Introducing Trigonometric Ratios
Meet sin, cos and tan — the three ratios that connect a right-angled triangle's angle $\theta$ to its sides. Memorise SOH-CAH-TOA.
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Two right triangles both have an angle of 40°. One has hypotenuse 5 cm, the other 50 cm. Will the ratio ‘opposite ÷ hypotenuse’ be the same in both? Why or why not?
For any right triangle, the THREE side-pair ratios (opp/hyp, adj/hyp, opp/adj) depend ONLY on the angle $\theta$ — not on the size. We give them names: sine, cosine and tangent.
$\sin\theta = \dfrac{\text{opp}}{\text{hyp}}$, $\cos\theta = \dfrac{\text{adj}}{\text{hyp}}$, $\tan\theta = \dfrac{\text{opp}}{\text{adj}}$. Memorise these with SOH-CAH-TOA: Sine = Opp/Hyp, Cosine = Adj/Hyp, Tangent = Opp/Adj. Same angle → same ratio, every time.
Know
- The three trig ratios: sin, cos, tan
- SOH-CAH-TOA mnemonic
- Ratios depend on the angle only, not triangle size
Understand
- Why similar triangles (same angles) share trig ratios
- How sin and cos always lie between 0 and 1 for acute angles
- Why tan can exceed 1 (when opp > adj)
Can Do
- Write each trig ratio in terms of opp, adj, hyp
- Calculate sin, cos, tan given two sides
- Recall SOH-CAH-TOA fluently
Wrong: “$\sin 30° = $ something different in a bigger triangle.” No — same angle, same sine, always.
Right: $\sin 30° = 0.5$ in EVERY right triangle that contains a 30° angle.
Wrong: “tan can't be bigger than 1.” Wrong — tan goes to infinity as the angle approaches 90°.
Right: For acute $\theta$: sin and cos are in $[0, 1]$, but tan can be any positive number.
To find a trig ratio from a triangle, identify the three sides relative to $\theta$, then choose the right formula.
With sides labelled opp, adj, hyp (relative to $\theta$), compute the ratio: $\sin\theta$ uses opp and hyp, $\cos\theta$ uses adj and hyp, $\tan\theta$ uses opp and adj. Notice that hyp appears in sin and cos but NOT in tan.
If you double a right triangle, you double every side — but the ratios opp/hyp, adj/hyp, opp/adj stay exactly the same. This is the magic of similar triangles.
| Triangle | opp | hyp | opp/hyp |
|---|---|---|---|
| 3-4-5 | 3 | 5 | 0.6 |
| 6-8-10 | 6 | 10 | 0.6 |
| 15-20-25 | 15 | 25 | 0.6 |
Each triangle has the same acute angle — so the same $\sin\theta = 0.6$.
Watch Me Solve It · 3 examples
- 1Sine$\sin\theta = \dfrac{\text{opp}}{\text{hyp}} = \dfrac{3}{5} = 0.6$
- 2Cosine$\cos\theta = \dfrac{\text{adj}}{\text{hyp}} = \dfrac{4}{5} = 0.8$
- 3Tangent$\tan\theta = \dfrac{\text{opp}}{\text{adj}} = \dfrac{3}{4} = 0.75$
- 1Compute$\tan\theta = 9/12$
- 2Simplify$= 3/4 = 0.75$
- 3ConcludeSame as 3-4-5 triangle.This triangle is just 3$\times$(3-4-5) — same angles, same trig ratios.
- 1Identify ratioopp/adj is the tangent definition.
- 2Apply$\tan\theta = 8/6 = 4/3$
- 3Approx$\approx 1.33$
Common Pitfalls
SOH-CAH-TOA
- $\sin\theta = $ Opp/Hyp
- $\cos\theta = $ Adj/Hyp
- $\tan\theta = $ Opp/Adj
Ratios
- sin: opp & hyp
- cos: adj & hyp
- tan: opp & adj
Properties
- Same angle → same ratio
- sin, cos $\in [0,1]$ for acute $\theta$
- tan can be very large
No hyp in tan
- Tan uses both legs
- Doesn't need hyp
- Useful when no hyp known
How are you completing this lesson?
Brain Trainer · 4 problems
Four quick drills to lock in today's skill. Try each, then reveal the answer.
-
1 $\sin\theta = $?
Sine = Opp / Hyp.Opp / Hyp -
2 $\cos\theta = $?
Cosine = Adj / Hyp.Adj / Hyp -
3 $\tan\theta = $?
Tangent = Opp / Adj.Opp / Adj -
4 opp = 5, hyp = 13. Find $\sin\theta$.
$\sin\theta = 5/13$.$\sin\theta = 5/13 \approx 0.385$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. In a right triangle, opp = 6, adj = 8, hyp = 10 with respect to $\theta$. Calculate (a) $\sin\theta$, (b) $\cos\theta$, (c) $\tan\theta$ as decimals.
Q7. State SOH-CAH-TOA and explain in your own words what each part means.
Q8. Triangle A has sides 5, 12, 13 (with $\theta$ at the angle opposite 5). Triangle B has sides 15, 36, 39 (with $\theta$ at the angle opposite 15). Show that $\sin\theta$ is identical in both triangles, and explain why.
Quick Check
1. C — SOH = Sine = Opp/Hyp.
2. B — adj=4, hyp=5.
3. D — Tan = opp/adj — no hyp.
4. A — $\tan\theta = 7/24$.
5. B — Same angle → same sine.
Show Your Working Model Answers
Q6 (3 marks): (a) $\sin\theta = 6/10 = 0.6$ [1]. (b) $\cos\theta = 8/10 = 0.8$ [1]. (c) $\tan\theta = 6/8 = 0.75$ [1].
Q7 (2 marks): S-O-H: Sine equals Opposite over Hypotenuse [1/2]. C-A-H: Cosine equals Adjacent over Hypotenuse [1/2]. T-O-A: Tangent equals Opposite over Adjacent [1]. Together they give the three trig ratios for any angle in a right triangle.
Q8 (4 marks): $\sin\theta_A = 5/13 \approx 0.385$ [1]. $\sin\theta_B = 15/39 = 5/13 \approx 0.385$ [1]. Identical [1]. Triangle B is $3\times$ triangle A — every side is scaled by 3, so opp/hyp = $3\cdot 5/(3\cdot 13) = 5/13$. The scaling cancels in the ratio, leaving the same value. Same angles → same trig ratios [1].
Linking sin, cos and tan
Show, using SOH-CAH-TOA, that $\tan\theta = \dfrac{\sin\theta}{\cos\theta}$ for any acute $\theta$ in a right triangle.
Reveal solution
$\dfrac{\sin\theta}{\cos\theta} = \dfrac{\text{opp}/\text{hyp}}{\text{adj}/\text{hyp}} = \dfrac{\text{opp}}{\text{hyp}} \cdot \dfrac{\text{hyp}}{\text{adj}} = \dfrac{\text{opp}}{\text{adj}} = \tan\theta$. The hyp cancels.
SOH
$\sin\theta = $ Opp/Hyp
CAH
$\cos\theta = $ Adj/Hyp
TOA
$\tan\theta = $ Opp/Adj
Ratio constant
Same angle → same ratio
Tan special
Doesn't use the hypotenuse
Identity
$\tan\theta = \sin\theta / \cos\theta$
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