Successive Percentage Changes
Why a $20\%$ rise followed by a $20\%$ drop doesn't bring you back to where you started.
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A price goes up $20\%$ then comes down $20\%$. Are you back to the original? Most people get this wrong. Jot down your first reaction — then we'll see who's right.
Two percentage changes applied in sequence DO NOT add. They multiply. A $20\%$ rise then $20\%$ fall ends with $96\%$ of the original — a $4\%$ overall LOSS.
Start with $\$100$. Rise $20\%$: $100 \times 1.20 = \$120$. Now fall $20\%$: $120 \times 0.80 = \$96$. NOT back to $\$100$. The percent rise was on $\$100$, but the percent fall was on the BIGGER $\$120$. Combined multiplier: $1.20 \times 0.80 = 0.96$ — a $4\%$ overall decrease.
Know
- Successive changes multiply, never add
- Combined multiplier = product of individual multipliers
- Overall % change = $(m_1 m_2 - 1) \times 100$
- Order of multiplication doesn't affect the final value
Understand
- Why the second percentage is on a different base than the first
- How equal-and-opposite percentage moves don't cancel
- Why this matters for sales, investments, and depreciation
Can Do
- Compute final value after multiple successive percentage changes
- Find the equivalent single percentage change
- Recognise common traps in everyday percentage thinking
Wrong: "$20\%$ up then $20\%$ down = $0\%$ change" — NO. It's a $4\%$ DECREASE.
Right: Multipliers: $1.20 \times 0.80 = 0.96$. That's $4\%$ down.
Wrong: "$10\%$ off then $5\%$ off = $15\%$ off" — NO. It's about $14.5\%$ off (multipliers $0.90 \times 0.95 = 0.855$).
Right: $0.90 \times 0.95 = 0.855$ — you pay $85.5\%$, save $14.5\%$, not $15\%$.
Each percentage change uses the CURRENT value as the base. So $20\%$ of $\$120$ is bigger than $20\%$ of $\$100$ — that's where the asymmetry comes from.
Start at $\$100$, rise $20\%$ to $\$120$. The next $20\%$ DECREASE is on the new $\$120$, not the original $\$100$. So the drop is $\$24$, not $\$20$. The price falls to $\$96$ — $\$4$ below where we started.
Multiply all the individual multipliers together to get one combined multiplier. This represents the entire chain of changes as a single multiplication.
Three changes: $+10\%, -20\%, +5\%$. Multipliers: $1.10, 0.80, 1.05$. Combined: $1.10 \times 0.80 \times 1.05 = 0.924$. So the overall change is $0.924 - 1 = -0.076 = -7.6\%$. The starting value ends up at $92.4\%$ of its original size — a $7.6\%$ overall decrease.
Watch Me Solve It · 3 examples
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1After $+20\%$$100 \times 1.20 = \$120$Multiplier 1.20.
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2After $-20\%$$120 \times 0.80 = \$96$New multiplier on the $\$120$.
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3Combined$1.20 \times 0.80 = 0.96 \Rightarrow$ $\$100 \times 0.96 = \$96$Same answer via one multiplier.
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1Multipliers$0.75 \times 0.90 = 0.675$Combined.
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2Final price$200 \times 0.675 = \$135$Sale price.
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3Equivalent single discount$1 - 0.675 = 0.325 = 32.5\%$Not $35\%$!
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1Set up multipliers$1.15, 0.90, 1.08$Convert each.
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2Combine$1.15 \times 0.90 \times 1.08 = 1.1178$Multiply all three.
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3Equivalent change$1.1178 - 1 = 0.1178 = 11.78\%$ increaseNet up, not $13\%$.
Common Pitfalls
Combined Multiplier
- Multiply all multipliers together
- $1.20 \times 0.80 = 0.96$
- $96\%$ = $4\%$ loss
Asymmetry Rule
- $+P\%$ then $-P\%$ $\neq 0$
- Always slight LOSS
- Different bases cause it
Equivalent Single %
- Combined $-$ 1, then $\times 100$
- $0.96 \to -4\%$
- $1.10 \to +10\%$
Order Doesn't Matter
- $0.80 \times 1.20 = 1.20 \times 0.80$
- Multiplication is commutative
- Apply in any order
How are you completing this lesson?
Brain Trainer · 4 problems
Four drill problems to sharpen your skills. Work each, then reveal the answer.
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1 $\$100 \to +10\% \to -10\%$. Final?
$100 \times 1.10 \times 0.90 = \$99$.$\$99$ -
2 $\$200, -25\%$ then $-20\%$. Final?
$200 \times 0.75 \times 0.80 = \$120$.$\$120$ -
3 Combined multiplier for $+30\%$ and $+20\%$:
$1.30 \times 1.20 = 1.56 \Rightarrow 56\%$ rise.$56\%$ -
4 $\$400 \to +50\%, -50\%$. Final?
$400 \times 1.50 \times 0.50 = \$300$.$\$300$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. A jacket has its price modified twice: $+20\%$, then $-15\%$, on an original of $\$80$. (a) Find the price after each change. (b) Compute the combined multiplier. (c) What is the equivalent single percentage change?
Q7. A shop offers $30\%$ off, then a $10\%$ student discount on top. What does a $\$200$ item cost the student?
Q8. Asha thinks a $40\%$ pay rise followed by a $40\%$ pay cut puts her back at her original salary. (a) Starting from $\$50\,000$, show with calculations whether she is right or wrong. (b) Calculate the actual percentage change. (c) Explain in plain words WHY two equal-and-opposite percentages don't cancel.
Quick Check
1. B — $\$99$.
2. B — $36\%$ off.
3. C — $\$585$.
4. A — $5.5\%$ decrease.
5. C — $-25\%$.
Show Your Working Model Answers
Q6 (3 marks): (a) After $+20\%$: $80 \times 1.20 = \$96$. After $-15\%$: $96 \times 0.85 = \$81.60$ [1]. (b) Combined: $1.20 \times 0.85 = 1.02$ [1]. (c) $2\%$ overall increase [1].
Q7 (2 marks): $200 \times 0.70 \times 0.90 = \$126$ [2].
Q8 (4 marks): (a) After $+40\%$: $50000 \times 1.40 = \$70\,000$. After $-40\%$: $70000 \times 0.60 = \$42\,000$ [2]. (b) She finishes at $\$42\,000$, an overall $16\%$ decrease ($1.40 \times 0.60 = 0.84$) [1]. (c) The $40\%$ rise was on her original $\$50k$ (a $\$20k$ gain), but the $40\%$ cut was on the larger $\$70k$ (a $\$28k$ loss). The second percentage acts on a DIFFERENT base, so the changes don't cancel [1].
The Compound Equivalent
A house price changes in 3 consecutive years: $+15\%$, $-8\%$, $+5\%$. (a) Find the combined multiplier. (b) Find the equivalent single percentage change. (c) If we replaced the three changes with three equal $+P\%$ changes (compounded), what single yearly $P\%$ would give the same total? (Hint: cube root.)
Reveal solution
(a) Combined $= 1.15 \times 0.92 \times 1.05 = 1.1109$. (b) Overall change $\approx +11.09\%$. (c) $1.1109^{1/3} \approx 1.0357$, so $P \approx 3.57\%$ per year, compounded.
Multiply
Multipliers multiply, percentages don't add
Different bases
Second % is on new value
Combined $= m_1 \times m_2$
One number captures the chain
$+P\%, -P\%$
Always slight loss
Order doesn't matter
Commutative multiplication
Equivalent single %
Combined $- 1$, then $\times 100$
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