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HSCScience Physics · Y11 · M1
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Year 11 Physics Module 1 ⏱ ~30 min 5 MC · 3 Short Answer Lesson 3 of 8

Speed and Velocity — Rates of Motion

A speed camera on the M4 clocks a car at 108 km/h. The car's GPS log, sampled every second, never shows a steady 108 — it dips to 95 in traffic and surges to 120 to overtake. One number is the average over the whole stretch; the other is the speed at a single instant. Telling those two apart — and adding direction to make it velocity — is what this lesson is about.

Today's hook: The speed camera says 108 km/h, but the car's speedo never sat on 108 the whole trip. How can a single "speed" describe a journey where the speed kept changing?
0/5TASKS
Before you read — predict

You drive 60 km to the coast in exactly 1 hour, so your "average speed" is 60 km/h. But on the open highway your speedo read 100 km/h, and at a level crossing it read 0 km/h while you waited. How can the average be 60 when the needle was almost never on 60? Which of these numbers — 60, 100, or 0 — is the instantaneous speed, and which is the average?

Which quantity describes how fast and in which direction an object is moving?

Learning Intentions
goals

Know

  • That speed is a scalar and velocity is a vector
  • The formulas for average speed ($v = d/t$) and average velocity ($\vec{v} = \Delta x / \Delta t$)
  • The difference between average and instantaneous values
  • The units m/s and km/h, and how to convert between them
  • How data loggers, ticker timers and video analysis record motion

Understand

  • Why average speed uses distance but average velocity uses displacement
  • Why an average can hide the changing instantaneous values inside it
  • Why instantaneous velocity is the velocity over a very small time interval
  • How a practical investigation reveals both average and instantaneous velocity

Can Do

  • Calculate average speed and average velocity from data
  • Convert between m/s and km/h confidently
  • Estimate an instantaneous velocity from closely spaced position–time data
  • Design or interpret a ticker-tape / data-logger experiment for velocity
Scan these before reading
vocab
Speeda scalar: the rate at which distance is covered; how fast, with no direction (e.g. 30 m/s)
Velocitya vector: the rate of change of position (displacement) — how fast AND in which direction (e.g. 30 m/s east)
Average speedtotal distance ÷ total time taken — one number for the whole journey
Average velocitytotal displacement ÷ total time, $\vec{v} = \Delta x / \Delta t$ — carries direction
Instantaneous velocitythe velocity at a single instant — found from the displacement over a very short time interval
Data loggeran electronic device (e.g. with a motion/light-gate sensor) that records position or time automatically and rapidly
Ticker timera device that punches dots on a tape at a fixed rate (e.g. 50 dots per second), so dot spacing reveals speed
Cross-lesson links: This lesson builds directly on L01 (scalars vs vectors) and L02 (distance vs displacement): speed pairs with distance, velocity pairs with displacement. The instantaneous-vs-average idea developed here becomes the gradient of a position–time graph in L05, and the velocity quantities you calculate here feed straight into acceleration ($a = \Delta v/\Delta t$) in L04 and the equations of motion in L06.
Misconceptions to fix
Speed and velocity are just two words for the same thing.Speed is a scalar (magnitude only); velocity is a vector (magnitude + direction). A car going around a roundabout at a steady 30 km/h has constant speed but constantly changing velocity, because its direction keeps changing.
If you know the average speed, you know how fast the object was going at every moment.An average is a single summary number; the instantaneous speed can be higher or lower than the average at any given instant. Averaging deliberately throws away the moment-to-moment detail.

True or false: a car driving around a circular track at a constant 40 km/h has a constant velocity.

01
Speed and Velocity — Rate, With or Without Direction
+5 XP

"How fast?" and "how fast, and which way?" are two different questions. A pedestrian sign saying "40 m/s" tells you a rate — distance covered per second — but says nothing about direction. The moment you add "east", you have answered a richer question. That extra word is the entire difference between speed and velocity.

Speed is a scalar: it measures how fast distance is being covered, with no direction. Velocity is a vector: it measures the rate of change of position (displacement), so it carries a direction. Speed pairs with distance (both scalars); velocity pairs with displacement (both vectors).

Same number, different meaning

Speed (scalar)

"30 m/s" — fully described by a size and a unit. A speedometer reads speed. It never goes negative and ignores which way you point.

Velocity (vector)

"30 m/s east" — the same size, but now with direction. In one dimension we use a sign: +30 m/s and −30 m/s are the same speed, opposite velocities.

Australian context: A Sydney ferry's bridge display shows "speed over ground: 12 knots" — a scalar the deckhand reads at a glance. The harbour-master's radar plot shows the same ferry as an arrow: "12 knots heading 075°" — a velocity, because collision avoidance needs the direction, not just the rate.

Speed is a scalar (how fast, no direction) and pairs with distance. Velocity is a vector (how fast AND which way) and pairs with displacement. In 1D, velocity carries a + or − sign; +30 m/s and −30 m/s are the same speed but opposite velocities.

Pause — copy the speed vs velocity definitions and the rule "speed↔distance, velocity↔displacement" into your book before moving on.

Three of these are speeds (scalars). Which one is the odd one out (a velocity)?

02
Average Speed and Average Velocity
+5 XP

We just saw that speed pairs with distance and velocity pairs with displacement. That raises a question: how do we put numbers on these rates over a whole journey? This card answers it → with the average formulas, where the only difference is whether you divide distance or displacement by time.

An average compresses a whole journey into one rate. To get it, you take the total amount of motion and share it evenly across the total time — as if the object had moved steadily the entire way, even though it usually did not.

Average speed uses the total distance (a scalar). Average velocity uses the total displacement (a vector), so it keeps a direction:

Average speed (scalar) $v_{\text{av}} = \dfrac{\text{total distance}}{\text{total time}} = \dfrac{d}{t}$
Average velocity (vector) $\vec{v}_{\text{av}} = \dfrac{\text{displacement}}{\text{time}} = \dfrac{\Delta x}{\Delta t}$

Here $\Delta x$ ("delta x") means the change in position — final position minus initial position — and $\Delta t$ is the time interval. Because displacement can be smaller than distance (or even zero), average velocity can be smaller than average speed for the same trip.

The key idea: for a trip that never reverses (straight line, one way), distance = displacement, so average speed and the magnitude of average velocity are equal. The moment the object backtracks, displacement < distance, and the two averages part company.
Exam trap: the out-and-back trip. A jogger runs 2 km out and 2 km back in 30 minutes. Average speed = 4 km ÷ 0.5 h = 8 km/h, but average velocity = 0 km displacement ÷ 0.5 h = 0 km/h. Always check whether the question wants distance or displacement.

Average speed $= d/t$ (total distance over time). Average velocity $\vec{v}_{\text{av}} = \Delta x/\Delta t$ (displacement over time, with direction). For a one-way straight trip they have equal magnitude; if the object backtracks, displacement < distance so average velocity < average speed.

Pause — copy both average formulas and the out-and-back jogger example (speed 8 km/h, velocity 0 km/h) into your book before moving on.

A cyclist travels 1200 m along a straight path in 80 s, without changing direction. What is the average speed?

03
Instantaneous vs Average Velocity
+5 XP

We just saw how to find the average velocity over a whole trip. That raises a question: the speedo doesn't show the trip average — it shows what's happening right now, so how do we measure the velocity at a single instant? This card answers it → by shrinking the time interval until it is almost zero.

Your car's speedometer does not wait until the end of the journey to report. It tells you how fast you are going at this moment. That moment-by-moment value is the instantaneous velocity — and it is what changes second to second as you accelerate, brake or turn.

Instantaneous velocity is the velocity at one particular instant. We find it by measuring displacement over a very small time interval — the smaller $\Delta t$, the closer the result is to the true value at that instant:

Instantaneous velocity (small interval) $\vec{v} \approx \dfrac{\Delta x}{\Delta t}$   as   $\Delta t \to 0$ (a tiny time interval)

The average velocity, by contrast, uses the whole trip. If the velocity never changes, the instantaneous and average values are identical. But whenever the motion speeds up or slows down, the instantaneous value drifts above or below the average.

How to picture it: average velocity is the "big picture" over a long interval; instantaneous velocity is a "snapshot" over a vanishingly short interval. In Lesson 5 you will see the instantaneous velocity is the gradient (steepness) of a position–time graph at a single point.

Instantaneous velocity is the velocity at one instant — found from $\Delta x/\Delta t$ over a very small $\Delta t$. Average velocity uses the whole interval. They are equal only when velocity is constant; otherwise the instantaneous value rises above or falls below the average.

Pause — copy the definition of instantaneous velocity and the "smaller $\Delta t$ = closer to the true instant" idea into your book before moving on.

Match each term to its meaning.

Average velocitydisplacement over the whole time interval
Instantaneous velocityvelocity at a single instant (tiny time interval)
Speeda scalar — how fast, no direction
Velocitya vector — how fast and in which direction
04
Units — m/s and km/h, and Converting Between Them
+5 XP

We just saw how to find velocity over both long and tiny time intervals. That raises a question: the speedo reads km/h but our formulas give m/s — so how do we move between the two units without error? This card answers it → with the factor of 3.6 that links m/s and km/h.

Physics calculations use the SI unit metres per second (m/s), but everyday speeds — and your speedometer — use kilometres per hour (km/h). You must be able to swap between them, because exam data often mixes the two.

There are 1000 m in a kilometre and 3600 s in an hour. Combining these gives a single conversion factor of 3.6:

Converting speed units m/s $\times\, 3.6 =$ km/h  ·  km/h $\div\, 3.6 =$ m/s

So 10 m/s $\times 3.6 = 36$ km/h, and 108 km/h $\div 3.6 = 30$ m/s. A handy benchmark: a relaxed walk is about 1.5 m/s ($\approx$ 5 km/h), and the urban speed limit of 50 km/h is about 14 m/s.

Worked example — converting and comparing
  1. Convert the highway speed to m/s. $110 \text{ km/h} \div 3.6 = 30.6$ m/s.
  2. Convert a runner's pace to km/h. $5.0 \text{ m/s} \times 3.6 = 18$ km/h.
  3. Compare. The car (30.6 m/s) is about six times faster than the runner (5.0 m/s) — easier to see once both are in the same unit.
Exam trap: mixing units mid-calculation. If a question gives distance in metres and a speed in km/h, convert the speed to m/s before you substitute. Forgetting the 3.6 factor is one of the most common avoidable errors in Module 1.

To convert speed: m/s $\times 3.6 =$ km/h, and km/h $\div 3.6 =$ m/s. The 3.6 comes from 3600 s/h ÷ 1000 m/km. Always convert everything to consistent units (usually m/s) before substituting into a formula.

Pause — copy the conversion rule (×3.6 and ÷3.6) and the worked conversions (108 km/h = 30 m/s) into your book before moving on.

A car travels at 90 km/h. Converting to SI units for a physics calculation, this speed is:

05
Measuring Velocity — The Practical Investigation
+5 XP

We just saw how to handle the units of velocity. That raises a question: in a real lab, how do we actually gather data to find both the average and the instantaneous velocity of a moving object? This card answers it → with three standard technologies: the ticker timer, the data logger, and video analysis.

The syllabus asks you to conduct a practical investigation to gather data to analyse instantaneous and average velocity. The trick is always the same: record an object's position at known, regular time intervals, then use $\vec{v} = \Delta x/\Delta t$ — over the whole run for the average, and over one tiny interval for the instantaneous value.

Three technologies do this job:

  • Ticker timer. A vibrating arm punches dots on a paper tape pulled by the moving trolley, typically 50 dots per second (so each gap = $\tfrac{1}{50}=0.02$ s). Close dots mean slow; widely spaced dots mean fast. Measuring one gap gives an instantaneous velocity; measuring the whole tape gives the average.
  • Data logger with a motion sensor. An ultrasonic or light-gate sensor records position or time automatically, hundreds of times a second, straight to a computer — far more precise than reading a tape by hand.
  • Video analysis. Film the motion against a measuring scale, then step through the frames (e.g. 30 frames per second, so $\Delta t = \tfrac{1}{30}$ s per frame). The position in each frame gives a position–time table.
Worked example — instantaneous velocity from a ticker tape
  1. Read the interval. Tape made at 50 dots/s → time between adjacent dots $\Delta t = 1/50 = 0.020$ s.
  2. Measure one gap. Near one point, two adjacent dots are 1.4 cm apart, so $\Delta x = 0.014$ m.
  3. Apply the formula. $v \approx \dfrac{\Delta x}{\Delta t} = \dfrac{0.014}{0.020} = 0.70$ m/s — the instantaneous velocity there.
  4. Average over the run. If the whole tape is 0.50 m long and took 1.0 s (50 gaps), $v_{\text{av}} = 0.50/1.0 = 0.50$ m/s — different from the instantaneous value because the trolley sped up.
Why both numbers matter: one short interval gives you a snapshot (instantaneous); the full tape gives you the trip summary (average). Comparing them tells you whether — and how — the object's velocity changed during the run. That comparison is the whole point of the investigation.

To gather velocity data, record position at regular known time intervals using a ticker timer (50 dots/s, $\Delta t = 0.02$ s), a data logger (motion/light-gate sensor), or video analysis (frames at known fps). Use one tiny gap for instantaneous velocity and the whole run for average velocity — both from $\vec{v}=\Delta x/\Delta t$.

Pause — copy the three technologies and the ticker-tape method ($\Delta t = 1/50 = 0.02$ s; one gap = instantaneous, whole tape = average) into your book before moving on.

A ticker timer makes 50 dots every second. What is the time interval between two adjacent dots?

Average versus instantaneous velocity on a journey A ticker tape with unevenly spaced dots above a position–time curve. Closely spaced dots show slow instantaneous velocity; widely spaced dots show fast instantaneous velocity. A straight dashed line from start to end represents the single average velocity for the whole trip. One journey, two kinds of velocity tape dots close → slow dots wide → fast time → position → average velocity (whole trip) instantaneous velocity (one instant)
The tape's dot spacing shows the instantaneous velocity changing along the trip; the dashed blue chord shows the single average velocity for the whole journey. They match only when the motion is steady.
Interactive Tool — Motion Grapher Open fullscreen ↗

What to do: set a moving object and watch its position–time graph build. Compare the steady average line (start to end) with the changing slope at each instant — the instantaneous velocity. Try a trip that backtracks and watch the average velocity fall below the average speed.

Activity 1 — Calculate and Convert
ApplyBand 4

Work through each calculation. Show the formula, substitute, and give the answer with a unit (and direction where it is a velocity).

  1. A train covers 4500 m of straight track in 150 s. Find its average speed in m/s, then convert to km/h.
  2. A drone flies 240 m east in 30 s, then 240 m west in 30 s. Find (a) its average speed and (b) its average velocity for the whole 60 s.
  3. A speed limit sign reads 50 km/h. Express this in m/s.

Two of these statements are true. One is a lie. Find the lie.

Activity 2 — Read the Ticker Tape
AnalyseBand 5

A trolley pulls a ticker tape through a timer that prints 50 dots per second. Three measured dot-gaps are:

  • Near the start: two adjacent dots are 0.8 cm apart.
  • In the middle: two adjacent dots are 1.6 cm apart.
  • Near the end: two adjacent dots are 2.4 cm apart.

For each, calculate the instantaneous velocity (in m/s). Then describe in one sentence how the trolley's motion changed along the tape, and explain why the dot spacing increased.

Quick recall — Speed and Velocity
+5 XP

A fresh five-question set drawn from this lesson's bank — feedback shown immediately.

Pick your answer, then rate your confidence.

Multiple Choice — 5 Questions
checkpoint

1. Which statement correctly distinguishes speed from velocity?

  1. Speed is a vector; velocity is a scalar
  2. Speed and velocity are identical quantities
  3. Speed is a scalar (no direction); velocity is a vector (has direction)
  4. Speed always has direction; velocity never does

2. A car travels 150 km in 2.0 hours. What is its average speed?

  1. 30 km/h
  2. 75 km/h
  3. 150 km/h
  4. 300 km/h

3. A motorbike is travelling at 72 km/h. What is this speed in m/s?

  1. 259 m/s
  2. 72 m/s
  3. 36 m/s
  4. 20 m/s

4. A swimmer does 4 lengths of a 25 m pool in 100 s, finishing back at the starting wall. What are her average speed and average velocity?

  1. Average speed 1.0 m/s; average velocity 0 m/s
  2. Average speed 0 m/s; average velocity 1.0 m/s
  3. Both are 1.0 m/s
  4. Both are 0 m/s

5. A ticker timer prints dots at 50 dots per second. Two adjacent dots on a tape are 3.0 cm apart. The instantaneous velocity at that point is:

  1. 0.60 m/s
  2. 1.5 m/s
  3. 15 m/s
  4. 150 m/s
Short Answer — 9 marks
+5 XP

UnderstandBand 3(2 marks) 1. Distinguish between average velocity and instantaneous velocity, and give an everyday example of each.

ApplyBand 4(3 marks) 2. A cyclist rides 600 m east in 40 s, then 200 m west in 20 s. Calculate (a) the average speed and (b) the average velocity (with direction) for the whole trip. Explain why the two values differ.

AnalyseBand 5(4 marks) 3. Describe a practical investigation, using a ticker timer, that would allow you to gather data to find both the average and an instantaneous velocity of a trolley. Include the equipment, the measurements you would take, and the calculations you would perform.

Show all answers

Multiple choice

Q1 — C. Speed is a scalar (magnitude only — how fast) while velocity is a vector (magnitude and direction). A is reversed; B is false (they differ by direction); D is reversed.

Q2 — B. Average speed = total distance ÷ total time = 150 km ÷ 2.0 h = 75 km/h. (A halves it, C ignores the time, D multiplies instead of dividing.)

Q3 — D. To convert km/h to m/s, divide by 3.6: 72 ÷ 3.6 = 20 m/s. (B leaves it unchanged; C halves; A multiplies by 3.6, the wrong direction.)

Q4 — A. Total distance = 4 × 25 = 100 m, so average speed = 100 ÷ 100 = 1.0 m/s. She finishes where she started, so the displacement is 0 m and the average velocity = 0 ÷ 100 = 0 m/s. Distance accumulates; displacement cancels.

Q5 — B. Time per gap Δt = 1/50 = 0.02 s; Δx = 3.0 cm = 0.030 m. v = Δx/Δt = 0.030 ÷ 0.02 = 1.5 m/s. (A divides the wrong way; C and D drop the cm→m conversion.)

Short Answer — Model Answers

Q1 (2 marks): Average velocity is the total displacement divided by the total time for a whole journey ($\vec{v}_{\text{av}} = \Delta x/\Delta t$) — e.g. a 60 km trip done in 1 h has an average velocity of 60 km/h. Instantaneous velocity is the velocity at a single instant, found over a very small time interval — e.g. the value your speedometer shows right now. (1 mark for each correctly distinguished, with a valid example.)

Q2 (3 marks): Total distance = 600 + 200 = 800 m; total time = 40 + 20 = 60 s. (a) Average speed = 800 ÷ 60 = 13.3 m/s. Taking east as positive, displacement = (+600) + (−200) = +400 m, so (b) average velocity = 400 ÷ 60 = 6.7 m/s east. The values differ because average speed uses the whole 800 m path (a scalar) while average velocity uses the 400 m net displacement (a vector), where the westward leg partly cancels the eastward leg. (1 mark speed, 1 mark velocity with direction, 1 mark explanation.)

Q3 (4 marks): Equipment: a trolley, a ticker timer (50 dots/s) and paper tape, a metre ruler, and a runway. Method: attach the tape to the trolley, start the timer, and release the trolley so it pulls the tape through. To find an instantaneous velocity, measure the distance between two adjacent dots ($\Delta x$) at a chosen point; since Δt = 1/50 = 0.02 s, calculate $v = \Delta x/\Delta t$. To find the average velocity, measure the total length of tape pulled through ($\Delta x_{\text{total}}$) and count the dots to get the total time, then calculate $v_{\text{av}} = \Delta x_{\text{total}}/\Delta t_{\text{total}}$. Comparing the two shows whether the trolley sped up or slowed down. (1 mark equipment, 1 mark valid method, 1 mark instantaneous calculation, 1 mark average calculation.)

Stretch — Think Ahead
stretch

You found instantaneous velocity by shrinking the time interval until it was tiny. In Lesson 5 you will draw a position–time graph and discover that the instantaneous velocity is exactly the gradient (steepness) of the curve at a point. Predict: on a position–time graph, what would a horizontal (flat) section mean about the object's velocity? And what would a steeper line mean compared with a shallower one?

How did your thinking change?

The speed camera's 108 km/h was an average over a measured stretch — total distance over total time — so it could sit at 108 even though the car's instantaneous speed dipped to 95 in traffic and surged to 120 to overtake. An average is a single summary number that smooths over every moment-to-moment change. Add direction to that rate and you have velocity, the vector that pairs with displacement. Tools like ticker timers, data loggers and video analysis let you capture both the average (whole run) and the instantaneous (one tiny interval) values from the same data — the heart of this lesson's practical investigation.