Area of Circles
Master $A = \pi r^2$ — and always square the RADIUS, never the diameter.
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A circle fits snugly inside a square whose side equals the circle's diameter. Is the circle's area more than half the square's area, less than half, or exactly half? Sketch and estimate.
The area of a circle depends on its radius $r$. The formula is $A = \pi r^2$. You must square the radius, then multiply by $\pi$. If you are given diameter $d$, always halve it first: $r = d \div 2$. Area is in square units (cm², m²). The formula shows that doubling the radius quadruples the area — because $r$ is squared.
Know
- $A = \pi r^2$ (must use radius)
- From diameter: $r = d/2$ first
- Reverse: $r = \sqrt{A/\pi}$
Understand
- Why the formula uses radius not diameter
- How sector rearrangement derives $A = \pi r^2$
- Why area scales with $r^2$ (doubling $r$ quadruples $A$)
Can Do
- Calculate circle area from radius or diameter
- Find radius when area is given
- Find area of semicircle and quarter circle
- Compare areas to solve real-world problems
Classic error: using the diameter in place of the radius — giving an area four times too large.
Wrong ($d = 10$, used as $r$)
$A = \pi \times 10^2 = 100\pi \approx 314$ cm² ✗
Correct ($r = 10 \div 2 = 5$)
$A = \pi \times 5^2 = 25\pi \approx 78.5$ cm² ✓
Rule: Always ask — is this a radius or a diameter? Halve if diameter.
Slice a circle into many thin sectors (pizza slices) and rearrange them alternating up/down to form a shape like a rectangle. As the number of slices increases, the shape approaches a true rectangle with width $\approx \pi r$ (half the circumference) and height $= r$. So: Area $= \pi r \times r = \pi r^2$.
When radius is given, substitute directly. Critical order: square $r$ first, then multiply by $\pi$. Example: $r = 5$ cm.
Step 1: $r^2 = 5^2 = 25$
Step 2: $A = \pi \times 25 = 25\pi \approx 78.54$ cm²
If diameter $d$ is given, halve it first to find $r$, then apply $A = \pi r^2$. Example: $d = 14$ cm.
Step 1: $r = 14 \div 2 = 7$ cm
Step 2: $r^2 = 49$
Step 3: $A = 49\pi \approx 153.94$ cm²
Finding $r$ from area: $A = \pi r^2 \Rightarrow r^2 = A/\pi \Rightarrow r = \sqrt{A/\pi}$
Semicircle (half circle): $A_{\text{semi}} = \dfrac{1}{2}\pi r^2$
Quarter circle (90° sector): $A_{\text{quarter}} = \dfrac{1}{4}\pi r^2$
Watch Me Solve It · 3 examples
- 1Write the formula$$A = \pi r^2$$
- 2Square the radius first$r^2 = 5^2 = 25$
- 3Multiply by $\pi$$A = \pi \times 25 = 25\pi \approx 78.54$ cm²
- 4State with units$A \approx 78.54$ cm²
- 1Find the radius$r = d \div 2 = 14 \div 2 = 7$ cm
- 2Square the radius$r^2 = 7^2 = 49$
- 3Multiply by $\pi$$A = \pi \times 49 = 49\pi \approx 153.94$ cm²
- 1Rearrange the formula$r^2 = A \div \pi = 78.5 \div \pi \approx 24.99$
- 2Take the square root$r = \sqrt{24.99} \approx 5.0$ cm
- 3Check$A = \pi \times 5^2 = 25\pi \approx 78.54$ cm² ✓
How are you completing this lesson?
Brain Trainer · 4 problems
Set a timer for 4 minutes. Show all working.
-
1 Find $A$ for $r = 3$ cm.
$A = \pi \times 9 = 9\pi \approx 28.27$ cm² -
2 Find $A$ for $d = 10$ cm. (Halve first!)
$r = 5$. $A = \pi \times 25 = 25\pi \approx 78.54$ cm² -
3 Find $r$ when $A = 200$ cm².
$r = \sqrt{200/\pi} \approx \sqrt{63.66} \approx 7.98 \approx 8$ cm -
4 Hook: circular pizza $d = 30$ cm vs square $20 \times 20$ cm. Which is bigger and by how much?
Circle: $r = 15$. $A = \pi \times 225 \approx 706.86$ cm². Square: $A = 400$ cm². Circle wins by $\approx 307$ cm²!
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. A circular pool has diameter 8 m. Find its area. Calculate the cost to tile the bottom at $45 per m².
Q7. A semicircle has radius 6 cm. Find its area. Round to 2 decimal places.
Q8. A circle has area 113.1 cm². (a) Find the radius. (b) Find the circumference. (c) A fence around the circle costs $12 per metre. Find the total cost.
MC: 1-A, 2-C, 3-B, 4-A, 5-B
Q6: $r = 4$ m. $A = \pi \times 16 = 16\pi \approx 50.27$ m². Cost $= 50.27 \times 45 \approx \$2\,262$.
Q7: $A_\text{semi} = \frac{1}{2} \times \pi \times 36 = 18\pi \approx 56.55$ cm².
Q8: (a) $r = \sqrt{113.1/\pi} \approx \sqrt{36} = 6$ cm. (b) $C = 2\pi \times 6 = 12\pi \approx 37.70$ cm. (c) Cost $= 37.70 \times 12 \approx \$452.40$.
Circular Garden Path
A circular garden has radius 5 m. It is surrounded by a path 1 m wide. Find the area of the path only. (Hint: outer circle minus inner circle.)
Reveal solution
Outer radius $= 6$ m. $A_\text{outer} = 36\pi$ m². Inner radius $= 5$ m. $A_\text{inner} = 25\pi$ m². Path area $= 36\pi - 25\pi = 11\pi \approx 34.56$ m².
Full circle
$A = \pi r^2$ (radius squared)
From diameter
$r = d/2$ first, then $A = \pi r^2$
Find radius
$r = \sqrt{A/\pi}$
Semicircle
$A = \frac{1}{2}\pi r^2$
Quarter circle
$A = \frac{1}{4}\pi r^2$
Annulus (ring)
$A = \pi R^2 - \pi r^2$
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