Skip to content
M
hscscience Maths Adv · Y11
0/100daily goal
0
0
0 due
0
L1 · 0 XP
KJ
Your weak spots
Insights load after your first practice round.
Module 2 · L2 of 15 ~35 min ⚡ +95 XP available

Arc Length & Area of Sectors

When a pizza chef cuts a slice, they create a sector — a wedge-shaped piece of a circle. But how much crust is on the curved edge? And what is the area of the topping? In this lesson you will learn the elegant formulas that answer both questions, and discover why radians make them beautifully simple.

Today's hook — A pizza has radius 20 cm. A slice is cut with an angle of 45° at the centre. Without using any formulas, estimate the arc length of the crust on this slice.
0/5QUESTS
Worksheets

Practise this lesson

Three printable worksheets that build from foundations to mastery — or build your own from any module’s questions.

01
Recall — your gut answer first
+5 XP warm-up

A pizza has radius 20 cm. A slice is cut with an angle of $45^\circ$ at the centre. Without using any formulas — estimate the arc length of the crust on this slice. Then consider how you might calculate it exactly if you knew a full circle's circumference is $2\pi r$.

auto-saved
02
The two moves
+5 XP to read

There are only two formulas in this entire lesson — and they both emerge from one idea. When $\theta$ is measured in radians, the formulas for arc length and sector area collapse into their simplest possible forms.

Every sector problem in this module travels along one of two roads: arc length uses $l = r\theta$, and sector area uses $A = \frac{1}{2}r^2\theta$. Both require $\theta$ in radians. Convert first, calculate second.

θ l r l = rθ A = ½r²θ
$l = r\theta$
$A = \tfrac{1}{2}r^2\theta$
Arc length
$l = r\theta$ when $\theta$ is in radians. This follows directly from the definition of a radian: $\theta = \frac{l}{r}$.
Sector area
$A = \frac{1}{2}r^2\theta$ when $\theta$ is in radians. Derived from taking the fraction $\frac{\theta}{2\pi}$ of the full circle area.
Convert first
If $\theta$ is given in degrees, convert to radians using $\theta_{\text{rad}} = \theta_{\text{deg}} \times \frac{\pi}{180}$ before substituting.
03
What you'll master
Know

Key facts

  • The formulas for arc length and sector area in radians
  • How to convert degree angles to radians before using the formulas
  • The relationship between arc length, radius, and angle
Understand

Concepts

  • Why the radian formulas are simpler than the degree formulas
  • How sector area relates to the proportion of a full circle
  • The connection between arc length and the definition of a radian
Can do

Skills

  • Calculate arc length given radius and central angle
  • Calculate sector area given radius and central angle
  • Solve for unknown radius or angle given arc length or area
  • Apply arc length and sector area to real-world problems
04
Key terms
Arc lengthThe distance along the curved part of a sector: $l = r\theta$ (radians).
Sector areaThe area of a "pizza slice" region: $A = \frac{1}{2}r^2\theta$ (radians).
Central angleThe angle subtended at the centre of the circle by the sector.
Minor arcThe shorter of the two arcs between two points on a circle.
Major arcThe longer of the two arcs between two points on a circle.
Chord lengthThe straight-line distance between the endpoints of an arc: $2r\sin\frac{\theta}{2}$.
05
Arc length and sector area — what's actually going on
core concept

When an angle $\theta$ is measured in radians, the arc length $l$ swept out by that angle in a circle of radius $r$ is given by:

$$l = r\theta$$

This formula is elegant because it follows directly from the definition of a radian: $\theta = \frac{l}{r}$. In degrees, the equivalent formula is $l = 2\pi r \times \frac{\theta}{360^\circ}$ — messier, and easy to misapply.

A sector is the "pizza slice" region bounded by two radii and an arc. Its area comes from taking the same fraction of the full circle's area ($\pi r^2$) as the angle is of a full revolution ($2\pi$ radians). When you simplify $\pi r^2 \times \frac{\theta}{2\pi}$, the $\pi$ cancels and you get:

$$A = \frac{1}{2}r^2\theta$$
centre r arc length l θ Formulas (radians) l = rθ A = ½r²θ Formulas (degrees) l = (θ/360) × 2πr A = (θ/360) × πr²

Circle sector with radius r, central angle θ, and arc length l — radian formulas are cleaner because radians are the natural unit.

If you know the arc length or sector area, you can rearrange to find the missing quantity:

  • Find angle from arc length: $\theta = \frac{l}{r}$
  • Find radius from arc length: $r = \frac{l}{\theta}$
  • Find angle from sector area: $\theta = \frac{2A}{r^2}$
  • Find radius from sector area: $r = \sqrt{\frac{2A}{\theta}}$
Why satellite dishes are parabolic (and how arc length matters). Satellite dishes collect signals and focus them to a single point using a parabolic shape. But the manufacturing process often starts with a flat sheet of metal that is cut into sectors and bent into a cone, then flattened into a parabola. Engineers must calculate the arc length of each sector precisely so the metal pieces fit together perfectly. An error of even a few millimetres in arc length can defocus the signal and reduce reception quality.

Arc length: $l = r\theta$ where $\theta$ is in radians — rearranges to $\theta = \frac{l}{r}$ or $r = \frac{l}{\theta}$; Sector area: $A = \frac{1}{2}r^2\theta$ — comes from $\pi r^2 \times \frac{\theta}{2\pi}$, the $\pi$ cancels

Pause — copy the arc length formula $l = r\theta$ and the sector area formula $A = \frac{1}{2}r^2\theta$ (with the $\pi$-cancellation derivation) into your book.

Complete: Arc length $l = $ where $\theta$ must be in .
PROBLEM 1 · ARC LENGTH

Find the arc length of a sector with radius 8 cm and central angle $\frac{\pi}{4}$ radians.

1
$l = r\theta$
Identify the arc length formula.
PROBLEM 2 · SECTOR AREA

A sector has radius 10 cm and central angle $60^\circ$. Find its area.

1
$60^\circ = 60 \times \frac{\pi}{180} = \frac{\pi}{3}$ rad
Convert degrees to radians first.
PROBLEM 3 · FINDING THE RADIUS

A sector has area $27\pi$ cm$^2$ and central angle $\frac{\pi}{2}$ radians. Find the radius.

1
$A = \frac{1}{2}r^2\theta$
Start with the area formula.
Quick check: A sector has $r = 6$ cm and $\theta = \frac{\pi}{3}$ rad. What is the arc length?
Trap 01
Using degrees directly in the radian formulas
The formulas $l = r\theta$ and $A = \frac{1}{2}r^2\theta$ ONLY work when $\theta$ is in radians. If you substitute $60$ (degrees) directly, your answer will be wrong by a factor of $\frac{\pi}{180}$. Always convert first.
Trap 02
Confusing arc length with chord length
The arc length is the curved distance along the circumference. The chord length is the straight-line distance between the two endpoints of the arc. These are different quantities with different formulas.
Trap 03
Forgetting the half in sector area
Some students write $A = r^2\theta$ instead of $A = \frac{1}{2}r^2\theta$, giving answers that are double the correct value. The $\frac{1}{2}$ appears because a sector is essentially a "curved triangle."
True or false: The formula $A = \frac{1}{2}r^2\theta$ gives the correct sector area when $\theta$ is in degrees.
Work mode · how are you completing this lesson?
1

$r = 6$ cm, $\theta = \frac{\pi}{3}$ rad. Find $l$.

2

$r = 10$ cm, $\theta = \frac{3\pi}{4}$ rad. Find $A$.

3

$r = 12$ cm, $\theta = 45^\circ$. Find $l$ and $A$.

4

$l = 8\pi$ cm, $r = 4$ cm. Find $\theta$ in radians.

5

$A = 50\pi$ cm$^2$, $\theta = \frac{\pi}{2}$ rad. Find $r$.

Match each formula to its purpose: Which formula finds the angle if you know arc length and radius?
12
Revisit your thinking

Earlier you were asked: A pizza has radius 20 cm and a slice angle of $45^\circ$. Estimate the arc length of the crust.

A full circle has circumference $2\pi r = 40\pi \approx 125.7$ cm. The slice is $\frac{45}{360} = \frac{1}{8}$ of the full pizza. So the arc length is $\frac{1}{8}$ of the circumference: $\frac{40\pi}{8} = 5\pi \approx 15.7$ cm. In radians, $45^\circ = \frac{\pi}{4}$, so $l = r\theta = 20 \times \frac{\pi}{4} = 5\pi$ cm. The radian formula gives the same answer instantly without needing to calculate the full circumference first.

auto-saved
In 10 words or fewer, explain why $A = \frac{1}{2}r^2\theta$ has a $\frac{1}{2}$ in it.
01
Multiple choice
+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

02
Short answer
ApplyBand 4

Q1. A sector has radius 9 cm and central angle $\frac{2\pi}{3}$ radians. (a) Find the exact arc length. (b) Find the exact area of the sector. 3 MARKS

auto-saved
ApplyBand 4

Q2. A piece of wire 40 cm long is bent to form the perimeter of a sector. If the radius of the sector is 12 cm, find the angle of the sector in radians. 3 MARKS

auto-saved
AnalyseBand 5

Q3. Two sectors have the same area. Sector A has radius 6 cm and angle $\frac{\pi}{2}$ radians. Sector B has radius 4 cm. Find the angle of Sector B in radians. Show all working. 3 MARKS

auto-saved
📖 Comprehensive answers (click to reveal)

Drill 1: $l = 6 \times \frac{\pi}{3} = 2\pi$ cm

Drill 2: $A = \frac{1}{2}(100) \times \frac{3\pi}{4} = \frac{75\pi}{2}$ cm$^2$

Drill 3: $45^\circ = \frac{\pi}{4}$ rad. $l = 12 \times \frac{\pi}{4} = 3\pi$ cm. $A = \frac{1}{2}(144) \times \frac{\pi}{4} = 18\pi$ cm$^2$.

Drill 4: $\theta = \frac{8\pi}{4} = 2\pi$ rad (a full circle)

Drill 5: $50\pi = \frac{1}{2}r^2 \times \frac{\pi}{2} \Rightarrow r^2 = 200 \Rightarrow r = 10\sqrt{2}$ cm

Q1 (3 marks): (a) $l = 9 \times \frac{2\pi}{3} = 6\pi$ cm [1.5]. (b) $A = \frac{1}{2}(81) \times \frac{2\pi}{3} = 27\pi$ cm$^2$ [1.5].

Q2 (3 marks): Perimeter $= 2r + l = 40$ [1]. So $l = 40 - 24 = 16$ cm [0.5]. Then $\theta = \frac{l}{r} = \frac{16}{12} = \frac{4}{3}$ rad [1.5].

Q3 (3 marks): Area of A $= \frac{1}{2}(36) \times \frac{\pi}{2} = 9\pi$ cm$^2$ [1]. Set equal to area of B: $9\pi = \frac{1}{2}(16) \times \theta_B$ [1]. So $\theta_B = \frac{9\pi}{8}$ rad [1].

01
Boss battle · The Slicer
earn bronze · silver · gold

Five timed questions. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

⚔ Enter the arena
02
Science Jump · platform challenge

Climb platforms by answering arc length and sector area questions. Lighter alternative to the boss.

Mark lesson as complete

Tick when you've finished the practice and review.

🎓
Want help with Arc Length and Area of Sectors?

Work through this topic 1-on-1 with an experienced HSC tutor.

Book a free session →