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Lesson 6 ~25 min Unit 3 · Trigonometry +85 XP

Introducing Trigonometric Ratios

Meet sin, cos and tan — the three ratios that connect a right-angled triangle's angle $\theta$ to its sides. Memorise SOH-CAH-TOA.

Today's hook: Any right-angled triangle with a 30° angle — whether tiny or huge — has EXACTLY the same ratio of opposite side to hypotenuse: 0.5. Why is that ratio always the same?
0/5QUESTS
Think First
warm-up

Two right triangles both have an angle of 40°. One has hypotenuse 5 cm, the other 50 cm. Will the ratio ‘opposite ÷ hypotenuse’ be the same in both? Why or why not?

Record your answer in your workbook.
1
The Big Idea
+5 XP

For any right triangle, the THREE side-pair ratios (opp/hyp, adj/hyp, opp/adj) depend ONLY on the angle $\theta$ — not on the size. We give them names: sine, cosine and tangent.

$\sin\theta = \dfrac{\text{opp}}{\text{hyp}}$,   $\cos\theta = \dfrac{\text{adj}}{\text{hyp}}$,   $\tan\theta = \dfrac{\text{opp}}{\text{adj}}$. Memorise these with SOH-CAH-TOA: Sine = Opp/Hyp, Cosine = Adj/Hyp, Tangent = Opp/Adj. Same angle → same ratio, every time.

adj opp hyp$\sin\theta = $opp/hyp$\cos\theta = $adj/hyp$\tan\theta = $opp/adj
SOH-CAH-TOA: Sin=Opp/Hyp, Cos=Adj/Hyp, Tan=Opp/Adj
Same angle, same ratio
Doubling the triangle doubles all sides — ratios stay constant.
Three ratios only
sin, cos, tan — that's it. They're the three pairwise ratios.
SOH-CAH-TOA
The memory phrase: $\sin = $O/H, $\cos = $A/H, $\tan = $O/A.
2
What You'll Master
objectives

Know

  • The three trig ratios: sin, cos, tan
  • SOH-CAH-TOA mnemonic
  • Ratios depend on the angle only, not triangle size

Understand

  • Why similar triangles (same angles) share trig ratios
  • How sin and cos always lie between 0 and 1 for acute angles
  • Why tan can exceed 1 (when opp > adj)

Can Do

  • Write each trig ratio in terms of opp, adj, hyp
  • Calculate sin, cos, tan given two sides
  • Recall SOH-CAH-TOA fluently
3
Words You Need
vocabulary
Sine ($\sin$)The ratio opposite/hypotenuse for a given angle. Always between 0 and 1 for acute angles.
Cosine ($\cos$)The ratio adjacent/hypotenuse. Always between 0 and 1 for acute angles.
Tangent ($\tan$)The ratio opposite/adjacent. Can be any positive value for acute angles — even much bigger than 1.
RatioA comparison of two quantities by division. Has no units when both quantities are lengths in the same unit.
SOH-CAH-TOAMemory aid: $\sin$=Opp/Hyp, $\cos$=Adj/Hyp, $\tan$=Opp/Adj.
Similar trianglesTriangles with the same angles but possibly different sizes. They share identical trig ratios.
4
Spot the Trap
heads-up

Wrong: “$\sin 30° = $ something different in a bigger triangle.” No — same angle, same sine, always.

Right: $\sin 30° = 0.5$ in EVERY right triangle that contains a 30° angle.

Wrong: “tan can't be bigger than 1.” Wrong — tan goes to infinity as the angle approaches 90°.

Right: For acute $\theta$: sin and cos are in $[0, 1]$, but tan can be any positive number.

5
Reading the Ratios
+5 XP

To find a trig ratio from a triangle, identify the three sides relative to $\theta$, then choose the right formula.

With sides labelled opp, adj, hyp (relative to $\theta$), compute the ratio: $\sin\theta$ uses opp and hyp, $\cos\theta$ uses adj and hyp, $\tan\theta$ uses opp and adj. Notice that hyp appears in sin and cos but NOT in tan.

adj = 4 opp = 3 hyp = 5$\sin\theta = 3/5 = 0.6$$\cos\theta = 4/5 = 0.8$$\tan\theta = 3/4 = 0.75$
sin needs hyp, cos needs hyp, tan does NOT
Identify $\theta$
Mark $\theta$ first, then label opp/adj/hyp.
sin + cos pair
Both use hyp on the bottom — only the top differs.
tan is special
Tan needs both legs, no hyp.
6
Why Ratios Don't Depend on Size
+5 XP

If you double a right triangle, you double every side — but the ratios opp/hyp, adj/hyp, opp/adj stay exactly the same. This is the magic of similar triangles.

Triangleopphypopp/hyp
3-4-5350.6
6-8-106100.6
15-20-2515250.6

Each triangle has the same acute angle — so the same $\sin\theta = 0.6$.

Scale the triangle → ratios unchanged
Same angle = same ratio
Any two right triangles sharing the angle $\theta$ have the same sin, cos, tan of $\theta$.
Calculator stores them
Your calculator remembers every sin, cos, tan value for you.
Greek letter
$\theta$ is just a variable name — like $x$ for length.
Watch Me Solve It · Compute all three ratios
+15 XP per step
Q1
PROBLEM
In a right triangle, opp = 3, adj = 4, hyp = 5. Find $\sin\theta$, $\cos\theta$, $\tan\theta$.
  1. 1
    Sine
    $\sin\theta = \dfrac{\text{opp}}{\text{hyp}} = \dfrac{3}{5} = 0.6$
  2. 2
    Cosine
    $\cos\theta = \dfrac{\text{adj}}{\text{hyp}} = \dfrac{4}{5} = 0.8$
  3. 3
    Tangent
    $\tan\theta = \dfrac{\text{opp}}{\text{adj}} = \dfrac{3}{4} = 0.75$
Answer$\sin\theta=0.6$, $\cos\theta=0.8$, $\tan\theta=0.75$
Watch Me Solve It · Same angle, scaled triangle
+15 XP per step
Q2
PROBLEM
A second triangle with the same angle $\theta$ has opp = 9, adj = 12, hyp = 15. Show $\tan\theta$ is the same.
  1. 1
    Compute
    $\tan\theta = 9/12$
  2. 2
    Simplify
    $= 3/4 = 0.75$
  3. 3
    Conclude
    Same as 3-4-5 triangle.
    This triangle is just 3$\times$(3-4-5) — same angles, same trig ratios.
Answer$\tan\theta = 0.75$, same as the smaller triangle.
Watch Me Solve It · Use SOH-CAH-TOA to choose
+15 XP per step
Q3
PROBLEM
A right triangle has opp = 8 and adj = 6 (with respect to $\theta$). Which trig ratio relates these two sides only? Compute it.
  1. 1
    Identify ratio
    opp/adj is the tangent definition.
  2. 2
    Apply
    $\tan\theta = 8/6 = 4/3$
  3. 3
    Approx
    $\approx 1.33$
Answer$\tan\theta = 4/3 \approx 1.33$
8
Common Pitfalls
heads-up
Swapping opp and adj in tan
Writing $\tan\theta = $ adj/opp instead of opp/adj.
Fix: TOA — Tangent = Opposite/Adjacent. Opp is on TOP.
Using hyp in tan
Putting the hypotenuse into a tan ratio.
Fix: Tan uses only the two legs — never the hypotenuse.
Mixing up which side is which
Calling the wrong side opposite or adjacent.
Fix: Identify $\theta$, find the side ACROSS = opp, find the leg NEXT = adj.
Copy Into Your Books

SOH-CAH-TOA

  • $\sin\theta = $ Opp/Hyp
  • $\cos\theta = $ Adj/Hyp
  • $\tan\theta = $ Opp/Adj

Ratios

  • sin: opp & hyp
  • cos: adj & hyp
  • tan: opp & adj

Properties

  • Same angle → same ratio
  • sin, cos $\in [0,1]$ for acute $\theta$
  • tan can be very large

No hyp in tan

  • Tan uses both legs
  • Doesn't need hyp
  • Useful when no hyp known

How are you completing this lesson?

D
Brain Trainer · SOH-CAH-TOA
4 problems

Four quick drills to lock in today's skill. Try each, then reveal the answer.

  1. 1 $\sin\theta = $?

    Sine = Opp / Hyp.Opp / Hyp
  2. 2 $\cos\theta = $?

    Cosine = Adj / Hyp.Adj / Hyp
  3. 3 $\tan\theta = $?

    Tangent = Opp / Adj.Opp / Adj
  4. 4 opp = 5, hyp = 13. Find $\sin\theta$.

    $\sin\theta = 5/13$.$\sin\theta = 5/13 \approx 0.385$
Complete in your workbook.
1
$\sin\theta$ equals:
+10 XP
2
In a 3-4-5 triangle with $\theta$ opposite the side of length 3, $\cos\theta = ?$
+10 XP
3
Which ratio does NOT use the hypotenuse?
+10 XP
4
opp = 7, adj = 24, hyp = 25. Find $\tan\theta$.
+10 XP
5
Two right triangles share an angle of 40°. Which is true about $\sin 40°$?
+10 XP
Show Your Working
9 marks total
ApplyMedium3 MARKS

Q6. In a right triangle, opp = 6, adj = 8, hyp = 10 with respect to $\theta$. Calculate (a) $\sin\theta$, (b) $\cos\theta$, (c) $\tan\theta$ as decimals.

Answer in your workbook.
UnderstandMedium2 MARKS

Q7. State SOH-CAH-TOA and explain in your own words what each part means.

Answer in your workbook.
ReasonHard4 MARKS

Q8. Triangle A has sides 5, 12, 13 (with $\theta$ at the angle opposite 5). Triangle B has sides 15, 36, 39 (with $\theta$ at the angle opposite 15). Show that $\sin\theta$ is identical in both triangles, and explain why.

Answer in your workbook.
Comprehensive Answers

Quick Check

1. C — SOH = Sine = Opp/Hyp.

2. B — adj=4, hyp=5.

3. D — Tan = opp/adj — no hyp.

4. A — $\tan\theta = 7/24$.

5. B — Same angle → same sine.

Show Your Working Model Answers

Q6 (3 marks): (a) $\sin\theta = 6/10 = 0.6$ [1]. (b) $\cos\theta = 8/10 = 0.8$ [1]. (c) $\tan\theta = 6/8 = 0.75$ [1].

Q7 (2 marks): S-O-H: Sine equals Opposite over Hypotenuse [1/2]. C-A-H: Cosine equals Adjacent over Hypotenuse [1/2]. T-O-A: Tangent equals Opposite over Adjacent [1]. Together they give the three trig ratios for any angle in a right triangle.

Q8 (4 marks): $\sin\theta_A = 5/13 \approx 0.385$ [1]. $\sin\theta_B = 15/39 = 5/13 \approx 0.385$ [1]. Identical [1]. Triangle B is $3\times$ triangle A — every side is scaled by 3, so opp/hyp = $3\cdot 5/(3\cdot 13) = 5/13$. The scaling cancels in the ratio, leaving the same value. Same angles → same trig ratios [1].

Stretch Challenge · +25 XP, +10 coins

Linking sin, cos and tan

Show, using SOH-CAH-TOA, that $\tan\theta = \dfrac{\sin\theta}{\cos\theta}$ for any acute $\theta$ in a right triangle.

Reveal solution

$\dfrac{\sin\theta}{\cos\theta} = \dfrac{\text{opp}/\text{hyp}}{\text{adj}/\text{hyp}} = \dfrac{\text{opp}}{\text{hyp}} \cdot \dfrac{\text{hyp}}{\text{adj}} = \dfrac{\text{opp}}{\text{adj}} = \tan\theta$. The hyp cancels.

R
Quick Review

SOH

$\sin\theta = $ Opp/Hyp

CAH

$\cos\theta = $ Adj/Hyp

TOA

$\tan\theta = $ Opp/Adj

Ratio constant

Same angle → same ratio

Tan special

Doesn't use the hypotenuse

Identity

$\tan\theta = \sin\theta / \cos\theta$

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