Adding and Subtracting Fractions
Same denominator? Just add the tops. Different denominators? Find the LCD first. Mixed numbers? Convert, compute, simplify.
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Before you read on — quickly: $rac{1}{2} + rac{1}{4} = ?$ Can you picture it? And what about $rac{1}{2} + rac{1}{3}$? Why is that harder?
Same denominator? Just add or subtract the numerators. Different denominators? Find the lowest common denominator (LCD), convert both fractions, then add or subtract. Mixed numbers? Convert to improper fractions first (or handle whole and fraction parts separately).
Think of fractions as slices of pizza. You can only add slices that are the same size. $rac{1}{2} + rac{1}{4}$ doesn't work directly because halves and quarters are different sizes. Convert $rac{1}{2}$ to $rac{2}{4}$, then add: $rac{2}{4} + rac{1}{4} = rac{3}{4}$. The key rule: denominators must match before you add or subtract.
Know
- Fractions need common denominators to add or subtract
- LCD is the LCM of the denominators
- Mixed numbers can be converted to improper fractions
Understand
- Why different denominators mean different-sized pieces
- Why converting to equivalent fractions preserves value
- When to use improper vs mixed number strategies
Can Do
- Add and subtract fractions with the same denominator
- Find the LCD and convert fractions
- Add and subtract mixed numbers
Wrong: $\frac{1}{2} + \frac{1}{3} = \frac{2}{5}$. No! You cannot add denominators. Different sizes need conversion first.
Right: LCD of 2 and 3 is 6. $\frac{1}{2} = \frac{3}{6}$, $\frac{1}{3} = \frac{2}{6}$. Then $\frac{3}{6} + \frac{2}{6} = \frac{5}{6}$.
Wrong: $2\frac{1}{4} + 1\frac{3}{4} = 3\frac{4}{8}$. Don\'t add denominators! The denominator stays 4.
Right: $2\frac{1}{4} + 1\frac{3}{4} = (2+1) + (\frac{1}{4}+\frac{3}{4}) = 3 + \frac{4}{4} = 3 + 1 = 4$.
Same denominator: add the numerators, keep the denominator. Different denominators: find LCD, convert both, then add. Always simplify your final answer.
Calculate $\frac{2}{5} + \frac{1}{3}$. LCD of 5 and 3 = 15. Convert: $\frac{2}{5} = \frac{2 \times 3}{5 \times 3} = \frac{6}{15}$. And $\frac{1}{3} = \frac{1 \times 5}{3 \times 5} = \frac{5}{15}$. Now add: $\frac{6}{15} + \frac{5}{15} = \frac{11}{15}$. Check: HCF(11, 15) = 1, so fully simplified.
Subtracting fractions follows the exact same process as adding. Find the LCD, convert both fractions, subtract the numerators, and simplify.
Calculate $\frac{5}{6} - \frac{1}{4}$. LCD of 6 and 4 = 12. Convert: $\frac{5}{6} = \frac{5 \times 2}{6 \times 2} = \frac{10}{12}$. And $\frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}$. Now subtract: $\frac{10}{12} - \frac{3}{12} = \frac{7}{12}$. Check: HCF(7, 12) = 1, fully simplified.
Method 1: Convert to improper fractions, add/subtract, convert back. Method 2: Handle wholes and fractions separately. If the fraction part goes negative, borrow 1 from the whole number.
Calculate $3\frac{1}{4} - 1\frac{3}{4}$. Method 2: Wholes: 3 - 1 = 2. Fractions: $\frac{1}{4} - \frac{3}{4} = -\frac{2}{4}$. So we have $2 - \frac{2}{4}$. Borrow 1: $1 + \frac{4}{4} - \frac{2}{4} = 1\frac{2}{4} = 1\frac{1}{2}$. Method 1 check: $\frac{13}{4} - \frac{7}{4} = \frac{6}{4} = 1\frac{2}{4} = 1\frac{1}{2}$.
Calculate $\frac{3}{8} + \frac{5}{12}$
Find the LCD of 8 and 12. Multiples of 8: 8, 16, 24, 32... Multiples of 12: 12, 24, 36... LCD = 24.
Convert: $\frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24}$ and $\frac{5}{12} = \frac{5 \times 2}{12 \times 2} = \frac{10}{24}$.
Add: $\frac{9}{24} + \frac{10}{24} = \frac{19}{24}$. Check: HCF(19, 24) = 1, fully simplified.
$\frac{3}{8} + \frac{5}{12} = \frac{19}{24}$
Calculate $4\frac{1}{6} - 2\frac{5}{6}$
Same denominator (6), so subtract whole and fraction parts separately. Wholes: 4 - 2 = 2. Fractions: $\frac{1}{6} - \frac{5}{6} = -\frac{4}{6}$. We have $2 - \frac{4}{6}$.
Borrow 1 from the 2: $1 + \frac{6}{6} - \frac{4}{6} = 1\frac{2}{6}$. Simplify: $\frac{2}{6} = \frac{1}{3}$.
Check with improper fractions: $\frac{25}{6} - \frac{17}{6} = \frac{8}{6} = 1\frac{2}{6} = 1\frac{1}{3}$.
$4\frac{1}{6} - 2\frac{5}{6} = 1\frac{1}{3}$
Calculate $2\frac{1}{3} + 1\frac{3}{4}$
Method: convert to improper fractions. $2\frac{1}{3} = \frac{7}{3}$ and $1\frac{3}{4} = \frac{7}{4}$.
LCD of 3 and 4 = 12. Convert: $\frac{7}{3} = \frac{28}{12}$ and $\frac{7}{4} = \frac{21}{12}$.
Add: $\frac{28}{12} + \frac{21}{12} = \frac{49}{12}$. Convert back: $\frac{49}{12} = 4\frac{1}{12}$.
$2\frac{1}{3} + 1\frac{3}{4} = 4\frac{1}{12}$
Mistake: Adding denominators. $\frac{1}{2} + \frac{1}{3} \ne \frac{2}{5}$. Denominators never add!
Fix: Find LCD, convert, then add numerators only. $\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}$.
Mistake: Forgetting to simplify the final answer. $\frac{6}{8}$ should be $\frac{3}{4}$.
Fix: Always check: are numerator and denominator both even? If yes, divide by 2.
Mistake: Borrowing incorrectly with mixed numbers. $3\frac{1}{4} - 1\frac{3}{4} \ne 2\frac{-2}{4}$.
Fix: Borrow 1 from the whole number. $3\frac{1}{4} = 2\frac{5}{4}$, then $2\frac{5}{4} - 1\frac{3}{4} = 1\frac{2}{4} = 1\frac{1}{2}$.
How are you completing this lesson?
Brain Trainer · 4 problems
Four drill problems to build your fraction addition and subtraction fluency. Work each, then reveal the answer.
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1 $\frac{3}{7} + \frac{2}{7}$
Same denominator, so add tops: 3 + 2 = 5. Keep denominator 7.5/7 -
2 $\frac{5}{6} - \frac{1}{4}$
LCD(6,4) = 12. 5/6 = 10/12, 1/4 = 3/12. 10/12 - 3/12 = 7/12.7/12 -
3 $2\frac{1}{5} + 1\frac{3}{5}$
Wholes: 2 + 1 = 3. Fractions: 1/5 + 3/5 = 4/5. So 3 4/5.3 4/5 -
4 $4\frac{1}{3} - 2\frac{2}{3}$
Wholes: 4 - 2 = 2. Fractions: 1/3 - 2/3 = -1/3. Borrow 1: 1 + 3/3 - 1/3 = 1 2/3.1 2/3
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. (a) Calculate $\frac{7}{10} + \frac{2}{5}$. Show the LCD and conversion steps. (b) Calculate $\frac{5}{6} - \frac{3}{8}$. Show all working.
Q7. A recipe needs $2\frac{1}{4}$ cups of flour and $1\frac{2}{3}$ cups of sugar. (a) What is the total amount? (b) How much more flour than sugar is needed? Show all working.
Q8. A student calculates $\frac{2}{3} + \frac{1}{6} = \frac{3}{9} = \frac{1}{3}$. Identify TWO mistakes they made, explain the correct method, and give the right answer.
Quick Check
1. B — Same denominator: 3/8 + 4/8 = 7/8.
2. C — LCD(4,6) = 12. 3/4 = 9/12, 1/6 = 2/12. 9/12 - 2/12 = 7/12.
3. A — 1 + 2 = 3, 1/2 + 1/2 = 1. So 3 + 1 = 4.
4. B — 11/4 - 5/4 = 6/4 = 1 1/2.
5. D — LCD(3,5) = 15. 2/3 = 10/15, 4/5 = 12/15. 10/15 + 12/15 = 22/15 = 1 7/15.
Show Your Working Model Answers
Q6 (4 marks): (a) LCD(10,5) = 10 [0.5]. 7/10 stays, 2/5 = 4/10 [0.5]. 7/10 + 4/10 = 11/10 [1]. (b) LCD(6,8) = 24 [0.5]. 5/6 = 20/24, 3/8 = 9/24 [0.5]. 20/24 - 9/24 = 11/24 [1].
Q7 (4 marks): (a) 2 1/4 + 1 2/3 = 9/4 + 5/3 [0.5]. LCD = 12: 27/12 + 20/12 = 47/12 = 3 11/12 cups [1.5]. (b) 9/4 - 5/3 [0.5]. 27/12 - 20/12 = 7/12 cups more flour [1.5].
Q8 (3 marks): Mistake 1: added denominators (3 + 6 = 9) [1]. Mistake 2: did not find LCD first [0.5]. Correct: LCD(3,6) = 6, so 2/3 = 4/6, then 4/6 + 1/6 = 5/6 [1.5].
The Egyptian Fraction Puzzle
Ancient Egyptians only used fractions with numerator 1 (like $\frac{1}{2}$, $\frac{1}{3}$, $\frac{1}{4}$). They wrote other fractions as sums of these "unit fractions." Can you write $\frac{5}{6}$ as a sum of two different unit fractions? What about $\frac{7}{12}$? Find at least one solution for each.
Reveal solution
$\frac{5}{6} = \frac{1}{2} + \frac{1}{3}$ (since $\frac{3}{6} + \frac{2}{6} = \frac{5}{6}$). $\frac{7}{12} = \frac{1}{3} + \frac{1}{4}$ (since $\frac{4}{12} + \frac{3}{12} = \frac{7}{12}$). There are often multiple solutions!
Same den
Add/subtract tops only
LCD
Find before converting
Convert
Multiply top and bottom equally
Mixed numbers
Convert to improper OR separate
Borrow
When fraction part goes negative
Simplify
Always final step
Interactive: Fraction Steps
Drag the steps into the correct order to solve fraction addition and subtraction problems. Remember: find the LCD first!
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