Checkpoint 1 ? Pythagoras' Theorem

⏱ 20 min📚 Year 9

Covers: Pythagoras' theorem, finding the hypotenuse, finding a shorter side, practical problems, sides of a right-angled triangle

Checkpoint 1

Test your understanding of Lessons 1-5

1 Easy Pythagoras' theorem states that, in a right-angled triangle:

A) $a + b = c$B) $a^2 + b^2 = c^2$, where $c$ is the hypotenuseC) $a^2 - b^2 = c^2$D) $a^2 + b^2 = c$

2 Easy A right-angled triangle has shorter sides $6$ cm and $8$ cm. Find the hypotenuse.

A) $7$ cmB) $10$ cmC) $14$ cmD) $48$ cm

3 Easy The two shorter sides of a right triangle are $5$ m and $12$ m. The hypotenuse is:

A) $13$ mB) $17$ mC) $7$ mD) $60$ m

4 Medium A right triangle has hypotenuse $13$ cm and one shorter side $5$ cm. The other shorter side is:

A) $8$ cmB) $18$ cmC) $12$ cmD) $14$ cm

5 Medium To find a shorter side when the hypotenuse is known, you should:

A) Add the squares of the two known sidesB) Subtract the square of the known short side from the square of the hypotenuse, then square rootC) Subtract the two side lengthsD) Multiply the two known sides

6 Medium A right triangle has shorter sides $7$ cm and $4$ cm. The hypotenuse, to 2 d.p., is:

A) $5.74$ cmB) $8.06$ cmC) $11.00$ cmD) $65.00$ cm

7 Hard Which set of side lengths forms a right-angled triangle?

A) $4, 5, 6$B) $8, 15, 17$C) $6, 7, 9$D) $5, 6, 8$

8 Hard A $5$ m ladder leans against a wall with its base $3$ m from the wall. How high up the wall does it reach?

A) $2$ mB) $8$ mC) $4$ mD) $5.83$ m

← Previous Next →

Subjects · Maths · Unit 3

Created for NSW Stage 5 students.