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hscscience Ext 1 · Y12
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Module 6 · L2 of 20 ~35 min ⚡ +95 XP available

Vector Notation and Representation

Vectors live in a world of symbols. You'll encounter $\vec{a}$, $\mathbf{a}$, $\underline{a}$, and $\vec{AB}$ all meaning the same thing — but only if you know the rules. This lesson fixes the notation so that the rest of Module 6 is frictionless. You'll also learn why you can freely move an arrow around a diagram without changing the vector it represents.

Today's hook — You see $\vec{AB}$ written on an exam paper. Before reading on: what are the three pieces of information this symbol carries? Write them down, then check your answer after card 05.
0/5QUESTS
01
Recall — your gut answer first
+5 XP warm-up

You see $\vec{AB}$ written on an exam paper. Without looking it up — what three pieces of information does this symbol carry? Also, how is the notation $\vec{AB}$ different from $|\vec{AB}|$?

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02
The notation system
+5 XP to read

Vectors are written in multiple ways depending on the context. You must recognise and use all of them.

The four main notations for a vector $a$:

  • Arrow notation: $\vec{a}$ (typed) or $\overrightarrow{AB}$ (from point $A$ to $B$)
  • Bold type: $\mathbf{a}$ (used in textbooks)
  • Underline: $\underline{a}$ (standard for handwriting in HSC)
  • Two-point form: $\vec{AB}$ — starts at tail $A$, ends at head $B$

The magnitude (length) is written $|\vec{a}|$, $|\mathbf{a}|$, or simply $a$ (italicised, no decoration).

A (tail) B (head) |AB| = magnitude of ⃗AB
$\vec{AB}$: from $A$ (tail) to $B$ (head)  |  $|\vec{AB}| = AB$ (magnitude)
HSC handwriting rule
In the HSC, always underline single-letter vectors when writing by hand: $\underline{a}$. Bold type ($\mathbf{a}$) is for printed text only. Examiners look for this.
Direction of $\vec{AB}$
$\vec{AB}$ travels from $A$ to $B$. The first letter is always the tail; the second is the head. $\vec{BA}$ goes in the opposite direction: $\vec{BA} = -\vec{AB}$.
Magnitude is always $\geq 0$
$|\vec{a}| \geq 0$ for all vectors. The zero vector $\vec{0}$ has magnitude 0 and is the only vector with no defined direction.
03
What you'll master
Know

Key facts

  • Four notations for vectors: $\vec{a}$, $\mathbf{a}$, $\underline{a}$, $\vec{AB}$
  • Magnitude is written $|\vec{a}|$ or $a$ (scalar, always $\geq 0$)
  • $\vec{BA} = -\vec{AB}$ (reversing points reverses direction)
  • Vectors are "free" — they can be translated without changing identity
Understand

Concepts

  • Why the same vector can appear anywhere on a diagram
  • The geometric meaning of the zero vector $\vec{0}$
  • The distinction between $\vec{AB}$ and $|\vec{AB}|$
Can do

Skills

  • Read and write vectors using all four notations correctly
  • Identify equal vectors in a geometric figure
  • State the negative of a given vector $\vec{AB}$
04
Key terms
$\vec{a}$ (arrow notation)Typed form of a single-letter vector. The arrow above indicates it is a vector, not a scalar.
$\mathbf{a}$ (bold type)Printed/textbook form of a vector. Equivalent to $\vec{a}$. Not used in handwriting.
$\underline{a}$ (underline)Handwriting convention for a vector. Required in the HSC when writing by hand.
$\vec{AB}$The vector from point $A$ (tail) to point $B$ (head). Direction: $A \to B$. Magnitude: $|\vec{AB}| = AB$.
Tail and headTail = starting point of the arrow; head = ending point (arrowhead). In $\vec{AB}$, $A$ is the tail and $B$ is the head.
Zero vector $\vec{0}$The vector with magnitude 0 and no defined direction. It is the only vector that equals its own negative.
05
The four notations in detail
core concept

You must be comfortable with all four notations used for vectors in the HSC:

$\vec{a} \;=\; \mathbf{a} \;=\; \underline{a} \quad$ (all mean the same vector)

In typed work (exams, textbooks): use $\vec{a}$ or $\mathbf{a}$.
In handwriting: use $\underline{a}$ (underline) — this is the HSC convention. The arrow or bold is impossible to reproduce clearly by hand.

The two-point form $\vec{AB}$: this notation tells you the tail ($A$) and the head ($B$). The three pieces of information in $\vec{AB}$ are:

  1. The starting point (tail): $A$
  2. The ending point (head): $B$
  3. The direction: from $A$ toward $B$ (the arrowhead points at $B$)

The magnitude of $\vec{AB}$ is $|\vec{AB}|$ or simply the length $AB$ (without arrow, without bold).

Important distinction: $\vec{AB}$ is a vector (has direction). $AB$ or $|\vec{AB}|$ is a scalar (the length of that vector, always positive). Never confuse the two in an exam.

Four notations: (1) bold $\mathbf{a}$; (2) tilde $\underset{\sim}{a}$; (3) arrow $\vec{a}$; (4) directed segment $\overrightarrow{AB}$. Equal vectors: same magnitude and direction.

Pause — copy all four HSC notations for the same vector: bold, tilde, arrow, and directed segment notation — and note which the exam typically uses into your book.

Quick check: In the vector $\vec{PQ}$, which point is the tail?

06
Geometric representation and free vectors
core concept

We just saw the four HSC vector notations: bold $\mathbf{a}$, tilde $\underset{\sim}{a}$, arrow $\vec{a}$, and directed segment $\overrightarrow{AB}$. That raises a question: geometrically, a vector is a directed line segment (an arrow), but a vector can be translated anywhere in the plane — what does it mean for two arrows to represent the same vector? This card answers it → two directed segments represent the same vector if and only if they have equal length and equal direction (they are parallel and of the same orientation).

Geometrically, every vector is represented by a directed line segment — an arrow from its tail to its head. The length of the arrow is the magnitude; the direction the arrow points is the vector's direction.

Crucially, vectors are free: you can translate (slide) an arrow anywhere on the plane without changing the vector. Two arrows represent the same vector if and only if they have the same length and point in the same direction.

$\vec{AB} = \vec{CD}$  iff  $|AB| = |CD|$ and $AB \parallel CD$ (same orientation)

This is exactly what happens in a parallelogram: $ABCD$ is a parallelogram iff $\vec{AB} = \vec{DC}$ (note the order of letters).

The zero vector $\vec{0}$: a degenerate arrow with zero length. It has no direction (or, by convention, every direction). $\vec{AA} = \vec{0}$ for any point $A$. Adding $\vec{0}$ to any vector leaves it unchanged: $\vec{a} + \vec{0} = \vec{a}$.

Geometrically, every vector is represented by a directed line segment — an arrow from its tail to its head. The length of the arrow is the magnitude; the direction the arrow points is the vector's direction.

Pause — copy the free-vector principle: two directed segments are equal vectors iff equal magnitude AND equal direction; include a diagram with three equal vectors in different positions into your book.

Did you get this? True or false: Moving a vector arrow to a different position on the diagram changes the vector.

PROBLEM 1 · READ AND WRITE NOTATION

Write the vector from point $M$ to point $N$ in all four notations. State its magnitude.

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Two-point form: $\vec{MN}$ — the tail is $M$ and the head is $N$, so the vector goes from $M$ to $N$.
Always write the tail first, then the head. This form is most explicit about direction.
PROBLEM 2 · EQUAL VECTORS IN A PARALLELOGRAM

In parallelogram $ABCD$, identify three pairs of equal vectors formed by the sides and diagonals.

1
Opposite sides of a parallelogram are parallel and equal in length. Therefore $\vec{AB} = \vec{DC}$ and $\vec{AD} = \vec{BC}$.
Check directions carefully: $\vec{AB}$ goes $A \to B$ (say, left to right). $\vec{DC}$ goes $D \to C$ (also left to right, on the opposite side) — same direction. $\vec{CD}$ would be right to left, which is the opposite direction.
PROBLEM 3 · NEGATIVE VECTOR

Given $\vec{PQ}$, express $\vec{QP}$ in terms of $\vec{PQ}$. Explain geometrically.

1
$\vec{QP}$ has the same magnitude as $\vec{PQ}$ but travels in the opposite direction (from $Q$ back to $P$ instead of $P$ to $Q$).
Reversing the start and end points reverses the direction of travel.

Fill the gap: In parallelogram $ABCD$, $\vec{AB} = $ and $\vec{BA} = $ .

Trap 01
Confusing $\vec{AB}$ and $AB$
$\vec{AB}$ is a vector (has direction). $AB$ (or $|\vec{AB}|$) is a scalar — the magnitude (length) of that vector. In an exam, if a question asks for the "vector $\vec{AB}$", give direction information. If it asks for "the length $AB$", give a positive number only.
Trap 02
Wrong direction in parallelograms
In parallelogram $ABCD$: $\vec{AB} = \vec{DC}$ (NOT $\vec{CD}$). Check: $\vec{DC}$ goes $D \to C$ (same direction as $A \to B$). $\vec{CD}$ goes $C \to D$ (opposite direction). Writing the wrong one loses marks. Always trace the arrow direction carefully.
Trap 03
Forgetting to underline in handwriting
In the HSC, a single-letter vector written without decoration (like $a$ instead of $\underline{a}$) is ambiguous and may be penalised. Always underline single-letter vectors in handwritten work. This is the agreed convention throughout NSW schools.

Did you get this? True or false: In parallelogram $ABCD$, $\vec{AB} = \vec{CD}$.

Work mode · how are you completing this lesson?
1

Write the vector from $X$ to $Y$ in all four notations, naming the single-letter vector $\mathbf{v}$.

2

In rectangle $PQRS$ (vertices in order), state three pairs of equal vectors formed by the sides.

3

Given $\vec{u} = \vec{AB}$, express $\vec{BA}$ in terms of $\vec{u}$, and verify that $\vec{AB} + \vec{BA} = \vec{0}$.

4

Explain in one sentence why an arrow representing a vector can be freely moved to any position in the plane.

5

If $|\vec{PQ}| = 7$ cm, what is $|\vec{QP}|$? Justify your answer.

Odd one out: Three of these statements are true. Which one is FALSE?

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Revisit your thinking

Earlier you were asked what three pieces of information $\vec{AB}$ carries.

The answer: (1) the tail $A$, (2) the head $B$, and (3) the direction from $A$ to $B$. The magnitude is captured implicitly by the length of the line segment from $A$ to $B$. And $|\vec{AB}|$ strips the direction away, leaving only the scalar length.

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01
Multiple choice
+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

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Short answer
ApplyBand 31 mark

Q1. Write the vector from point $C$ to point $D$ using all four standard notations (name the vector $\mathbf{w}$). (1 mark)

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ApplyBand 42 marks

Q2. In parallelogram $WXYZ$ (vertices in order), state which vector equals $\vec{WX}$ and explain why $\vec{WX} \neq \vec{XY}$. (2 marks)

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AnalyseBand 52 marks

Q3. Explain why $|\vec{AB}| = |\vec{BA}|$ even though $\vec{AB} \neq \vec{BA}$. (2 marks)

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Comprehensive answers (click to reveal)

Activity answers: 1. $\vec{XY}$ (two-point), $\vec{v}$ (typed), $\mathbf{v}$ (print), $\underline{v}$ (handwriting).  ·  2. $\vec{PQ} = \vec{SR}$; $\vec{QR} = \vec{PS}$; plus diagonal midpoint pairs.  ·  3. $\vec{BA} = -\vec{u}$; $\vec{AB} + \vec{BA} = \vec{u} + (-\vec{u}) = \vec{0}$.  ·  4. A vector is defined only by its magnitude and direction, not its position.  ·  5. $|\vec{QP}| = 7$ cm — the negative reverses direction but keeps the same magnitude.

Q1 (1 mark): $\vec{CD}$ (two-point); $\vec{w}$ (typed); $\mathbf{w}$ (print); $\underline{w}$ (handwriting) [1 — all four correct].

Q2 (2 marks): In parallelogram $WXYZ$, $\vec{WX} = \vec{ZY}$ (opposite sides, same direction $W \to X$ and $Z \to Y$) [1]. $\vec{WX} \neq \vec{XY}$ because although they share point $X$, they point in different directions (one horizontal, one diagonal in a general parallelogram) [1].

Q3 (2 marks): $\vec{BA} = -\vec{AB}$ [1]. The negative of a vector reverses direction but does not change magnitude, so $|\vec{BA}| = |-\vec{AB}| = |\vec{AB}|$. However $\vec{AB} \neq \vec{BA}$ because they point in opposite directions [1].

01
Boss battle · The Notation Master
earn bronze · silver · gold

Five timed questions. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

⚔ Enter the arena
02
Science Jump · platform challenge

Climb platforms by answering vector notation questions. Lighter alternative to the boss.

Mark lesson as complete

Tick when you've finished the practice and review.

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