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hscscienceMaths Std · Y11
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Module 1 · L16 of 20 ~45 min ⚡ +90 XP available

Compound Inequalities

Combine two inequalities into one double inequality (AND) or union (OR). Solve by applying the same operation to all three parts simultaneously, then graph the combined solution on a number line.

Today's hook — A swimming pool is safe to use when the temperature is above 5°C AND below 35°C. Can you write this as a single inequality? That is exactly what a compound inequality does — it captures both limits at once.
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Recall — your gut answer first
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A temperature must be above 5°C and below 35°C. Can you write this as one inequality using two inequality signs? What do you think the graph looks like?

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Compound inequalities — AND and OR
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A compound inequality combines two inequalities. When both must be true (AND), the result is a double inequality: $a < x \leq b$. The solution is the set of values in both ranges.

To solve a double inequality such as $-1 \leq 2x + 3 \leq 9$: apply the same operation to all three parts simultaneously. Treat the middle expression like the "subject" and isolate $x$.

APPLY TO ALL THREE PARTS -1 ≤ 2x + 3 ≤ 9 SUBTRACT 3, THEN DIVIDE BY 2 -2 ≤ x ≤ 3
$-1 \leq 2x + 3 \leq 9 \Rightarrow -4 \leq 2x \leq 6 \Rightarrow -2 \leq x \leq 3$
Apply to ALL three parts
Every operation (add, subtract, multiply, divide) must be applied to the left side, the middle, and the right side simultaneously.
Bounded solution set
A double inequality (AND) produces a bounded set — values between two endpoints. Both endpoints may be open or closed.
Real-world fit
Double inequalities naturally model "safe ranges" — temperature, pH, concentration, speed limits with minimum and maximum.
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What you'll master
Know

Key facts

  • A double inequality $a < x \leq b$ means $x$ must satisfy BOTH inequalities simultaneously.
  • Apply operations to all three parts when solving.
  • The graph shows a bounded segment between two endpoints.
Understand

Concepts

  • Why "and" produces an intersection (bounded set) while "or" produces a union (two rays).
  • How to use open and closed circles at both endpoints.
  • How to translate real-world "safe range" contexts into a double inequality.
Can do

Skills

  • Solve double inequalities by applying operations to all three parts.
  • Graph compound inequalities on a number line with correct circle types.
  • Translate a worded range into a compound inequality.
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Key terms
Compound inequalityTwo inequalities joined by AND (both must be true) or OR (at least one must be true).
Double inequalityA compound AND inequality written in the form $a < x \leq b$, combining two boundaries.
IntersectionThe set of values satisfying BOTH conditions simultaneously — the overlap of the two solution sets.
UnionThe set of all values satisfying at least ONE condition — the combined set of the two solution sets.
Bounded setA solution set that has both a lower and an upper boundary — a finite segment of the number line.
Safe rangeA real-world interval where a quantity (temperature, pH, speed) must remain between a minimum and maximum value.
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Solving double inequalities
core concept

To solve $-1 \leq 2x + 3 \leq 9$: treat it as a single inequality with three parts. Subtract 3 from all three parts, then divide by 2. The variable ends up isolated in the middle.

The answer $-2 \leq x \leq 3$ represents all values from $-2$ to $3$ inclusive. The graph shows a segment with two closed circles.

Key rule: Whatever you do to isolate the middle variable, you must do to all three parts. This includes any flip rule if you divide by a negative — all three signs flip.
Quick check: solve $2 < 3x - 1 < 8$.
What to write in your book
  • Double inequality: apply each step to all three parts (left, middle, right).
  • The result isolates the variable in the middle: $a \leq x \leq b$.
  • Draw a segment between the two boundary values using the appropriate circle types.
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Graphing compound inequalities
core concept

A compound inequality $-4 < x \leq 2$ graphs as a segment on the number line: open circle at $-4$ (strict, not included), closed circle at $2$ (non-strict, included), shaded between them.

The shaded region represents all values that satisfy both conditions simultaneously.

Common error: Using the same type of circle at both endpoints when the inequality has different symbols at each end. Check each endpoint separately.
Which is NOT a valid compound inequality?
What to write in your book
  • Compound inequality graph = segment between two endpoints (not an arrow).
  • Each endpoint gets its own circle type: open ($<$, $>$) or closed ($\leq$, $\geq$).
  • The lower boundary must be smaller than the upper boundary for the solution set to exist.
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Translating real-world ranges
core concept

Many real-world situations describe a safe or acceptable range. Translate keywords: "between 6.5 and 8.5" means $6.5 \leq x \leq 8.5$ (if both endpoints are included). Always check whether the boundary values are included.

Example: "Water pH is safe between 6.5 and 8.5 inclusive" → $6.5 \leq \text{pH} \leq 8.5$.

Fill the blank: in the compound inequality $3 < x < 7$, $x$ must be greater than _______ and less than _______.
What to write in your book
  • "Between a and b inclusive" → $a \leq x \leq b$ (closed circles at both ends).
  • "Strictly between a and b" → $a < x < b$ (open circles at both ends).
  • Always define your variable before writing the compound inequality.
PROBLEM 1 · SOLVE A DOUBLE INEQUALITY

Solve $-1 \leq 2x + 3 \leq 9$.

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Subtract 3 from all three parts: $-1 - 3 \leq 2x + 3 - 3 \leq 9 - 3 \Rightarrow -4 \leq 2x \leq 6$
Apply the operation to every part simultaneously.
PROBLEM 2 · GRAPH A COMPOUND INEQUALITY

Graph $-4 < x \leq 2$ on a number line.

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Left endpoint: $x > -4$ (strict) → open circle at $-4$. Right endpoint: $x \leq 2$ (non-strict) → closed circle at $2$.
Each endpoint gets its own circle type.
PROBLEM 3 · REAL-WORLD TRANSLATION

Pool water is safe when the pH is between 6.5 and 8.5 (inclusive). Write and graph the compound inequality.

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Let $p$ = pH level. "Between 6.5 and 8.5 inclusive" → both boundaries included → closed circles.
The word "inclusive" tells us both endpoints are part of the solution set.
What to write in your book
  • Compound AND: solve all three parts together, graph a bounded segment.
  • Real-world: define variable, identify lower and upper bounds, check inclusive/exclusive.
  • Verify with at least one interior value and both boundary values.
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Quick-fire practice
  1. Solve $0 \leq 3x - 6 < 12$ and graph the solution.
  2. Write the compound inequality for: closed circle at $-2$, shaded segment, open circle at $4$.
  3. A school corridor temperature must be between 18°C and 26°C inclusive. Write the inequality.
  4. Is $x = 4$ in the solution set of $-4 < x \leq 2$? Explain.
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Revisit the swimming pool

The safe temperature range above 5°C AND below 35°C is written as $5 < T < 35$ — an open-circle compound inequality because the boundary values themselves are not "safe".

Earlier you guessed what this might look like. Now explain in full: how does the compound inequality $5 < T < 35$ capture both the minimum and maximum temperature in a single statement?

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Multiple choice
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Pick your answer, then rate your confidence.

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Short answer
ApplyBand 44 marks

Q1. Solve $-3 \leq 2x + 1 \leq 11$ and draw the solution on a number line. (4 marks)

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ApplyBand 33 marks

Q2. A fridge must keep food between 1°C and 5°C inclusive. Write the compound inequality, state the boundary values, and explain whether they are included. (3 marks)

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UnderstandBand 32 marks

Q3. Explain why $5 < x < 2$ has no solution. (2 marks)

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📖 Comprehensive answers (click to reveal)

Practice: 1. $2 \leq x < 6$, closed at 2, open at 6. 2. $-2 \leq x < 4$. 3. $18 \leq T \leq 26$. 4. No — $4 > 2$ so $x = 4$ is not in $(-4, 2]$.

Q1 (4 marks): $-3-1 \leq 2x \leq 11-1 \Rightarrow -4 \leq 2x \leq 10$ [1]. Divide by 2: $-2 \leq x \leq 5$ [1]. Closed circle at $-2$, segment, closed circle at $5$ [1]. Check: $x=0$: $-3\leq1\leq11$ ✓ [1].

Q2 (3 marks): $1 \leq T \leq 5$ [1]. Boundary values 1°C and 5°C [1]. Both included (closed circles — "inclusive") [1].

Q3 (2 marks): The left bound $5$ is greater than the right bound $2$ [1], so no value can simultaneously satisfy $x > 5$ and $x < 2$ [1].

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Boss battle · Compound Sort
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Solve compound inequalities and match them to their graphs. Beat the boss to bank a tier.

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Science Jump · platform challenge

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