Before diving into the practice questions, take a moment to think about what you already know about this topic.
Know
- Arithmetic sequences have a fixed common difference $d$ between consecutive terms
- $d$ can be found by calculating $T_2 - T_1$
- The first term is labelled $a$
Understand
- Each term can be expressed using the nth-term formula $T_n = a + (n-1)d$
- This formula always simplifies to a linear expression of the form $T_n = dn + c$
- If substituting a value gives a non-integer $n$, that value is not in the sequence
Can Do
- Find the common difference of any arithmetic sequence
- Write the nth-term rule for a given sequence
- Find any specific term or test whether a value belongs to a sequence
A sequence is an ordered list of numbers following a rule. In an arithmetic sequence, you add (or subtract) the same amount each time — this fixed amount is called the common difference $d$.
Instead of listing every term, we use a formula that gives any term directly. For an arithmetic sequence with first term $a$ and common difference $d$:
$$T_n = a + (n-1)d$$
To use it: substitute $a$, $d$, and the term number $n$. Then expand and simplify to get a clean linear expression.
Example: Find the nth-term formula for 3, 7, 11, 15, ...
- $a = 3$, $d = 4$
- $T_n = 3 + (n-1) \times 4 = 3 + 4n - 4 = 4n - 1$
Check: $T_1 = 4(1) - 1 = 3$ ✓ $T_4 = 4(4) - 1 = 15$ ✓
The simplified form is always $T_n = dn + c$ — a linear expression in $n$.
Once you have the nth-term formula, you can find any term instantly — or test whether a number belongs to the sequence.
$a = 5$, $d = 4$ → $T_n = 4n + 1$
$T_{20} = 4(20) + 1 = 80 + 1 = 81$
Set $4n - 1 = 45$ → $4n = 46$ → $n = \frac{46}{4} = 11.5$ — not a whole number, so 45 is NOT in this sequence.
Watch Me Solve It · Worked example
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1Find the common difference$d = 5 - 2 = 3$Subtract any term from the next. Check: $8 - 5 = 3$ and $11 - 8 = 3$. Consistent — so this is arithmetic with $d = 3$.
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2Write the formula and simplify$T_n = 2 + (n-1) \times 3 = 2 + 3n - 3 = 3n - 1$Substitute $a = 2$ and $d = 3$ into $T_n = a + (n-1)d$. Expand the bracket, then collect the constants: $2 - 3 = -1$.
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3Find $T_{15}$$T_{15} = 3(15) - 1 = 45 - 1 = 44$Substitute $n = 15$ into the simplified formula. Multiply first, then subtract.
Quick Check · 5 questions
Q1. Find the term-to-term rule and the next two terms of: 15, 11, 7, 3, -1, ...
Q2. Find the $n$th term of the sequence: 6, 10, 14, 18, 22, ...
Q3. The $n$th term of a sequence is $6n - 5$.
Extension Problems
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Key Concept
Review the main ideas from this lesson.
Formulas
Key formulas and rules.
Watch Out
Common mistakes to avoid.
Check
Always verify your answers.
Practice
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Next
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Interactive: Algebra Machine
Substitute numbers into algebraic expressions and see them evaluate step by step.
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Brain Trainer
Set a timer for 3 minutes. Find the $n$th term for each sequence.