Mathematics • Year 9 • Unit 4 • Lesson 9

Congruence and Similarity in the Real World

Use the congruence and similarity tests in everyday contexts: a surveyor measuring a river, the shadow of a flagpole, a roof truss made of identical triangles, a kite design, and tessellated patio tiles. Then explain your method in your own words.

Apply · Real-World Maths

1. Word problems

Each problem uses a similarity or congruence test from Lesson 9, with a real-world twist. Show your working — a single final answer with no working only earns half marks.

1.1 — Surveying a river. A surveyor stands on a riverbank at point $A$, directly opposite a tree at point $T$ on the far bank. She walks $30$ m along her bank to point $B$, then turns $90°$ and walks $40$ m to point $C$, sighting the tree along $CB$ extended. She constructs similar triangles to find the width $AT$ of the river. Using similar triangles with $AT/AB = AB/BC$ — solve for the width.

Given $AB = 30$ m, $BC = 40$ m, find $AT$. State which similarity test the construction relies on.    3 marks

Stuck? Set up the proportion: $\dfrac{AT}{30} = \dfrac{30}{40}$, then solve for $AT$.

1.2 — Flagpole shadow. A flagpole and a $1.6$ m student standing nearby both cast shadows at the same moment. The student's shadow is $2.0$ m long; the flagpole's shadow is $12.5$ m long. The sun's rays hit both at the same angle, so the two right-triangle "person + shadow" and "pole + shadow" diagrams are similar.

(a) State which similarity test applies (the sun's angle is the same for both, and both have a right angle to the ground).
(b) Find the height of the flagpole.    3 marks

Stuck on (b)? Set up $\dfrac{\text{flag height}}{12.5} = \dfrac{1.6}{2.0}$.

1.3 — Roof truss. A roof truss is built from $12$ identical right-angled triangles. Each triangle has base $1.2$ m, height $0.9$ m, and hypotenuse $1.5$ m.

(a) Are the triangles congruent or merely similar? Justify with a test.
(b) Find the total length of timber needed for all the hypotenuses combined.    3 marks

Stuck on (a)? "Identical" means all measurements are equal, not merely proportional.

1.4 — Kite design. A kite has a vertical line of symmetry. The diagonal along this axis divides it into two triangles. Prove that these two triangles are congruent. State the given information, the test you use, and the conclusion.

3 marks

Stuck? A kite has two pairs of adjacent equal sides. Together with the common diagonal, that's three pairs.

1.5 — Tessellated tiles. An outdoor patio is paved with $40$ identical equilateral triangular tiles, side $30$ cm. A landscaper offers a "larger but identical-style" patio with similar tiles of side $45$ cm.

(a) Are the larger tiles congruent or similar to the original tiles? Justify briefly.
(b) What is the scale factor $k$?
(c) By what factor will the total tile area increase? (You may use scale-factor results from Lesson 8.)    3 marks

Stuck on (a)? All equilateral triangles have the same angles ($60°$ each), so they're always similar. They're only congruent if the sides match.

2. Explain your thinking

This question is about communication, not just answers. Use full sentences. 4 marks

2.1 A classmate looks at two equilateral triangles — one with side $5$ cm and one with side $8$ cm — and says "they have all the same angles ($60°$ each), so they must be congruent." In your own words, explain (i) what mistake they have made, (ii) which test they are confusing (and what it actually proves), and (iii) the correct relationship between the two triangles. Refer to "AA" or "AAA" somewhere in your explanation.

Stuck? Revisit lesson § "Common Misconceptions" — the first misconception listed and "all equilateral triangles" is the third.

How did this worksheet feel?

What I'll revisit before next class:

Answers — Do not peek before attempting

1.1 — Surveying a river

Set up similar right triangles: $\triangle ABT \sim \triangle BCA$ (both have a right angle and share/use the common angle at $B$ — AA similarity).
Proportion: $\dfrac{AT}{30} = \dfrac{30}{40}$, so $AT = \dfrac{30 \times 30}{40} = \dfrac{900}{40} = \mathbf{22.5}$ m.
Test used: AA similarity (right angle + shared angle).
Real surveyors use exactly this method — the lesson's Great Trigonometric Survey of India anchor describes it.

1.2 — Flagpole shadow

(a) The two right triangles have a right angle (ground) and the same sun-angle → similar by AA.
(b) $\dfrac{h}{12.5} = \dfrac{1.6}{2.0} = 0.8$, so $h = 12.5 \times 0.8 = \mathbf{10}$ m.
This is the classic "Thales' theorem" trick — Thales used it 2500 years ago to measure the Great Pyramid.

1.3 — Roof truss

(a) All measurements (sides 1.2, 0.9, 1.5) are equal across all 12 triangles → congruent by SSS. Note: $0.9^2 + 1.2^2 = 0.81 + 1.44 = 2.25 = 1.5^2$, confirming right angles. RHS would also work.
(b) Total hypotenuse length $= 12 \times 1.5 = \mathbf{18}$ m of timber.

1.4 — Kite

Given: Kite $ABCD$ with line of symmetry $BD$, so $AB = CB$ and $AD = CD$.
To prove: $\triangle ABD \equiv \triangle CBD$.
Proof:
$AB = CB$ (kite — pair of adjacent equal sides)
$AD = CD$ (kite — second pair of adjacent equal sides)
$BD = BD$ (common side)
Therefore $\triangle ABD \equiv \triangle CBD$ by SSS.
Conclusion: The two halves of a kite separated by the symmetry diagonal are congruent triangles.

1.5 — Tessellated tiles

(a) The tiles have the same angles ($60°$ all round) but different sides ($30$ vs $45$ cm) → similar, not congruent. Similar by AA (or AAA).
(b) $k = 45/30 = \mathbf{1.5}$.
(c) Each tile's area scales by $k^2 = 2.25$, so total tile area increases by a factor of $\mathbf{2.25}$ (assuming the same number of tiles).

2.1 — Explain your thinking (sample response)

My classmate has assumed that equal angles alone are enough to prove congruence — but they only prove similarity, not congruence. The test they are confusing is AA (or AAA): if two (or three) angles of one triangle equal two (or three) angles of another, the triangles are similar — meaning the same shape, but possibly different sizes. The correct relationship is that the two equilateral triangles (side $5$ cm and side $8$ cm) are similar, with scale factor $k = 8/5 = 1.6$. They are not congruent because their sides are different lengths; congruence requires sides to be equal, not merely proportional.

Marking: 1 for naming the mistake; 1 for naming AA/AAA correctly; 1 for the correct relationship (similar, $k = 1.6$); 1 for clear, full-sentence explanation.