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Algebraic Relationships · L3 of 6 ~50 min MST-12-S2-01 ⚡ +90 XP available

Exponential Relationships

Exponential growth and decay are everywhere — bacteria doubling, radioactive materials decaying, compound interest accumulating. The model $y = Ab^x$ captures all of these. Learn to recognise, graph, build, and critically analyse exponential models.

Today's hook — If a bacteria population doubles every hour, and starts with 100 bacteria, how many will there be after 10 hours? Is your answer closer to 100,000 or 100,000,000? Exponential growth surprises almost everyone.
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Recall — your gut answer first
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A bacteria population starts at 100 and doubles every hour. How many bacteria will there be after 10 hours? And what do you think the graph of this relationship looks like — does it grow at a constant rate, or does it speed up?

Write your guess — you'll revisit it at the end.

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The key formula you need to own
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An exponential relationship has the form $y = Ab^x$ (growth, $b > 1$) or $y = Ab^{-x}$ (decay, $0 < b < 1$). The base $b$ controls how fast the quantity grows or shrinks. The constant $A$ is the initial value (the $y$-intercept).

Key parameters: $A$ = initial value (value when $x = 0$, i.e. the $y$-intercept). $b$ = growth factor (each period, the quantity is multiplied by $b$). If $b > 1$ the quantity grows; if $0 < b < 1$ it decays.

Growth: $b > 1$  |  Decay: $0 < b < 1$  |  $y$-intercept $= A$ (at $x = 0$)
$b$ must be positive
The base $b$ must satisfy $b > 0$ and $b \neq 1$. If $b = 1$, the equation becomes $y = A$, a horizontal line (not exponential).
Never reaches zero (in theory)
A decay curve approaches zero but never actually reaches it — the $x$-axis is a horizontal asymptote. In practice, quantities do eventually reach zero, which is a model limitation.
$y$-intercept is always $A$
Substituting $x = 0$: $y = Ab^0 = A \times 1 = A$. So $A$ is the starting value — bacterial count at time 0, initial investment, radioactive atoms at the start, etc.
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What you'll master
Know

Key facts

  • An exponential relationship has the form $y = Ab^x$ or $y = Ab^{-x}$, where $b > 0$, $b \neq 1$
  • $A$ = initial value (the $y$-intercept: value when $x = 0$)
  • $b > 1$ → growth; $0 < b < 1$ → decay
  • An exponential graph has a horizontal asymptote at $y = 0$
Understand

Concepts

  • Why exponential growth accelerates — the rate of increase grows over time
  • How to move between equations, tables of values, ordered pairs and graphs
  • What the $y$-intercept tells you in a real-world context
  • Why exponential models have limitations (can't predict forever; can't reach 0)
Can do

Skills

  • Graph $y = Ab^x$ and $y = Ab^{-x}$ using a table or graphing technology
  • Identify $A$, $b$ and the growth/decay type from the equation
  • Construct an exponential model from a practical scenario
  • Use the model to solve growth/decay problems by substitution or graphically
  • Explain the limitations of an exponential model in context
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Key terms
Exponential functionA function of the form $y = Ab^x$ where $b > 0$, $b \neq 1$. The variable appears in the exponent (power), not the base.
Growth factor ($b$)The multiplier applied each time period. If $b = 2$, the quantity doubles each period. If $b = 1.05$, it grows 5% each period.
Initial value ($A$)The value of $y$ when $x = 0$ — the $y$-intercept. It represents the starting quantity in a model.
Exponential decayAn exponential relationship where $y$ decreases as $x$ increases — represented by $y = Ab^{-x}$ or $y = Ab^x$ when $0 < b < 1$.
Horizontal asymptoteA line that the graph approaches but never reaches. For $y = Ab^x$, the graph approaches $y = 0$ as $x \to -\infty$ (growth) or $x \to +\infty$ (decay).
Model limitationThe conditions under which the model breaks down — e.g. a bacteria model fails when nutrients run out; a decay model predicts non-zero values that don't occur in reality.
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Recognising and Representing Exponential Relationships
core concept

An exponential relationship can be expressed in four equivalent forms. Being able to move between them fluently is the key skill in this topic — and NESA tests all four forms.

The four representations:

  • Equation: $y = 3 \times 2^x$ — gives the exact rule; use it to substitute any $x$ value and find $y$.
  • Table of values: list $(x, y)$ pairs: $(-1, 1.5),\ (0, 3),\ (1, 6),\ (2, 12),\ (3, 24)$. Notice each $y$-value is double the previous one — that's the growth factor $b = 2$.
  • Set of ordered pairs: the same table written as $\{(-1, 1.5),\ (0, 3),\ (1, 6),\ (2, 12),\ (3, 24)\}$.
  • Graph: plot the points and draw a smooth curve through them. The graph is curved (not straight), increasing, and has a horizontal asymptote at $y = 0$.
How to identify exponential from a table: In a linear table, differences between consecutive $y$-values are constant. In an exponential table, the ratio between consecutive $y$-values is constant (equal to $b$). Check: divide each $y$-value by the previous one — if the ratio is constant, the relationship is exponential.
Graphing tip: When drawing an exponential curve by hand, plot at least 5 points spanning negative and positive $x$-values. Connect with a smooth curve — do not use a ruler. Show the horizontal asymptote as a dashed line at $y = 0$.
What to write in your book
  • Equation: $y = Ab^x$ (growth, $b > 1$) or $y = Ab^{-x}$ (decay). $y$-intercept $= A$.
  • Identify exponential from table: constant ratio between successive $y$-values (not constant difference).
  • Graph: smooth curve, horizontal asymptote at $y = 0$, passes through $(0, A)$.

Quick check: A table of values has $y$-values: 4, 8, 16, 32, 64 for consecutive integer $x$-values. What type of relationship is this, and what is the growth factor?

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Graphing $y = Ab^x$ and $y = Ab^{-x}$
core concept

The shape of an exponential graph is determined entirely by $b$. Values of $b > 1$ give an increasing curve (growth); values $0 < b < 1$ give a decreasing curve (decay). The value of $A$ shifts the curve vertically, changing the $y$-intercept but not the shape.

Key features of $y = Ab^x$ ($b > 1$, growth):

  • $y$-intercept at $(0,\ A)$ — always positive if $A > 0$
  • Increasing at an increasing rate (the curve accelerates upward)
  • Horizontal asymptote: $y = 0$ as $x \to -\infty$
  • Domain: all real $x$; Range: $y > 0$ (if $A > 0$)

Key features of $y = Ab^{-x}$ (decay, or equivalently $y = A \left(\frac{1}{b}\right)^x$):

  • $y$-intercept at $(0,\ A)$ — same starting point as the growth curve
  • Decreasing at a decreasing rate (the curve flattens out)
  • Horizontal asymptote: $y = 0$ as $x \to +\infty$
  • Domain: all real $x$; Range: $y > 0$ (if $A > 0$)
$y = Ab^{-x}$ is a reflection: The graph of $y = Ab^{-x}$ is the reflection of $y = Ab^x$ in the $y$-axis. Both pass through $(0,\ A)$. On a graph, growth curves go up to the right; decay curves go down to the right.
Using graphing technology: In GeoGebra or Desmos, type y = 2 * 3^x for the growth curve or y = 2 * 3^(-x) for decay. Adjust $A$ and $b$ using sliders to see how each parameter changes the graph.
What to write in your book
  • Growth ($b > 1$): increasing curve, passes through $(0, A)$, asymptote $y = 0$ on the left.
  • Decay ($0 < b < 1$ or use $b^{-x}$): decreasing curve, passes through $(0, A)$, asymptote $y = 0$ on the right.
  • $y$-intercept $= A$ in both cases (substitute $x = 0$).

True or false: The graph of $y = 5 \times 0.6^x$ shows exponential growth because the coefficient $A = 5$ is greater than 1.

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Exponential Models — Construction, Interpretation and Limitations
core concept

An exponential model turns a real-world situation into an equation. Once you have the equation, you can predict values, interpret the starting condition, and critically evaluate where the model breaks down.

Constructing the model:

  • Identify the initial value $A$ (the quantity at $x = 0$ — e.g. starting population, initial investment)
  • Identify the growth or decay factor $b$ per period (e.g. doubles each hour → $b = 2$; reduces by 20% each year → $b = 0.8$ since $100\% - 20\% = 80\% = 0.8$)
  • Write the equation: $y = Ab^x$ (growth) or $y = Ab^{-x}$ (decay)

Interpreting the $y$-intercept: Substituting $x = 0$ gives $y = A$. In context, $A$ is the value of the quantity at the start (time zero, beginning of the observation period). Always state $A$ with its units and meaning.

Limitations of exponential models:

  • Growth models eventually become unrealistic — bacteria can't grow forever (food/space limits exist).
  • Decay models approach zero but never reach it — in practice, quantities do reach zero.
  • The model assumes a constant growth/decay factor — in reality, rates often change over time.
  • Models should only be used within a reasonable domain — extrapolating too far gives nonsense predictions.
Bacteria example resolved: $y = 100 \times 2^x$ (where $x$ = hours). At $x = 10$: $y = 100 \times 2^{10} = 100 \times 1024 = 102{,}400$ bacteria. Much closer to 100,000 than 100,000,000. The model works for a few hours but would predict trillions by day 2 — clearly unrealistic. This is a model limitation.
Reducing by a percentage: A quantity reducing by $r\%$ per period has $b = 1 - \frac{r}{100}$. Reducing by 15% per year gives $b = 0.85$; the decay model is $y = A \times 0.85^x$.
What to write in your book
  • $y$-intercept $= A$ = initial value (state its meaning in context).
  • Growth by $r\%$: $b = 1 + r/100$. Decay by $r\%$: $b = 1 - r/100$.
  • Limitations: constant rate assumed; growth can't continue indefinitely; decay approaches but never reaches zero.

Fill the blanks: A radioactive substance decays by 10% each year. The growth factor $b$ is . The equation, starting from 500 grams, is $y = $ $\times$ $^x$.

PROBLEM 1 · GRAPHING A GROWTH CURVE

Graph $y = 3 \times 2^x$ for $x \in \{-2, -1, 0, 1, 2, 3\}$ and identify the $y$-intercept, growth factor and any asymptote.

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Build table of values
$x=-2$: $y = 3 \times 2^{-2} = 3 \times 0.25 = 0.75$
$x=-1$: $y = 3 \times 0.5 = 1.5$
$x=0$: $y = 3 \times 1 = 3$
$x=1$: $y = 3 \times 2 = 6$
$x=2$: $y = 3 \times 4 = 12$
$x=3$: $y = 3 \times 8 = 24$
Substitute each $x$ into the formula. Note: $2^{-2} = 1/4$ and $2^{-1} = 1/2$.
PROBLEM 2 · CONSTRUCTING AND USING A MODEL

A city's population is 250,000 and grows at 3% per year. (a) Write an exponential model for the population $P$ after $t$ years. (b) Interpret the $y$-intercept. (c) Predict the population after 20 years (to the nearest thousand). (d) State one limitation of this model.

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Part (a) — write the model
$b = 1 + \frac{3}{100} = 1.03$ (3% growth per year)
$P = 250\,000 \times 1.03^t$
$A = 250{,}000$ (initial population). $b = 1.03$ (3% growth means quantity × 1.03 each year).
PROBLEM 3 · DECAY MODEL

A car is purchased for $24,000 and depreciates by 18% per year. (a) Write the decay model. (b) Find its value after 5 years. (c) Is the car ever worth $0 according to this model? Explain.

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Part (a) — decay model
$b = 1 - 0.18 = 0.82$
$V = 24\,000 \times 0.82^t$ (where $t$ = years after purchase)
18% depreciation means the car retains 82% of its value each year. $A = 24{,}000$, $b = 0.82$.

Match each scenario to its exponential equation:

Top 3 list: Name THREE limitations of using an exponential growth model to predict a real-world population.

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Revisit your thinking

Bacteria starting at 100, doubling every hour: $y = 100 \times 2^{10} = 100 \times 1024 = 102{,}400$ bacteria after 10 hours — much closer to 100,000 than to 100,000,000. Most people underestimate exponential growth because early growth looks slow. After just 20 hours the model gives $100 \times 2^{20} \approx 104{,}857{,}600$ — over 100 million. This is why limitations matter.

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Short answer — exam-style questions
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ApplyBand 33 marks

SA 1. The table below shows the value of an antique item over time:

Year ($x$)0123
Value ($y$)$1000$1200$1440$1728

(a) Show that this is an exponential relationship. (b) Write the equation. (c) Predict the value after 6 years. (3 marks)

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SA 2. A hospital patient receives 80 mg of a drug. The drug decays by 25% per hour. (a) Write the decay model for the amount $D$ mg remaining after $t$ hours. (b) Interpret the $y$-intercept. (c) How much drug remains after 4 hours? Give your answer to 1 decimal place. (d) The drug is effective while more than 15 mg remains. Use your model to determine whether it is still effective after 8 hours — justify your answer with a calculation. (4 marks)

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EvaluateBand 54 marks

SA 3. A model for a bushfire spreading is given by $A = 50 \times 1.8^t$, where $A$ is the area in hectares and $t$ is the time in hours. (a) What does the 50 represent in this context? (b) What does the 1.8 represent? (c) Predict the area after 3 hours. (d) State TWO limitations of using this model to predict the spread of the bushfire over 24 hours. (4 marks)

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📖 Comprehensive answers (click to reveal)

SA 1 (3 marks): (a) Ratios: $1200/1000=1.2$, $1440/1200=1.2$, $1728/1440=1.2$ — constant ratio $b=1.2$ confirms exponential [1]. (b) $y=1000 \times 1.2^x$ [1]. (c) $y=1000 \times 1.2^6=1000 \times 2.986\approx\$2{,}986$ [1].

SA 2 (4 marks): (a) $D=80\times0.75^t$ ($b=1-0.25=0.75$) [1]. (b) $y$-intercept is 80 mg — the initial dose given to the patient [1]. (c) $D=80\times0.75^4=80\times0.3164\approx25.3$ mg [1]. (d) $D=80\times0.75^8=80\times0.1001\approx8.0$ mg $<$ 15 mg — no longer effective after 8 hours [1].

SA 3 (4 marks): (a) 50 represents the initial area of the bushfire at $t=0$ (50 hectares) [1]. (b) 1.8 represents the growth factor — the area is multiplied by 1.8 each hour (80% increase per hour) [1]. (c) $A=50\times1.8^3=50\times5.832=291.6$ ha [1]. (d) Any TWO of: the model assumes a constant growth rate, but wind/terrain/humidity affect spread; no upper bound (eventually exceeds available land); model doesn't account for firefighting or natural barriers; weather/wind direction changes can stop or accelerate spread unpredictably [1 per valid limitation, max 1 mark].

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Boss battle · The Exponential Analyst
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Five timed questions on exponential relationships. Gold tier requires 90% + speed.

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