Finding Unknown Sides
Learn to select the correct trig ratio and use your calculator to find missing sides in right-angled triangles. From building ramps to calculating cliff heights, this skill unlocks real-world measurement.
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A roof truss forms a right-angled triangle. If you know one of the acute angles and the length of the hypotenuse, what else could you work out? How?
Every side-finding problem follows the same three-step pattern. Master these three steps and you can solve any right-angled triangle problem -- from a wheelchair ramp to the height of a cliff.
Label the sides relative to the marked angle. Choose the ratio that connects the side you know to the side you want. Solve the equation, rearranging if the unknown is on the bottom.
Know
- How to rearrange $\sin \theta$, $\cos \theta$ and $\tan \theta$ to make any side the subject
- That your calculator must be in degree (DEG) mode
- How to round to a given number of decimal places
Understand
- That choosing the correct ratio depends only on which two sides are involved
- Why the answer is always a length and must carry correct units
Can Do
- Label the opposite, adjacent and hypotenuse for the marked angle
- Select sin, cos or tan based on the given information
- Write and solve an equation to find the unknown side
Wrong: Using $\sin \theta = \frac{\text{hypotenuse}}{\text{opposite}}$ to find the opposite side.
Right: Always write the ratio correctly first: $\sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}}$, then rearrange to $\text{Opposite} = \text{Hypotenuse} \times \sin \theta$.
Wrong: Leaving the calculator in RAD mode and getting an answer like $0.0349$ instead of $2$.
Right: Check the top-right corner of your calculator screen for DEG before you start.
Every side-finding problem has the same three ingredients: a marked angle, a given side whose length you know, and an unknown side you need to find.
Before you touch your calculator, identify the marked angle, the given side and the unknown side. These three pieces determine everything else.
The ratio you choose depends only on which two sides are involved. Opposite + Hypotenuse = sine. Adjacent + Hypotenuse = cosine. Opposite + Adjacent = tangent.
Look at the given side and the unknown side. Match that pair to one of the three ratios. If the hypotenuse is involved, you are using sine or cosine. If not, use tangent.
When the unknown side is on the bottom of the fraction, multiply both sides by it. Then isolate. Think of it as solving a mini-equation.
If the unknown is on top, multiply. If it is on the bottom, multiply both sides by the unknown first, then divide. Never reach for the calculator until the unknown stands alone.
Before you press sine, check the screen says DEG. After you calculate, round to the requested precision and always attach the correct unit.
CASIO: Press SHIFT then SETUP, select Angle Unit, then Degree. Look for D at the top. TI: Press MODE, scroll to Degree, press ENTER. If you see R or G, your answer will be completely wrong.
Watch Me Solve It · 3 examples
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1Label the sidesHypotenuse = 12 cm, Opposite = $x$, Adjacent = unknown (not needed)Identify which sides are involved before choosing a ratio.
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2Choose the ratioWe have Hypotenuse and want Opposite → use $\sin \theta$Opposite + Hypotenuse pairs with sine (SOH).
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3Write the equation$\sin 35° = \frac{x}{12}$
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4Solve and round$x = 12 \times \sin 35° = 12 \times 0.5736 = 6.883$ → 6.9 cmCheck DEG mode, calculate, then round to 1 decimal place.
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1Label the sidesOpposite = 15 m, Adjacent = $x$, Angle = 50°
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2Choose the ratioWe have Opposite and want Adjacent → use $\tan \theta$Opposite + Adjacent pairs with tangent (TOA).
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3Write and rearrange$\tan 50° = \frac{15}{x}$ → $x = \frac{15}{\tan 50°}$The unknown is on the bottom -- multiply both sides by $x$ first, then divide.
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4Calculate and round$x = \frac{15}{1.1918} = 12.586$ → 12.59 m
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1Label the sidesOpposite = 0.5 m (rise), Hypotenuse = $x$ (ramp), Angle = 4°
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2Choose the ratioWe have Opposite and want Hypotenuse → use $\sin \theta$
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3Write and rearrange$\sin 4° = \frac{0.5}{x}$ → $x = \frac{0.5}{\sin 4°}$
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4Calculate and round$x = \frac{0.5}{0.06976} = 7.166$ → 7.2 mA shallow angle means a long ramp -- the answer makes sense.
Rearranged Formulas
- $\text{Opposite} = \text{Hypotenuse} \times \sin \theta$
- $\text{Adjacent} = \text{Hypotenuse} \times \cos \theta$
- $\text{Opposite} = \text{Adjacent} \times \tan \theta$
Hypotenuse Formulas
- $\text{Hypotenuse} = \frac{\text{Opposite}}{\sin \theta}$
- $\text{Hypotenuse} = \frac{\text{Adjacent}}{\cos \theta}$
- $\text{Adjacent} = \frac{\text{Opposite}}{\tan \theta}$
The Three Steps
- 1. Label -- name O, A, H
- 2. Choose -- match pair to ratio
- 3. Solve -- rearrange and calculate
Calculator Check
- Confirm DEG mode
- Write full display before rounding
- Always include units
How are you completing this lesson?
Brain Trainer · 4 problems
Four problems finding different unknown sides. Work each one, then reveal the answer.
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1 θ = 28°, hypotenuse = 18 cm. Find the opposite side to 1 decimal place.
$\sin 28° = \frac{x}{18}$ → $x = 18 \times \sin 28° = 18 \times 0.4695$$= 8.5$ cm -
2 A kite string makes 52° with the horizontal. The kite is 35 m above ground. How long is the string to the nearest metre?
$\sin 52° = \frac{35}{x}$ → $x = \frac{35}{\sin 52°} = \frac{35}{0.7880}$$= 44$ m -
3 θ = 60°, adjacent = 8 cm. Find the opposite side to 1 decimal place.
$\tan 60° = \frac{x}{8}$ → $x = 8 \times \tan 60° = 8 \times 1.732$$= 13.9$ cm -
4 θ = 40°, opposite = 10 m. Find the hypotenuse to 1 decimal place.
$\sin 40° = \frac{10}{x}$ → $x = \frac{10}{\sin 40°} = \frac{10}{0.6428}$$= 15.6$ m
Quick Check · 5 questions
Show Your Working · 3 questions
Q6. A right-angled triangle has angle θ = 42° and hypotenuse 20 cm. (a) Find the opposite side to 1 decimal place. (b) Find the adjacent side to 1 decimal place.
Q7. A surveyor stands 45 m from the base of a cliff. The angle of elevation to the top is 38°. (a) Draw a diagram and label the known and unknown sides. (b) Choose the correct ratio and calculate the height of the cliff to the nearest metre.
Q8. A kayak ramp rises at 6° to the horizontal. The vertical rise is 0.8 m. (a) Find the length of the ramp surface to 2 decimal places. (b) Find the horizontal distance to 2 decimal places. (c) If the vertical rise is doubled but the angle stays the same, explain what happens to the ramp length and horizontal distance.
Quick Check
1. B -- Opposite + Hypotenuse = sine.
2. C -- Opposite + Adjacent = tangent.
3. B -- Always check DEG mode first.
4. B -- $x = 14 \times \cos 60° = 14 \times 0.5 = 7$.
5. C -- Height = opposite, shadow = adjacent. Use tan.
Show Your Working Model Answers
Q6 (2 marks): (a) $\sin 42° = \frac{x}{20}$ → $x = 20 \times \sin 42° = 13.4$ cm [1]. (b) $\cos 42° = \frac{y}{20}$ → $y = 20 \times \cos 42° = 14.9$ cm [1].
Q7 (2 marks): (a) Diagram showing right triangle with base 45 m, height $h$, angle 38° [1]. (b) $\tan 38° = \frac{h}{45}$ → $h = 45 \times \tan 38° = 45 \times 0.7813 = 35$ m [1].
Q8 (3 marks): (a) $\sin 6° = \frac{0.8}{L}$ → $L = \frac{0.8}{\sin 6°} = 7.65$ m [1]. (b) $\tan 6° = \frac{0.8}{d}$ → $d = \frac{0.8}{\tan 6°} = 7.61$ m [1]. (c) Doubling the opposite while keeping the angle constant doubles both the hypotenuse and adjacent because the triangle is scaled by factor 2 [1].
The Park Path
A rectangular park has a diagonal path 120 m long that makes an angle of 35° with the longer side. Find the length and width of the park to 1 decimal place. Verify your answers using Pythagoras' theorem.
Reveal solution
Length = $120 \times \cos 35° = 120 \times 0.8192 = 98.3$ m. Width = $120 \times \sin 35° = 120 \times 0.5736 = 68.8$ m. Verification: $98.3^2 + 68.8^2 = 9662.9 + 4733.4 = 14396.3 \approx 14400 = 120^2$.
Label first
Name O, A and H
Match the pair
O+H=sin, A+H=cos, O+A=tan
Make it the subject
Isolate the unknown before calculating
DEG mode
Check before every problem
Round carefully
Full display, then round
Always use units
cm, m or km
Interactive: Side Finder
Practise choosing the correct ratio and calculating missing sides on random triangles.
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