Mathematics • Year 7 • Unit 4 • Lesson 19

Two-Stage Experiments — Real World

Apply with/without replacement to real selections: a lolly bag, dealing cards, picking student leaders, a raffle barrel and selecting band members. State the procedure first, then multiply along the branches.

Apply · Real-World Maths

1. Word problems

For each problem state "with replacement" or "without replacement" before showing the multiplication line.

1.1 — Lolly bag. A bag has 6 strawberry and 4 lemon lollies. Maya takes one lolly, eats it, then takes a second. (a) Is this with or without replacement? (b) Find P(strawberry then strawberry). (c) Find P(strawberry then lemon).    4 marks

Stuck on (b)? After eating a strawberry there are 5 strawberry + 4 lemon = 9 total left.

1.2 — Card deal. Two cards are dealt from a standard 52-card deck without replacement. (a) Find P(first card is a heart AND second card is a heart). (b) Find P(both red cards).    3 marks

Stuck on (a)? 13 hearts in 52. After dealing a heart: 12 hearts in 51 cards left.

1.3 — Student leaders. A class has 12 girls and 8 boys. The teacher writes every name on a card and picks two cards without replacement to choose the captain and vice-captain. (a) Find P(captain is a girl AND vice-captain is a girl). (b) Find P(captain is a boy AND vice-captain is a girl).    3 marks

Stuck? Total students = 20. After picking 1 person: 19 left.

1.4 — Raffle barrel (returned). A school raffle barrel has 50 tickets — 5 of them are "prize" tickets. A student draws one ticket, records it, then PUTS IT BACK before the next draw. (a) Is this with or without replacement? (b) Find P(2 prize tickets in 2 draws). (c) Repeat without replacement and compare.    4 marks

Stuck on (c)? Without replacement: 4/49 on the second draw.

1.5 — Selecting band members. A school band has 7 woodwind and 5 brass players, total 12. Two players are chosen at random without replacement to perform a duet. Find P(one woodwind AND one brass, in any order).    3 marks

Stuck? P(W then B) + P(B then W) — both orders count.

2. Explain your thinking

Communication matters. Use full sentences. 4 marks

2.1 A Year 7 student writes: "A bag has 3 red and 2 blue marbles. Two marbles are drawn without replacement. P(R then B) = 3/5 × 2/5 = 6/25." Using the lesson, explain (i) which factor is wrong and why, (ii) what the correct second-draw probability is, and (iii) write the right calculation and the correct answer.

Stuck? Revisit lesson § "Spot the Trap" — without replacement, BOTH numerator and denominator change on the second draw.

How did this worksheet feel?

What I'll revisit before next class:

Answers — Do not peek before attempting

1.1 — Lolly bag (6 strawberry, 4 lemon)

(a) Without replacement — she eats the first one.
(b) P(S then S) = 6/10 × 5/9 = 30/90 = 1/3 ≈ 0.333.
(c) P(S then L) = 6/10 × 4/9 = 24/90 = 4/15 ≈ 0.267.

1.2 — Card deal

(a) P(heart then heart) = 13/52 × 12/51 = 156/2652 = 1/17 ≈ 0.0588.
(b) P(both red) = 26/52 × 25/51 = 25/102 ≈ 0.245.

1.3 — Student leaders

(a) P(G then G) = 12/20 × 11/19 = 132/380 = 33/95 ≈ 0.347.
(b) P(B then G) = 8/20 × 12/19 = 96/380 = 24/95 ≈ 0.253.

1.4 — Raffle barrel (with replacement)

(a) With replacement (the ticket is put back).
(b) P(prize then prize) = 5/50 × 5/50 = 25/2500 = 1/100 = 0.01.
(c) Without replacement: 5/50 × 4/49 = 20/2450 = 2/245 ≈ 0.00816. Slightly lower, because after pulling out a prize ticket there is one fewer prize in a smaller barrel.

1.5 — Band duet

P(W then B) = 7/12 × 5/11 = 35/132. P(B then W) = 5/12 × 7/11 = 35/132. Total = 35/132 + 35/132 = 70/132 = 35/66 ≈ 0.530.

2.1 — Explain your thinking (sample response)

(i) The second factor (2/5) is wrong. The student has kept the denominator at 5, but without replacement, after taking a red marble the pool has shrunk from 5 marbles to 4.
(ii) The correct second-draw probability is P(B | R first) = 2/4 = 1/2. There are still 2 blue marbles, but only 4 marbles remain in the bag.
(iii) Correct working: P(R then B) = 3/5 × 2/4 = 6/20 = 3/10 = 0.30.

Marking: 1 for naming the wrong factor, 1 for the correct second-draw value, 1 for the right answer, 1 for clear sentences.