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📖 Lesson 13 ⏱ ~30 min Year 10 · Unit 3 ⚡ +115 XP

Newton's Second Law, F = ma

In 1999, Cadbury engineers used F = ma to design a production line that accelerates 1.2 kg chocolate blocks at 4 m/s² without breaking them.

Today's hook: At the 2000 Sydney Olympics, sprint start data showed that 70 kg Cathy Freeman left her starting block with a ground reaction force of about 700 N, accelerating at 10 m/s², exactly matching $F = ma$. A 100 kg rugby player receiving the same 700 N push accelerates at only 7 m/s². That three-symbol formula predicted both results 313 years before modern sensors confirmed them. What do you predict would happen to Cathy Freeman's acceleration if she carried a 30 kg backpack?
0/5QUESTS
Warm-up
Think First
+5 XP each

Imagine pushing two trolleys with the same force, one empty and one loaded with bricks. Which one accelerates faster? What does this suggest about the relationship between mass and acceleration?

If you double the force applied to an object AND double its mass at the same time, what happens to its acceleration? Try to predict before you learn the formula.

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Learning objectives
What you'll master
3 areas

● Know

  • That acceleration is proportional to net force and inversely proportional to mass
  • The equation F = ma and the units newton (N), kilogram (kg) and metres per second squared (m/s²)
  • How to rearrange F = ma to find force, mass or acceleration

● Understand

  • Why a larger mass requires a larger force for the same acceleration
  • That F = ma only applies to the net (unbalanced) force on an object
  • How experimental data can confirm the relationship between force, mass and acceleration

● Can do

  • Calculate force, mass or acceleration using F = ma
  • Design and describe a practical investigation into force, mass and acceleration
  • Analyse data from an investigation to identify the F = ma relationship
Cross-lesson links: F = ma unifies the force ideas from Lessons 11-12 with the motion graphs you will draw in Lesson 15; it also reappears in Lesson 20 when you link Newton's laws to wave energy and tsunamis.
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Vocabulary · tap to flip
Words You Need
6 terms
Core term Concept Skill Reference
Newton's second law
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Newton's second law
The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass: F = ma.
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Force (F)
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Force (F)
A push or pull measured in newtons (N). One newton is the force needed to accelerate a 1 kg mass at 1 m/s².
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Mass (m)
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Mass (m)
The amount of matter in an object, measured in kilograms (kg). Mass resists changes in motion (inertia).
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Acceleration (a)
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Acceleration (a)
The rate at which velocity changes, measured in metres per second squared (m/s²).
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Net force
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Net force
The overall force on an object when all individual forces are combined. Only a net force causes acceleration.
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Newton (N)
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Newton (N)
The SI unit of force. 1 N = 1 kg × 1 m/s².
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Stop & Check, What Is F = ma
Quick Check
+5 XP

Push an empty shopping trolley gently and it rolls away easily; push a trolley loaded with 40 kg of groceries with the same force and it barely moves. Double the force on the full trolley and it accelerates just as the empty one did. Newton's Second Law of Motionthe cornerstone of classical mechanics, captures this exactly: the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

F = ma

Where F is net force (in newtons), m is mass (in kilograms), and a is acceleration (in m/s²).

This equation tells us three crucial things:

  1. Acceleration is in the same direction as the net force.
  2. For a given mass, greater force produces greater acceleration.
  3. For a given force, greater mass produces smaller acceleration.

The unit of force, the newton, is defined from this law: 1 N is the force required to accelerate 1 kg at 1 m/s².

Newton Second Law is a vector equation. In two or three dimensions, it applies separately to each component: Fx = max, Fy = may, Fz = maz.

Formula Triangle F m a Cover what you want to find Force ↑ → Acceleration ↑ F = 10N a = 2 m/s² F = 20N a = 4 m/s² Mass ↑ → Acceleration ↓ m = 5kg a = 4 m/s² m = 10kg a = 2 m/s² Units F = m × a N = kg × m/s² F (force) → Newtons (N) m (mass) → kilograms (kg) a (acceleration) → m/s² 1 N = 1 kg·m/s²
Example

A 1,000 kg car accelerates from 0 to 100 km/h (27.8 m/s) in 10 seconds. What net force is required?

Acceleration a = Δv/Δt = 27.8/10 = 2.78 m/s².

Force F = ma = 1,000 × 2.78 = 2,780 N.

This is about the force needed to lift a 280 kg mass. In reality, the engine must produce more force than this to overcome rolling resistance and air drag. At 100 km/h, air drag might be 500 N and rolling resistance 200 N, so the engine must provide about 3,500 N total at the wheels. This is why acceleration decreases at high speeds - more force is diverted to overcoming drag, leaving less for acceleration.

Real-world anchor

Australian automotive engineering: Holden (now defunct) and other Australian automotive engineers used F=ma in every aspect of vehicle design. Crashworthiness analysis calculates the forces on occupants during collisions. Acceleration performance determines engine and transmission specifications. Braking systems must generate sufficient friction force to decelerate the vehicle mass safely. The Australasian New Car Assessment Program (ANCAP) uses Newton Second Law to evaluate how well vehicles protect occupants in crashes, measuring the forces transmitted to crash test dummies.

Watch out

F = ma means force causes mass or mass causes force. This is false. The equation is a relationship between three quantities, not a causal chain. Force causes acceleration; mass resists it. You cannot rearrange the equation to say m = F/a and conclude that force causes mass. Mass is an intrinsic property. The equation tells us how much acceleration results from a given force on a given mass. It does not imply that any one variable causes another in a unidirectional sense.

Fill the blanks+4 XP

Complete Newton Second Law equation and explanation.

Newton Second Law states that = × . This means acceleration is directly proportional to the force and inversely proportional to the . If you double the force on an object while keeping mass constant, the acceleration .
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Working with F = ma at this level
Units and Calculations
+5 XP

Net force (or resultant force) is the vector sum of all forces acting on an object. It is the single force that would produce the same acceleration as all the actual forces combined.

To find net force:

  1. Identify all forces acting on the object.
  2. Resolve forces into components if necessary.
  3. Add forces in each direction separately.
  4. The net force in each direction gives the acceleration in that direction via F=ma.

Common force combinations:

  • Object on horizontal surface: Net force = applied force - friction. If no applied force, net force = 0 and object remains at rest or constant velocity.
  • Object on slope: Resolve weight into components parallel and perpendicular to the slope. Net force parallel to slope = mg sin(θ) - friction.
  • Object in lift: Net force = normal force - weight. If lift accelerates upward, normal force > weight (you feel heavier). If downward, normal force < weight (you feel lighter).
Example

A 70 kg person stands in a lift that accelerates upward at 2 m/s². What is the normal force from the floor?

Forces acting: Normal force N (upward), weight W = mg = 70 × 9.8 = 686 N (downward).

Net force F = ma = 70 × 2 = 140 N (upward).

Since F = N - W, we have N = F + W = 140 + 686 = 826 N.

The person feels heavier because the floor pushes up with 826 N instead of the usual 686 N. This apparent weight increase is why you feel pushed into your seat when a lift accelerates upward. Conversely, if the lift accelerates downward at 2 m/s², N = 686 - 140 = 546 N, and you feel lighter. If the cable breaks and the lift falls freely (a = g), N = 0 and you feel weightless.

Real-world anchor

Australian elevator safety: Australian Standard AS 1735 governs lift design and safety. Engineers calculate the maximum forces on lift components using F=ma, including emergency braking scenarios where deceleration can reach several g. The safety gear must arrest a falling lift without exceeding forces that would injure occupants. Australian skyscrapers like Q1 on the Gold Coast (height 323 m) have lifts that accelerate and decelerate carefully to manage passenger comfort while minimising travel time. The physics of F=ma is built into every lift controller.

Watch out

An object moving at constant velocity has no forces acting on it. This is false. An object moving at constant velocity has zero net force (balanced forces), but individual forces may be present. A car at constant speed has engine thrust balancing drag and friction. A skydiver at terminal velocity has weight balancing air resistance. Newton First Law says constant velocity implies zero net force, not zero force. This distinction is crucial for analysing real-world situations where multiple forces act simultaneously.

A 500 kg rocket experiences 8,000 N upward thrust and 4,900 N downward weight. What is its upward acceleration?
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Stop & Check, Practical Investigation
Quick Check
+5 XP

Free-body diagrams are essential tools for applying Newton Second Law. They show all forces acting on a single object, represented as arrows pointing in the direction of each force.

Steps for drawing a free-body diagram:

  1. Identify the object of interest.
  2. Draw it as a simple shape (usually a dot or box).
  3. Identify all forces acting ON the object (not forces the object exerts on others).
  4. Draw arrows from the object in the direction of each force. Label each arrow.
  5. Choose a coordinate system (usually horizontal and vertical, or parallel and perpendicular to a slope).
  6. Resolve forces into components if necessary.
  7. Apply F=ma in each direction.

Free-body diagrams prevent common errors like double-counting action-reaction pairs or including forces that act on other objects.

Example

A 5 kg box is pushed up a 30° frictionless slope by a 40 N force parallel to the slope.

Free-body diagram forces:

  • Applied force: 40 N up the slope
  • Weight: mg = 49 N vertically down
  • Normal force: perpendicular to slope (unknown magnitude)

Resolve weight into components:

  • Parallel to slope (down): mg sin(30°) = 49 × 0.5 = 24.5 N
  • Perpendicular to slope: mg cos(30°) = 49 × 0.866 = 42.4 N

Net force parallel to slope: 40 - 24.5 = 15.5 N up the slope.

Acceleration: a = F/m = 15.5/5 = 3.1 m/s² up the slope.

Normal force balances the perpendicular component: N = 42.4 N.

This systematic approach works for any mechanics problem.

Real-world anchor

Australian engineering education: Australian universities teaching engineering mechanics emphasise free-body diagrams as the foundation of statics and dynamics. The University of Sydney, UNSW, and Monash have strong civil and mechanical engineering programs where students analyse forces on bridges, buildings, and machines. The Institution of Engineers Australia requires graduates to demonstrate competency in force analysis and Newtonian mechanics. Free-body diagrams are not just academic exercises - they are the starting point for designing safe, efficient Australian infrastructure.

Watch out

Action-reaction pairs appear on the same free-body diagram. This is false. Newton Third Law action-reaction pairs act on different objects and never appear on the same free-body diagram. If you are drawing a free-body diagram for a book on a table, you include the table upward force on the book. You do NOT include the book downward force on the table - that force acts on the table, not the book. Including action-reaction pairs on the same diagram is one of the most common errors in mechanics and leads to incorrect net force calculations.

A 2 kg block is pulled across a frictionless surface by a 10 N horizontal force. What is its acceleration?
Heads-up · common traps
Spot the Trap
3 myths

Wrong: "Heavier objects fall faster than light objects." No, in the absence of air resistance, all objects fall with the same acceleration (about 9.8 m/s² near Earth's surface). A hammer and a feather dropped on the Moon land together. Air resistance on Earth makes lighter objects with large surface areas fall more slowly.

Right: All objects experience the same gravitational acceleration (g ≈ 9.8 m/s²) near Earth's surface, regardless of their mass. On the Moon, where there is no air resistance, a hammer and a feather fall at exactly the same rate. On Earth, air resistance slows some objects more than others, but this is not because of their weight.

Wrong: "More force always means more acceleration, no matter the mass." Not necessarily. Acceleration depends on both force and mass. A small force on a tiny mass can produce a huge acceleration, while a large force on a massive object might produce only a small acceleration.

Right: Acceleration depends on BOTH force and mass: a = F ÷ m. Doubling the force doubles acceleration, but doubling the mass halves it. A small car with a powerful engine can out-accelerate a heavy truck with the same engine, because the lower mass makes the force more effective.

Wrong: "Mass and weight are the same thing." No, mass is the amount of matter (kg) and does not change with location. Weight is the force of gravity on that mass (N) and changes depending on gravity. On the Moon you have the same mass but less weight.

Right: Mass (kg) is the amount of matter in an object and stays the same everywhere in the universe. Weight (N) is the gravitational force acting on that mass and changes with location, on the Moon, you have the same mass but about one-sixth of your Earth weight. Weight = mass × gravitational field strength (W = mg).

Australian Context

Forces in Australian Sport and Transport

Australian Rules Football: When a player kicks a football, the force they apply and the mass of the ball determine its acceleration off the boot. A lighter ball (like a Sherrin) accelerates more for the same kick force than a heavier medicine ball would.

V8 Supercars: Engineers constantly balance force and mass. A lighter car with a powerful engine achieves greater acceleration. Race teams use carbon fibre and lightweight materials to reduce mass while maintaining structural strength and safety.

Road trains: Australia's long road trains can have a total mass exceeding 100 tonnes. Drivers must allow enormous stopping distances because the massive mass resists changes in motion, a direct consequence of F = ma. A small car can brake much more quickly because its smaller mass means the same braking force produces a larger deceleration.

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From the lesson
Copy Into Books

✍ Copy Into Your Books

Newton's Second Law

  • F = ma
  • Acceleration is proportional to net force
  • Acceleration is inversely proportional to mass

Units

  • Force: newton (N)
  • Mass: kilogram (kg)
  • Acceleration: m/s²
  • 1 N = 1 kg × 1 m/s²

Rearranging F = ma

  • F = ma
  • m = F ÷ a
  • a = F ÷ m
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From the lesson
Activity 1
Activity 1

Calculate with F = ma

Use the equation F = ma to solve each problem. Show your working and include units.

1 A 20 kg box is pushed with a net force of 60 N. Calculate its acceleration.
Answer in your book.
2 A car accelerates at 3 m/s² when a net force of 4500 N acts on it. What is the car's mass?
Answer in your book.
3 A 0.5 kg hockey ball is hit and accelerates at 20 m/s². What is the net force on the ball?
Answer in your book.
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From the lesson
Activity 2
Activity 2

Investigate the Relationship

Apply your understanding of force, mass and acceleration to these practical thinking questions.

1 Describe how you would test whether acceleration is proportional to force using a trolley, runway and hanging masses.
Answer in your book.
2 Explain why a fully loaded truck accelerates much more slowly than the same truck when empty, even with the same engine force.
Answer in your book.
3 A student claims that because F = ma, doubling both the force and the mass will keep the acceleration the same. Is the student correct? Explain with a calculation.
Answer in your book.
Reflect
Revisit your thinking
reflect

At the start of this lesson you were shown a 70 kg sprinter and a 100 kg rugby player receiving the same push from a starting block, the lighter sprinter accelerating faster, proving that force, mass, and acceleration are tightly linked.

Now that you've worked through the lesson, how has your thinking shifted? Can you explain that hook idea more precisely using what you've learned today?

Interactive Tool, Newton's Laws Lab Open fullscreen ↗
Newton's Second Law: F = ma. If mass doubles and force stays the same, acceleration:
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Quick check
According to Newton's second law, what happens to the acceleration of an object if the net force on it doubles while the mass stays the same?
+10 XP
2
Quick check
A 10 kg object experiences a net force of 40 N. What is its acceleration?
+10 XP
3
Quick check
Which set of units is correct for calculating with F = ma?
+10 XP
4
Quick check
Two identical rockets are launched. Rocket A carries a 500 kg satellite; Rocket B carries a 1000 kg satellite. Both engines produce the same thrust. Which statement is true?
+10 XP
5
Quick check
In a trolley investigation, a student keeps the pulling force constant and doubles the mass of the trolley each time. Which graph shape correctly shows acceleration against mass?
+10 XP
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From the lesson
Additional content
Short answer · explain in your own words
Show your reasoning
3 questions
Understand Core 2 marks

Q1. 1. Explain what Newton's second law (F = ma) tells us about the relationship between force, mass and acceleration. Use the terms "directly proportional" and "inversely proportional" in your answer. 4 MARKS

Apply Core 3 marks

Q2. 2. A 1200 kg car accelerates from rest to 15 m/s in 5 seconds. Calculate the net force acting on the car. Show all working. 4 MARKS

Analyse Core 3 marks

Q3. 3. Describe a practical investigation you could conduct to show that acceleration is inversely proportional to mass. Include the equipment you would use, the variables you would control, and how you would process your data. 4 MARKS

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From the lesson
Revisit

Revisit Your Thinking

Go back to your Think First answer. Has your understanding changed?

  • Would you now explain why the empty trolley accelerates faster?
  • Can you use F = ma to predict what happens when the force on the full trolley is doubled?
Update your thinking in your book.
Model answers (click to reveal)

Answers

MCQ 1

CIf the net force doubles while mass stays constant, acceleration also doubles. This is because acceleration is directly proportional to force (a = F/m).

MCQ 2

BUsing a = F ÷ m = 40 N ÷ 10 kg = 4 m/s².

MCQ 3

DThe correct SI units are: force in newtons (N), mass in kilograms (kg), and acceleration in metres per second squared (m/s²).

MCQ 4

ASince a = F/m and the thrust (F) is the same for both rockets, the rocket with less mass (Rocket A) will have a larger acceleration. Mass and acceleration are inversely proportional when force is constant.

MCQ 5

BAcceleration is inversely proportional to mass (a ∝ 1/m). As mass increases, acceleration decreases. This produces a curved graph that falls as mass rises, not a straight line.

Short Answer 1

Model answer: Newton's second law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. "Directly proportional" means that if the net force doubles (and mass stays the same), the acceleration also doubles. "Inversely proportional" means that if the mass doubles (and force stays the same), the acceleration halves. The equation F = ma combines both relationships: a larger force produces more acceleration, while a larger mass produces less acceleration for the same force.

Short Answer 2

Model answer: First, calculate acceleration using a = Δv ÷ Δt = (15 m/s − 0 m/s) ÷ 5 s = 3 m/s². Then use F = ma to find the net force: F = 1200 kg × 3 m/s² = 3600 N. The net force acting on the car is 3600 N.

Short Answer 3

Model answer: Equipment: dynamics trolley, runway, pulley, string, hanging masses, ticker timer or motion sensor, balance. Method: keep the pulling force constant by using the same hanging mass each time, but vary the mass of the trolley by adding known masses to it. Measure the acceleration for each trolley mass using the motion sensor. Control variables: pulling force, runway angle, surface type. Process data: plot a graph of acceleration (y-axis) against 1/mass (x-axis). If acceleration is inversely proportional to mass, this graph should be a straight line passing through the origin, confirming the relationship.

Quick-fire challenge
Game time
+25 XP
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