Mathematics • Year 9 • Unit 4 • Lesson 11

Centre and Spread in the Real World

Use mean, median, mode and IQR to make sense of real data — sneaker sales, household incomes, weekly screen time, soccer goals and Sydney house prices. Then explain your reasoning in your own words.

Apply · Real-World Maths

1. Word problems

Each problem uses mean, median, mode, range or IQR from Lesson 11. Show your working — a single final answer with no working only earns half marks.

1.1 — Sneaker sales. A shoe shop records the number of pairs of sneakers sold each day for one week:

Mon 12, Tue 18, Wed 15, Thu 14, Fri 22, Sat 35, Sun 9.

(a) Find the mean and the median daily sales.
(b) Which value better describes a "typical" day, and why? 4 marks

Stuck? Saturday is a busy day that lifts the mean. Order the data and find the middle value for the median.

1.2 — Household income. Seven households on one street have weekly incomes (in $):

900, 1100, 1200, 1300, 1400, 1600, 8500.

(a) Find the mean and the median weekly income.
(b) The Australian Bureau of Statistics reports median household income, not mean. Use this street's data to explain why. 4 marks

Stuck? Revisit lesson § "Real-World Anchor — Economics and Policy".

1.3 — Weekly screen time. A Year 9 class records weekly screen time (in hours) for 9 students:

10, 14, 16, 18, 20, 22, 24, 28, 60.

(a) Find Q1, Q3 and the IQR.
(b) Use the 1.5 × IQR rule to decide whether the 60-hour reading is an outlier. 4 marks

Stuck? n = 9, so the median is the 5th value. Split the remaining 4 values either side into the two halves.

1.4 — Soccer goals. Across 10 games an A-League striker scores:

0, 0, 1, 1, 1, 2, 2, 3, 4, 5.

(a) Find the mean, median and mode.
(b) The striker's agent wants to argue she is "a consistent 1-goal-a-game player". Which measure best supports this claim and why? 4 marks

Stuck? Mode is the most frequent value — count how many times each goal tally appears.

1.5 — Sydney house prices. Six recent house sales in a Sydney suburb (in $ millions) are:

1.1, 1.2, 1.3, 1.4, 1.6, 4.5.

(a) Find the mean and median sale price.
(b) A real-estate ad reports the "average sale price in the area was $1.85 million". Is this technically true? Is it misleading? Explain. 4 marks

Stuck? The $4.5m sale acts as an outlier on the mean. Compare what the mean and median each tell a buyer.

2. Explain your thinking

This question is about communication, not just answers. Use full sentences. 4 marks

2.1 A classmate says: "The range is a great way to describe spread because it uses every number." In your own words, explain (i) why the range is easy to calculate, (ii) what its main weakness is when a data set contains an outlier, and (iii) why the IQR is often preferred. Use an example with numbers somewhere in your answer.

Stuck? Revisit lesson § "Misconceptions" — the contrast between range (all data) and IQR (middle 50%) is exactly the point.

How did this worksheet feel?

What I'll revisit before next class:

Answers — Do not peek before attempting

1.1 — Sneaker sales

Ordered: 9, 12, 14, 15, 18, 22, 35. Sum = 125, n = 7.
(a) Mean = 125 ÷ 7 ≈ 17.86. Median = 4th value = 15.
(b) Median better describes a typical day, because the unusually high Saturday (35) pulls the mean above what most weekdays actually look like.

1.2 — Household income

(a) Sum = 16 000, n = 7. Mean = 16 000 ÷ 7 ≈ $2 286. Median = 4th value = $1 300.
(b) The $8 500 household acts as an outlier and pulls the mean far above what most households actually earn. The median ($1 300) better represents a typical household, which is why the ABS reports it.

1.3 — Weekly screen time

n = 9, median = 5th value = 20. Lower half: 10, 14, 16, 18 → Q1 = (14 + 16) ÷ 2 = 15. Upper half: 22, 24, 28, 60 → Q3 = (24 + 28) ÷ 2 = 26.
IQR = 26 − 15 = 11.
Upper fence = 26 + 1.5(11) = 26 + 16.5 = 42.5. 60 > 42.5, so yes, 60 hours is an outlier.

1.4 — Soccer goals

Sum = 19, n = 10. Mean = 19 ÷ 10 = 1.9.
Median = (1 + 2) ÷ 2 = 1.5.
Mode = 1 (appears 3 times).
The mode best supports the agent's "consistent 1-goal-a-game" claim, but it ignores the high-scoring games. A more honest summary would also mention the mean of 1.9 to show she sometimes scores more.

1.5 — Sydney house prices

(a) Sum = 11.1, n = 6. Mean = 11.1 ÷ 6 = $1.85 m. Median = (1.3 + 1.4) ÷ 2 = $1.35 m.
(b) Technically true — $1.85 m is the mean. But it is misleading because the $4.5 m sale is an outlier; five out of six houses actually sold for less than $1.7 m. Reporting the median ($1.35 m) would give a much more honest picture for typical buyers.

2.1 — Explain your thinking (sample response)

The range is easy because you only need the maximum and minimum: range = max − min. For example, in 2, 5, 7, 8, 10, 12, 200 the range is 200 − 2 = 198. The weakness is that this 198 is almost entirely caused by the single outlier 200 — every other value sits between 2 and 12. The IQR (Q3 − Q1) avoids this problem because it only uses the middle 50% of the data, so a single very large or very small value barely changes it. This is why the IQR is preferred when a data set may contain outliers.

Marking: 1 mark for "range = max − min"; 1 mark for naming outliers as the weakness; 1 mark for "middle 50%" / IQR definition; 1 mark for a concrete numerical example.