Exponential Relationships
Exponential growth and decay are everywhere — bacteria doubling, radioactive materials decaying, compound interest accumulating. The model $y = Ab^x$ captures all of these. Learn to recognise, graph, build, and critically analyse exponential models.
A bacteria population starts at 100 and doubles every hour. How many bacteria will there be after 10 hours? And what do you think the graph of this relationship looks like — does it grow at a constant rate, or does it speed up?
Write your guess — you'll revisit it at the end.
An exponential relationship has the form $y = Ab^x$ (growth, $b > 1$) or $y = Ab^{-x}$ (decay, $0 < b < 1$). The base $b$ controls how fast the quantity grows or shrinks. The constant $A$ is the initial value (the $y$-intercept).
Key parameters: $A$ = initial value (value when $x = 0$, i.e. the $y$-intercept). $b$ = growth factor (each period, the quantity is multiplied by $b$). If $b > 1$ the quantity grows; if $0 < b < 1$ it decays.
Key facts
- An exponential relationship has the form $y = Ab^x$ or $y = Ab^{-x}$, where $b > 0$, $b \neq 1$
- $A$ = initial value (the $y$-intercept: value when $x = 0$)
- $b > 1$ → growth; $0 < b < 1$ → decay
- An exponential graph has a horizontal asymptote at $y = 0$
Concepts
- Why exponential growth accelerates — the rate of increase grows over time
- How to move between equations, tables of values, ordered pairs and graphs
- What the $y$-intercept tells you in a real-world context
- Why exponential models have limitations (can't predict forever; can't reach 0)
Skills
- Graph $y = Ab^x$ and $y = Ab^{-x}$ using a table or graphing technology
- Identify $A$, $b$ and the growth/decay type from the equation
- Construct an exponential model from a practical scenario
- Use the model to solve growth/decay problems by substitution or graphically
- Explain the limitations of an exponential model in context
An exponential relationship can be expressed in four equivalent forms. Being able to move between them fluently is the key skill in this topic — and NESA tests all four forms.
The four representations:
- Equation: $y = 3 \times 2^x$ — gives the exact rule; use it to substitute any $x$ value and find $y$.
- Table of values: list $(x, y)$ pairs: $(-1, 1.5),\ (0, 3),\ (1, 6),\ (2, 12),\ (3, 24)$. Notice each $y$-value is double the previous one — that's the growth factor $b = 2$.
- Set of ordered pairs: the same table written as $\{(-1, 1.5),\ (0, 3),\ (1, 6),\ (2, 12),\ (3, 24)\}$.
- Graph: plot the points and draw a smooth curve through them. The graph is curved (not straight), increasing, and has a horizontal asymptote at $y = 0$.
What to write in your book
- Equation: $y = Ab^x$ (growth, $b > 1$) or $y = Ab^{-x}$ (decay). $y$-intercept $= A$.
- Identify exponential from table: constant ratio between successive $y$-values (not constant difference).
- Graph: smooth curve, horizontal asymptote at $y = 0$, passes through $(0, A)$.
Quick check: A table of values has $y$-values: 4, 8, 16, 32, 64 for consecutive integer $x$-values. What type of relationship is this, and what is the growth factor?
The shape of an exponential graph is determined entirely by $b$. Values of $b > 1$ give an increasing curve (growth); values $0 < b < 1$ give a decreasing curve (decay). The value of $A$ shifts the curve vertically, changing the $y$-intercept but not the shape.
Key features of $y = Ab^x$ ($b > 1$, growth):
- $y$-intercept at $(0,\ A)$ — always positive if $A > 0$
- Increasing at an increasing rate (the curve accelerates upward)
- Horizontal asymptote: $y = 0$ as $x \to -\infty$
- Domain: all real $x$; Range: $y > 0$ (if $A > 0$)
Key features of $y = Ab^{-x}$ (decay, or equivalently $y = A \left(\frac{1}{b}\right)^x$):
- $y$-intercept at $(0,\ A)$ — same starting point as the growth curve
- Decreasing at a decreasing rate (the curve flattens out)
- Horizontal asymptote: $y = 0$ as $x \to +\infty$
- Domain: all real $x$; Range: $y > 0$ (if $A > 0$)
y = 2 * 3^x for the growth curve or y = 2 * 3^(-x) for decay. Adjust $A$ and $b$ using sliders to see how each parameter changes the graph.
What to write in your book
- Growth ($b > 1$): increasing curve, passes through $(0, A)$, asymptote $y = 0$ on the left.
- Decay ($0 < b < 1$ or use $b^{-x}$): decreasing curve, passes through $(0, A)$, asymptote $y = 0$ on the right.
- $y$-intercept $= A$ in both cases (substitute $x = 0$).
True or false: The graph of $y = 5 \times 0.6^x$ shows exponential growth because the coefficient $A = 5$ is greater than 1.
An exponential model turns a real-world situation into an equation. Once you have the equation, you can predict values, interpret the starting condition, and critically evaluate where the model breaks down.
Constructing the model:
- Identify the initial value $A$ (the quantity at $x = 0$ — e.g. starting population, initial investment)
- Identify the growth or decay factor $b$ per period (e.g. doubles each hour → $b = 2$; reduces by 20% each year → $b = 0.8$ since $100\% - 20\% = 80\% = 0.8$)
- Write the equation: $y = Ab^x$ (growth) or $y = Ab^{-x}$ (decay)
Interpreting the $y$-intercept: Substituting $x = 0$ gives $y = A$. In context, $A$ is the value of the quantity at the start (time zero, beginning of the observation period). Always state $A$ with its units and meaning.
Limitations of exponential models:
- Growth models eventually become unrealistic — bacteria can't grow forever (food/space limits exist).
- Decay models approach zero but never reach it — in practice, quantities do reach zero.
- The model assumes a constant growth/decay factor — in reality, rates often change over time.
- Models should only be used within a reasonable domain — extrapolating too far gives nonsense predictions.
What to write in your book
- $y$-intercept $= A$ = initial value (state its meaning in context).
- Growth by $r\%$: $b = 1 + r/100$. Decay by $r\%$: $b = 1 - r/100$.
- Limitations: constant rate assumed; growth can't continue indefinitely; decay approaches but never reaches zero.
Fill the blanks: A radioactive substance decays by 10% each year. The growth factor $b$ is . The equation, starting from 500 grams, is $y = $ $\times$ $^x$.
Worked examples · 3 problems
Graph $y = 3 \times 2^x$ for $x \in \{-2, -1, 0, 1, 2, 3\}$ and identify the $y$-intercept, growth factor and any asymptote.
$x=-2$: $y = 3 \times 2^{-2} = 3 \times 0.25 = 0.75$
$x=-1$: $y = 3 \times 0.5 = 1.5$
$x=0$: $y = 3 \times 1 = 3$
$x=1$: $y = 3 \times 2 = 6$
$x=2$: $y = 3 \times 4 = 12$
$x=3$: $y = 3 \times 8 = 24$
$y$-intercept: $(0, 3)$ — the value of $A$
Growth factor: $b = 2$ (each $y$ is double the previous)
Asymptote: $y = 0$ (the curve approaches $y = 0$ as $x \to -\infty$)
Plot the 6 points. Connect with a smooth curve (not straight lines). Show a dashed horizontal line at $y = 0$ for the asymptote. The curve rises steeply to the right and flattens near zero to the left.
y = 3 * 2^x in Desmos.A city's population is 250,000 and grows at 3% per year. (a) Write an exponential model for the population $P$ after $t$ years. (b) Interpret the $y$-intercept. (c) Predict the population after 20 years (to the nearest thousand). (d) State one limitation of this model.
$b = 1 + \frac{3}{100} = 1.03$ (3% growth per year)
$P = 250\,000 \times 1.03^t$
When $t = 0$: $P = 250{,}000 \times 1.03^0 = 250{,}000$
The $y$-intercept represents the population at the start of the observation period: 250,000 people.
$P = 250\,000 \times 1.03^{20} = 250\,000 \times 1.8061 \approx 451\,528$
$\approx 452\,000$ (to the nearest thousand)
The model assumes a constant 3% growth rate every year. In reality, population growth depends on birth rates, migration, economic factors, and environmental constraints that can change year to year. The model would become increasingly inaccurate over a long time horizon.
A car is purchased for $24,000 and depreciates by 18% per year. (a) Write the decay model. (b) Find its value after 5 years. (c) Is the car ever worth $0 according to this model? Explain.
$b = 1 - 0.18 = 0.82$
$V = 24\,000 \times 0.82^t$ (where $t$ = years after purchase)
$V = 24\,000 \times 0.82^5 = 24\,000 \times 0.3707 \approx \$8{,}897$
No. $V = 24\,000 \times 0.82^t > 0$ for all finite $t$. As $t \to \infty$, $V \to 0$ but never actually equals zero. The model has a horizontal asymptote at $V = 0$.
Match each scenario to its exponential equation:
Top 3 list: Name THREE limitations of using an exponential growth model to predict a real-world population.
Bacteria starting at 100, doubling every hour: $y = 100 \times 2^{10} = 100 \times 1024 = 102{,}400$ bacteria after 10 hours — much closer to 100,000 than to 100,000,000. Most people underestimate exponential growth because early growth looks slow. After just 20 hours the model gives $100 \times 2^{20} \approx 104{,}857{,}600$ — over 100 million. This is why limitations matter.
SA 1. The table below shows the value of an antique item over time:
| Year ($x$) | 0 | 1 | 2 | 3 |
|---|---|---|---|---|
| Value ($y$) | $1000 | $1200 | $1440 | $1728 |
(a) Show that this is an exponential relationship. (b) Write the equation. (c) Predict the value after 6 years. (3 marks)
SA 2. A hospital patient receives 80 mg of a drug. The drug decays by 25% per hour. (a) Write the decay model for the amount $D$ mg remaining after $t$ hours. (b) Interpret the $y$-intercept. (c) How much drug remains after 4 hours? Give your answer to 1 decimal place. (d) The drug is effective while more than 15 mg remains. Use your model to determine whether it is still effective after 8 hours — justify your answer with a calculation. (4 marks)
SA 3. A model for a bushfire spreading is given by $A = 50 \times 1.8^t$, where $A$ is the area in hectares and $t$ is the time in hours. (a) What does the 50 represent in this context? (b) What does the 1.8 represent? (c) Predict the area after 3 hours. (d) State TWO limitations of using this model to predict the spread of the bushfire over 24 hours. (4 marks)
📖 Comprehensive answers (click to reveal)
SA 1 (3 marks): (a) Ratios: $1200/1000=1.2$, $1440/1200=1.2$, $1728/1440=1.2$ — constant ratio $b=1.2$ confirms exponential [1]. (b) $y=1000 \times 1.2^x$ [1]. (c) $y=1000 \times 1.2^6=1000 \times 2.986\approx\$2{,}986$ [1].
SA 2 (4 marks): (a) $D=80\times0.75^t$ ($b=1-0.25=0.75$) [1]. (b) $y$-intercept is 80 mg — the initial dose given to the patient [1]. (c) $D=80\times0.75^4=80\times0.3164\approx25.3$ mg [1]. (d) $D=80\times0.75^8=80\times0.1001\approx8.0$ mg $<$ 15 mg — no longer effective after 8 hours [1].
SA 3 (4 marks): (a) 50 represents the initial area of the bushfire at $t=0$ (50 hectares) [1]. (b) 1.8 represents the growth factor — the area is multiplied by 1.8 each hour (80% increase per hour) [1]. (c) $A=50\times1.8^3=50\times5.832=291.6$ ha [1]. (d) Any TWO of: the model assumes a constant growth rate, but wind/terrain/humidity affect spread; no upper bound (eventually exceeds available land); model doesn't account for firefighting or natural barriers; weather/wind direction changes can stop or accelerate spread unpredictably [1 per valid limitation, max 1 mark].
Five timed questions on exponential relationships. Gold tier requires 90% + speed.
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