Skip to content
mathlab
0
0
0 XP
Lvl 1
KJ
Lesson 3 ~25 min Unit 3 · Trigonometry +85 XP

Finding a Shorter Side

When the hypotenuse and one leg are known, rearrange $a^2 + b^2 = c^2$ to solve for the missing leg. Subtract from the hypotenuse squared.

Today's hook: A 65-inch TV measures 56.7 inches across. Pythagoras says the height isn't 65 minus 56.7 — it's something smaller. How do you find the missing leg?
0/5QUESTS
Think First
warm-up

You know the hypotenuse is 13 cm and one leg is 5 cm. Without calculating, do you ADD the squares or SUBTRACT them to find the other leg? Why?

Record your answer in your workbook.
1
The Big Idea
+5 XP

When the hypotenuse is known, rearrange Pythagoras to: $a^2 = c^2 - b^2$. The shorter side is always found by SUBTRACTING the leg-squared from the hypotenuse-squared.

Start with $a^2 + b^2 = c^2$. To isolate $a^2$, subtract $b^2$ from both sides: $a^2 = c^2 - b^2$. Then square-root. The order matters: the hypotenuse squared comes first, then subtract the known leg squared. Doing it the other way gives a negative number — impossible.

$b$=5 $a$=? $c$=13
$a = \sqrt{c^2 - b^2}$
Subtract, don't add
Finding a LEG uses minus; finding the hypotenuse uses plus.
Hyp first
$c^2 - b^2$, not $b^2 - c^2$. The hypotenuse-squared is the biggest.
Smaller answer
A leg is always shorter than the hypotenuse — check your answer.
2
What You'll Master
objectives

Know

  • The rearranged formula $a^2 = c^2 - b^2$
  • The hypotenuse squared comes first
  • A leg is always shorter than the hypotenuse

Understand

  • Why the hypotenuse squared is the largest of the three
  • Why $c^2 - b^2$ (not $b^2 - c^2$) gives a positive result
  • How to identify which side is missing

Can Do

  • Rearrange $a^2 + b^2 = c^2$ to solve for either leg
  • Substitute correctly with $c$ as the largest
  • Sanity-check that the answer is smaller than the hypotenuse
3
Words You Need
vocabulary
RearrangeUse inverse operations to isolate the unknown letter on one side of the equation.
Inverse operationThe operation that “undoes” another. Subtraction undoes addition; square root undoes squaring.
Leg (shorter side)Either of the two sides that meet at the right angle. Always shorter than the hypotenuse.
Subtraction order$c^2 - b^2$ is positive when $c > b$. The hypotenuse is largest, so this order is correct.
Negative under root$\sqrt{\text{negative}}$ is not a real number. If you get one, you have your $c$ and $b$ swapped.
$c^2$ priorityThe hypotenuse squared is the biggest of the three squares. Always.
4
Spot the Trap
heads-up

Wrong: “$a^2 = b^2 - c^2$.” Wrong order — this gives a negative number.

Right: $a^2 = c^2 - b^2$ — hypotenuse squared minus leg squared.

Wrong: “$a^2 + b^2 = c^2$, so $a = c - b$.” You can't square-root each term separately.

Right: Subtract the squares, THEN take the square root: $a = \sqrt{c^2 - b^2}$.

5
Decision Question: Add or Subtract?
+5 XP

Ask yourself: is the unknown the longest side? If yes, ADD ($c^2 = a^2 + b^2$). If no, SUBTRACT ($a^2 = c^2 - b^2$).

Identify what's missing FIRST. If the hypotenuse is missing, ADD the squares of both legs. If a leg is missing, SUBTRACT the known leg squared from the hypotenuse squared.

8 ? 17 SUBTRACT: $a^2 = 17^2 - 8^2$
Missing hyp? Add. Missing leg? Subtract.
What's unknown?
Always check first whether the missing side is the hypotenuse or a leg.
Hyp = largest
$c$ is always the biggest of the three sides.
Sign test
If the result under $\sqrt{}$ is negative, swap $b$ and $c$.
6
Four-Step Method for a Leg
+5 XP

Solving for a shorter side follows a clear sequence. Practice it until it's automatic.

StepAction
1Label sides — mark hypotenuse as $c$
2Write $a^2 = c^2 - b^2$ (hyp first)
3Substitute, compute the subtraction
4Take $\sqrt{}$, round, add units
Label → rearrange → substitute → root
Mark $c$ clearly
Circle the hypotenuse in your diagram before writing equations.
Brackets again
Type $(c^2 - b^2)$ in brackets before the square root.
Answer < hyp
A leg must be less than the hypotenuse — quick sanity check.
Watch Me Solve It · Standard 13-5-? triangle
+15 XP per step
Q1
PROBLEM
A right triangle has hypotenuse 13 cm and one leg 5 cm. Find the other leg.
  1. 1
    Identify hyp
    $c=13$, $b=5$, $a=?$
    13 is the biggest, so it's the hypotenuse.
  2. 2
    Rearrange + substitute
    $a^2 = 13^2 - 5^2 = 169 - 25 = 144$
  3. 3
    Square root
    $a = \sqrt{144} = 12$ cm
    Recognise 5-12-13 triple.
Answer$a = 12$ cm
Watch Me Solve It · TV diagonal → height
+15 XP per step
Q2
PROBLEM
A 65-inch TV has a width of 56.7 inches. Find its height (2 d.p.).
  1. 1
    Set up
    $c = 65$ (diagonal), $b = 56.7$ (width), $a = $ height
  2. 2
    Compute
    $a^2 = 65^2 - 56.7^2 = 4225 - 3214.89 = 1010.11$
  3. 3
    Root
    $a = \sqrt{1010.11} \approx 31.78$ inches
Answer$\approx 31.78$ in
Watch Me Solve It · A non-perfect square
+15 XP per step
Q3
PROBLEM
Find the unknown leg of a right triangle with hypotenuse 10 cm and other leg 7 cm. Give the answer to 2 d.p.
  1. 1
    Rearrange
    $a^2 = c^2 - b^2 = 10^2 - 7^2$
  2. 2
    Compute
    $= 100 - 49 = 51$
  3. 3
    Root
    $a = \sqrt{51} \approx 7.14$ cm
Answer$a \approx 7.14$ cm
8
Common Pitfalls
heads-up
Wrong subtraction order
Computing $b^2 - c^2$ instead of $c^2 - b^2$.
Fix: The hypotenuse squared is always the BIGGER number, so it goes first.
Adding when you should subtract
Treating a leg problem like a hypotenuse problem.
Fix: Ask: is the unknown the longest side? If no → subtract.
Forgetting to identify $c$ first
Substituting the wrong number as the hypotenuse.
Fix: Mark the right angle and find the side opposite it — that's $c$.
Copy Into Your Books

Leg formula

  • $a^2 = c^2 - b^2$
  • $a = \sqrt{c^2 - b^2}$
  • Hyp-squared FIRST

Identify

  • Find right angle
  • Opposite side = $c$
  • $c$ goes into formula first

Method

  • Label
  • Rearrange
  • Substitute
  • Root + round

Sanity

  • Leg < hyp
  • If $\sqrt{}$ of negative, swap
  • Recognise triples for speed

How are you completing this lesson?

D
Brain Trainer · Shorter-Side Sprint
4 problems

Four quick drills to lock in today's skill. Try each, then reveal the answer.

  1. 1 $c=10$, $b=6$ — find $a$.

    $a^2=100-36=64$.$a=8$
  2. 2 $c=25$, $b=7$ — find $a$.

    $a^2=625-49=576$, $\sqrt{576}=24$.$a=24$
  3. 3 $c=17$, $b=15$ — find $a$.

    $a^2=289-225=64$.$a=8$
  4. 4 $c=20$, $b=12$ — find $a$.

    $a^2=400-144=256$, $\sqrt{256}=16$.$a=16$
Complete in your workbook.
1
Hypotenuse 13, one leg 5. The other leg is:
+10 XP
2
To find a shorter side you should:
+10 XP
3
Hyp 25 cm, leg 7 cm. Other leg?
+10 XP
4
If $\sqrt{c^2 - b^2}$ gives a negative number under the root, what went wrong?
+10 XP
5
Hyp 10, leg 7. Other leg to 2 d.p.?
+10 XP
Show Your Working
9 marks total
ApplyMedium3 MARKS

Q6. Find the missing leg in each triangle (2 d.p.): (a) $c=17$, $b=8$   (b) $c=15$, $b=9$   (c) $c=20$, $b=11$

Answer in your workbook.
ApplyEasy2 MARKS

Q7. A 5 m ladder leans against a wall. The base is 1.4 m from the wall. How high up the wall does the top of the ladder reach (2 d.p.)?

Answer in your workbook.
ReasonHard4 MARKS

Q8. A 65-inch TV has aspect ratio 16:9. The diagonal is 65 inches. By letting the width be $16k$ and height $9k$, find $k$ and hence the width and height of the TV (2 d.p.).

Answer in your workbook.
Comprehensive Answers

Quick Check

1. D — 5-12-13 triple.

2. B — $a^2 = c^2 - b^2$.

3. C — 7-24-25 triple.

4. A — $c$ must be the hypotenuse (largest), so $c^2 > b^2$.

5. C — $\sqrt{51}\approx 7.14$.

Show Your Working Model Answers

Q6 (3 marks): (a) $a^2=289-64=225$, $a=15$ [1]. (b) $a^2=225-81=144$, $a=12$ [1]. (c) $a^2=400-121=279$, $a\approx 16.70$ [1].

Q7 (2 marks): Height$^2 = 5^2 - 1.4^2 = 25 - 1.96 = 23.04$ [1]. Height $= \sqrt{23.04} = 4.80$ m [1].

Q8 (4 marks): $(16k)^2 + (9k)^2 = 65^2$ [1]. $256k^2 + 81k^2 = 337k^2 = 4225$ [1]. $k^2 = 12.539...$, $k\approx 3.5410$ [1]. Width $\approx 56.66$ in, height $\approx 31.87$ in [1].

Stretch Challenge · +25 XP, +10 coins

Sliding ladder

A 5 m ladder is set up with its base 3 m from a wall. The top of the ladder reaches some height $h$ up the wall. Someone then pulls the base out so it is 4 m from the wall instead. By how many metres does the top of the ladder drop?

Reveal solution

Original height $= \sqrt{25-9} = 4$ m. New height $= \sqrt{25-16} = 3$ m. The top drops by $4 - 3 = 1$ m.

R
Quick Review

Formula

$a = \sqrt{c^2 - b^2}$

Order

Hyp squared FIRST, then subtract

Sign

Result under $\sqrt{}$ must be positive

Sanity

Leg shorter than hyp

Identify

Hyp = side opposite right angle

Triples

5-12-13, 7-24-25, 8-15-17, 9-40-41

Your Badges

0 of 6
First Steps
3-Day Streak
3 in a Row
Lesson Ace
Stretch Seeker
Daily Warrior

Mark lesson as complete

Tick when you've finished Learn, Practice and the Stretch. Earns +85 XP and +25 coins.