Physics • Year 12 • Module 6: Electromagnetism • Lesson 1

Electric Fields and Coulomb’s Law Review

Lock in the core vocabulary, the key formulas E = V/d and F = qE, and the direction rules for charged particles before tackling harder problems.

Build · Vocab & Recall

1. Term–definition match

The definitions below are shuffled. In the right-hand column write the matching term from this list: electric field, uniform electric field, potential difference, electric field strength (parallel plates), elementary charge, Coulomb’s law, Coulomb’s constant, field line, test charge, coulomb. 10 marks (1 each)

#DefinitionMatching term
1.1A region in space where a charged particle experiences a force; defined as force per unit positive charge at a point.
1.2A field with constant magnitude and direction at every point in the region, produced between two large parallel conducting plates.
1.3The work done per unit positive charge to move between two points; measured in volts (V).
1.4The relationship E = V/d, where d is the perpendicular separation of the plates.
1.5The magnitude of the charge carried by a single proton or electron: 1.60 × 10−19 C.
1.6The law stating that the electrostatic force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.
1.7The proportionality constant k ≈ 8.99 × 109 N m2 C−2 that appears in Coulomb’s law F = kq1q2/r2; its SI units ensure that forces are in newtons when charges are in coulombs and distances in metres.
1.8An imaginary line drawn in a field such that the tangent at any point gives the direction of the force on a positive test charge.
1.9A hypothetical particle with a tiny positive charge used to probe the field without disturbing it.
1.10The SI unit of electric charge, equal to the charge transported by a current of one ampere in one second.
Stuck? Revisit the Key Terms panel and Cards 1–3 in the lesson.

2. True or false — with correction

Circle T or F for each statement. If the statement is false, write the corrected version on the line below it. 12 marks (1 T/F + 1 correction each)

2.1 Between two large parallel plates connected to a battery, the electric field is stronger near the positive plate than near the negative plate.    T  /  F

2.2 A negative charge placed in a uniform electric field experiences a force in the opposite direction to the field.    T  /  F

2.3 If the plate separation is doubled while the battery voltage is kept constant, the electric field strength doubles.    T  /  F

2.4 Coulomb’s law applies to point charges; the field between parallel plates does not follow an inverse-square law.    T  /  F

2.5 An electron has a larger charge magnitude than a proton, which is why it accelerates faster in an electric field.    T  /  F

2.6 Electric field lines between parallel plates always point from the positive plate toward the negative plate.    T  /  F

Stuck? Revisit the “Misconceptions to Fix” box and the field-line diagram in the lesson.

3. Fill-in-the-blank paragraph

Use the word bank to complete the passage. Each word or phrase is used once. 8 marks (1 per blank)

Word bank:

coulombs  ·  opposite  ·  uniform  ·  potential difference  ·  inverse-square  ·  qE  ·  V/d  ·  positive plate

Between two large parallel plates, the electric field is ___________ in magnitude and direction because the contributions from many surface charges add up evenly. Its strength is given by the formula E = ___________, where the numerator is the ___________ in volts and the denominator is the plate separation in metres. In contrast, the field around a single point charge follows an ___________ law and is not uniform. The force on any charge q in the field is F = ___________, measured in newtons when q is in ___________. A positive charge experiences force toward the negative plate; a negative charge experiences force toward the ___________. This is because the force on a negative charge is ___________ in direction to the electric field vector.

Stuck? Revisit Cards 1, 2, and 3 in the lesson, and the formula panel for E = V/d.

4. Function recall

Answer each question in 1–2 sentences using precise terms from the lesson. 8 marks (2 each)

4.1 What physical quantity does the spacing of electric field lines represent?

4.2 Why is gravitational force on an electron negligible compared with the electric force in a typical parallel-plate problem?

4.3 What is the function of the constant k in Coulomb’s law, and what are its SI units?

4.4 Why can the formula E = V/d not be applied to the field around a single point charge?

Stuck? Revisit the Key Terms panel, the stop-and-check boxes, and Cards 1 and 3 in the lesson.

5. Build a concept map

Draw labelled arrows between the six terms below to show how they connect. Each arrow must carry a linking phrase (e.g. “is calculated using”, “determines the”, “causes a”). Aim for at least 6 labelled arrows. 6 marks (1 per valid labelled arrow)

Supplied terms: electric field (E) · potential difference (V) · plate separation (d) · force on charge (F) · charge (q) · acceleration (a).

electric field (E)
potential difference (V)
plate separation (d)
force on charge (F)
charge (q)
acceleration (a)
Try: V and d → determine → E; E and q → give → F; F and mass → give → a; V doubles → E doubles; d halves → E doubles.

6. Label the parallel-plate diagram

The diagram below shows two parallel plates and a charged particle between them. Write the correct label or value for each box A–F. 6 marks (1 each)

Label the parallel-plate diagram
BoxLabel or description
A
B
C
D
E
F
Stuck? Revisit Figure 1 and Figure 2 in the lesson and the “Force on a Charged Particle” card.
Answers — Do not peek before attempting

Q1 — Term–definition match

1.1 electric field • 1.2 uniform electric field • 1.3 potential difference • 1.4 electric field strength (parallel plates) • 1.5 elementary charge • 1.6 Coulomb’s law • 1.7 Coulomb’s constant • 1.8 field line • 1.9 test charge • 1.10 coulomb.

Q2 — True / false with correction

2.1 False. Between large parallel plates the field is uniform — it has the same magnitude everywhere between the plates, not stronger near one plate. E = V/d is constant throughout the gap.

2.2 True. The force on a negative charge is F = qE; since q is negative, F is in the opposite direction to E.

2.3 False. If the separation is doubled (d → 2d) and voltage is constant, E = V/d halves, not doubles.

2.4 True. Coulomb’s law (F ∝ 1/r2) applies to point charges; the parallel-plate field is an idealisation for large plates where many surface charges produce a uniform field independent of position.

2.5 False. An electron and a proton have the same magnitude of charge (1.60 × 10−19 C). The electron accelerates faster because it has a much smaller mass, not a larger charge.

2.6 True. By convention, field lines point in the direction a positive test charge would move — from positive to negative plate.

Q3 — Cloze paragraph

In order: uniform / V/d / potential difference / inverse-square / qE / coulombs / positive plate / opposite.

Q4.1 — Spacing of field lines

The spacing (density) of field lines represents the magnitude of the electric field strength. Closely spaced lines indicate a stronger field; widely spaced lines indicate a weaker field. Between parallel plates, the lines are equally spaced because the field is uniform.

Q4.2 — Negligible gravity

The gravitational force on an electron is Fg = meg ≈ (9.11 × 10−31)(9.8) ≈ 8.9 × 10−30 N. Even in a weak electric field of 10 V/m, the electric force is FE = eE = 1.60 × 10−18 N — about 1011 times larger. Gravity is therefore completely negligible for charged particles in electric fields.

Q4.3 — Coulomb’s constant k

Coulomb’s constant k = 8.99 × 109 N m2 C−2 is the proportionality constant in Coulomb’s law F = kq1q2/r2. Its SI units (N m2 C−2) ensure that when charges are in coulombs and distance is in metres, the calculated force is in newtons.

Q4.4 — Why E = V/d cannot be used for a point charge

E = V/d assumes the field is uniform — constant in magnitude and direction between two plates with a fixed separation d. Around a single point charge the field is radial and follows E = kQ/r2; the field strength varies with distance. There is no single “separation” d to use in E = V/d.

Q5 — Sample concept map

Correct maps should include arrows such as:

  • potential difference (V) and plate separation (d)together determineelectric field (E) via E = V/d
  • electric field (E) and charge (q)together determineforce on charge (F) via F = qE
  • force on charge (F)causesacceleration (a) via Newton’s second law
  • potential difference (V)increaseselectric field (E) increases (for fixed d)
  • plate separation (d)increaseselectric field (E) decreases
  • charge (q)sign determines direction offorce on charge (F)

Award 1 mark per valid labelled arrow with a linking phrase (minimum 6).

Q6 — Parallel-plate diagram labels

A: Positive plate (+) • B: Negative plate (−) • C: Electric field line (directed downward, from + to −) • D: Direction of E-field (from positive to negative plate) • E: Positive test charge (+q) • F: Force on positive charge (arrow pointing downward / toward negative plate, in same direction as E).