Mathematics • Year 8 • Unit 1 • Lesson 17

Ratio Division — Mixed Challenge

Pull together everything from Lesson 17: two-part and three-part splits, reverse problems, and sum checks. Six mixed problems, one "find the mistake", and one open-ended challenge.

Master · Mixed Challenge

1. Mixed problems — choose the right move

Each question uses a different mix of ideas from Lesson 17. Decide which move applies before you start writing. Show your working and ALWAYS do a sum check. 3 marks each

1.1 Split $700 in the ratio 3 : 4.

1.2 Split 45 kg in the ratio 1 : 2 : 6.

1.3 Split $360 in the ratio 5 : 3 : 2.

1.4 In a ratio split of 3 : 4 : 5 totalling 48 kg, find the middle share.

1.5 Reverse problem: Two people share a sum in the ratio 4 : 5. The bigger share is $200. Find the total.

1.6 Three friends agreed to split a $540 prize in the ratio 1 : 2 : 3. Find the smallest share, the largest share, and the difference between them.

Stuck on 1.5? Bigger share is 5 parts = $200, so 1 part = $40, total parts = 9, total = $360.

2. Find the mistake

Another student has tried to split $540 in the ratio 1 : 2 : 3. Their working is shown below. Exactly one line contains a mistake. Spot it, explain why it's wrong, then re-do the working correctly. 3 marks

Student's working — split $540 in 1 : 2 : 3:

Line 1:   Total parts = 1 + 2 + 3 = 6.

Line 2:   Value of 1 part = $540 ÷ 3 = $180.

Line 3:   Shares: 1 × $180 = $180, 2 × $180 = $360, 3 × $180 = $540.

Line 4:   Final shares: $180, $360, $540.

(a) Which line contains the mistake?

(b) Explain in one or two sentences why that line is wrong. (Hint: do the sum check — do the three shares add to $540?)

(c) Write out the corrected working in full, including the corrected final shares and a sum check.

Stuck? Look at the divisor in Line 2. Should we divide by the NUMBER OF PEOPLE or by the TOTAL PARTS from Line 1?

3. Open-ended challenge — design a fair-share scenario

This question has more than one valid answer. 4 marks

3.1 Design your OWN ratio-split scenario. Make sure the total divides cleanly into the parts (no decimal shares).

(i) Choose three people (or three groups) to share something. Write down a short scenario sentence.
(ii) Choose a ratio with three parts where the parts sum to a number between 6 and 15 (e.g., 2 : 3 : 4 or 1 : 3 : 5).
(iii) Choose a total amount (money, mass, or time) such that the total ÷ sum of parts is a whole number.
(iv) Work out each share using the unitary method and check that the three shares add back to your total.

Bonus: Re-do the scenario with the SAME ratio but DOUBLE the total. What happens to each share?

Stuck? Easy starting point: ratio 2 : 3 : 5 (sum 10), total = $100 → 1 part = $10 → shares $20, $30, $50. Then make up a scenario sentence that fits.

How did this worksheet feel?

What I'll revisit before next class:

Answers — Do not peek before attempting

1.1 — $700 in 3 : 4

Parts = 7; 1 part = $100. Shares: $300 and $400. Check: $300 + $400 = $700 ✓.

1.2 — 45 kg in 1 : 2 : 6

Parts = 9; 1 part = 5 kg. Shares: 5 kg, 10 kg, 30 kg. Check: 5 + 10 + 30 = 45 ✓.

1.3 — $360 in 5 : 3 : 2

Parts = 10; 1 part = $36. Shares: $180, $108, $72. Check: 180 + 108 + 72 = $360 ✓.

1.4 — 48 kg in 3 : 4 : 5, middle share

Parts = 12; 1 part = 48 ÷ 12 = 4 kg. Middle share (4 parts) = 4 × 4 = 16 kg.

1.5 — Reverse: 4 : 5, bigger share $200

Bigger share is 5 parts = $200, so 1 part = $40. Total parts = 9. Total = 9 × $40 = $360. (Or: smaller share = 4 × $40 = $160; $160 + $200 = $360.)

1.6 — $540 in 1 : 2 : 3

Parts = 6; 1 part = $90. Smallest = $90, largest = $270, difference = $180. Check: 90 + 180 + 270 = $540 ✓.

2 — Find the mistake

(a) The mistake is on Line 2 (and the wrong "1 part" value is then used in Line 3).
(b) The student divided $540 by 3 (the number of people / largest ratio number), but they should have divided by 6 (the TOTAL PARTS from Line 1). The sum check fails: $180 + $360 + $540 = $1080, not $540 — the shares overshoot by double.
(c) Corrected working:
Total parts = 1 + 2 + 3 = 6.
Value of 1 part = $540 ÷ 6 = $90.
Shares: 1 × $90 = $90, 2 × $90 = $180, 3 × $90 = $270.
Sum check: $90 + $180 + $270 = $540 ✓.
Corrected shares: $90, $180, $270.

3 — Open-ended challenge (sample solution)

Sample scenario: "Three students split $80 babysitting money in the ratio 2 : 3 : 3 because two of them stayed the whole night and one left early."

Sum of parts = 2 + 3 + 3 = 8. Total ÷ parts = $80 ÷ 8 = $10 per part.

Shares: 2 × $10 = $20, 3 × $10 = $30, 3 × $10 = $30.

Sum check: 20 + 30 + 30 = $80 ✓.

Bonus: Double the total ($160 in 2 : 3 : 3). 1 part now = $20. Shares: $40, $60, $60 (each share is also doubled). The ratio is unchanged.

Other valid scenarios: $60 in 1 : 2 : 3 ($10, $20, $30); 90 minutes in 2 : 3 : 4 (20, 30, 40 min); 120 kg in 3 : 4 : 5 (30, 40, 50 kg).

Marking: 1 mark for a plausible scenario sentence; 1 mark for a valid ratio with whole-number 1-part value; 1 mark for correct shares with sum check; 1 mark for the doubling bonus answered correctly.