Your weak spots

Insights load after your first practice round.

Module 2 · L15 of 15 ~40 min ⚡ +95 XP available

Module Synthesis & Exam Technique

You've covered polynomial definition and evaluation, long division, the Remainder and Factor Theorems, Vieta's formulas, symmetric identities, reducible polynomials, multiple roots, graphing, inequalities, and applications. This final lesson ties it all together and shows you how to approach exam questions on polynomials with confidence and efficiency.

Today's hook — In an exam, a student sees $P(x) = x^3 + ax^2 + bx - 8$ and immediately starts long division. Another student uses the Factor Theorem and has the answer in 30 seconds. Which approach is yours? By the end of this lesson you'll know the fastest pathway through every polynomial question type — and exactly where the mark-losing traps are hidden.

0/5QUESTS

Recall — your gut answer first

+5 XP warm-up

What are the three most important theorems in this module? How do they connect to each other? Write your gut answer before reading on.

auto-saved

What you'll master

Know

Key facts

The key results and techniques from all 14 lessons
Common HSC question types and mark allocations for polynomial topics
The specific traps examiners build into polynomial questions

Understand

Concepts

How topics interconnect: division → Remainder Theorem → Factor Theorem → zeros → Vieta
Why the Factor Theorem test is faster than long division for finding factors
How method marks work and how to secure them even with wrong answers

Can do

Skills

Approach exam-style polynomial questions with confidence and efficiency
Apply the standard factorisation workflow: Factor Theorem → long division → factorise quotient
Self-diagnose which topic areas still need practice

Module 2 at a glance — the core flow

+5 XP to read

The 14 lessons of this module follow a logical chain. Understanding how each topic leads to the next is the key to navigating exam questions:

#	Topic	Key idea
1	Polynomial basics	Definition, degree, evaluation
2	Division	Long division, division algorithm $P = DQ + R$
3	Remainder Theorem	Find remainders without division: $R = P(a)$
4–5	Factor Theorem	$(x-a)$ is a factor $\Leftrightarrow P(a)=0$; Rational Root Theorem
6–8	Vieta's formulas & symmetric identities	Link coefficients to sums/products of roots; evaluate expressions without finding roots
9	Reducible polynomials	Substitution techniques to lower degree
10	Multiple roots	Multiplicity and graph behaviour at repeated zeros
11	Graphing polynomials	Intercepts, end behaviour, multiplicity, sketching
12	Polynomial inequalities	Sign tables, test points, include/exclude endpoints
13–14	Applications	Modelling real problems with polynomials

Key terms — the non-negotiables

Division algorithm$P(x) = D(x) \cdot Q(x) + R(x)$ where $\deg R < \deg D$.

Remainder TheoremThe remainder on dividing $P(x)$ by $(x-a)$ is $P(a)$.

Factor Theorem$(x-a)$ is a factor of $P(x)$ if and only if $P(a) = 0$.

Vieta's formulasLink coefficients to elementary symmetric polynomials in the roots.

MultiplicityA root $x = a$ has multiplicity $k$ if $(x-a)^k$ divides $P(x)$ but $(x-a)^{k+1}$ does not.

Sign tableSystematic method to determine the sign of a polynomial expression over each interval between critical values.

Exam techniques — the non-negotiables

core technique

Always check small integers first ($\pm 1, \pm 2$) when looking for factors using the Factor Theorem — it is nearly always faster than starting with long division.
Factor Theorem → long division → factorise quotient is the standard workflow for fully factorising a polynomial.
Use the Remainder Theorem for quick remainder calculations without performing division.
Watch signs in Vieta's formulas — the sum of roots of $ax^n + bx^{n-1} + \cdots$ is $-b/a$, not $b/a$. This is the most common error.
For inequalities, always check whether endpoints are included or excluded; use a sign table for reliability.
For graphing, label all intercepts and indicate end behaviour with arrows — unlabelled features earn no marks.
Show all working — method marks are generous in polynomial questions and can be awarded even when the final answer is wrong.

The factorisation workflow. Given $P(x) = 2x^3 - 5x^2 - x + 6$, test $P(1) = 2$, $P(-1) = -8$, $P(2) = 0$ ✔. So $(x-2)$ is a factor. Divide to get $2x^2 - x - 3$. Factorise: $(2x-3)(x+1)$. Final answer: $(x-2)(2x-3)(x+1)$. Total time: about 90 seconds.

Factorisation workflow: Factor Theorem test ( 1, 2, ) → long division → factorise quotient; Remainder Theorem: sub x = a directly into P(x) to get the remainder on dividing by (x-a)

Pause — copy the factorisation workflow into your book: Factor Theorem test ($\pm 1$, $\pm 2$, …) → long division by $(x-a)$ → factorise the quotient quadratic; Remainder Theorem: substitute $x = a$ directly into $P(x)$ to find the remainder when dividing by $(x-a)$.

Quick check: When factorising $P(x) = x^3 - 7x + 6$, what is the most efficient first step in an exam?

Worked examples · 3 in a row, reveal as you go

PROBLEM 1 · FACTOR & REMAINDER CONDITIONS (4 marks)

The polynomial $P(x) = x^3 + ax^2 + bx - 8$ has $(x-2)$ as a factor. When divided by $(x+1)$, the remainder is $-18$. Find $a$ and $b$.

$(x-2)$ is a factor $\Rightarrow P(2) = 0$
$8 + 4a + 2b - 8 = 0 \;\Rightarrow\; 4a + 2b = 0 \;\Rightarrow\; 2a + b = 0$ …(1)

Use the Factor Theorem: sub $x = 2$ and set equal to zero.

PROBLEM 2 · VIETA'S FORMULAS & SYMMETRIC IDENTITIES (3 marks)

$\alpha$, $\beta$, $\gamma$ are the roots of $2x^3 - 3x^2 + x - 5 = 0$. Find $\alpha + \beta + \gamma$, $\alpha\beta\gamma$, and $\alpha^2 + \beta^2 + \gamma^2$.

$\alpha + \beta + \gamma = \dfrac{3}{2}$ and $\alpha\beta\gamma = \dfrac{5}{2}$

Vieta's for $ax^3+bx^2+cx+d$: sum of roots $= -b/a = -(-3)/2 = 3/2$; product of roots $= -d/a = -(-5)/2 = 5/2$.

PROBLEM 3 · POLYNOMIAL INEQUALITY (2 marks)

Solve $(x^2 - 4)(x - 1) \ge 0$.

$(x-2)(x+2)(x-1) \ge 0$
Critical values: $x = -2,\; 1,\; 2$

Factorise completely. Identify all zeros — these are the boundary points for the sign table.

Did you get this? True or false: to find the remainder when $P(x)$ is divided by $(x+3)$, you should evaluate $P(3)$.

Misconceptions to fix · the 4 traps that cost marks

Trap 01

Starting with long division instead of the Factor Theorem

In an exam, performing long division before testing the Factor Theorem wastes time. Always test small integer values first: $P(\pm1), P(\pm2), P(\pm3), \ldots$. Long division is only needed after you have found a factor.

Trap 02

Wrong sign in Vieta's formulas

For $ax^3 + bx^2 + cx + d$, the sum of roots is $-b/a$, not $b/a$. Students who write $\alpha + \beta + \gamma = b/a$ will get every Vieta's question wrong. The negative sign comes from the sign convention in the factored form.

Trap 03

Wrong substitution value in the Remainder Theorem

The remainder when dividing by $(x+3)$ is $P(-3)$, not $P(3)$. The theorem says divide by $(x-a)$, so you substitute $x = a$. Since $(x+3) = (x-(-3))$, you substitute $a = -3$.

Trap 04

Including or excluding wrong endpoints in inequalities

For a strict inequality ($>$ or $<$), all critical values are excluded (open brackets). For a non-strict inequality ($\ge$ or $\le$), critical values where the expression equals zero are included (closed brackets). Always re-read the inequality sign before writing the final answer.

Fill the gap: For $P(x) = 3x^3 - 2x^2 + x - 4$, if $\alpha, \beta, \gamma$ are its roots, then $\alpha + \beta + \gamma = $ .

Module 2 key skills recap

Polynomial basicsIdentify degree, leading coefficient, evaluate $P(a)$ by direct substitution.

Division algorithm$P(x) = D(x) \cdot Q(x) + R(x)$; degree of $R$ is strictly less than degree of $D$.

Remainder TheoremRemainder of $P(x) \div (x-a)$ is $P(a)$. Sub $x = -a$ when divisor is $(x+a)$.

Factor Theorem$(x-a)$ is a factor $\Leftrightarrow P(a) = 0$. Use rational root candidates $\pm p/q$ to search.

Full factorisationFind one factor by Factor Theorem → divide → factorise quotient → repeat.

Vieta's formulas (cubic)$\sum\alpha = -b/a$; $\sum\alpha\beta = c/a$; $\alpha\beta\gamma = -d/a$.

Symmetric identities$\alpha^2+\beta^2+\gamma^2 = (\sum\alpha)^2 - 2\sum\alpha\beta$; avoid solving the polynomial directly.

Reducible polynomialsSubstitute $u = x^k$ or $u = f(x)$ to convert to a lower-degree equation.

Multiple roots & graphingOdd multiplicity → crosses $x$-axis; even multiplicity → touches and turns. Label end behaviour.

Polynomial inequalitiesFactorise → sign table → intervals; include endpoints for $\ge / \le$, exclude for $> / <$.

Work mode · how are you completing this lesson?

Activities · practice under exam conditions

$P(x) = x^3 + px^2 + qx + 6$ has $(x+1)$ and $(x-2)$ as factors. Find $p$ and $q$, then write $P(x)$ in fully factorised form.

If $\alpha, \beta, \gamma$ are roots of $2x^3 - 3x^2 + x - 5 = 0$, find $\alpha + \beta + \gamma$, $\alpha\beta\gamma$, and $\dfrac{1}{\alpha} + \dfrac{1}{\beta} + \dfrac{1}{\gamma}$.

Solve $(x^2-4)(x-1) \ge 0$ and express your answer in interval notation.

Sketch $y = P(x) = (x+2)^2(x-1)(x-3)$, labelling all $x$-intercepts (with their multiplicity behaviour), the $y$-intercept, and indicating end behaviour.

Identify which Module 2 topic you find most difficult. Explain why, and state one specific strategy you will use to address it before the exam.

Did you get this? True or false: if $x = a$ is a root of even multiplicity, the graph of $y = P(x)$ crosses the $x$-axis at $x = a$.

Odd one out: Three of these are valid exam techniques for Module 2. Which one is NOT?

Revisit your thinking

Earlier you were asked to name the three most important theorems and describe how they connect. The answer: Division Algorithm → Remainder Theorem → Factor Theorem.

The chain runs like this: the Division Algorithm tells you that dividing $P(x)$ by $(x-a)$ leaves a constant remainder $R$. The Remainder Theorem then tells you $R = P(a)$ — no division needed. The Factor Theorem is the special case: if $P(a) = 0$, the remainder is zero, so $(x-a)$ divides evenly, making it a factor. Vieta's formulas then use that factored form to link coefficients to roots.

Which topic in this module do you feel most confident about, and which needs more practice before the exam?

auto-saved

Multiple choice

+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

Short answer

ApplyBand 43 marks

Q1. $P(x) = x^3 + px^2 + qx + 6$ has $(x+1)$ and $(x-2)$ as factors. Find $p$ and $q$. (3 marks)

auto-saved

ApplyBand 42 marks

Q2. If $\alpha, \beta, \gamma$ are roots of $2x^3 - 3x^2 + x - 5 = 0$, find $\alpha + \beta + \gamma$ and $\alpha\beta\gamma$. (2 marks)

auto-saved

AnalyseBand 52 marks

Q3. Solve $(x^2-4)(x-1) \ge 0$ and express your answer in interval notation. (2 marks)

auto-saved

Comprehensive answers (click to reveal)

Activity 1:

1. $P(-1)=0$: $-1+p-q+6=0 \Rightarrow p-q=-5$ …(1). $P(2)=0$: $8+4p+2q+6=0 \Rightarrow 4p+2q=-14 \Rightarrow 2p+q=-7$ …(2). From (1)+(2): $3p=-12 \Rightarrow p=-4$; $q=-1$. So $P(x)=x^3-4x^2-x+6=(x+1)(x-2)(x-3)$.

2. Vieta's: $\alpha+\beta+\gamma=3/2$; $\alpha\beta\gamma=5/2$; $\alpha\beta+\beta\gamma+\gamma\alpha=1/2$. Then $1/\alpha+1/\beta+1/\gamma = (\alpha\beta+\beta\gamma+\gamma\alpha)/(\alpha\beta\gamma) = (1/2)/(5/2) = 1/5$.

3. $(x-2)(x+2)(x-1)\ge0$. Sign table: $x\in[-2,1]\cup[2,+\infty)$.

4. $P(0)=(2)^2(-1)(-3)=12$. $y$-intercept: $(0,12)$. Touches at $x=-2$ (even multiplicity), crosses at $x=1$ and $x=3$. Leading term $x^4 \Rightarrow$ both ends → $+\infty$.

Q1 (3 marks): $P(-1)=0$: $p-q=-5$ [1]. $P(2)=0$: $2p+q=-7$ [1]. $p=-4$, $q=-1$ [1].

Q2 (2 marks): $\alpha+\beta+\gamma = 3/2$ [1]. $\alpha\beta\gamma = 5/2$ [1].

Q3 (2 marks): Correct factorisation and critical values identified [1]. Solution $x\in[-2,1]\cup[2,+\infty)$ [1].

Boss battle · The Polynomial Master

earn bronze · silver · gold

Five timed questions drawn from all Module 2 topics. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

⚔ Enter the arena

Module 2 complete — key skills achieved

Congratulations on completing Module 2: Polynomials!

Key skills you have developed across these 15 lessons:

Applying the Division Algorithm and performing polynomial long division
Using the Remainder Theorem to find remainders without dividing
Applying the Factor Theorem and the Rational Root Theorem to factorise polynomials
Using Vieta's formulas to find sums and products of roots from coefficients
Evaluating symmetric expressions in the roots without solving the polynomial
Solving reducible polynomial equations by substitution
Sketching polynomial graphs, identifying multiplicity, intercepts, and end behaviour
Solving polynomial inequalities using sign tables
Applying polynomial techniques to real-world modelling problems

Ready to tackle Module 3? Head to the first lesson to begin your next module.

Complete Checkpoint 3 and the Module Quiz to consolidate and verify your learning.

Mark lesson as complete

Tick when you've finished the practice and review.

← L14 · Applications of Polynomials M3 L1 →

Module overview · Extension 1 subject page · Checkpoint 3 · Module quiz