Practical Investigation: Validating Projectile Motion
Between 1941 and 1945, the US Army Ballistic Research Laboratory compiled the first systematic projectile motion tables for anti-aircraft guns — measuring actual shell ranges against theoretical predictions. They found systematic deviations from the ideal model due to air resistance, providing the first large-scale experimental validation that ideal projectile motion is an approximation to physical reality.
Practise this lesson
Four printable worksheets that build from the foundations up to exam-style questions — start at whatever level suits you.
If you launch a ball horizontally from a ramp at different heights, how will the horizontal range depend on the launch height? Sketch your predicted graph before reading on.
Know
- Identify independent, dependent and controlled variables
- Select appropriate equipment and measurement techniques
Understand
- Record raw data with correct units and appropriate precision
- Process data to validate theoretical predictions
Can Do
- Compare experimental results to theoretical models
- Identify sources of error and suggest improvements
Aim & Theory
What we expect to observe based on the model
Practical setup: ball bearing rolls from ramp exit at height $h$ and lands at horizontal range $R$.
Detailed equipment layout showing retort stand, ramp exit, measuring positions and landing zone.
Aim: To determine the relationship between the launch height and the horizontal range of a projectile launched horizontally, and to compare the experimental results with the theoretical model.
Assumptions of the model:
- The vertical acceleration is constant and equal to $g = 9.8\ \text{m/s}^2$ downward
- Air resistance is negligible
- The launch velocity is horizontal (launch angle $\theta = 0°$)
For a horizontal launch from height $h$ with speed $v_x$:
Theoretical Prediction
If $v_x$ and $g$ are constant, then $R \propto \sqrt{h}$. A graph of $R$ versus $\sqrt{h}$ should be a straight line through the origin with gradient $v_x\sqrt{2/g}$.
Because $R \propto \sqrt{h}$, doubling the launch height does not double the range. Quadrupling the height doubles the range. This non-linear relationship is what the experiment will test.
For a horizontal launch from height $h$: time of flight $t = \sqrt{2h/g}$ and range $R = v_x\sqrt{2h/g}$, so $R \propto \sqrt{h}$. Plot $R$ vs $\sqrt{h}$ — a straight line through the origin with gradient $v_x\sqrt{2/g}$ validates the model.
Pause — copy the highlighted theoretical prediction and the graph strategy into your book before moving on.
Quick check: According to the theoretical model, if the launch height is quadrupled (multiplied by 4), the horizontal range will:
Method
A reproducible procedure for collecting valid data
We just saw the theoretical prediction: $R \propto \sqrt{h}$. That raises a question: how do we design the experiment to test this fairly and reproducibly? This card answers it → variables, equipment, and a step-by-step procedure that controls $v_x$ at each height.
Equipment:
- Ball bearing or small solid sphere (minimise air resistance)
- Smooth ramp or track with horizontal exit section
- Retort stand and clamp
- Metre ruler (±1 mm)
- Carbon paper and white paper (or motion sensor / video camera)
- Balance (to measure mass, optional)
- Stopwatch (±0.01 s, optional for time-of-flight check)
Variables:
- Independent: Launch height $h$ (measured from floor to exit point)
- Dependent: Horizontal range $R$ (measured from base of ramp to landing point)
- Controlled: Launch speed $v_x$ (same release position on ramp), same ball, same surface, minimal air movement
Procedure:
- Set up the ramp so the exit is perfectly horizontal. Check with a spirit level.
- Place carbon paper over white paper on the floor to mark landing positions.
- Release the ball from a fixed position on the ramp. Do not push — let it roll from rest to ensure consistent speed.
- Measure the vertical height $h$ from the floor to the centre of the ball at the exit point.
- Measure the horizontal range $R$ from the point directly below the exit to the centre of the landing mark.
- Repeat for at least 5 different heights, keeping the release position constant.
- At each height, perform at least 3 trials and average the range.
Ensure the landing area is clear. Use a ball that will not roll into traffic or off benches. Wear safety glasses if using a spring launcher.
IV = launch height $h$ (m); DV = horizontal range $R$ (m); controlled = same release point on ramp (constant $v_x$), same ball. Use minimum 5 heights, 3 trials each; carbon paper marks the first-contact point.
Add the highlighted variables table to your notes before the check below.
Did you get this? True or false: releasing the ball from a different position on the ramp for each trial is an acceptable way to vary the launch height.
Results
Record your primary data here
We just saw the method — 5 heights, 3 trials each, carbon paper landing marks. That raises a question: how should the results be organised to make analysis straightforward? This card answers it → a table with $\sqrt{h}$ pre-computed and uncertainty as half-spread of the three trials.
| Trial | Height $h$ (m) | $\sqrt{h}$ (m½) | Range $R_1$ (m) | Range $R_2$ (m) | Range $R_3$ (m) | Mean Range $\bar{R}$ (m) | Uncertainty (m) |
|---|---|---|---|---|---|---|---|
| 1 | |||||||
| 2 | |||||||
| 3 | |||||||
| 4 | |||||||
| 5 |
Sample data (for comparison if you cannot perform the experiment):
| Height $h$ (m) | $\sqrt{h}$ (m½) | Mean Range $\bar{R}$ (m) |
|---|---|---|
| 0.10 | 0.316 | 0.32 |
| 0.20 | 0.447 | 0.45 |
| 0.30 | 0.548 | 0.55 |
| 0.40 | 0.632 | 0.64 |
| 0.50 | 0.707 | 0.71 |
These sample data assume $v_x \approx 1.0\ \text{m/s}$ and $g = 9.8\ \text{m/s}^2$.
Results table must include: $h$, $\sqrt{h}$, three range trials, mean $\bar{R}$, and uncertainty $\Delta R = (R_\text{max} - R_\text{min})/2$. The $\sqrt{h}$ column is essential — it linearises the relationship for graphing.
Pause — draw the results table with these column headings in your book before the next section.
Fill the gap: To linearise the relationship $R = v_x\sqrt{2h/g}$, you should plot $R$ (vertical axis) versus (horizontal axis).
Analysis
Compare experiment to theory
We just saw how to set up the results table with $\sqrt{h}$ values. That raises a question: how do we extract a launch speed from the graph and check how well the model fits? This card answers it → measure the gradient of the $R$ vs $\sqrt{h}$ line and compare it to $m_\text{theory} = v_x\sqrt{2/g}$.
Step 1 — Plot the graph
Plot $\bar{R}$ (vertical axis) versus $\sqrt{h}$ (horizontal axis). Draw a line of best fit.
Step 2 — Determine the gradient
The theoretical gradient is:
$$m_{\text{theory}} = v_x \sqrt{\dfrac{2}{g}}$$
From your graph, calculate the experimental gradient $m_{\text{exp}}$ using:
$$m_{\text{exp}} = \dfrac{\Delta R}{\Delta \sqrt{h}}$$
Step 3 — Compare
Calculate the percentage difference:
$$\%\ \text{difference} = \dfrac{|m_{\text{exp}} - m_{\text{theory}}|}{m_{\text{theory}}} \times 100\%$$
Step 4 — Calculate launch speed from data
Rearranging the gradient formula:
$$v_x = m_{\text{exp}} \sqrt{\dfrac{g}{2}}$$
Compare this calculated $v_x$ to any independent measurement of launch speed (e.g., from a motion sensor or timing gate).
A well-conducted investigation should yield a percentage difference under 10%. If your difference is larger than 15%, review your measurement technique and controlled variables.
Plot $\bar{R}$ vs $\sqrt{h}$; gradient $m_\text{exp} = \Delta R/\Delta\sqrt{h}$; theoretical gradient $m_\text{theory} = v_x\sqrt{2/g}$; accept $<10\%$ difference. Launch speed from data: $v_x = m_\text{exp}\sqrt{g/2}$.
Add the highlighted analysis steps and acceptance criterion to your notes before the check below.
Quick check: A student obtains an experimental gradient of $m_\text{exp} = 1.02$ m½ from their graph. The theoretical gradient is $m_\text{theory} = 0.95$ m½. The percentage difference is closest to:
Error Analysis
Working Scientifically — identify and address limitations
We just saw how to validate the model by comparing experimental and theoretical gradients. That raises a question: what causes discrepancies, and how can the experiment be improved? This card answers it → classify errors as systematic or random, then propose targeted improvements.
Systematic errors:
- Ramp not perfectly horizontal: A slight upward angle increases range; downward decreases it. Check with a spirit level.
- Air resistance: Significant for light objects or high speeds. Use a dense ball bearing.
- Release position inconsistent: If the ball is pushed or released from slightly different points, $v_x$ varies. Use a release gate or marked release line.
Random errors:
- Parallax in height measurement: Read the ruler at eye level.
- Uncertainty in landing position: The ball may bounce or roll slightly. Carbon paper helps mark the first contact point.
- Timing uncertainty: If measuring time of flight with a stopwatch, human reaction time (~0.2 s) is a significant source of error.
Reliability:
- Repeating trials at each height and averaging reduces random error.
- A spread of at least 5 different heights tests the model across a range of conditions.
Improvements:
- Use a video camera or motion sensor to measure $v_x$ independently and compare.
- Conduct the experiment in a vacuum chamber (advanced) to eliminate air resistance.
- Use a photogate at the exit to measure $v_x$ directly and verify the constant-speed assumption.
Systematic errors (tilted ramp, air resistance, inconsistent release) shift all results in one direction; random errors (parallax, landing spread) are reduced by averaging. Key improvement: photogate at ramp exit directly measures $v_x$.
Pause — copy the highlighted error classification and improvement into your book before moving on.
Quick check: A student finds that the ball consistently lands slightly further than predicted. This is most likely caused by:
A second validation using a different relationship
We just saw how to classify and address experimental errors. That raises a question: is there an independent check that confirms the horizontal and vertical motions are truly independent? This card answers it → if $v_x = R/t$ is constant across all heights, it directly confirms the independence principle.
The theoretical time of flight is $t = \sqrt{2h/g}$. If you can measure $t$ independently (e.g., with a motion sensor or slow-motion video), you can validate:
$$R = v_x \cdot t$$
Rearranging: $v_x = R/t$. Calculate $v_x$ from each $(R, t)$ pair. If $v_x$ is approximately constant across all heights, this confirms that horizontal speed is unaffected by vertical motion — a fundamental assumption of the projectile model.
| Height $h$ (m) | Theoretical $t$ (s) | Measured $t$ (s) | $\%$ difference |
|---|---|---|---|
| 0.20 | 0.20 | ||
| 0.40 | 0.29 | ||
| 0.60 | 0.35 |
Theoretical times use $t = \sqrt{2h/g}$ with $g = 9.8\ \text{m/s}^2$.
Reliability check: compute $v_x = R/t$ at each height (using theoretical $t = \sqrt{2h/g}$). A constant $v_x$ across all heights confirms that horizontal speed is unaffected by vertical motion — the key assumption of the projectile model.
Add the highlighted reliability-check method to your notes before the activities.
Did you get this? True or false: if $v_x = R/t$ is approximately constant across all five heights, this supports the claim that horizontal and vertical motion are independent.
Activities
Practise resolving and analysing motion.
A projectile is launched at 24 m/s, 44° above the horizontal. Find the horizontal and vertical components of the initial velocity.
At a point in flight, the horizontal velocity is 16 m/s and the vertical velocity is 12 m/s. Find the resultant velocity (magnitude and direction).
A ball is thrown horizontally at 12 m/s from a cliff 24 m high. Calculate the time of flight and the horizontal distance travelled.
Explain the independence of horizontal and vertical motion.
Explain why a projectile launched horizontally and one dropped from the same height hit the ground simultaneously. Use the concept of independence of horizontal and vertical motion in your answer.
At the start you were asked to predict the graph of horizontal range versus launch height. The model shows $R \propto \sqrt{h}$ — a square-root relationship, not a linear one.
This is exactly what the US Army Ballistic Research Laboratory (1941–1945) discovered when they systematically measured shell ranges against predictions: the ideal model gave a consistent baseline, and deviations from it (due to air resistance) were systematic and repeatable. Doubling $h$ multiplies $R$ by $\sqrt{2} \approx 1.41$; quadrupling $h$ doubles $R$. Plotting $R$ vs $\sqrt{h}$ gives the straight line that validates — or exposes gaps in — the ideal projectile model.
A fresh set drawn from this lesson's question bank. Pick your answer, then rate your confidence.
Q1. Explain why the ball must be released from the same position on the ramp for every trial. What variable would be affected if the release position changed? (3 marks)
Q2. A student obtains a curved graph when plotting $R$ versus $h$, but a straight line when plotting $R$ versus $\sqrt{h}$. Explain why this observation validates the theoretical model $R = v_x\sqrt{2h/g}$. Include the physical meaning of the gradient in your answer. (4 marks)
Q3. Evaluate the assumption that air resistance is negligible in this experiment. Under what conditions would air resistance become significant? Describe how the experimental graph would deviate from the theoretical prediction if air resistance were significant, and explain the shape of this deviation. (5 marks)
Show model answers
Multiple Choice
MC answers and full explanations are shown inline as you complete each question. Use the retry button to attempt a fresh set from the lesson bank.
Q1 (3 marks)
The release position determines the gravitational potential energy converted to kinetic energy, which controls the horizontal launch speed $v_x$ (1 mark). If the release position changes, $v_x$ changes, making $v_x$ an uncontrolled variable (1 mark). Since $R \propto v_x$, any change in $v_x$ directly affects the range, confounding the relationship between $h$ and $R$ that we are trying to validate (1 mark).
Q2 (4 marks)
The theoretical model predicts $R = v_x\sqrt{2/g} \cdot \sqrt{h}$, which is a linear relationship between $R$ and $\sqrt{h}$ passing through the origin (1 mark). The straight-line graph confirms this proportional relationship, while the curved $R$-$h$ graph reflects the square-root dependence (1 mark). The gradient of the $R$ versus $\sqrt{h}$ graph equals $v_x\sqrt{2/g}$ (1 mark), which is constant because $v_x$ and $g$ are constant in the experiment. This provides quantitative validation: the experimental gradient can be compared to the theoretical value (1 mark).
Q3 (5 marks)
Air resistance is negligible for dense objects at low speeds, but becomes significant for light objects (e.g., ping-pong balls), large surface areas, or high speeds (1 mark). Air resistance opposes motion, reducing both horizontal speed and vertical acceleration below $g$ (1 mark). With air resistance, the experimental range would be less than the theoretical prediction at larger heights/speeds (1 mark). The graph of $R$ versus $\sqrt{h}$ would curve downward at higher values rather than remaining straight (1 mark), because air resistance increases with speed, causing greater fractional reduction in range as $h$ increases (1 mark).
Five timed questions on projectile motion and practical investigation skills. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.
⚔ Enter the arenaClimb platforms by answering projectile motion questions. Lighter alternative to the boss.
Mark Practical Complete
Tick when you have finished all sections of this practical investigation.