Tables of Values
Tables are the bridge between rules and graphs. Learn to build them, read them, and use first differences to instantly test if a relationship is linear.
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Before you read on — quickly: Look at these pairs of numbers carefully.
| $x$ | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| $y$ | 3 | 5 | 7 | 9 |
As $x$ increases by 1, what happens to $y$? Is this a linear relationship? What is the rule?
A table of values shows how input ($x$) connects to output ($y$) through a rule. The secret to detecting linear relationships is first differences — the change in $y$ when $x$ increases by 1.
The linear test:
- Calculate the change in $y$ when $x$ increases by 1
- If all differences are constant, the relationship is linear (straight line)
- If differences change, it’s non-linear (curve)
Think First answer: $y$ increases by 2 each time. First differences are all 2 — linear! Rule: $y = 2x + 1$.
Know
- A table shows $x$ and $y$ pairs systematically
- Linear relationships have constant first differences
- Non-linear relationships have changing first differences
Understand
- How to use a table to predict whether points form a straight line
- The connection between the rule, the table, and the graph
- Why constant rate of change means linearity
Can Do
- Create tables of values from rules
- Calculate first differences between consecutive $y$ values
- Determine if a relationship is linear from its table
- Plot points from a table to visually confirm linearity
Wrong: Calculating $y - x$ (e.g., $5 - 2 = 3$) instead of consecutive $y$ differences. First differences are ALWAYS $y_{n+1} - y_n$, not $y - x$.
Right: Calculate $\Delta y$ by subtracting each $y$ value from the one below it in the table. Only compare $y$ values to $y$ values.
Wrong: Checking only 2 differences and declaring it linear. Consider $y: 2, 4, 6, 9$ — the first two differences are 2, but the last is 3. It is not linear.
Right: Always check ALL first differences in the table. Use at least 4–5 rows for convincing evidence of linearity.
Given a rule, create a table by substituting each $x$ value. Then check first differences to test linearity.
- Set up the table with $x$ values from 0 to 5 and substitute into $y = 2x + 1$.
- Calculate each $y$ value: $x=0 \to 1$; $x=1 \to 3$; $x=2 \to 5$; $x=3 \to 7$; $x=4 \to 9$; $x=5 \to 11$.
- Check first differences: $3-1=2$; $5-3=2$; $7-5=2$; $9-7=2$; $11-9=2$. All equal 2 — the relationship is linear!
| $x$ | $y = 2x+1$ | First Difference |
|---|---|---|
| 0 | 1 | — |
| 1 | 3 | 2 |
| 2 | 5 | 2 |
| 3 | 7 | 2 |
| 4 | 9 | 2 |
| 5 | 11 | 2 |
All first differences = 2. This is LINEAR. Rule: $y = 2x + 1$.
- Verify $x$ increases by 1 each step: $1-0=1$, $2-1=1$, $3-2=1$, $4-3=1$. ✓
- Calculate first differences: $7-4=3$; $10-7=3$; $13-10=3$; $16-13=3$.
- All differences = 3 (constant). The relationship is linear. Rule: $y = 3x + 4$ (since $m = 3$ and $c = 4$ when $x = 0$).
- Table A: $x: 1,2,3,4$ and $y: 5,8,11,14$. Differences: $8-5=3$, $11-8=3$, $14-11=3$. All equal 3 → LINEAR. Rule: $y = 3x + 2$.
- Table B: $x: 1,2,3,4$ and $y: 2,4,8,16$. Differences: $4-2=2$, $8-4=4$, $16-8=8$. NOT equal → NON-LINEAR. Rule: $y = 2^x$.
- Why? A linear rule $y = mx + c$ gives $\Delta y = m$ always. For non-linear rules (like $y = x^2$ or $y = 2^x$), the change in $y$ depends on where you are in the table.
Non-linear examples:
| $x$ | $y = x^2$ | $\Delta y$ |
|---|---|---|
| 0 | 0 | — |
| 1 | 1 | 1 |
| 2 | 4 | 3 |
| 3 | 9 | 5 |
| 4 | 16 | 7 |
Differences: 1, 3, 5, 7 — NOT constant → NON-LINEAR
Common Pitfalls
- Calculating $y - x$ instead of $\Delta y$: First differences are ALWAYS between consecutive $y$ values. Calculate $y_{n+1} - y_n$, never $y - x$. For $x=2, y=5$: the first difference is $5 - \text{previous y}$, not $5 - 2 = 3$.
- Checking only 2 differences: One mismatch breaks the pattern. Always check every first difference. For $y: 2, 4, 6, 9$: the first two differences are 2, but $9 - 6 = 3$ — not linear!
- Using too few rows: Use at least 4–5 rows in your table. This gives 3–4 first differences to compare, which is convincing evidence.
Copy Into Books
Creating a Table from a Rule
- Write $x$ values in order (increasing by 1)
- Substitute each $x$ into the rule to find $y$
- Fill in the table systematically
The Linear Test
- Check $x$ increases by 1 each step
- Calculate ALL first differences ($y_{n+1} - y_n$)
- All equal? → LINEAR
- Not equal? → NON-LINEAR
Reading the Rule from a Table
- First difference = $m$ (slope)
- $y$ when $x = 0$ = $c$ (constant)
- Rule: $y = mx + c$
- Check: verify with another row
How are you completing this lesson?
Brain Trainer · 4 problems
Four drill problems to sharpen your table skills. Work each, then reveal the answer.
-
1 First differences: $y = 5, 9, 13, 17$. What is $\Delta y$?
$9-5=4$, $13-9=4$, $17-13=4$. All equal.$\Delta y = 4$ (linear) -
2 Is this linear? $y: 2, 5, 9, 14$ (find all differences first).
Differences: $5-2=3$; $9-5=4$; $14-9=5$. Not equal.No — non-linear (diffs: 3, 4, 5) -
3 Table: $x=1,2,3$ and $y=6,10,14$. Find the rule.
Diff $= 4$, so $m = 4$. For $n=1$: $6 = 4(1) + c \Rightarrow c = 2$.$y = 4x + 2$ -
4 Linear table: constant diff $= 3$, at $x=1$, $y=2$. What is $y$ when $x=5$?
$x=1\to2$; $x=2\to5$; $x=3\to8$; $x=4\to11$; $x=5\to14$. Adding 3 each time.14
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Create a table of values for $y = 2x + 3$ with $x$ from 0 to 5. Calculate the first differences and determine whether the relationship is linear.
Q7. A table has $x: 1,2,3,4,5$ and $y: 1,4,9,16,25$. Explain why this is NOT linear using first differences.
Q8. A linear relationship passes through $(1, 3)$ and $(2, 5)$. Complete the table for $x = 3, 4, 5$ and state the rule.
Quick Check
1. B — Linear. Differences $5-2=3$, $8-5=3$, $11-8=3$ are all equal.
2. C — 4. Every consecutive $y$ difference is 4.
3. A — $y = x + 3$. Only rule in the form $y = mx + c$.
4. C — $1, 4, 7, 10$. Substitute $x = 1,2,3,4$ into $3x - 2$.
5. B — 19. Start at $y=7$, add 4 three times: $7 \to 11 \to 15 \to 19$.
Show Your Working Model Answers
Q6 (3 marks): Table: $x=0\to3$; $x=1\to5$; $x=2\to7$; $x=3\to9$; $x=4\to11$; $x=5\to13$ [1]. First differences: $5-3=2$, $7-5=2$, $9-7=2$, $11-9=2$, $13-11=2$ [1]. All differences equal 2 — the relationship is linear [1].
Q7 (3 marks): Calculate first differences: $4-1=3$; $9-4=5$; $16-9=7$; $25-16=9$ [1]. The differences are $3, 5, 7, 9$ — NOT constant (they increase by 2 each time) [1]. For a linear relationship, ALL first differences must be equal. Since $3 \neq 5 \neq 7 \neq 9$, this is non-linear (the rule is $y = x^2$) [1].
Q8 (3 marks): First difference $= 5 - 3 = 2$ [1]. Continue adding 2: $x=3\to7$; $x=4\to9$; $x=5\to11$ [1]. Rule: slope $m = 2$. Using $(1,3)$: $3 = 2(1) + c \Rightarrow c = 1$. Rule: $y = 2x + 1$ [1].
Finding Rules from Tables
Challenge 1: This table is linear. Find the rule $y = mx + c$.
| $x$ | 0 | 1 | 2 | 3 |
|---|---|---|---|---|
| $y$ | 5 | 8 | 11 | 14 |
Challenge 2: Complete the table and find the rule for this linear relationship.
| $x$ | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| $y$ | 6 | ? | ? | ? | 22 |
Challenge 3: A table starts with $x = 0$, $y = -1$ and has constant first differences of $-3$ (decreasing by 3).
(a) Write the first 5 rows. (b) Find the rule. (c) What is $y$ when $x = 10$?
Reveal solutions
C1: First differences $= 3$, so $m = 3$. When $x=0$, $y=5$, so $c=5$. Rule: $y = 3x + 5$.
C2: Total change $= 22 - 6 = 16$ over 4 steps. First difference $= 16 \div 4 = 4$. Values: $6, 10, 14, 18, 22$. Find $c$: $6 = 4(1) + c \Rightarrow c = 2$. Rule: $y = 4x + 2$.
C3: (a) $y$ values: $-1, -4, -7, -10, -13$. (b) $m = -3$, $c = -1$. Rule: $y = -3x - 1$. (c) $y = -3(10) - 1 = -31$.
Table of values
Organised $(x, y)$ pairs from a rule, with $x$ increasing by 1
First difference
$\Delta y = y_{n+1} - y_n$ (consecutive $y$ values only)
Linear test
All $\Delta y$ equal? → Linear. Any different? → Non-linear
Reading the rule
First diff $= m$; $y$ at $x=0$ gives $c$; rule: $y = mx + c$
Check ALL diffs
Don’t stop after 2 matches — verify every difference
Plotting confirms
Linear table → straight line. Non-linear table → curve
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