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Module 4 · L7 of 15 ~35 min ⚡ +95 XP available

Laws of Logarithms

A slide rule converts multiplication into addition. That's exactly what logarithms do — the product law turns $\log(xy)$ into $\log x + \log y$, the quotient law turns division into subtraction, and the power law brings exponents down to the front. By the end of this lesson you'll manipulate logarithmic expressions with the same confidence as your index laws.

Today's hook — Astronomers measure star brightness on a logarithmic scale. When they say one star is "2 magnitudes brighter" than another, they mean it's $10^{0.8} \approx 6.3$ times brighter — not $2$ times. Without the log laws, every comparison would require computing large exponents. With them, it collapses to arithmetic.
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Worksheets

Practise this lesson

Three printable worksheets that build from foundations to mastery — or build your own from any module’s questions.

01
Recall — your gut answer first
+5 XP warm-up

Without a calculator: is $\log_2 8 + \log_2 4$ bigger, smaller, or equal to $\log_2 32$? Justify your gut answer in one line.

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02
The two moves
+5 XP to read

There are only three log laws in this whole lesson, and each one mirrors a law of exponents you already know. Lock them in and every simplification problem becomes mechanical.

The key insight: multiplication becomes addition, division becomes subtraction, and powers move out front. Each law is a direct consequence of the corresponding index law.

PRODUCT log(xy) = log x + log y QUOTIENT log(x/y) = log x − log y POWER log(xⁿ) = n · log x
$$\log_a(x^n) = n\log_a x$$
Match the operation
Multiplication becomes addition, division becomes subtraction, powers become multiplication.
Power law is key
The power law is the most frequently used: it brings exponents down in front of the log.
Sums inside don't expand
$\log_a(x + y)$ cannot be simplified. Log laws only apply to products, quotients, and powers.
03
What you'll master
Know

Key facts

  • Product law: $\log_a(xy) = \log_a x + \log_a y$
  • Quotient law: $\log_a\!\left(\frac{x}{y}\right) = \log_a x - \log_a y$
  • Power law: $\log_a(x^n) = n\log_a x$
Understand

Concepts

  • Why each log law mirrors an index law
  • The difference between expanding and condensing expressions
  • Why $\log_a(x+y)$ has no further simplification
Can do

Skills

  • Apply product, quotient, and power laws to simplify expressions
  • Expand a single log into sums and differences
  • Condense sums and differences into a single logarithm
04
Key terms
Product law$\log_a(xy) = \log_a x + \log_a y$ — log of a product equals sum of logs.
Quotient law$\log_a\!\left(\tfrac{x}{y}\right) = \log_a x - \log_a y$ — log of a quotient equals difference of logs.
Power law$\log_a(x^n) = n\log_a x$ — the exponent moves to the front as a coefficient.
ExpandWrite a single log as a sum/difference of simpler logs using the laws.
CondenseWrite a sum/difference of logs as a single logarithm.
Domain restrictionLog laws hold only for $x, y > 0$ and base $a > 0$, $a \neq 1$.
05
Why do the log laws work?
core concept

The laws of logarithms mirror the laws of exponents because logarithms are exponents. If $m = \log_a x$ and $n = \log_a y$, then $x = a^m$ and $y = a^n$. Multiplying gives $xy = a^m \cdot a^n = a^{m+n}$, so $\log_a(xy) = m + n = \log_a x + \log_a y$. The same reasoning yields the quotient and power laws.

$$\begin{aligned} \log_a(xy) &= \log_a x + \log_a y \\ \log_a\!\left(\frac{x}{y}\right) &= \log_a x - \log_a y \\ \log_a(x^n) &= n\log_a x \end{aligned}$$

These hold for $x, y > 0$ and $a > 0$, $a \neq 1$.

These laws are essential. They allow us to expand, condense, and simplify logarithmic expressions — skills required for solving exponential equations, differentiating logarithmic functions, and evaluating logarithms with any base. Every algebraic manipulation of logs this year relies on exactly these three rules.

Product law: $\log_a(xy) = \log_a x + \log_a y$ (multiplication → addition); Quotient law: $\log_a\!\left(\frac{x}{y}\right) = \log_a x - \log_a y$ (division → subtraction)

Pause — copy the product law ($\log_a(xy) = \log_a x + \log_a y$) and quotient law ($\log_a(x/y) = \log_a x - \log_a y$) with the mnemonic (multiplication becomes addition, division becomes subtraction) into your book.

Did you get this? True or false: the product law states that $\log_a x \cdot \log_a y = \log_a(xy)$.

PROBLEM 1 · PRODUCT LAW

Simplify $\log_2 3 + \log_2 4$.

1
$\log_2 3 + \log_2 4 = \log_2(3 \times 4)$
Product law: sum of logs = log of product.
PROBLEM 2 · QUOTIENT LAW

Simplify $\log_3 54 - \log_3 2$.

1
$\log_3 54 - \log_3 2 = \log_3\!\left(\dfrac{54}{2}\right)$
Quotient law: difference of logs = log of quotient.
PROBLEM 3 · ALL THREE LAWS

Express $\log_a\!\left(\dfrac{x^2\sqrt{y}}{z^3}\right)$ in terms of $\log_a x$, $\log_a y$, and $\log_a z$.

1
$= \log_a(x^2\sqrt{y}) - \log_a(z^3)$
Quotient law first.

Quick check: Which expression equals $\log_5 2 + \log_5 3$?

Trap 01
Applying log laws to sums inside the argument
$\log_a(x + y)$ cannot be expanded using the product or quotient laws. Log laws only apply to products, quotients, and powers inside the argument. $\log_a(x + y)$ must stay as is.
Trap 02
Confusing $\log_a(x^n)$ with $(\log_a x)^n$
$(\log_a x)^n \neq n\log_a x$. The power law applies when the entire argument is raised to a power — not when the logarithm itself is raised to a power.
Trap 03
Writing $\log_a x \cdot \log_a y = \log_a(xy)$
A product of two logarithms is not the same as a log of a product. $\log_a x \cdot \log_a y$ has no simple closed form. Only $\log_a x + \log_a y = \log_a(xy)$ is valid.

Fill in the blank: $3\log_a x - \log_a y + \tfrac{1}{2}\log_a z$ condensed to a single logarithm is $\log_a\!\left(\rule{60px}{0.5px}\right)$.

Type the argument, e.g. x^3 sqrt(z) / y or equivalent.

Work mode · how are you completing this lesson?
1

Simplify $\log_5 2 + \log_5 3$.

2

Simplify $\log_2 24 - \log_2 3$.

3

Express $\log_a(x^3 y^2)$ in expanded form.

4

Simplify $2\log_a x + 3\log_a y - \log_a z$.

5

Evaluate $\log_2 8 + \log_2 4 - \log_2 2$.

Two truths, one lie: Two of these statements are correct. Which one is the lie?

Odd one out: Three of these can be simplified using a single log law. Which one cannot?

12
Revisit your thinking

Earlier you compared $\log_2 8 + \log_2 4$ to $\log_2 32$. They are equal — because the product law gives $\log_2 8 + \log_2 4 = \log_2(8 \times 4) = \log_2 32$. The three log laws (product, quotient, power) are direct consequences of the corresponding exponent laws and they convert multiplication problems into addition problems.

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01
Multiple choice
+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

02
Short answer
ApplyBand 42 marks

Q1. Simplify $\log_3 6 + \log_3 \dfrac{3}{2}$. Show working. (2 marks)

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ApplyBand 43 marks

Q2. Express $\log_a\!\left(\dfrac{x^2 y}{\sqrt{z}}\right)$ in terms of $\log_a x$, $\log_a y$, and $\log_a z$. (3 marks)

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ApplyBand 43 marks

Q3. Write $3\log_a x - \log_a y + \dfrac{1}{2}\log_a z$ as a single logarithm. (3 marks)

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Comprehensive answers (click to reveal)

Drill 1: $\log_5 6$ · 2: $\log_2 8 = 3$ · 3: $3\log_a x + 2\log_a y$ · 4: $\log_a\!\left(\dfrac{x^2 y^3}{z}\right)$ · 5: $\log_2 16 = 4$

Q1 (2 marks): $\log_3\!\left(6 \times \tfrac{3}{2}\right)$ [0.5] $= \log_3 9 = \log_3(3^2) = 2$ [1.5].

Q2 (3 marks): $= \log_a(x^2 y) - \log_a(z^{1/2})$ [0.5] $= \log_a(x^2) + \log_a y - \log_a(z^{1/2})$ [0.5] $= 2\log_a x + \log_a y - \tfrac{1}{2}\log_a z$ [2].

Q3 (3 marks): $= \log_a(x^3) - \log_a y + \log_a(z^{1/2})$ [1] $= \log_a\!\left(\dfrac{x^3\sqrt{z}}{y}\right)$ [2].

01
Boss battle · The Logarithm Lord
earn bronze · silver · gold

Five timed questions. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

Enter the arena
02
Science Jump · platform challenge

Climb platforms by answering log law questions. Lighter alternative to the boss.

Mark lesson as complete

Tick when you've finished the practice and review.

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