Introduction to Simultaneous Equations
Apples cost $2, bananas cost $1. Two purchases, two equations, one answer — that is the power of simultaneous equations: solving two unknowns at the same time.
Printable Worksheets
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Know
- Simultaneous equations are two equations with two unknowns
- The solution satisfies both equations at once
- The solution is the intersection point on a graph
Understand
- Why the intersection point is the only point satisfying both equations
- There are three types of solutions: one, none, infinite
Can Do
- Set up simultaneous equations from word problems
- Solve by graphing — find the intersection point
- Identify the number of solutions from a graph
When we have one equation with one unknown, like $2x = 6$, we can solve it easily: $x = 3$.
But what if we have two unknowns? One equation like $x + y = 5$ has many solutions: $(1, 4)$, $(2, 3)$, $(0, 5)$, and so on. To find one specific answer, we need a second equation.
Definition: Simultaneous equations are two (or more) equations that use the same variables and must be solved together. The solution is the pair of values that makes both equations true.
Example system: $\begin{cases} x + y = 5 \\ x - y = 1 \end{cases}$
Check if $(3, 2)$ is the solution: Equation 1: $3 + 2 = 5$ ✓ Equation 2: $3 - 2 = 1$ ✓. Both satisfied!
A single equation with two unknowns has infinitely many solutions. A second equation pins down the one unique point that works for both.
To solve simultaneous equations graphically: draw both lines on the same axes, then find where they intersect. The coordinates of that point are the solution.
Why it works: Every point on a line satisfies that line's equation. The intersection is on both lines, so it satisfies both equations.
Watch Me Solve It · Graphical method
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1Identify both equations and their featuresEquation 1: $y = 2x + 1$ — gradient = 2, $y$-intercept = 1
Equation 2: $y = -x + 4$ — gradient = −1, $y$-intercept = 4 -
2Sketch both lines on the same axes
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3Locate the intersection and verifyLines appear to cross at $x = 1$, $y = 3$. Check: Eq 1: $3 = 2(1) + 1 = 3$ ✓ Eq 2: $3 = -(1) + 4 = 3$ ✓Solution: $(1, 3)$
Two lines can relate in three ways:
Pitfall: “No solution” does NOT mean the solution is zero! It means there is no pair of values that satisfies both equations — the lines are parallel.
Remember: Always check if the intersection point actually satisfies both equations. Read $x$ first, then $y$ when reading from a graph.
No solution — Parallel lines:
The first step in solving word problems is to identify the two unknowns and find two different relationships between them.
Strategy:
- Define variables (say what $x$ and $y$ represent).
- Use the first piece of information to write Equation 1.
- Use the second piece of information to write Equation 2.
- Solve the system.
Watch Me Solve It · Setting up equations
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1Define the variablesLet $c$ = cost of one coffee (dollars) Let $m$ = cost of one muffin (dollars)
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2Translate the first sentence“2 coffees and 3 muffins cost $13” → $2c + 3m = 13$
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3Translate the second sentence“3 coffees and 1 muffin cost $11” → $3c + m = 11$System: $\begin{cases} 2c + 3m = 13 \\ 3c + m = 11 \end{cases}$
Brain Trainer · 10 quick questions
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1 Two lines intersect at $(4, 5)$. What is $x$ in the solution?
$x = 4$ -
2 Two lines intersect at $(-1, 3)$. What is $y$ in the solution?
$y = 3$ -
3 Two lines both have gradient $m = 3$ but different $y$-intercepts. How many solutions?
No solutions (parallel lines). -
4 Two equations describe the exact same line. How many solutions?
Infinitely many solutions. -
5 Does $(2, 3)$ satisfy $y = 2x - 1$?
Yes! $3 = 2(2) - 1 = 3$ ✓ -
6 Does $(2, 3)$ satisfy $y = x + 2$?
No! $3 \neq 2 + 2 = 4$ ✗ -
7 A line has gradient 2 and passes through $(0, 3)$. Write its equation.
$y = 2x + 3$ -
8 What does “simultaneous” literally mean?
“At the same time” — both equations must be satisfied together. -
9 Lines $y = x + 2$ and $y = -x$ intersect where $x + 2 = -x$. Solve for $x$.
$2x = -2 \Rightarrow x = -1$ -
10 Which type of system is $y = 2x + 1$ and $y = 2x + 1$? (consistent / inconsistent / dependent)
Dependent (same line, infinitely many solutions).
Quick Check · 5 questions
Show Your Working · 3 questions
SAQ 1. On the same set of axes, sketch the lines $y = x + 1$ and $y = -x + 3$. Find the solution to this system by identifying the intersection point. Show your working.
SAQ 2. Explain, in your own words, why parallel lines have no simultaneous solution. Use the words “gradient” and “intersect” in your answer.
SAQ 3. Write a word problem that could be solved using simultaneous equations. Define your variables and set up the two equations. Do not solve the system.
Quick Check
1. B — ‘Simultaneous’ means at the same time.
2. C — $x = 2$ and $y = 3$ (both values together).
3. A — No solutions (parallel lines never meet).
4. B — $(2, 2)$ (intersection 2 units across and 2 up).
5. D — $y = 2x + 1$ and $y = 2x - 3$ (same gradient $m = 2$, different intercepts).
Short Answer Model Answers
SAQ 1 (5 marks): Line 1: gradient 1, $y$-int 1. Line 2: gradient −1, $y$-int 3. Sketch both [1+1]. At intersection: $x + 1 = -x + 3 \Rightarrow 2x = 2 \Rightarrow x = 1$ [1]. Then $y = 1 + 1 = 2$ [1]. Check: $2 = -(1) + 3 = 2$ ✓ [1]. Solution: $(1, 2)$.
SAQ 2 (3 marks): Parallel lines have the same gradient [1] but different $y$-intercepts. Because they have the same steepness, they never get closer to each other and will never intersect [1]. Since the solution to simultaneous equations is the intersection point, and parallel lines don’t intersect, there is no solution [1].
SAQ 3 (4 marks): Any valid word problem [1] with two unknowns clearly defined [1] and two correct equations [2]. Example: A cinema sells adult tickets for $a$ and child tickets for $c$. 4 adults and 2 children pay $72, 3 adults and 5 children pay $78. Equations: $4a + 2c = 72$ and $3a + 5c = 78$.
Lesson Review
- Simultaneous equations are two equations with the same two variables, solved together.
- The solution is the pair $(x, y)$ that makes both equations true.
- Graphically, the solution is the intersection point of the two lines.
- One solution: Different gradients ⇒ lines cross once.
- No solution: Same gradient, different intercepts ⇒ parallel lines.
- Infinite solutions: Same gradient, same intercept ⇒ same line.
Finding Lines Through Points
Challenge 1: A line passes through $(1, 3)$ and $(3, 7)$. Another line passes through $(0, 5)$ and $(2, 1)$. Find the equations of both lines, then solve simultaneously to find their intersection point.
Challenge 2: Consider the system $y = kx + 2$ and $y = 3x - 1$. For what value(s) of $k$ will the system have: (a) one solution, (b) no solution, (c) infinitely many solutions? Explain your reasoning.
Reveal solutions
Challenge 1: Line 1: $m = (7-3)/(3-1) = 2$, using $(1,3)$: $3 = 2(1) + b \Rightarrow b = 1$. So $y = 2x + 1$. Line 2: $m = (1-5)/(2-0) = -2$, $b = 5$. So $y = -2x + 5$. Solve: $2x + 1 = -2x + 5 \Rightarrow 4x = 4 \Rightarrow x = 1$, $y = 3$. Intersection: $(1, 3)$.
Challenge 2: (a) One solution when $k \neq 3$. (b) No solution when $k = 3$ (same gradient, intercepts $2 \neq -1$ are different). (c) Infinitely many: never possible since $2 \neq -1$.
Lesson Complete!
You have mastered Introduction to Simultaneous Equations.