True Bearings
Three-digit bearings measured clockwise from North. N=000°, E=090°, S=180°, W=270°. Convert between compass and true; find reverse bearings.
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True bearings ALWAYS use three digits. Why might 045° be written instead of just 45°? (Hint: ambiguity and convention.)
True bearings are a more modern, computer-friendly way to write directions. Always three digits, measured CLOCKWISE from North, ranging 000° to 360°.
N = 000° or 360°; E = 090°; S = 180°; W = 270°. To find a true bearing from a compass bearing $N\theta E$: bearing = $\theta$ (e.g., $N40°E = 040°$). For $N\theta W$: bearing = $360° - \theta$. For $S\theta E$: bearing = $180° - \theta$. For $S\theta W$: bearing = $180° + \theta$.
Know
- True bearings are three digits clockwise from N
- N=000°, E=090°, S=180°, W=270°
- Reverse bearing = original $\pm$ 180°
Understand
- Why true bearings are used in navigation (no ambiguity)
- How to convert between compass and true bearings
- Why reverse bearings differ by exactly 180°
Can Do
- Convert compass ↔ true bearings
- Find reverse bearings
- Identify direction from a true bearing
Wrong: Writing 45° instead of 045° — true bearings need three digits.
Right: Always pad to 3 digits: 045°, 005°, 270°.
Wrong: Measuring counter-clockwise (the wrong direction).
Right: True bearings ALWAYS go clockwise from N.
To switch between the two systems, use the quadrant rules:
| Compass | True |
|---|---|
| $N\theta E$ | $\theta$ |
| $S\theta E$ | $180° - \theta$ |
| $S\theta W$ | $180° + \theta$ |
| $N\theta W$ | $360° - \theta$ |
The reverse bearing is the direction looking BACK along the path you came — differing from your original bearing by exactly 180°.
Watch Me Solve It · 3 examples
- 1Find quadrantSW → true bearing is between 180° and 270°.
- 2Apply formula$180° + \theta = 180° + 60° = 240°$
- 3FormatTrue bearing: 240°
- 1Find quadrant135° is between 090° and 180° → SE quadrant.
- 2Apply formula$180° - \theta_{compass} = 135°$, so $\theta_{compass} = 45°$.
- 3WriteCompass: $S45°E$
- 1Original less than 180°Add 180°: $70 + 180 = 250°$
- 2FormatReturn bearing: 250°
- 3VerifyAdd 180° to 250° → 430° → 430 - 360 = 70° ✓
Common Pitfalls
True bearings
- Three digits
- Clockwise from N
- 000-360
Cardinal
- N = 000°
- E = 090°
- S = 180°
- W = 270°
Conversion
- $N\theta E \rightarrow \theta$
- $S\theta E \rightarrow 180-\theta$
- $S\theta W \rightarrow 180+\theta$
- $N\theta W \rightarrow 360-\theta$
Reverse
- $\pm 180°$
- Keep in 0-360
- Same line, opposite
How are you completing this lesson?
Brain Trainer · 4 problems
Four quick drills to lock in today's skill. Try each, then reveal the answer.
-
1 $N20°E$ as true bearing.
NE quadrant: $\theta = 20°$.020° -
2 $S40°W$ as true bearing.
SW: $180 + 40 = 220$.220° -
3 True 290° as compass.
NW: $\theta = 360 - 290 = 70$.$N70°W$ -
4 Reverse of 080°.
$80 + 180 = 260$.260°
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Convert (a) $S70°E$ to a true bearing, (b) the true bearing 315° to a compass bearing.
Q7. A plane flies from town A to town B on true bearing 125°. (a) Express this as a compass bearing. (b) State the reverse bearing for the return flight. (c) Express the reverse as a compass bearing.
Q8. A walker is at point P. They want to travel to a hut on a true bearing of 070°, 3 km away. (a) Find their northward and eastward displacement. (b) From the hut, they walk back on the reverse bearing for 1 km. Find their new location relative to P (in N/E components).
Quick Check
1. B — 090°.
2. D — 310°.
3. A — $S20°W$.
4. C — 015°.
5. B — Avoids ambiguity.
Show Your Working Model Answers
Q6 (2 marks): (a) SE quadrant: true bearing $= 180° - 70° = 110°$ [1]. (b) NW quadrant: $\theta = 360° - 315° = 45°$, so compass = $N45°W$ [1].
Q7 (3 marks): (a) SE: $S(180-125)°E = S55°E$ [1]. (b) Reverse: $125 + 180 = 305°$ [1]. (c) 305° is in NW: $\theta = 360-305 = 55$, so $N55°W$ [1].
Q8 (4 marks): (a) North = $3\cos 70° \approx 1.026$ km, East = $3\sin 70° \approx 2.819$ km [1]. (b) Reverse bearing = 070 + 180 = 250°. Walking back: South = $1\cos 70° \approx 0.342$ km, West = $1\sin 70° \approx 0.940$ km [1]. Net from P: North $= 1.026 - 0.342 = 0.684$ km, East $= 2.819 - 0.940 = 1.879$ km [1]. So 0.68 km N and 1.88 km E of P [1].
Three towns triangle
Town A is at $N40°E$ from town B. Town C is due south of town A. What's the true bearing of town C from B if A is 5 km from B and C is 4 km south of A?
Reveal solution
Place B at origin. A = $(5\sin 40°, 5\cos 40°) \approx (3.21, 3.83)$. C = $(3.21, 3.83 - 4) = (3.21, -0.17)$. Bearing of C from B: nearly due east, slightly south. $\tan^{-1}(0.17/3.21) \approx 3°$. Bearing $\approx 090° + 3° = 093°$.
Three digits
045°, not 45°
Clockwise from N
Always
Cardinal
E=090, S=180, W=270
Conversion
Quadrant formulas
Reverse
$\pm 180°$, in 0-360
Pad zeros
005°, 045°
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