Mathematics • Year 9 • Unit 1 • Lesson 17

Operations in Scientific Notation

Build fluency with $\times$, $\div$, $+$ and $-$ on numbers in $a \times 10^n$ form. Multiply coefficients and add indices, divide coefficients and subtract indices, match powers before adding or subtracting, and re-standardise the coefficient back into $[1, 10)$ when it drifts.

Build · I Do / We Do / You Do

1. I do — fully worked example

Read every line. Each step has a short reason on the right so you can see why, not just what.

Problem. Calculate $(5 \times 10^3) \times (4 \times 10^2)$. Give your answer in scientific notation.

Step 1 — Spot the operation.

Two numbers in $a \times 10^n$ form being multiplied. So: $\times$ on the coefficients, $+$ on the indices.

Reason: $(a \times 10^m)(b \times 10^n) = (a \cdot b) \times 10^{m+n}$ — the product rule on $10^m \cdot 10^n$ adds indices.

Step 2 — Multiply the coefficients.

$5 \times 4 = 20$

Reason: the coefficients are just ordinary numbers — handle them with ordinary arithmetic.

Step 3 — Add the indices.

$10^3 \times 10^2 = 10^{3+2} = 10^5$

Reason: product rule on powers of the same base — add the indices.

Step 4 — Combine.

$20 \times 10^5$

Reason: $20$ is outside $[1, 10)$ — this is right value, wrong form. Re-standardise.

Step 5 — Re-standardise.

$20 \times 10^5 = 2.0 \times 10^6$   (decimal shifts one left $\to$ index goes up by 1)

Reason: shift the decimal one place left, bump the power of 10 up by 1, so the value is unchanged.

Answer: $\mathbf{2 \times 10^6}$.

Stuck? Revisit lesson § "Spot the Trap" — multiplying the indices instead of adding them is the most common slip.

2. We do — fill in the missing steps

Same structure as Section 1, with the working faded. Fill in each blank. 4 marks

Problem. Calculate $3 \times 10^4 + 2 \times 10^3$. Give your answer in scientific notation.

Step 1 — Spot the operation: addition — so the powers of $10$ must __________________ first.

Step 2 — Rewrite the smaller-power term to share the larger power $10^4$:

$2 \times 10^3 = \_\_\_\_ \times 10^4$

Step 3 — Now both terms share $10^4$. Add the coefficients:

$3 + \_\_\_\_ = \_\_\_\_$

Step 4 — Write the result:

$3 \times 10^4 + 2 \times 10^3 = \_\_\_\_\_\_\_ \times 10^4$

Step 5 — Check the form: Is the coefficient in $[1, 10)$?   __________ (yes / no)

Stuck? Revisit lesson § "Watch Me Solve It · Add" — that worked the exact same calculation step-by-step.

3. You do — independent practice

Show your working under each problem. The first four are foundation (single operation, clean numbers). The middle two are standard (need a re-standardise or negative index). The last two are extension (real context or extra step).

Foundation — single operation

3.1 Calculate $(4 \times 10^3) \times (2 \times 10^5)$.    1 mark

3.2 Calculate $\dfrac{9 \times 10^8}{3 \times 10^3}$.    1 mark

3.3 Calculate $\dfrac{6 \times 10^9}{3 \times 10^4}$.    1 mark

3.4 Calculate $4 \times 10^5 + 3 \times 10^4$.    1 mark

Standard — re-standardise or negatives

3.5 Calculate $(6 \times 10^5) \times (5 \times 10^{-2})$. Give your answer in scientific notation.    2 marks

3.6 Calculate $5 \times 10^{-3} - 2 \times 10^{-4}$. Give your answer in scientific notation.    2 marks

Extension — push your thinking

3.7 Calculate $(8 \times 10^4) \times (5 \times 10^3)$, giving the answer in scientific notation. (Hint: the coefficient won't stay in $[1, 10)$ at first.)    2 marks

3.8 A student writes "$3 \times 10^4 + 2 \times 10^3 = 5 \times 10^7$." Explain in one sentence what they did wrong, then give the correct answer in scientific notation.    2 marks

Stuck on 3.7? Multiply coefficients first ($8 \times 5 = 40$), then add indices, then re-standardise the $40$.

How did this worksheet feel?

What I'll revisit before next class:

Answers — Do not peek before attempting

Section 2 — We do (faded $3 \times 10^4 + 2 \times 10^3$)

Step 1: powers of 10 must match first.
Step 2: $2 \times 10^3 = \mathbf{0.2} \times 10^4$.
Step 3: $3 + \mathbf{0.2} = \mathbf{3.2}$.
Step 4: $3 \times 10^4 + 2 \times 10^3 = \mathbf{3.2} \times 10^4$.
Step 5: $3.2$ is in $[1, 10)$ — yes, already in standard form.

3.1 — $(4 \times 10^3) \times (2 \times 10^5)$

Coefficients: $4 \times 2 = 8$. Indices: $10^{3+5} = 10^8$. Answer: $\mathbf{8 \times 10^8}$.

3.2 — $\dfrac{9 \times 10^8}{3 \times 10^3}$

Coefficients: $9 / 3 = 3$. Indices: $10^{8 - 3} = 10^5$. Answer: $\mathbf{3 \times 10^5}$.

3.3 — $\dfrac{6 \times 10^9}{3 \times 10^4}$

Coefficients: $6 / 3 = 2$. Indices: $10^{9 - 4} = 10^5$. Answer: $\mathbf{2 \times 10^5}$.

3.4 — $4 \times 10^5 + 3 \times 10^4$

Match powers: $3 \times 10^4 = 0.3 \times 10^5$. Add coefficients: $4 + 0.3 = 4.3$. Answer: $\mathbf{4.3 \times 10^5}$.

3.5 — $(6 \times 10^5) \times (5 \times 10^{-2})$

Coefficients: $6 \times 5 = 30$. Indices: $10^{5 + (-2)} = 10^3$. Current: $30 \times 10^3$ — coefficient out of $[1, 10)$. Re-standardise: $\mathbf{3 \times 10^4}$.

3.6 — $5 \times 10^{-3} - 2 \times 10^{-4}$

Match powers to the larger index ($-3$): $2 \times 10^{-4} = 0.2 \times 10^{-3}$. Subtract: $5 - 0.2 = 4.8$. Answer: $\mathbf{4.8 \times 10^{-3}}$.

3.7 — $(8 \times 10^4) \times (5 \times 10^3)$

Coefficients: $8 \times 5 = 40$. Indices: $10^{4+3} = 10^7$. Current: $40 \times 10^7$ — $40$ is outside $[1, 10)$. Re-standardise: $40 = 4.0 \times 10^1$, so $40 \times 10^7 = 4 \times 10^8$. Answer: $\mathbf{4 \times 10^8}$.

3.8 — Find the mistake in $3 \times 10^4 + 2 \times 10^3$

The student added the coefficients and the indices together ($3 + 2 = 5$ and $4 + 3 = 7$), but addition of scientific-notation terms requires the powers of $10$ to match first — you never add indices when adding terms.
Correct working: rewrite $2 \times 10^3 = 0.2 \times 10^4$, then $(3 + 0.2) \times 10^4 = \mathbf{3.2 \times 10^4}$.