Finding Angles with Inverse Trig
When you know two sides but not the angle, use $\sin^{-1}$, $\cos^{-1}$ and $\tan^{-1}$ — the inverse trig functions — to recover $\theta$.
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$\sin\theta = 0.5$. What is $\theta$? Hint: at which classic angle does sine equal exactly one-half?
To find an angle when you know its sine/cosine/tangent, use the inverse functions $\sin^{-1}$, $\cos^{-1}$, $\tan^{-1}$ (also written arcsin, arccos, arctan). They are the ‘undo’ buttons.
If $\sin\theta = x$ then $\theta = \sin^{-1}(x)$. Same for cos and tan. On the calculator: SHIFT (or 2nd) then the trig key. The inverse takes a ratio (0 to 1 for sin/cos) and returns the corresponding angle.
Know
- The inverse functions $\sin^{-1}$, $\cos^{-1}$, $\tan^{-1}$
- How to set up a ratio then apply the inverse
- That inverse trig gives an acute angle in right triangles
Understand
- Why we need the inverse to find an angle
- That $\sin^{-1}$ is NOT the same as $1/\sin$
- That for acute angles the inverse always gives 0° to 90°
Can Do
- Find an angle given any two sides
- Round angles to the nearest degree or one decimal place
- Use SHIFT (or 2nd) on the calculator correctly
Wrong: “$\sin^{-1}(x) = 1/\sin(x)$.” Wrong — that's the reciprocal, not the inverse.
Right: $\sin^{-1}$ is the INVERSE FUNCTION — the angle whose sine is $x$.
Wrong: Pressing sin instead of SHIFT-sin — gives a ratio, not an angle.
Right: To find an angle, ALWAYS use SHIFT (or 2nd) before the trig key.
Practise the exact key sequence to compute inverse trig without errors.
| Goal | Casio FX-82AU keys |
|---|---|
| $\sin^{-1}(0.5)$ | SHIFT → sin → 0.5 → = → 30° |
| $\cos^{-1}(4/5)$ | SHIFT → cos → ( 4 $\div$ 5 ) → = → 36.87° |
| $\tan^{-1}(2)$ | SHIFT → tan → 2 → = → 63.43° |
Finding an angle follows the same pattern as finding a side, just one extra inverse-trig step at the end.
| Step | Action |
|---|---|
| 1 | Label sides relative to $\theta$ |
| 2 | Identify which ratio (sin/cos/tan) links the two known sides |
| 3 | Set up & apply inverse: $\theta = $ ratio$^{-1}$(value) |
Watch Me Solve It · 3 examples
- 1Set up ratio$\sin\theta = 4/7 \approx 0.5714$
- 2Apply inverse$\theta = \sin^{-1}(4/7)$
- 3Compute$\theta \approx 34.8°$
- 1Use tan$\tan\theta = 3/4 = 0.75$
- 2Inverse$\theta = \tan^{-1}(0.75)$
- 3Compute$\theta \approx 36.87°$ — the famous 3-4-5 acute angle.
- 1Set upadj = 50 (horizontal), opp = 30 (height). Use tan.
- 2Apply$\tan\theta = 30/50 = 0.6$
- 3Inverse$\theta = \tan^{-1}(0.6) \approx 31.0°$
Common Pitfalls
Inverse functions
- $\sin^{-1}(x)$
- $\cos^{-1}(x)$
- $\tan^{-1}(x)$
Calculator
- SHIFT (2nd) before sin/cos/tan
- DEG mode
- Returns the angle
Method
- Label sides
- Pick ratio
- Inverse for $\theta$
Sanity
- Acute → $0 < \theta < 90°$
- $\sin^{-1}(0.5) = 30°$
- $\tan^{-1}(1) = 45°$
How are you completing this lesson?
Brain Trainer · 4 problems
Four quick drills to lock in today's skill. Try each, then reveal the answer.
-
1 $\sin\theta = 0.5$. Find $\theta$.
$\theta = \sin^{-1}(0.5)$.$\theta = 30°$ -
2 $\cos\theta = 0.8$. Find $\theta$ (1 d.p.).
$\theta = \cos^{-1}(0.8)$.$\theta \approx 36.9°$ -
3 $\tan\theta = 1$. Find $\theta$.
$\theta = \tan^{-1}(1)$.$\theta = 45°$ -
4 opp = 5, hyp = 13. Find $\theta$ (1 d.p.).
$\theta = \sin^{-1}(5/13)$.$\theta \approx 22.6°$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Find $\theta$ to 1 d.p. in each case. (a) opp = 5, hyp = 13. (b) adj = 8, opp = 6. (c) adj = 4, hyp = 5.
Q7. You stand 20 m from the foot of a 15 m flagpole. At what angle above horizontal do you see the top (1 d.p.)?
Q8. A 7 m ladder leans against a wall with its base 2 m from the wall. (a) Find the angle the ladder makes with the ground. (b) Building safety guidance says ladders should be at 70-80° for safety. Is this ladder safe? Explain.
Quick Check
1. B — $\sin 30° = 0.5$.
2. D — SHIFT + tan.
3. C — $\sin^{-1}(0.7) \approx 44.4°$.
4. A — Inverse function.
5. A — $\tan^{-1}(1) = 45°$.
Show Your Working Model Answers
Q6 (3 marks): (a) $\theta = \sin^{-1}(5/13) \approx 22.6°$ [1]. (b) $\theta = \tan^{-1}(6/8) \approx 36.9°$ [1]. (c) $\theta = \cos^{-1}(4/5) \approx 36.9°$ [1].
Q7 (2 marks): $\tan\theta = 15/20 = 0.75$ [1]. $\theta = \tan^{-1}(0.75) \approx 36.9°$ [1].
Q8 (4 marks): (a) $\cos\theta = 2/7 \approx 0.2857$ [1]. $\theta = \cos^{-1}(2/7) \approx 73.4°$ [1]. (b) $73.4°$ lies within 70-80°, so the ladder IS safely placed [1]. Explanation: the angle is steep enough to keep the foot from slipping but not too steep to topple [1].
Match the angle to the world
A wheelchair ramp must rise 1 unit for every 12 horizontal units (a 1-in-12 gradient). What angle does this ramp make with the ground (1 d.p.)? Compare with a steep mountain pass that climbs 1 unit in 4 horizontal units.
Reveal solution
Wheelchair: $\theta = \tan^{-1}(1/12) \approx 4.8°$. Mountain: $\theta = \tan^{-1}(1/4) \approx 14.0°$ — nearly three times as steep.
Inverse functions
$\sin^{-1}$, $\cos^{-1}$, $\tan^{-1}$
On calculator
SHIFT + trig key
Same ratio rule
opp+hyp → sin, etc.
$\sin^{-1} \neq 1/\sin$
Inverse function, not reciprocal
Acute answer
$0 < \theta < 90°$
Three steps
Label, pick, inverse
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