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Lesson 7 ~25 min Unit 3 · Measurement & Geometry +85 XP

Circumference of Circles

Discover $\pi$, master $C = \pi d$ and $C = 2\pi r$, and find how far a wheel travels in one spin.

Today's hook: A cyclist rides around a circular velodrome of diameter 90 m. How many laps does it take to cover exactly 1 km?
0/5QUESTS
Think First
warm-up

Without measuring, roughly how many times does the diameter of a circle fit around its edge? Try sketching a circle and marking off its diameter along the outside. What number do you get close to?

Record your answer in your workbook.
1
The Big Idea
+5 XP

The circumference is the perimeter of a circle — the distance all the way around its edge. For any circle, the ratio of circumference to diameter is always the same special number: $\pi$ (pi) $\approx 3.14159\ldots$ So if you know the diameter $d$ or the radius $r$, you can find the circumference with one formula.

r d = 2r $C = \pi d$ $C = 2\pi r$ $\pi \approx 3.14159$
$C = \pi d \quad$ or $\quad C = 2\pi r$
Same formula, two forms
Since $d = 2r$, both forms are identical: $\pi d = \pi(2r) = 2\pi r$. Use whichever suits the given information.
$\pi$ on your calculator
Use the $\pi$ button on your calculator for full accuracy, or approximate $\pi \approx 3.14$ for estimates.
Units
Circumference is a length — same units as $r$ and $d$ (cm, m, mm, etc.).
2
What You'll Master
objectives

Know

  • $C = \pi d$ and $C = 2\pi r$
  • $\pi \approx 3.14159$ is irrational
  • $d = 2r$ and $r = d/2$

Understand

  • Why $\pi$ is the ratio $C/d$ for every circle
  • When to use $C = \pi d$ versus $C = 2\pi r$
  • How to rearrange to find $d$ or $r$ from $C$

Can Do

  • Calculate circumference given radius or diameter
  • Find diameter/radius given circumference
  • Solve real-world problems involving circular perimeters
  • Find perimeter of semicircles and composite shapes
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Words You Need
vocabulary
CircumferenceThe perimeter of a circle — the total distance around the outside of the circle.
Diameter ($d$)A chord passing through the centre of a circle. Equal to twice the radius: $d = 2r$.
Radius ($r$)The distance from the centre of a circle to any point on its circumference. $r = d/2$.
Pi ($\pi$)The ratio of circumference to diameter for every circle: $\pi = C/d \approx 3.14159\ldots$ It is irrational — its decimal never repeats or terminates.
Irrational numberA number that cannot be written as a fraction of two integers. Its decimal expansion goes on forever without repeating.
Exact formLeaving $\pi$ in the answer (e.g. $14\pi$ cm) rather than approximating. Use when asked for an exact answer.
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Spot the Trap
heads-up

The most common error: using the diameter in the radius formula, or the radius in the diameter formula — getting double or half the correct answer.

Wrong (radius = 7, using diameter formula with r)

$C = \pi \times 7 = 22$ cm ✗ (forgot to double)

Correct

$C = 2\pi \times 7 \approx 44$ cm ✓

Rule: Given radius → use $C = 2\pi r$. Given diameter → use $C = \pi d$. Do not mix them.

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What Is $\pi$?
+5 XP

$\pi$ is the ratio of any circle's circumference to its diameter: $\pi = C \div d$. Measure any circular object — a plate, a coin, a wheel — divide its circumference by its diameter, and you always get approximately $3.14159\ldots$ This works for every circle, no matter how big or small. $\pi$ is irrational: it cannot be written as a simple fraction (though $\frac{22}{7}$ is a useful approximation).

d $\pi = \dfrac{C}{d}$ $\approx 3.14159\ldots$ $\approx \tfrac{22}{7}$
$$\pi = \frac{C}{d} \approx 3.14159$$
$\frac{22}{7}$ trick
When the radius is a multiple of 7, using $\pi \approx \frac{22}{7}$ often gives a clean whole-number answer.
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Using $C = \pi d$ — When Diameter Is Given
+5 XP

If the problem gives you the diameter, plug straight into $C = \pi d$. No need to halve first. This is the most direct route when $d$ is known.

Example: $d = 15$ m $\Rightarrow C = \pi \times 15 \approx 47.12$ m.

To leave the answer in exact form, write $C = 15\pi$ m.

d = 15 m $C = \pi d$ $= \pi \times 15$ $\approx 47.12$ m
$$C = \pi d$$
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Using $C = 2\pi r$ — When Radius Is Given
+5 XP

If the problem gives the radius, multiply by $2\pi$. Do not forget the factor of 2 — this is the most common careless error. The $2$ comes from the fact that the diameter equals two radii: $d = 2r$.

Example: $r = 7$ cm $\Rightarrow C = 2\pi \times 7 = 14\pi \approx 43.98$ cm.

r = 7 $C = 2\pi r$ $= 2\pi \times 7$ $= 14\pi$ $\approx 43.98$ cm
$$C = 2\pi r$$
Don't forget the 2!
$C = \pi r$ (missing the 2) gives only half the correct circumference. Always double-check you've included it.
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Finding $d$ or $r$ from $C$
+5 XP

Rearrange the circumference formula to find diameter or radius:

From $C = \pi d$:   $d = \dfrac{C}{\pi}$

From $C = 2\pi r$:   $r = \dfrac{C}{2\pi}$

Example: $C = 44$ cm. Using $\pi \approx \frac{22}{7}$: $r = \frac{44}{2 \times \frac{22}{7}} = \frac{44 \times 7}{44} = 7$ cm exactly.

$C = \pi d$ $\Rightarrow d = C \div \pi$ $C = 2\pi r$ $\Rightarrow r = C \div 2\pi$
$d = \dfrac{C}{\pi}$     $r = \dfrac{C}{2\pi}$
WE 1 — Circumference from Radius
+10 XP
Q1
PROBLEM
Find the circumference of a circle with radius $r = 7$ cm. Give both an exact answer and an approximation.
  1. 1
    Choose the formula (radius given)
    $$C = 2\pi r$$
  2. 2
    Substitute $r = 7$
    $C = 2 \times \pi \times 7 = 14\pi$ cm (exact)
  3. 3
    Approximate
    $C \approx 14 \times 3.14159 \approx 43.98$ cm
  4. 4
    State answer with units
    $C = 14\pi \approx 43.98$ cm
Answer$C = 14\pi \approx 43.98$ cm
WE 2 — Circumference from Diameter
+10 XP
Q2
PROBLEM
A circular pond has diameter $d = 15$ m. Find its circumference, correct to 2 decimal places.
  1. 1
    Choose the formula (diameter given)
    $$C = \pi d$$
  2. 2
    Substitute $d = 15$
    $C = \pi \times 15 = 15\pi$
  3. 3
    Evaluate
    $C \approx 47.12$ m
Answer$C \approx 47.12$ m
WE 3 — Find Radius from Circumference
+10 XP
Q3
PROBLEM
A circle has circumference $C = 44$ cm. Find the radius (use $\pi \approx \frac{22}{7}$).
  1. 1
    Write the rearranged formula
    $$r = \frac{C}{2\pi}$$
  2. 2
    Substitute values
    $r = \dfrac{44}{2 \times \frac{22}{7}} = \dfrac{44}{\frac{44}{7}} = 44 \times \dfrac{7}{44} = 7$ cm
  3. 3
    Check
    $C = 2 \times \frac{22}{7} \times 7 = 2 \times 22 = 44$ cm ✓
Answer$r = 7$ cm
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Common Pitfalls
heads-up
Forgetting the Factor of 2
Mistake: $C = \pi r = \pi \times 7 \approx 22$ cm (using radius but not doubling).
Fix: $C = 2\pi r = 2 \times \pi \times 7 \approx 44$ cm. The 2 converts radius to diameter.
Confusing Radius and Diameter
Mistake: Treating the diameter as the radius (or vice versa) — gives an answer 2× too big or half too small.
Fix: Identify what you're given: $d$ → use $C = \pi d$; $r$ → use $C = 2\pi r$.
Using $\pi = 3$ Instead of $3.14$
Mistake: Rounding $\pi$ to 3 for convenience, causing significant error in final answer.
Fix: Use the $\pi$ button on your calculator, or at minimum use $3.14$. Only use $\frac{22}{7}$ when the numbers cancel cleanly.
Copy Into Your Books
Given diameter: $C = \pi d$
Given radius: $C = 2\pi r$
Find diameter: $d = C \div \pi$
Find radius: $r = C \div (2\pi)$    $\pi \approx 3.14159 \approx \frac{22}{7}$

How are you completing this lesson?

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Brain Trainer · Circumference
4 problems

Set a timer for 4 minutes. Show all working. Use $\pi \approx 3.14$ or the $\pi$ button.

  1. 1 Find $C$ for a circle with $r = 5$ cm.

    $C = 2\pi \times 5 = 10\pi \approx 31.42$ cm
  2. 2 Find $C$ for a circle with $d = 20$ cm.

    $C = \pi \times 20 = 20\pi \approx 62.83$ cm
  3. 3 $C = 62.8$ cm. Find $d$.

    $d = 62.8 \div \pi \approx 62.8 \div 3.14 = 20$ cm
  4. 4 Velodrome hook: diameter 90 m. How many laps to cover exactly 1 km?

    $C = \pi \times 90 \approx 282.74$ m. Laps $= 1000 \div 282.74 \approx 3.5$ laps.
Complete in your workbook.
1
Which formula uses the diameter directly?
+10 XP
2
Circle with $r = 5$ cm. What is its circumference?
+10 XP
3
Circle with $d = 20$ cm. What is its circumference?
+10 XP
4
$C = 62.8$ cm. Find the diameter to the nearest cm.
+10 XP
5
Velodrome diameter 90 m. Approximately how many laps to cover 1 km?
+10 XP
Show Your Working
9 marks total
ApplyMedium3 MARKS

Q6. A bicycle wheel has radius 35 cm. (a) How far does it travel in one full revolution? (b) How many revolutions to travel 2.2 km? (Give answers to 2 d.p.)

Show full working in your book.
UnderstandEasy2 MARKS

Q7. A semicircle has diameter 20 cm. Find the total perimeter (curved arc + straight edge). Round to 1 d.p.

Show full working in your book.
ReasonHard4 MARKS

Q8. A clock face has diameter 30 cm. (a) How far does the tip of the minute hand (length 15 cm from centre) travel in 1 hour? (b) How far does the hour hand tip (radius 10 cm) travel in 12 hours?

Show full working in your book.
Comprehensive Answers

MC: 1-B, 2-C, 3-A, 4-B, 5-C

Q6: (a) $C = 2\pi \times 35 = 70\pi \approx 219.91$ cm. (b) $2.2$ km $= 220\,000$ cm. Revolutions $= 220\,000 \div 219.91 \approx 1000.41$ revolutions.

Q7: Arc $= \frac{1}{2} \times \pi \times 20 = 10\pi \approx 31.4$ cm. Straight edge $= 20$ cm. Total perimeter $= 31.4 + 20 = 51.4$ cm.

Q8: (a) Minute hand: $C = 2\pi \times 15 = 30\pi \approx 94.25$ cm in 1 hour. (b) Hour hand: $C = 2\pi \times 10 = 20\pi \approx 62.83$ cm in 12 hours (one full revolution).

Stretch Challenge · +25 XP

Running Track Total Length

A running track has two straight sections of 80 m each and two semicircular ends of diameter 56 m. Find the total track length. (Hint: the two semicircles together form one full circle.)

Reveal solution

Two straight sections: $2 \times 80 = 160$ m. Two semicircular ends $=$ one full circle: $C = \pi \times 56 \approx 175.93$ m. Total $= 160 + 175.93 \approx 335.93$ m.

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Quick Review

Given diameter

$C = \pi d$

Given radius

$C = 2\pi r$

Find $d$

$d = C \div \pi$

Find $r$

$r = C \div 2\pi$

Semicircle perimeter

Arc $+ d = \frac{1}{2}\pi d + d$

$\pi$

$\approx 3.14159$ or $\frac{22}{7}$ for multiples of 7

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