Mixed — Finding Sides with Any Ratio
Decide between sin, cos and tan based on which two sides are involved. A simple decision flowchart turns any problem into a solved one.
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A triangle has angle $\theta = 35°$, hyp = 12, and you want adj. Which ratio uses adj and hyp? Pick it, then rearrange.
Picking sin vs cos vs tan is the single most-tested skill in trigonometry. The trick: ignore everything else — just look at the TWO sides involved.
opp + hyp → sin. adj + hyp → cos. opp + adj → tan. Three combinations, three ratios — that's it. Label, list, decide, rearrange, compute.
Know
- The three side-pairings and their ratios
- SOH-CAH-TOA used in reverse to choose
- Each rearrangement direction
Understand
- How to read a diagram to identify which sides are known/wanted
- Why the choice of ratio depends ONLY on the sides involved
- How to verify with Pythagoras after computing
Can Do
- Identify and apply the correct ratio in any single-step problem
- Solve for any single side given an angle and another side
- Switch between ratios fluently
Wrong: Picking a ratio at random — gives the wrong answer.
Right: List the two sides involved FIRST, then choose.
Wrong: Picking based on which side is ‘easier to compute’ rather than which fits.
Right: Pick the ratio with EXACTLY the two sides you have/need; the rearrange isolates your unknown.
For any side problem, ask three quick questions:
Q1: What angle is given? → that's $\theta$. Q2: Which side is known (and what name)? Q3: Which side do I want (and what name)? The pair of names tells you which ratio.
Every trig ratio has TWO useful rearrangements — one to find the top, one to find the bottom.
| Original | Find top | Find bottom |
|---|---|---|
| $\sin\theta = $ opp/hyp | opp = hyp$\cdot \sin\theta$ | hyp = opp$/\sin\theta$ |
| $\cos\theta = $ adj/hyp | adj = hyp$\cdot \cos\theta$ | hyp = adj$/\cos\theta$ |
| $\tan\theta = $ opp/adj | opp = adj$\cdot \tan\theta$ | adj = opp$/\tan\theta$ |
Watch Me Solve It · 3 examples
- 1List sidesKnown: hyp = 14, $\theta = 50°$. Want: opp.
- 2Pick ratioopp + hyp → sin (SOH).sin uses opp/hyp.
- 3Computeopp $= 14\sin 50° \approx 14 \times 0.766 \approx 10.72$
- 1List sidesKnown: opp = 9, $\theta = 28°$. Want: adj.
- 2Pickopp + adj → tan (TOA).
- 3Solveadj $= 9/\tan 28° \approx 9/0.5317 \approx 16.93$
- 1List sidesadj = 8, $\theta = 40°$. Want: hyp.
- 2Pickadj + hyp → cos (CAH).
- 3Solvehyp $= 8/\cos 40° \approx 8/0.766 \approx 10.44$
Common Pitfalls
Decision
- opp + hyp → sin
- adj + hyp → cos
- opp + adj → tan
Find top
- Multiply bottom by ratio
- Find opp = hyp $\sin$
- Find adj = hyp $\cos$
Find bottom
- Divide top by ratio
- Find hyp = opp$/\sin$
- Find adj = opp$/\tan$
Always
- Sketch
- Label
- List sides
- Pick ratio
- Compute
How are you completing this lesson?
Brain Trainer · 4 problems
Four quick drills to lock in today's skill. Try each, then reveal the answer.
-
1 Known: opp, $\theta$. Want: hyp. Which ratio?
opp + hyp → sin.sin -
2 Known: adj, $\theta$. Want: opp. Which ratio?
opp + adj → tan.tan -
3 Known: hyp, $\theta$. Want: adj. Which ratio?
adj + hyp → cos.cos -
4 $\theta = 30°$, opp = 6. Find adj (2 d.p.).
adj = $6/\tan 30° \approx 10.39$.$\approx 10.39$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Find the requested side in each case to 2 d.p. (a) $\theta = 50°$, hyp = 9, find opp. (b) $\theta = 25°$, adj = 14, find opp. (c) $\theta = 70°$, opp = 18, find hyp.
Q7. Write a one-sentence rule for deciding between sin, cos and tan in a right-triangle side problem.
Q8. A right triangle has angle 32° and hypotenuse 10. Without using Pythagoras, find both legs (2 d.p.). Then verify using Pythagoras.
Quick Check
1. A — SOH.
2. D — $4\tan 60° \approx 6.93$.
3. B — $20\cos 35° \approx 16.38$.
4. C — $5/\sin 25° \approx 11.83$.
5. A — Pair identification first.
Show Your Working Model Answers
Q6 (3 marks): (a) opp = $9\sin 50° \approx 6.89$ [1]. (b) opp = $14\tan 25° \approx 6.53$ [1]. (c) hyp = $18/\sin 70° \approx 19.16$ [1].
Q7 (2 marks): Identify which two of opp, adj, hyp are involved [1]. Then: opp+hyp → sin, adj+hyp → cos, opp+adj → tan [1].
Q8 (4 marks): opp $= 10\sin 32° \approx 5.30$ [1]. adj $= 10\cos 32° \approx 8.48$ [1]. Pythagoras check: $5.30^2 + 8.48^2 \approx 28.09 + 71.91 = 100.00 = 10^2$ [1]. The check confirms the sides are correct — rounding errors are tiny [1].
Without a calculator
Using the special angles 30°, 45°, 60° (where you might know exact values like $\sin 30° = 0.5$, $\cos 60° = 0.5$, $\tan 45° = 1$), find an exact answer for: a right triangle with $\theta = 30°$ and hyp = 12, find opp.
Reveal solution
opp = $12 \cdot \sin 30° = 12 \cdot 0.5 = 6$ exactly (no rounding).
Decision
opp+hyp→sin, adj+hyp→cos, opp+adj→tan
Find top
Top = bottom $\cdot$ ratio
Find bottom
Bottom = top $/$ ratio
Always sketch
Label sides before picking ratio
DEG mode
$\sin 30° = 0.5$ check
Verify
Use Pythagoras as a final check
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