Angles: Types and Naming
Classify angles, identify complementary and supplementary pairs, and use vertically opposite angles and angles at a point to find unknowns.
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Look around the room right now. Find examples of angles that are: less than 90°, exactly 90°, between 90° and 180°, and greater than 180°.
Without measuring, estimate the size of the angle between the hands of a clock at 3:00, at 6:00, and at 2:00. Write your guesses.
An angle measures the amount of turn between two rays from a common vertex. Key relationships let you find unknown angles without measuring:
Complementary Two angles summing to 90°.
Supplementary Two angles summing to 180°.
Vertically opposite When two lines cross, opposite angles are equal.
Angles at a point All angles at a point sum to 360°.
Know
- Angle types: acute, right, obtuse, straight, reflex, revolution
- Complementary angles sum to 90°
- Supplementary angles sum to 180°
- Vertically opposite angles are equal; angles at a point sum to 360°
Understand
- Why vertically opposite angles are equal (both supplement the same angle)
- How to use angle relationships to find unknowns algebraically
Can Do
- Name and classify angles
- Find complements and supplements
- Find unknown angles using vertically opposite and angle-at-a-point rules
- Set up and solve equations for angle problems
The six main angle types are defined by their size in degrees:
| Type | Size | Example |
|---|---|---|
| Acute | 0° < x < 90° | 55° |
| Right | x = 90° | 90° |
| Obtuse | 90° < x < 180° | 130° |
| Straight | x = 180° | 180° |
| Reflex | 180° < x < 360° | 240° |
| Revolution | x = 360° | 360° |
Tip: A reflex angle of $x°$ and its non-reflex partner sum to 360°. So if the non-reflex angle is 70°, the reflex angle is 290°.
Two angles are complementary if they sum to 90°. To find the complement of an angle $x$, calculate $90 - x$.
- Complement of 30° = 90 − 30 = 60°
- Complement of 55° = 90 − 55 = 35°
- Complement of 89° = 90 − 89 = 1°
Complementary angles do not need to be adjacent — they just need to sum to 90°. When they are adjacent, they form a right angle together.
Memory: Complementary = Corner (right angle, 90°).
What to write in your book
- Complementary: two angles summing to 90°.
- Complement of x = 90 − x.
- Memory: C for Corner.
Two angles are supplementary if they sum to 180°. To find the supplement of $x$, calculate $180 - x$.
- Supplement of 60° = 180 − 60 = 120°
- Supplement of 115° = 180 − 115 = 65°
- Supplement of 90° = 180 − 90 = 90° (right angles are self-supplementary!)
Adjacent supplementary angles form a straight line. These are also called a linear pair.
Ratios example: Two supplementary angles in ratio 2:3. Total 5 parts = 180°, so 1 part = 36°. Angles: 72° and 108°.
Memory: Supplementary = Straight line (180°).
What to write in your book
- Supplementary: two angles summing to 180°.
- Supplement of x = 180 − x.
- Adjacent supplementary angles form a straight line.
- Memory: S for Straight.
When two straight lines cross, they form four angles. The angles directly across from each other are called vertically opposite and are always equal.
Why? Both $\alpha$ and the other $\alpha$ are supplements of the same $\beta$. Since supplements are unique, they must be equal.
What to write in your book
- Vertically opposite angles are equal (abbreviated: vert. opp. ∠s).
- Adjacent angles at an intersection are supplementary (sum to 180°).
- When two lines cross, the 4 angles form two pairs of vertically opposite angles.
All the angles that meet at a single point (going all the way around) sum to 360°. This is called the angles at a point (or revolution) rule.
$$\text{angles at a point} = 360°$$
Example: Three angles at a point: 85°, 120°, and $x$.
$85 + 120 + x = 360$
$205 + x = 360$
$x = 155°$
Check: A straight line creates two angles at a point summing to 180°. A full turn is 360°. These are both special cases of the angles-at-a-point rule.
What to write in your book
- Angles at a point sum to 360°.
- To find an unknown: subtract the sum of known angles from 360°.
- Special case: angles on a straight line = 180° (2 angles at a point on one side).
Watch Me Solve It · 3 examples
- 1Complement90 − 37 = 53°Complementary angles sum to 90°.
- 2Supplement180 − 37 = 143°Supplementary angles sum to 180°.
- 3Check37 + 53 = 90 ✓ 37 + 143 = 180 ✓
- 1Total parts2 + 3 = 5 partsThe ratio 2:3 has 5 total parts.
- 2Value of 1 part180° ÷ 5 = 36° per partThe total is 180° (supplementary).
- 3Find the angles2 × 36 = 72° 3 × 36 = 108°Check: 72 + 108 = 180 ✓
- 1Vertically oppositeAngle opposite 58° = 58°Vertically opposite angles are equal.
- 2Adjacent angles (supplementary)180 − 58 = 122°Angles on a straight line sum to 180°.
- 3All four angles58°, 122°, 58°, 122°Check: 58 + 122 + 58 + 122 = 360 ✓
Angle Types
- Acute: 0°–90°
- Right: 90°
- Obtuse: 90°–180°
- Straight: 180°
- Reflex: 180°–360°
Relationships
- Complementary: sum = 90° (C for Corner)
- Supplementary: sum = 180° (S for Straight)
- Vertically opposite: equal
- Angles at a point: sum = 360°
Finding Unknowns
- Complement: 90 − x
- Supplement: 180 − x
- At a point: 360 − (sum of others)
How are you completing this lesson?
Brain Trainer · 10 problems
Quick mental maths. Name the relationship you use.
1 Complement of 45°?
90 − 45 = 45°2 Supplement of 70°?
180 − 70 = 110°3 Complement of 23°?
90 − 23 = 67°4 Supplement of 135°?
180 − 135 = 45°5 Two lines cross. One angle = 40°. Find all 4.
Vert. opp. = 40°. Adjacent = 180 − 40 = 140°. 40°, 140°, 40°, 140°6 Angles at a point: 90°, 120°, x. Find x.
x = 360 − 90 − 120 = 150°7 Is 95° acute, right, or obtuse?
Obtuse (between 90° and 180°)8 Supp. angles in ratio 1:4. Find each.
1 part = 36°. 36° and 144°9 Angle on straight line: one part is 65°. Other part?
180 − 65 = 115°10 Reflex angle if the non-reflex angle is 50°?
360 − 50 = 310°
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Four angles at a point are 3x°, 2x°, and x° (only 3 rays from a point, but wait — actually the angles around a point from 3 rays are 3x, 2x, and x if they are all the angles). Wait — three angles 3x, 2x, x at a point. Find x and all three angles. (3 marks)
Q7. Two supplementary angles are such that one is 40° more than the other. Find both angles. (2 marks)
Q8. Two straight lines cross. One of the four angles formed is $(2x + 15)$°. Given that vertically opposite angles are equal, find x and all four angles. (4 marks)
Quick Check
1. B — 90 − 64 = 26°.
2. C — 180 − 115 = 65°.
3. B — 135° is obtuse (between 90° and 180°).
4. A — Vertically opposite angles are equal: 72°.
5. D — 360 − 85 − 120 = 155°.
Model Answers
Q6: 3x + 2x + x = 360. 6x = 360. x = 60°. Angles: 180°, 120°, 60° [3].
Q7: x + (x+40) = 180. 2x = 140. x = 70°. Angles: 70° and 110° [2].
Q8: One angle = (2x+15)°. Adjacent (supplementary) = 180−(2x+15) = (165−2x)°. Vertically opposite pair: (2x+15) and (2x+15); other pair: (165−2x) and (165−2x). Without another equation, x can be any value. If the problem states the two distinct angles are equal (i.e., it is a special case where all four angles are equal = 90°), then 2x+15=90, x=37.5. Otherwise, x is underdetermined and you would need an extra condition. [4 marks for correct reasoning and all four angles expressed in terms of x].
Clock Angle Challenge
A clock at 3:00 has the minute hand at 12 and the hour hand at 3. The angle between them is 90°.
Part A: At 3:20, where are the hands? The minute hand has moved 120° and the hour hand has moved 10° from 3:00. What is the angle between them now?
Part B: The minute hand moves at 6°/min and the hour hand at 0.5°/min. At what time between 3:00 and 4:00 are the hands at exactly 90° again?
Reveal solution
Part A: At 3:20: minute hand = 120° from 12 (at 4); hour hand = 90 + 10 = 100° from 12. Angle = |120 − 100| = 20°.
Part B: Minute hand position = 6t°. Hour hand = 90 + 0.5t°. For 90° apart (and minute hand past hour hand): 6t − (90 + 0.5t) = 90. 5.5t = 180. t = 180/5.5 ≈ 32.7 min. Time: approximately 3:33.
Angle Types
Acute < 90° < Obtuse < 180° < Reflex
Complementary
Sum = 90°. C for Corner.
Supplementary
Sum = 180°. S for Straight.
Vert. opposite
Equal when two lines cross.
Angles at point
Sum = 360°.
Finding unknowns
Set up equation, solve for x.
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