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hscscience Maths Std · Y11
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Module 2 · L9 of 22 ~55 min MS-M1 ⚡ +95 XP available

Volume of Prisms and Cylinders

Volume = cross-sectional area × length. Identify the uniform cross-section first — everything else follows. Unit conversions between cm³, m³, and litres are critical for practical problems.

Today's hook — A swimming pool is 25 m long, 10 m wide, and slopes from 1.2 m to 2.4 m deep. How many litres of water does it hold? Which shape would you use to model it — and why?
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Worksheets

Practise this lesson

Three printable worksheets that build from foundations to mastery — or build your own from any module’s questions.

01
Recall — your gut answer first
+5 XP warm-up

A swimming pool is 25 m long, 10 m wide, and has a depth that slopes from 1.2 m at the shallow end to 2.4 m at the deep end. How would you estimate how many litres of water it holds? What shape would you use, and why?

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02
The core rule and conversion facts
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Every prism and cylinder obeys one rule: volume equals the cross-sectional area multiplied by the perpendicular length. Unit conversions link the result to real-world capacities.

$V = Ah$ — where $A$ is the area of the uniform cross-section and $h$ is the perpendicular length. The cross-section is the shape you see when you slice perpendicular to the length.

Unit conversions: $1\text{ m}^3 = 1000\text{ L} = 1\text{ kL}$; $1\text{ L} = 1000\text{ cm}^3$; $1\text{ cm}^3 = 1\text{ mL}$.

V = Ah — THE CROSS-SECTION RULE A h A V = A×h VOLUME ↔ CAPACITY 1 m³ = 1000 L = 1 kL 1 L = 1000 cm³ 1 cm³ = 1 mL
$V = Ah$ — same cross-section from end to end
Rectangular prism
Cross-section is a rectangle. $A = \ell w$, so $V = \ell wh$.
Triangular prism
Cross-section is a triangle. $A = \tfrac{1}{2}bh_\triangle$, then multiply by length $\ell$.
Cylinder
Cross-section is a circle. $A = \pi r^2$, so $V = \pi r^2 h$.
03
What you'll master
Know

Key facts

  • $V = Ah$ applies to any prism or cylinder
  • The cross-section is the shape perpendicular to the length
  • Unit conversions: $1\text{ m}^3 = 1000\text{ L}$, $1\text{ L} = 1000\text{ cm}^3$
  • Composite volumes are found by addition or subtraction
Understand

Concepts

  • Why identifying the cross-section first simplifies every volume problem
  • How a trapezoidal prism models real-world sloped containers
  • Why unit consistency matters before substituting values
Can do

Skills

  • Calculate volume of rectangular prisms, triangular prisms, cylinders
  • Find volume of composite prisms by addition/subtraction
  • Convert between cm³, m³, and litres
  • Solve capacity/tank/pipe problems
04
Key terms
VolumeThe amount of three-dimensional space a solid occupies; measured in cubic units (mm³, cm³, m³).
PrismA solid with two identical parallel faces (the cross-sections) joined by rectangular faces.
Cross-sectionThe shape obtained by cutting a solid with a plane perpendicular to its length — must be uniform (constant) along a prism.
CapacityThe volume of liquid a container can hold; typically measured in litres (L) or kilolitres (kL).
05
The universal rule: Volume = Area × Height
core concept

Every prism — regardless of its cross-sectional shape — has volume equal to the cross-sectional area multiplied by the perpendicular length.

The key is correctly identifying the cross-section. Ask: "If I sliced this solid perpendicular to its longest dimension, what shape would I see?" That area is $A$.

  • Rectangular prism: cross-section is a rectangle → $A = \ell w$, so $V = \ell wh$
  • Triangular prism: cross-section is a triangle → $A = \frac{1}{2}bh_{\triangle}$, then multiply by length $\ell$
  • Trapezoidal prism: cross-section is a trapezium → $A = \frac{1}{2}(a+b)h$, then multiply by length
  • Cylinder: cross-section is a circle → $A = \pi r^2$, then multiply by height
A = ½bh b h L V = A × L = ½bh × L
The orange face is the cross-section — find its area first, then multiply by L
Key insight: Label your cross-section dimensions separately from the prism length. A "height" can refer to two different things in the same problem.
What to write in your book
  • The universal rule: $V = Ah$ — area of cross-section × perpendicular length. Works for every prism and cylinder.
  • Identify the cross-section first: slice perpendicular to the length and ask "what shape do I see?"
  • Cylinder: $V = \pi r^2 h$ (circular cross-section). If given diameter, find $r = d \div 2$ first.
  • Unit conversions: $1\text{ m}^3 = 1000\text{ L} = 1\text{ kL}$; $1\text{ L} = 1000\text{ cm}^3$; $1\text{ cm}^3 = 1\text{ mL}$.

Quick check: A triangular prism has cross-sectional base 6 cm, cross-sectional height 4 cm, and length 15 cm. Which expression gives its volume?

PROBLEM 1 · RECTANGULAR PRISM

A fish tank is 80 cm long, 40 cm wide, and 35 cm deep. Find its volume in cm³ and capacity in litres.

1
$V = \ell w h = 80 \times 40 \times 35$
Rectangular prism formula; identify all three dimensions.
PROBLEM 2 · TRIANGULAR PRISM

A triangular prism has a right-triangular cross-section with base 6 cm and perpendicular height 4 cm. The prism is 15 cm long. Find its volume.

1
$A = \dfrac{1}{2} \times 6 \times 4 = 12 \text{ cm}^2$
Find the cross-sectional area first — a triangle with base 6, height 4.
PROBLEM 3 · CYLINDER

A cylindrical water tank has diameter 1.4 m and height 2.2 m. Find its volume in m³ and capacity in kilolitres (kL).

1
$r = 1.4 \div 2 = 0.7 \text{ m}$
Always find radius from diameter first.
What to write in your book
  • Trapezoidal prism: $A = \tfrac{1}{2}(a+b)h$, then $V = A \times \text{length}$. Used for sloped containers like swimming pools.
  • Cylinder: $V = \pi r^2 h$. If given diameter, $r = d \div 2$ first.
  • Composite solids: split into recognisable shapes, find each volume, then add or subtract.
  • Hollow cylinders (pipes): $V = \pi(R^2 - r^2)h$ where $R$ = outer radius, $r$ = inner radius.

True or false: $1\text{ m}^3$ is equal to 1000 litres.

V=Ah Cross-Section Rule and Volume Conversions V = Ah — THE CROSS-SECTION RULE A h A V = A × h same cross-section throughout length VOLUME ↔ CAPACITY 1 m³ = 1000 L = 1 kL cubic metres → kilolitres 1 L = 1000 cm³ litres → cubic centimetres 1 cm³ = 1 mL cubic centimetre = millilitre
Trap 01
Using the wrong dimension as h
In a triangular prism, the cross-section has its own height $h_\triangle$, and the prism also has a length $\ell$. These are different — always label which is which before substituting.
Trap 02
Mixing units before substituting
Always check your units are consistent before substituting into formulas. Converting to consistent units (e.g. all in cm or all in m) is a common source of errors in assessment tasks.
Trap 03
Forgetting to convert volume to capacity
If the question asks for litres or kL, you must convert your cubic answer. $1\text{ m}^3 = 1000\text{ L}$; $1\text{ L} = 1000\text{ cm}^3$. Forgetting to convert loses the final mark.
What to write in your book
  • Always label which dimension is the cross-section height and which is the prism length.
  • Check unit consistency before substituting — don't mix cm and m in the same calculation.
  • $1\text{ m}^3 = 1000\text{ L}$: multiply by 1000 to go from m³ to L; divide to go from L to m³.
  • Composite volumes: identify each component shape, calculate separately, then add or subtract.

Type the answer: A swimming pool (trapezoidal cross-section) has parallel sides 1.0 m and 2.5 m, horizontal length 20 m, and width 8 m. What is the volume in m³?

1

A brick is 22 cm × 11 cm × 7.5 cm. Find its volume in cm³.

2

A rectangular storage container is 2.4 m long, 1.2 m wide, and 1.5 m high. Find its volume in m³.

3

A can has radius 4 cm and height 12 cm. Find its volume in cm³ (to 2 d.p.).

4

A cylindrical fuel drum has diameter 0.6 m and height 1.0 m. Find its capacity in litres (nearest litre).

5

A pipe has outer radius 8 cm, inner radius 6 cm, and length 50 cm. Find the volume of metal in the pipe in cm³ (leave in terms of $\pi$).

Fill the gap: To convert a volume in m³ to litres, by . To convert cm³ to mL, the value stays the .

10
Revisit your thinking

Earlier you predicted how to model the pool and estimate its volume. Let's confirm:

The pool's cross-section (viewed from the side) is a trapezium with parallel sides 1.2 m and 2.4 m, and horizontal length 25 m. The width is 10 m.

$A = \tfrac{1}{2}(1.2 + 2.4)(25) = \tfrac{1}{2}(3.6)(25) = 45\text{ m}^2$

$V = 45 \times 10 = 450\text{ m}^3 = \mathbf{450\,000\text{ L}}$

The trapezoidal prism model works because the depth changes uniformly — the cross-section is a consistent trapezium from side to side.

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01
Multiple choice
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Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

02
Short answer
ApplyBand 43 marks

Q1. A concrete retaining wall has a trapezoidal cross-section with parallel sides of 0.5 m and 0.8 m, a perpendicular height of 1.2 m, and a length of 15 m. (a) Find the area of the trapezoidal cross-section. (b) Find the volume of concrete required in m³. (c) Concrete costs $220 per m³. Find the cost of the concrete. (3 marks)

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ApplyBand 43 marks

Q2. A cylindrical rainwater tank has an internal diameter of 2.4 m and a height of 3.0 m. (a) Find the volume of the tank in m³ (correct to 2 decimal places). (b) Find the capacity in kilolitres. (3 marks)

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AnalyseBand 54 marks

Q3. A garden bed has a composite cross-section consisting of a rectangle (1.2 m wide, 0.4 m deep) sitting on top of a trapezium (parallel sides 1.2 m and 2.0 m, height 0.3 m). The garden bed is 8 m long. (a) Find the area of the trapezoidal portion. (b) Find the total cross-sectional area. (c) Find the total volume of soil required in m³. (d) Soil is sold in bags of 0.1 m³. How many bags are needed? (4 marks)

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📖 Comprehensive answers (click to reveal)

Drill 1: $22 \times 11 \times 7.5 = 1815\text{ cm}^3$  ·  2: $2.4 \times 1.2 \times 1.5 = 4.32\text{ m}^3$  ·  3: $\pi(4)^2(12) = 192\pi \approx 603.19\text{ cm}^3$  ·  4: $r = 0.3$; $V = \pi(0.09)(1.0) \approx 0.2827\text{ m}^3 = 283\text{ L}$  ·  5: $\pi(64-36)(50) = 1400\pi\text{ cm}^3$

Q1 (3 marks): (a) $A = \frac{1}{2}(0.5+0.8)(1.2) = \frac{1}{2}(1.3)(1.2) = 0.78\text{ m}^2$ [1]. (b) $V = 0.78 \times 15 = 11.7\text{ m}^3$ [1]. (c) $\text{Cost} = 11.7 \times 220 = \$2574$ [1].

Q2 (3 marks): (a) $r = 1.2$; $V = \pi(1.44)(3) = 4.32\pi \approx 13.57\text{ m}^3$ [2]. (b) $13.57\text{ kL}$ (since $1\text{ m}^3 = 1\text{ kL}$) [1].

Q3 (4 marks): (a) $A_{\text{trap}} = \frac{1}{2}(1.2+2.0)(0.3) = 0.48\text{ m}^2$ [1]. (b) $A_{\text{rect}} = 1.2 \times 0.4 = 0.48$; Total $= 0.96\text{ m}^2$ [1]. (c) $V = 0.96 \times 8 = 7.68\text{ m}^3$ [1]. (d) $7.68 \div 0.1 = 76.8 \to 77\text{ bags}$ [1].

01
Boss battle · Volume Showdown
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Five timed questions on prism and cylinder volumes. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

⚔ Enter the arena
02
Science Jump · platform challenge

Climb platforms by answering volume of prisms and cylinders questions. Pool: lessons 1–9.

Mark lesson as complete

Tick when you've finished the practice and review.