Mathematics • Year 7 • Unit 3 • Lesson 13

Polygon Angles — Real World

Honeycomb hexagons, stop-sign octagons, soccer-ball pentagons, paving tiles. Use the interior-sum and exterior-sum formulas to figure out the angles in real shapes around you.

Apply · Real-World Maths

1. Word problems

For each, name the polygon, apply the formula, show your working.

1.1 — Honeycomb. Bee honeycomb cells are regular hexagons. What is the size of each interior angle of one honeycomb cell?    2 marks

Stuck? Regular hexagon: each interior = (6 − 2) × 180° ÷ 6.

1.2 — Stop sign. A standard road STOP sign is a regular octagon. (a) What is the sum of its interior angles? (b) What is the size of each interior angle?    2 marks

Stuck? n = 8: sum = (8 − 2) × 180°; each = sum ÷ 8.

1.3 — Soccer ball. A traditional soccer ball is made of black regular pentagons and white regular hexagons stitched together. (a) Each interior angle of a regular pentagon = ? (b) Each interior angle of a regular hexagon = ? (c) At a vertex where ONE pentagon and TWO hexagons meet, what is the total of the three angles? (d) Is that less than, equal to, or greater than 360°?    3 marks

Stuck? If the three angles sum to less than 360°, the surface curves like a ball — that's why the ball isn't flat!

1.4 — Paving tile. An architect designs a paving tile shaped like an irregular pentagon. Four of its interior angles measure 110°, 130°, 100° and 105°. Find the fifth interior angle.    2 marks

Stuck? Pentagon interior sum = (5 − 2) × 180° = 540°.

1.5 — Designer's puzzle. A landscape designer wants to make a regular polygon-shaped flowerbed whose each interior angle is 162°. How many sides does the flowerbed have?    2 marks

Stuck? Exterior = 180 − 162. Then n = 360 ÷ exterior.

2. Explain your thinking

Full sentences. 4 marks

2.1 A floor tiler is trying to tile a floor using only regular pentagons (5-sided regular polygons). She finds that no matter how she lays the tiles, there are always gaps at the vertices. In a short paragraph: (i) Calculate each interior angle of a regular pentagon. (ii) Calculate how many pentagons would meet at a vertex if there were NO gap (i.e. 360° at each vertex). (iii) Explain why the number you get is NOT a whole number — and what that means for tiling. (iv) Suggest one regular polygon that DOES tile the floor with no gaps, and explain why.

Stuck? Equilateral triangles (60°), squares (90°) and regular hexagons (120°) all divide 360° exactly. Pentagons (108°) do not.

How did this worksheet feel?

What I'll revisit before next class:

Answers — Do not peek before attempting

1.1 — Honeycomb (regular hexagon)

S = (6 − 2) × 180° = 720°. Each interior = 720° ÷ 6 = 120°.

1.2 — STOP sign (regular octagon)

(a) S = (8 − 2) × 180° = 6 × 180° = 1080°.
(b) Each interior = 1080° ÷ 8 = 135°.

1.3 — Soccer ball vertex

(a) Pentagon: (5 − 2) × 180° ÷ 5 = 540° ÷ 5 = 108°.
(b) Hexagon: (6 − 2) × 180° ÷ 6 = 720° ÷ 6 = 120°.
(c) Total at vertex = 108° + 120° + 120° = 348°.
(d) 348° is less than 360°. The missing 12° forces the surface to curve into a ball — it can't lie flat.

1.4 — Irregular pentagon (110, 130, 100, 105, x)

Sum = (5 − 2) × 180° = 540°. 110 + 130 + 100 + 105 + x = 540 → 445 + x = 540 → x = 95°.

1.5 — Flowerbed, each interior 162°

Exterior = 180° − 162° = 18°. n = 360° ÷ 18° = 20 sides (a regular icosagon).

2.1 — Why regular pentagons don't tile (sample response)

Each interior angle of a regular pentagon is (5 − 2) × 180° ÷ 5 = 108°. For tiles to fit around a single vertex with NO gap, the angles meeting at that vertex must sum to exactly 360°. The number of pentagons needed = 360° ÷ 108° = 3.333…, which is NOT a whole number. Because you can't have a fraction of a tile meet at the vertex, three pentagons leave a gap (3 × 108 = 324°, short by 36°) and four pentagons overlap (4 × 108 = 432°). So regular pentagons cannot tile a flat floor. A regular polygon that DOES tile is the regular hexagon: each interior angle is 120°, and 360 ÷ 120 = 3 exactly — three hexagons meet perfectly at every vertex (like a honeycomb). Equilateral triangles (60°, 6 per vertex) and squares (90°, 4 per vertex) also tile.

Marking: 1 for 108°; 1 for 360 ÷ 108 = 3.33…; 1 for explaining the non-integer = no tiling; 1 for naming a polygon that does tile with valid reason.