m}$ is irrational"
Trigger: irrationality. Default: contradiction.

"Prove that there are infinitely many…" or "Prove there is no…"
Trigger: infinitude or impossibility. Default: contradiction.

Exam tip. In the HSC, proof questions that don't specify a technique usually have a "natural" one that makes the working clean. If your chosen technique leads to a wall of algebra, consider switching. A two-line direct proof beats a five-step induction every time.

Quick check: Which technique is most appropriate for: "Prove that $n^3 - n$ is divisible by $6$ for all integers $n$"?

Train yourself to read these trigger phrases and automatically map them to a technique.

Pause — copy the trigger-word-to-technique table (sums/products/divisibility → induction; irrational/no-solution → contradiction; "if P then Q" → direct or contrapositive) into your book.

PROOF 1 · DIRECT PROOF

Prove that $n^3 - n$ is divisible by $6$ for all integers $n$.

1
Technique selection: the statement involves "all integers $n$" but the expression factors cleanly. Try direct proof first.
Direct proof is simpler here — no base case or inductive hypothesis needed.
PROOF 2 · INDUCTION FOR A DERIVATIVE PATTERN

Prove by induction that $\dfrac{d^n}{dx^n}(x^{n-1}\ln x) = \dfrac{(n-1)!}{x}$ for all $n \geq 1$.

1
Technique selection: statement indexed by $n \geq 1$, involves $n$-th derivative. Use mathematical induction.
The formula changes with $n$ in a recursive way — induction is the natural choice.
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Exam tips for proof questions
marks strategy

We just saw that trigger phrases like "prove for all $n$", "prove divisible by $d$", and "prove the $n$th derivative" map directly to induction, while "prove irrational" or "prove no real solution" call contradiction. That raises a question: beyond recognising the technique, what exam-room habits separate a B6 answer from a B4 answer? This card answers it → state proof structure explicitly, write the conclusion sentence, and use $k$ not $n$ in the hypothesis.

  • State your assumptions. Write "Assume $P(k)$ is true" or "Suppose, for contradiction, that…" — these are often worth 1 mark each.
  • Show all working. Examiners follow your logic step by step. A missing step cannot earn a mark.
  • Conclude clearly. "Hence, by mathematical induction, $P(n)$ is true for all $n \geq 1$." or "This is a contradiction, therefore…". These closing sentences are frequently mark-awarded.
  • Check base cases. An induction proof without a valid base case is not a proof. Do not skip it.
  • Allocate time wisely. Proof questions carry 3–5 marks. Allow roughly 1 minute per mark. If you're in minute 6 of a 3-mark proof, reconsider the technique.

Did you get this? True or false: in an induction proof, omitting the base case means the argument is still valid as long as the inductive step is correct.

Did you get this? True or false: in an induction proof, omitting the base case means the argument is still valid as long as the inductive step is correct.

Pause — copy the three exam habits that protect marks on every proof question: (1) state proof structure, (2) write conclusion sentence, (3) use $k$ not $n$ in the hypothesis into your book.

Fill the gap: The correct closing sentence for an induction proof is: "Hence, by mathematical , $P(n)$ is true for all $n \geq 1$."

Trap 01
Using induction when direct proof is simpler
Not every "for all $n$" needs induction. $n^3 - n = (n-1)n(n+1)$ takes two lines directly. Forcing induction for this adds unnecessary complexity and risks error in the inductive step.
Trap 02
Vague or missing conclusions
"QED" alone is insufficient. Reference the proof technique: "Hence, by mathematical induction, $P(n)$ is true for all $n \geq 1$." Examiners award the conclusion sentence as a distinct mark.
Trap 03
Assuming what you want to prove
In induction, only the hypothesis $P(k)$ is assumed — never $P(k+1)$. In contradiction, only $\neg P$ is assumed — never $P$ itself. Working backwards from the conclusion is circular and earns zero marks.
Trap 04
Poor presentation
Messy working is hard for examiners to follow and can cause you to lose marks even for correct reasoning. Use clear line breaks, label steps ("Base case", "Inductive hypothesis", "Inductive step"), and box or highlight the final answer.

Did you get this? True or false: in the inductive step, you are allowed to assume both $P(k)$ and $P(k+1)$ to prove the result.

Work mode · how are you completing this lesson?
1

State the best technique and carry out the proof: "Prove $n^3 - n$ is divisible by $6$ for all integers $n$." (Direct or induction?)

2

Use induction to prove that $\sum_{k=1}^{n} k = \frac{n(n+1)}{2}$ for all $n \geq 1$.

3

Prove by contradiction that $\sqrt{5}$ is irrational. Follow the four steps.

4

Identify the technique error: "We want to prove $P(n)$. Assume $P(k+1)$ holds. Then $P(k)$ must also hold because…"

5

Write the correct closing sentence for: (a) an induction proof, and (b) a contradiction proof.

Odd one out: Three of these statements are correctly matched to their best proof technique. Which pairing is WRONG?

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Revisit your thinking

At the start you chose techniques for three statements. For $n^3 - n \div 6$: the answer is direct proof (factor into three consecutive integers). For the sum of squares identity: induction. For $\sqrt{5}$ irrational: contradiction. Did your initial instincts align?

The biggest lesson from Module 5: the technique choice is part of the mathematical thinking, not just a formality. Selecting the right method and executing it cleanly is what earns Band 6 marks.

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01
Multiple choice
+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

02
Short answer
ApplyBand 43 marks

Q1. Determine the most appropriate proof technique for "Prove $n^3 - n$ is divisible by $6$ for all $n$" and carry out the proof. (3 marks)

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ApplyBand 53 marks

Q2. Prove by induction that $\dfrac{d^n}{dx^n}(x^{n-1}\ln x) = \dfrac{(n-1)!}{x}$ for all $n \geq 1$. (3 marks)

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AnalyseBand 52 marks

Q3. A student writes: "To prove $P(n)$ by induction, I assume $P(k+1)$ is true and then show $P(k)$ must hold." Identify the error and explain the correct approach. (2 marks)

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Comprehensive answers (click to reveal)

Activity answers:

1. Direct proof: $n^3-n = (n-1)n(n+1)$. Consecutive integers $\Rightarrow$ one divisible by 2, one by 3, product by 6. $\square$

2. Base ($n=1$): $\sum_{k=1}^{1}k = 1 = \frac{1\cdot2}{2}$ ✓. Assume $\sum_{k=1}^{m}k = \frac{m(m+1)}{2}$. Then $\sum_{k=1}^{m+1}k = \frac{m(m+1)}{2} + (m+1) = \frac{(m+1)(m+2)}{2}$. By induction, true for all $n \geq 1$. $\square$

3. See worked example in the lesson.

4. Error: you cannot assume $P(k+1)$ in an induction proof. You assume $P(k)$ (the inductive hypothesis) and prove $P(k+1)$ follows.

5. (a) "Hence, by mathematical induction, $P(n)$ is true for all $n \geq 1$." (b) "This is a contradiction. Therefore [original statement] must be true."

Q1 (3 marks): [1] Identifies direct proof as most efficient. [1] Factors $n^3-n = (n-1)n(n+1)$. [1] Argues consecutive integers divisibility and concludes.

Q2 (3 marks): [1] Base case verified. [1] Inductive step correctly applies product rule and hypothesis. [1] Explicit conclusion naming mathematical induction.

Q3 (2 marks): [1] Error identified: assuming $P(k+1)$ is circular. [1] Correct approach: assume $P(k)$ is true, then derive that $P(k+1)$ must also be true.

01
Boss battle · The Proof Master
earn bronze · silver · gold

Five timed questions spanning all Module 5 proof techniques. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). This is the module finale — give it your best.

⚔ Enter the arena
02
Science Jump · platform challenge

Climb platforms by answering mixed proof questions. Lighter alternative to the boss.

Mark lesson as complete

Tick when you've finished the practice and review. You've completed Module 5!

🎓
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