Finding a Shorter Side
When the hypotenuse and one leg are known, rearrange $a^2 + b^2 = c^2$ to solve for the missing leg. Subtract from the hypotenuse squared.
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You know the hypotenuse is 13 cm and one leg is 5 cm. Without calculating, do you ADD the squares or SUBTRACT them to find the other leg? Why?
When the hypotenuse is known, rearrange Pythagoras to: $a^2 = c^2 - b^2$. The shorter side is always found by SUBTRACTING the leg-squared from the hypotenuse-squared.
Start with $a^2 + b^2 = c^2$. To isolate $a^2$, subtract $b^2$ from both sides: $a^2 = c^2 - b^2$. Then square-root. The order matters: the hypotenuse squared comes first, then subtract the known leg squared. Doing it the other way gives a negative number — impossible.
Know
- The rearranged formula $a^2 = c^2 - b^2$
- The hypotenuse squared comes first
- A leg is always shorter than the hypotenuse
Understand
- Why the hypotenuse squared is the largest of the three
- Why $c^2 - b^2$ (not $b^2 - c^2$) gives a positive result
- How to identify which side is missing
Can Do
- Rearrange $a^2 + b^2 = c^2$ to solve for either leg
- Substitute correctly with $c$ as the largest
- Sanity-check that the answer is smaller than the hypotenuse
Wrong: “$a^2 = b^2 - c^2$.” Wrong order — this gives a negative number.
Right: $a^2 = c^2 - b^2$ — hypotenuse squared minus leg squared.
Wrong: “$a^2 + b^2 = c^2$, so $a = c - b$.” You can't square-root each term separately.
Right: Subtract the squares, THEN take the square root: $a = \sqrt{c^2 - b^2}$.
Ask yourself: is the unknown the longest side? If yes, ADD ($c^2 = a^2 + b^2$). If no, SUBTRACT ($a^2 = c^2 - b^2$).
Identify what's missing FIRST. If the hypotenuse is missing, ADD the squares of both legs. If a leg is missing, SUBTRACT the known leg squared from the hypotenuse squared.
Solving for a shorter side follows a clear sequence. Practice it until it's automatic.
| Step | Action |
|---|---|
| 1 | Label sides — mark hypotenuse as $c$ |
| 2 | Write $a^2 = c^2 - b^2$ (hyp first) |
| 3 | Substitute, compute the subtraction |
| 4 | Take $\sqrt{}$, round, add units |
Watch Me Solve It · 3 examples
- 1Identify hyp$c=13$, $b=5$, $a=?$13 is the biggest, so it's the hypotenuse.
- 2Rearrange + substitute$a^2 = 13^2 - 5^2 = 169 - 25 = 144$
- 3Square root$a = \sqrt{144} = 12$ cmRecognise 5-12-13 triple.
- 1Set up$c = 65$ (diagonal), $b = 56.7$ (width), $a = $ height
- 2Compute$a^2 = 65^2 - 56.7^2 = 4225 - 3214.89 = 1010.11$
- 3Root$a = \sqrt{1010.11} \approx 31.78$ inches
- 1Rearrange$a^2 = c^2 - b^2 = 10^2 - 7^2$
- 2Compute$= 100 - 49 = 51$
- 3Root$a = \sqrt{51} \approx 7.14$ cm
Common Pitfalls
Leg formula
- $a^2 = c^2 - b^2$
- $a = \sqrt{c^2 - b^2}$
- Hyp-squared FIRST
Identify
- Find right angle
- Opposite side = $c$
- $c$ goes into formula first
Method
- Label
- Rearrange
- Substitute
- Root + round
Sanity
- Leg < hyp
- If $\sqrt{}$ of negative, swap
- Recognise triples for speed
How are you completing this lesson?
Brain Trainer · 4 problems
Four quick drills to lock in today's skill. Try each, then reveal the answer.
-
1 $c=10$, $b=6$ — find $a$.
$a^2=100-36=64$.$a=8$ -
2 $c=25$, $b=7$ — find $a$.
$a^2=625-49=576$, $\sqrt{576}=24$.$a=24$ -
3 $c=17$, $b=15$ — find $a$.
$a^2=289-225=64$.$a=8$ -
4 $c=20$, $b=12$ — find $a$.
$a^2=400-144=256$, $\sqrt{256}=16$.$a=16$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Find the missing leg in each triangle (2 d.p.): (a) $c=17$, $b=8$ (b) $c=15$, $b=9$ (c) $c=20$, $b=11$
Q7. A 5 m ladder leans against a wall. The base is 1.4 m from the wall. How high up the wall does the top of the ladder reach (2 d.p.)?
Q8. A 65-inch TV has aspect ratio 16:9. The diagonal is 65 inches. By letting the width be $16k$ and height $9k$, find $k$ and hence the width and height of the TV (2 d.p.).
Quick Check
1. D — 5-12-13 triple.
2. B — $a^2 = c^2 - b^2$.
3. C — 7-24-25 triple.
4. A — $c$ must be the hypotenuse (largest), so $c^2 > b^2$.
5. C — $\sqrt{51}\approx 7.14$.
Show Your Working Model Answers
Q6 (3 marks): (a) $a^2=289-64=225$, $a=15$ [1]. (b) $a^2=225-81=144$, $a=12$ [1]. (c) $a^2=400-121=279$, $a\approx 16.70$ [1].
Q7 (2 marks): Height$^2 = 5^2 - 1.4^2 = 25 - 1.96 = 23.04$ [1]. Height $= \sqrt{23.04} = 4.80$ m [1].
Q8 (4 marks): $(16k)^2 + (9k)^2 = 65^2$ [1]. $256k^2 + 81k^2 = 337k^2 = 4225$ [1]. $k^2 = 12.539...$, $k\approx 3.5410$ [1]. Width $\approx 56.66$ in, height $\approx 31.87$ in [1].
Sliding ladder
A 5 m ladder is set up with its base 3 m from a wall. The top of the ladder reaches some height $h$ up the wall. Someone then pulls the base out so it is 4 m from the wall instead. By how many metres does the top of the ladder drop?
Reveal solution
Original height $= \sqrt{25-9} = 4$ m. New height $= \sqrt{25-16} = 3$ m. The top drops by $4 - 3 = 1$ m.
Formula
$a = \sqrt{c^2 - b^2}$
Order
Hyp squared FIRST, then subtract
Sign
Result under $\sqrt{}$ must be positive
Sanity
Leg shorter than hyp
Identify
Hyp = side opposite right angle
Triples
5-12-13, 7-24-25, 8-15-17, 9-40-41
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