Mathematics • Year 8 • Unit 3 • Lesson 14

Angles in Parallel Lines — Mixed Challenge

Six mixed problems mixing F, Z, C, and vertically opposite rules. One "find the mistake" and one open-ended diagram-building challenge.

Master · Mixed Challenge

1. Mixed problems — choose the right rule

Decide which rule applies (corresponding F, alternate Z, co-interior C, vertically opposite, or angles on a straight line) BEFORE you set up the calculation. Every angle answer needs a written reason. 3 marks each

1.1 Two parallel lines are cut by a transversal. One angle is 137°. Find (a) the corresponding angle, (b) the co-interior angle on the same side, (c) the vertically opposite angle. State the rule for each.

1.2 Alternate angles are (5x − 15)° and (2x + 30)°. Find x and each angle.

1.3 Co-interior angles are (3x + 10)° and (x + 30)°. Find x and each angle.

1.4 Two parallel lines L1 and L2 are cut by a transversal. At L1, the angle on the upper-left of the intersection is 64°. Find all eight angles (state each rule used).

1.5 A transversal cuts two parallel lines and makes a 90° angle with one of them. What angle does it make with the other? Justify with a parallel-line rule.

1.6 Three parallel lines are cut by a single transversal. The angle between the transversal and the TOP parallel line is 50° (measured on the right). Find the corresponding angle on the right at each of the three parallel lines, and explain why all three are equal.

Stuck on 1.6? When three or more lines are all parallel, the corresponding angle rule applies at every intersection — every angle in the same position equals the original.

2. Find the mistake

A Year 8 student tried to solve: "Co-interior angles in a pair of parallel lines are (2x + 30)° and (x + 60)°. Find x." Their working is shown below. Exactly one line contains a mistake. Spot it, explain why it's wrong, and re-do the working. 3 marks

Student's working:

Line 1:   Co-interior angles are equal (parallel lines)

Line 2:   2x + 30 = x + 60

Line 3:   x = 30

Line 4:   So both angles = 2(30) + 30 = 90°.

(a) Which line contains the mistake?

(b) Explain in one or two sentences why that line is wrong.

(c) Write out the corrected working in full, including the correct value of x and both angles.

Stuck? Revisit lesson § Card 6 — co-interior angles are NOT equal. They are SUPPLEMENTARY (add to 180°). Only alternate and corresponding angles are equal.

3. Open-ended challenge — design your own parallel-line diagram

This question has more than one valid answer. 4 marks

3.1 Sketch a diagram with TWO parallel lines and ONE transversal. Label EIGHT angles a, b, c, d, e, f, g, h (four at each intersection).

Then choose ONE angle to be exactly 43° and find ALL the other seven angles. For EACH of the other seven, state the rule used (e.g. "vertically opposite", "corresponding", "alternate", "co-interior", or "angles on a straight line").

Bonus: after solving, write down how many DISTINCT angle values appear in the diagram, and explain why (in 1 sentence).

Stuck? Start by labelling one angle 43°. The vertically opposite angle is also 43°. The other two at the same intersection are 180° − 43° = 137° each. Then transfer to the other intersection using corresponding angles.

How did this worksheet feel?

What I'll revisit before next class:

Answers — Do not peek before attempting

1.1 — One angle = 137°

(a) Corresponding = 137° (corresponding angles, parallel lines).
(b) Co-interior = 180° − 137° = 43° (co-interior angles add to 180°).
(c) Vertically opposite = 137° (vertically opposite angles).

1.2 — Alternate (5x−15)° and (2x+30)°

Alternate angles are equal: 5x − 15 = 2x + 30 → 3x = 45 → x = 15. Each angle = 5(15) − 15 = 60°.

1.3 — Co-interior (3x+10)° and (x+30)°

Co-interior add to 180°: (3x + 10) + (x + 30) = 180 → 4x + 40 = 180 → 4x = 140 → x = 35. Angles: 3(35)+10 = 115° and 35+30 = 65°.

1.4 — One angle at L1 = 64°

At L1: upper-left = 64°; upper-right = 116° (straight line); lower-right = 64° (vertically opposite); lower-left = 116° (vertically opposite).
At L2: corresponding to L1 → upper-left = 64°, upper-right = 116°, lower-right = 64°, lower-left = 116°. All eight angles are either 64° or 116°.

1.5 — Transversal perpendicular to one parallel line

It also makes 90° with the other parallel line (corresponding angles equal). If one is perpendicular, both intersections form right angles.

1.6 — Three parallel lines + one transversal

The corresponding angle on the right at each of the three parallel lines is 50°. They are all equal because corresponding angles (parallel lines) are equal — and this rule extends to any number of parallel lines cut by the same transversal.

2 — Find the mistake

(a) The mistake is on Line 1 (carried into Line 2).
(b) Co-interior angles are NOT equal — they are SUPPLEMENTARY (they add to 180°). The student set the two expressions equal when they should have set their sum equal to 180.
(c) Corrected: Co-interior angles add to 180°. (2x + 30) + (x + 60) = 180 → 3x + 90 = 180 → 3x = 90 → x = 30. Angles: 2(30)+30 = 90° and 30+60 = 90° ✓ (the transversal is perpendicular to both parallel lines).

3 — Diagram with one angle = 43° (sample solution)

At the first intersection (say where the transversal hits L1):
a = 43°; b = 180° − 43° = 137° (straight line); c = 43° (vertically opposite to a); d = 137° (vertically opposite to b).
At the second intersection (where the transversal hits L2):
e = 43° (corresponding to a); f = 137° (corresponding to b); g = 43° (vertically opposite to e); h = 137° (vertically opposite to f).

Distinct values: only TWO distinct angles appear (43° and 137°). This is because vertically opposite angles match, and corresponding angles match — so the entire diagram collapses into just two possibilities: the original and its supplement.

Marking: 2 marks for correctly labelling all 8 angles with values; 1 mark for naming the rules used; 1 mark for correctly identifying that only 2 distinct values appear, with reason.