Percentage Decrease
Sales, write-downs and depreciation — find the new value when something loses a percentage of its worth.
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A $\$250$ pair of shoes is $30\%$ off. Method 1 or Method 2 — which is faster? Jot down your first reaction — then we'll see who's right.
A percentage decrease SUBTRACTS a percentage from the original. Again, two equivalent methods — subtract or multiply by $(1 - $ rate$)$.
Take $\$250$ shoes $30\%$ off. Method 1: $30\%$ of $250 = \$75$; new price $= 250 - 75 = \$175$. Method 2: multiplier $= 1 - 0.30 = 0.70$; so $250 \times 0.70 = \$175$. Method 2 is often faster — one operation, no intermediate value needed.
Know
- New value = original $-$ (% of original)
- New value = original $\times (1 - \tfrac{P}{100})$
- $25\%$ decrease $\to$ multiplier $0.75$
- You pay $(100 - P)\%$ of the original
Understand
- Why $1 - \tfrac{P}{100}$ is the “sale fraction”
- How a $30\%$ discount means paying $70\%$
- Why the decrease method mirrors increase
Can Do
- Apply a percentage discount with confidence
- Choose between subtract and multiplier methods
- Recognise when a problem is a percentage decrease
Wrong: "$30\%$ off $\$250$ means I pay $\$30$" — NO. You SAVE $\$75$ ($30\%$ of $250$), not 30 dollars.
Right: $30\%$ of $250 = \$75$. New $= 250 - 75 = \$175$.
Wrong: "Multiplier for $25\%$ decrease = $\times 1.25$" — NO. Decrease means SMALLER, multiplier is BELOW 1.
Right: Decrease multiplier $= 1 - 0.25 = 0.75$. Pay $75\%$ of original.
Two clear steps: find the discount as a dollar amount, then subtract.
For $30\%$ off a $\$250$ jacket: Step 1: $30\%$ of $250 = 0.30 \times 250 = \$75$ (the discount). Step 2: $250 - 75 = \$175$ (sale price). Useful for advertising — “Save $\$75$!” sounds louder than “Pay $\$175$”.
A single multiplication. New value = original $\times (1 - $ rate$)$.
A $25\%$ discount means you pay $75\%$ — multiplier $0.75$. A $40\%$ discount means you pay $60\%$ — multiplier $0.60$. The pattern: multiplier $+$ discount rate $=$ 1. Always.
Watch Me Solve It · 3 examples
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1Method 1: subtractDiscount $= 0.30 \times 250 = \$75$. Sale $= 250 - 75 = \$175$Two steps.
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2Method 2: multiplier$1 - 0.30 = 0.70$. Sale $= 250 \times 0.70 = \$175$One step.
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3CompareSame answer, Method 2 is fasterSave your brainpower for harder bits.
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1Set up multiplier$1 - 0.15 = 0.85$You pay $85\%$.
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2Multiply$80 \times 0.85$One step.
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3Compute$80 \times 0.85 = \$68$Final price.
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1Set up multiplier$1 - 0.18 = 0.82$Keeps $82\%$ of value.
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2Multiply$25\,000 \times 0.82$Single operation.
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3Compute$25\,000 \times 0.82 = \$20\,500$Worth after 1 year.
Common Pitfalls
Method 1: Subtract
- Discount $= \tfrac{P}{100} \times $ Original
- Sale $= $ Original $-$ Discount
- Tells you the $\$$ saved
Method 2: Multiplier
- Multiplier $= 1 - \tfrac{P}{100}$
- Sale $= $ Original $\times $ Multiplier
- Always $< 1$
Common Multipliers
- $10\%$ off: $\times 0.90$
- $20\%$ off: $\times 0.80$
- $25\%$ off: $\times 0.75$
- $50\%$ off: $\times 0.50$
Pay-Fraction Trick
- $P\%$ off = pay $(100 - P)\%$
- $30\%$ off = pay $70\%$
- Sum is always $100\%$
How are you completing this lesson?
Brain Trainer · 4 problems
Four drill problems to sharpen your skills. Work each, then reveal the answer.
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1 Decrease $\$160$ by $25\%$.
$160 \times 0.75 = 120$.$\$120$ -
2 A $\$45$ shirt has $20\%$ off. Sale price?
$45 \times 0.80 = 36$.$\$36$ -
3 Decrease $400$ kg by $15\%$.
$400 \times 0.85 = 340$.$340$ kg -
4 A $\$30\,000$ car loses $20\%$ in year 1. Worth then?
$30000 \times 0.80 = 24000$.$\$24\,000$
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. Apply the discount using the multiplier method: (a) $\$300$ less $40\%$ (b) $\$85$ less $22\%$ (c) $\$1500$ less $7.5\%$
Q7. A $\$240$ desk is reduced by $15\%$. What is the discount AND the sale price?
Q8. Two clothing stores both sell the same $\$200$ jacket. Store A offers “$25\%$ off, then a further $10\%$ at checkout”. Store B offers “$30\%$ off everything”. (a) Find the final price at each store. (b) Which is the better deal? (c) Explain why $25\% + 10\%$ does NOT equal $35\%$ off.
Quick Check
1. A — $120 \times 0.75 = \$90$.
2. C — $1 - 0.40 = 0.60$.
3. B — $240 \times 0.65 = \$156$.
4. C — $\tfrac{15}{60} = 25\%$.
5. B — $40000 \times 0.85 = \$34000$.
Show Your Working Model Answers
Q6 (3 marks): (a) $300 \times 0.60 = \$180$ [1]. (b) $85 \times 0.78 = \$66.30$ [1]. (c) $1500 \times 0.925 = \$1387.50$ [1].
Q7 (2 marks): Discount $= 0.15 \times 240 = \$36$ [1]. Sale $= 240 - 36 = \$204$ [1].
Q8 (4 marks): (a) Store A: $200 \times 0.75 \times 0.90 = \$135$ [1]. Store B: $200 \times 0.70 = \$140$ [1]. (b) Store A is cheaper by $\$5$ [1]. (c) The $10\%$ second discount applies to the ALREADY-discounted price ($\$150$), not the original $\$200$, so the $10\%$ is worth only $\$15$ — making the total saving $\$50 + \$15 = \$65$, equivalent to $32.5\%$, not $35\%$ [1].
The Devaluing Phone
A phone is worth $\$1200$ new. It loses $25\%$ of its value each year. (a) What is it worth at the end of year 1, 2 and 3? (b) After how many full years is it worth less than $\$300$?
Reveal solution
(a) Y1: $1200 \times 0.75 = \$900$. Y2: $900 \times 0.75 = \$675$. Y3: $675 \times 0.75 = \$506.25$. (b) Y4: $506.25 \times 0.75 \approx \$379.69$. Y5: $\approx \$284.77$. After 5 years it dips below $\$300$.
Subtract
Find discount, then subtract
Multiplier
$1 - \tfrac{P}{100}$
$25\%$ off
$\times 0.75$ (pay $75\%$)
$50\%$ off
$\times 0.50$ (half price)
Multiplier $< 1$
Always for a decrease
Sum = $100\%$
Discount + pay fraction = 100%
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