The Number $e$ and Natural Exponentials
You've met $\pi$ — the ratio that circles chose. Now meet $e \approx 2.71828$, the number calculus itself chose. It's the unique base where the exponential function is its own derivative. By the end of this lesson you'll know why every growth and decay model in science defaults to it.
Practise this lesson
Three printable worksheets that build from foundations to mastery — or build your own from any module’s questions.
You invest $\$1$ at $100\%$ interest. As you compound more often — yearly, monthly, daily, every second — the final amount climbs. Without using a formula: does it grow without limit, or does it approach a ceiling? Pick a guess: under 2, between 2–3, or above 3?
Everything in this lesson spins out of two core skills. Lock these in and the rest is just applying them to new contexts.
Key facts
- The definition $e = \lim_{n\to\infty}(1+\frac{1}{n})^n$
- That $e \approx 2.71828$ is irrational
- The continuous compounding formula $A = Pe^{rt}$
Concepts
- Why $e^x$ is its own derivative
- How $y = e^x$ and $y = e^{-x}$ relate as reflections
- The difference between $e^x$ (exponential) and $x^e$ (power function)
Skills
- Evaluate $e^x$ for any value using a calculator
- Sketch $y = e^x$, $y = e^{-x}$, and transformations
- Solve continuous compounding problems
The number $e$ is defined as the limit of $(1 + \frac{1}{n})^n$ as $n$ grows without bound. The table below shows how this converges:
As $n$ increases, $(1 + \frac{1}{n})^n$ approaches $e$ from below. It never exceeds $e$ — this is why continuously compounded interest hits a ceiling. The function $y = e^x$ is special because $\dfrac{d}{dx}(e^x) = e^x$ exactly — no scaling factor, no remainder. That's what makes it the natural base for calculus.
The graph of $y = e^x$ is an increasing exponential with asymptote $y = 0$, $y$-intercept $(0,1)$, and it passes through $(1, e) \approx (1, 2.718)$. Its mirror image $y = e^{-x}$ is a decreasing exponential, reflected in the $y$-axis.
$e = \lim_{n \to \infty}(1 + \frac{1}{n})^n \approx 2.71828$ — irrational like $\pi$; $\frac{d}{dx}(e^x) = e^x$ — the self-derivative property
Pause — copy the definition of $e$ ($\approx 2.71828$, irrational) and the self-derivative property $\frac{d}{dx}(e^x) = e^x$ — the reason $e$ is the natural base into your book.
Did you get this? True or false: $e^x$ is the only function whose derivative equals itself (up to a constant multiple).
Worked examples · 3 in a row, reveal as you go
Evaluate $e^2$ and $e^{-1}$ to 3 decimal places.
Sketch $y = e^x$ and $y = e^{-x}$ on the same axes, identifying key features.
$\$10{,}000$ is invested at $5\%$ p.a. compounded continuously. Find the value after 10 years.
Quick check: $\$5000$ is invested at $4\%$ p.a. compounded continuously for 5 years. Which expression gives the correct final amount?
Common errors · the 3 traps that cost marks
Complete the sentence: The continuous compounding formula is $A = P e^{[\,]}$, where $r$ is the annual rate as a decimal and $t$ is time in years.
Quick-fire practice · 5 problems
Evaluate $e^3$ and $e^{-2}$ to 2 decimal places.
State the exact value of $\dfrac{d}{dx}(e^x)$.
Sketch $y = e^x + 1$ showing the asymptote and $y$-intercept.
$\$5000$ is invested at $4\%$ p.a. compounded continuously. Find the value after 5 years.
Simplify $\ln(e^5)$.
Odd one out: Which of the following does NOT have $y$-intercept $(0, 1)$?
Earlier you were asked: does continuous compounding at $100\%$ grow without limit? It approaches $e \approx 2.718$ — never exceeding it. The function $e^x$ is the only exponential whose derivative equals itself, which is why it sits at the heart of growth, decay, and modelling across all of science.
Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.
Q1. Evaluate $e^{1.5}$ and $e^{-0.5}$ to 3 decimal places. (2 marks)
Q2. $\$20{,}000$ is invested at $6\%$ p.a. compounded continuously. How many years until the investment doubles? Give your answer to 1 decimal place. (3 marks)
Q3. $\$10{,}000$ is invested at $8\%$ p.a. Compare the value after 5 years for: (i) annual compounding, (ii) monthly compounding, (iii) continuous compounding. Give answers to the nearest dollar. (4 marks)
Comprehensive answers (click to reveal)
Drill 1: $e^3 \approx 20.09$; $e^{-2} \approx 0.14$ · 2: $e^x$ · 3: asymptote $y=1$, $y$-int $(0,2)$ · 4: $5000e^{0.2} \approx \$6107$ · 5: $5$
Q1 (2 marks): $e^{1.5} \approx 4.482$ [1]. $e^{-0.5} \approx 0.607$ [1].
Q2 (3 marks): $20000e^{0.06t} = 40000$ [0.5]. $e^{0.06t} = 2$ [0.5]. $0.06t = \ln 2$, so $t = \frac{\ln 2}{0.06} \approx \frac{0.693}{0.06} \approx 11.6$ years [2].
Q3 (4 marks): (i) Annual: $10000(1.08)^5 \approx \$14{,}693$ [1]. (ii) Monthly: $10000(1+\frac{0.08}{12})^{60} \approx \$14{,}890$ [1.5]. (iii) Continuous: $10000e^{0.4} \approx \$14{,}918$ [1.5].
Five timed questions. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.
Enter the arenaClimb platforms by answering natural exponential questions. Lighter alternative to the boss.
Mark lesson as complete
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