Mathematics • Year 9 • Unit 1 • Lesson 3

The Product Rule in the Real World

Use $a^m \times a^n = a^{m+n}$ in everyday contexts: stacking boxes, video uploads, file storage, school enrolment growth and biology lab cultures. Then explain your method in your own words.

Apply · Real-World Maths

1. Word problems

Each problem uses the product rule from Lesson 3: $a^m \times a^n = a^{m+n}$. Show your working — a single final answer with no working only earns half marks.

1.1 — Stacking storage boxes. Aaliyah packs her belongings into small boxes, then puts those into larger crates. There are $2^4$ small boxes per crate, and she has $2^3$ crates.

(a) Write the total number of small boxes as a product of two powers of $2$.
(b) Apply the product rule to express the total as a single power of $2$, then evaluate it.    3 marks

Stuck? Total $= 2^4 \times 2^3$. Same base, ADD indices.

1.2 — Video uploads. A YouTuber uploads $3^2$ videos per month for $3^3$ months in a row.

(a) Write the total number of videos as a single power of $3$.
(b) Evaluate it as a normal number.    3 marks

Stuck? Total videos $= 3^2 \times 3^3$. Add the indices.

1.3 — Phone storage breakdown. A phone has $2^{10}$ bytes per kilobyte and $2^{10}$ kilobytes per megabyte. So one megabyte equals $2^{10} \times 2^{10}$ bytes.

(a) Use the product rule to write one megabyte as a single power of $2$.
(b) Explain in one sentence what the index now represents.    3 marks

Stuck? $2^{10} \times 2^{10} = 2^{10+10}$.

1.4 — School enrolment growth. A small school had $5^2$ students in $2020$. By $2024$, the number had grown by a factor of $5^3$.

(a) Write the new enrolment in $2024$ as a single power of $5$.
(b) Evaluate it as a normal number. (Hint: $5^5 = 3125$.)    3 marks

Stuck? New enrolment $= 5^2 \times 5^3$.

1.5 — Bacteria culture. A biology lab has a starting culture of $10^4$ bacteria. The culture multiplies by $10^2$ over the weekend, then multiplies by another $10$ on Monday morning.

(a) Write the final population as a product of three powers of $10$.
(b) Use the product rule to write it as a single power of $10$.
(c) Evaluate it as a normal number.    3 marks

Stuck on (a)? $10^4 \times 10^2 \times 10^1$ (Monday's growth is a single $\times 10$ = $10^1$).

2. Explain your thinking

This question is about communication, not just answers. Use full sentences. 4 marks

2.1 A classmate writes "$2^3 \times 3^4 = 6^7$". They're confident they're right. In your own words, explain (i) what mistake they have made, (ii) which condition of the product rule they have ignored, and (iii) the correct value of $2^3 \times 3^4$ as a normal number. Use the words "same base" somewhere in your explanation.

Stuck? Revisit lesson § "Spot the Trap" — combining different bases is exactly the trap shown there.

How did this worksheet feel?

What I'll revisit before next class:

Answers — Do not peek before attempting

1.1 — Stacking storage boxes

(a) Total $= 2^4 \times 2^3$ small boxes.
(b) Same base, add indices: $2^{4+3} = \mathbf{2^7} = 128$ small boxes.
Quick check: $2^4 = 16$ boxes per crate, $2^3 = 8$ crates, so $16 \times 8 = 128$ ✓.

1.2 — Video uploads

(a) Total $= 3^2 \times 3^3 = 3^{2+3} = \mathbf{3^5}$ videos.
(b) $3^5 = 243$ videos.
Quick check: $9 \times 27 = 243$ ✓.

1.3 — Phone storage breakdown

(a) $1$ MB $= 2^{10} \times 2^{10} = 2^{10+10} = \mathbf{2^{20}}$ bytes.
(b) The index $20$ counts the total number of $2$s multiplied — equivalently, the total number of "doublings" from $1$ byte to reach one megabyte.
So a megabyte ($2^{20}$ bytes) $= 1{,}048{,}576$ bytes — sometimes rounded to "about a million bytes".

1.4 — School enrolment growth

(a) New enrolment $= 5^2 \times 5^3 = 5^{2+3} = \mathbf{5^5}$ students.
(b) $5^5 = \mathbf{3125}$ students.
That's a 125-fold increase — clearly hypothetical for one school, but the index arithmetic is real!

1.5 — Bacteria culture

(a) Final population $= 10^4 \times 10^2 \times 10^1$.
(b) Same base $10$, add all three indices: $4 + 2 + 1 = 7$. So $\mathbf{10^7}$.
(c) $10^7 = \mathbf{10{,}000{,}000}$ bacteria (ten million).
For base $10$, the index = number of zeros.

2.1 — Explain your thinking (sample response)

My classmate has tried to use the product rule with two different bases ($2$ and $3$). The rule $a^m \times a^n = a^{m+n}$ only works when the bases are the same base. Adding the indices to get $6^7$ is meaningless here, because $2$ and $3$ are different numbers — you cannot combine them into base $6$. To work out $2^3 \times 3^4$ correctly, you have to evaluate each power separately: $2^3 = 8$ and $3^4 = 81$, then multiply normally: $8 \times 81 = \mathbf{648}$. A quick check: $6^7 = 279{,}936$, which is enormously larger than $648$ — the wrong answer is wildly off, confirming the rule was misused.

Marking: 1 mark for naming the rule's "same base" condition; 1 for identifying the bases are different; 1 for the correct answer $648$; 1 for a clear, full-sentence explanation.