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hscscience Maths Ext 1 · Y11
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Module 2 · L1 of 15 ~30 min ⚡ +95 XP available

Introduction to Polynomials

A degree-6 polynomial can describe a roller-coaster track. A constant polynomial is just a flat line. Between those two extremes lies a rich family of expressions that power everything from graphics engines to engineering simulations. In this lesson you'll learn to identify, classify, and evaluate polynomials — the foundation of all that follows in Module 2.

Today's hook — Is $f(x) = x^2 + \frac{1}{x}$ a polynomial? What about $g(x) = \sqrt{x} + 3$? The answer hinges on one single rule — and knowing it instantly separates polynomials from impostors. By the end of this lesson you'll spot the difference in under two seconds.
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Recall — your gut answer first
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Without using a definition — is $f(x) = x^2 + \dfrac{1}{x}$ a polynomial? What about $g(x) = \sqrt{x} + 3$? Write your instinct and explain your reasoning before reading on.

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The two moves
+5 XP to read

There are only two core skills in this lesson — and everything else flows from them. Lock the polynomial definition (non-negative integer powers only) and direct substitution for evaluation into muscle memory.

Every polynomial question sits on one of two roads: identify whether an expression is a polynomial by checking powers, or evaluate the polynomial by substituting a value and simplifying.

IDENTIFY integer n≥0 EVALUATE substitute & simplify is it valid? what's P(a)?
$P(x) = a_n x^n + \cdots + a_0$
Check the powers
Every exponent of $x$ must be a non-negative integer: 0, 1, 2, 3, … Fractions or negatives? Not a polynomial.
Rewrite first
Always rewrite in descending powers before stating degree and leading coefficient. Don't trust the order as written.
Leading coefficient
If the leading coefficient equals 1 the polynomial is called monic — this term appears often in factorisation questions.
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What you'll master
Know

Key facts

  • The formal definition of a polynomial in $x$
  • The meaning of degree and leading coefficient
  • What it means for a polynomial to be monic
Understand

Concepts

  • Why negative and fractional powers are excluded
  • Why $7$ is a degree-0 polynomial (not "not a polynomial")
  • How the degree determines the shape of the graph
Can do

Skills

  • Identify polynomials and non-polynomials from a list of expressions
  • State the degree and leading coefficient of any polynomial
  • Evaluate $P(a)$ for any value $a$ by direct substitution
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Key terms
PolynomialAn expression of the form $P(x) = a_n x^n + \cdots + a_1 x + a_0$ where $n$ is a non-negative integer and each $a_i$ is a constant.
DegreeThe highest power of $x$ with a non-zero coefficient; determines the polynomial's overall shape.
Leading coefficientThe coefficient $a_n$ of the highest-power term; determines end behaviour of the graph.
Monic polynomialA polynomial whose leading coefficient equals 1, e.g. $x^3 - 2x + 5$.
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What is a polynomial?
core concept

A polynomial in $x$ is an expression of the form:

$$P(x) = a_n x^n + a_{n-1} x^{n-1} + \cdots + a_1 x + a_0$$

where $n$ is a non-negative integer (the degree), each $a_i$ is a constant coefficient, and $a_n \ne 0$ (so the degree is exactly $n$).

Examples of polynomials:

  • $3x^2 - 2x + 5$ — degree 2, leading coefficient 3
  • $x^4 - 1$ — degree 4, leading coefficient 1 (monic)
  • $7$ — degree 0, a constant polynomial

Not polynomials:

  • $x^2 + \dfrac{1}{x} = x^2 + x^{-1}$ — negative power $(-1)$
  • $\sqrt{x} + 2 = x^{1/2} + 2$ — fractional power $(\frac{1}{2})$
  • $2^x$ — variable in the exponent, not the base
Why does it matter? The restriction to non-negative integer powers is what gives polynomials their smoothness — they are infinitely differentiable everywhere on the real line. That's why they're the go-to tool for approximating any smooth function (Taylor series).

Polynomial: P(x) = a_n x^n + + a_0 where each power is a non-negative integer; Degree = highest power with a non-zero coefficient

Pause — copy the polynomial definition into your book: $P(x) = a_n x^n + \cdots + a_1 x + a_0$ where each power is a non-negative integer; degree = highest power with a non-zero coefficient.

Quick check: Which of the following is a polynomial?

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Evaluating polynomials
core concept

We just saw that a polynomial $P(x) = a_n x^n + \cdots + a_0$ has degree $n$ (highest non-zero power). That raises a question: to check whether a given value $x = a$ satisfies $P(x) = 0$, you need to evaluate $P(a)$ — what is the safest method to avoid sign errors? This card answers it → substitute using brackets around the value, evaluate each term separately, then combine.

To evaluate a polynomial at a specific value, substitute the value for $x$ and simplify step by step. Do not skip steps — sign errors are the main source of lost marks.

Example: If $P(x) = 2x^3 - x^2 + 3x - 4$, find $P(2)$.

$$P(2) = 2(2)^3 - (2)^2 + 3(2) - 4 = 16 - 4 + 6 - 4 = 14$$

You can also use evaluation to find unknown coefficients. If $P(x) = x^3 - 2x^2 + kx + 5$ and $P(2) = 11$:

$$8 - 8 + 2k + 5 = 11 \implies 2k = 6 \implies k = 3$$

Substitute x = a and evaluate each term separately before combining; Use brackets around substituted values: write 2(2)^3 not 22^3

Pause — copy the evaluation rule into your book: substitute using brackets — write $2(2)^3$ not $22^3$; evaluate each term separately before combining to avoid sign errors.

Did you get this? True or false: if $P(x) = 3x^2 - x + 2$, then $P(-1) = 6$.

PROBLEM 1 · DEGREE & LEADING COEFFICIENT

Determine the degree and leading coefficient of $P(x) = 5x^4 - 2x^6 + 3x - 1$.

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Rewrite in descending powers: $P(x) = -2x^6 + 5x^4 + 3x - 1$
Always arrange terms from highest to lowest power first — this prevents misidentifying the degree.
PROBLEM 2 · EVALUATION

If $P(x) = 2x^3 - x^2 + 3x - 4$, find $P(-2)$.

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$P(-2) = 2(-2)^3 - (-2)^2 + 3(-2) - 4$
Substitute $x = -2$ with brackets around every substituted value to protect signs.
PROBLEM 3 · FIND THE COEFFICIENT

Find the value of $k$ if $P(x) = x^3 - 2x^2 + kx + 5$ has $P(2) = 11$.

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$P(2) = (2)^3 - 2(2)^2 + k(2) + 5 = 8 - 8 + 2k + 5 = 2k + 5$
Substitute $x = 2$ and simplify all terms except those involving $k$.

Fill the gap: If $P(x) = x^3 - 4x + 1$, then $P(2) =$ .

Trap 01
Misidentifying the degree
Students read the degree from the first term as written, not the highest power. Always rewrite in descending powers first. In $5x^4 - 2x^6 + 3x - 1$, the degree is 6, not 4.
Trap 02
Thinking $\sqrt{x}$ or $\frac{1}{x}$ are polynomials
$\sqrt{x} = x^{1/2}$ (fractional power) and $\frac{1}{x} = x^{-1}$ (negative power) both disqualify an expression from being a polynomial. Any non-integer or negative exponent is a red flag.
Trap 03
Sign errors when evaluating at negative values
$(-2)^2 = +4$, not $-4$. $(-2)^3 = -8$. Always use brackets around substituted values. This is the most common source of wrong evaluation answers in exams.

Did you get this? True or false: $f(x) = x^3 + \sqrt{x}$ is a polynomial.

Work mode · how are you completing this lesson?
1

State whether each expression is a polynomial. If not, explain why: (a) $4x^3 - 7x + 2$   (b) $x^{-2} + 3x$   (c) $6$   (d) $\dfrac{x^2 + 1}{x}$

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Find the degree and leading coefficient of $Q(x) = 7 - 3x^5 + x^2 - 9x^3$.

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If $P(x) = 2x^2 - 3x + k$ and $P(1) = 4$, find $k$.

4

Evaluate $P(x) = x^4 - 3x^2 + 2x - 5$ at $x = -1$.

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Explain in your own words why every constant (e.g. $P(x) = 7$) qualifies as a polynomial, and what its degree is.

Odd one out: Which expression does NOT belong with the others? Select and explain.

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Revisit your thinking

Earlier you were asked whether $f(x) = x^2 + \dfrac{1}{x}$ and $g(x) = \sqrt{x} + 3$ are polynomials.

$f(x) = x^2 + x^{-1}$ — the $x^{-1}$ term has a negative power, so $f$ is not a polynomial. $g(x) = x^{1/2} + 3$ — the $x^{1/2}$ term has a fractional power, so $g$ is also not a polynomial. A polynomial requires all powers to be non-negative integers.

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Multiple choice
+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

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Short answer
UnderstandBand 32 marks

Q1. State the degree and leading coefficient of $P(x) = 3x^5 - 2x^3 + x - 7$. (2 marks)

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ApplyBand 42 marks

Q2. If $P(x) = 2x^2 - 3x + k$ and $P(1) = 4$, find $k$. (2 marks)

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AnalyseBand 52 marks

Q3. Explain why $f(x) = x^{-2} + 3x$ is not a polynomial. What would need to change to make it a polynomial? (2 marks)

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Comprehensive answers (click to reveal)

Activity 1: (a) Polynomial — all non-negative integer powers. (b) Not a polynomial — $x^{-2}$ has a negative power. (c) Polynomial — constant, degree 0. (d) Not a polynomial — $\frac{x^2+1}{x} = x + x^{-1}$, contains $x^{-1}$.

Activity 2: Rewrite: $-3x^5 + x^2 - 9x^3 + 7 = -3x^5 - 9x^3 + x^2 + 7$. Degree = 5; leading coefficient = $-3$.

Activity 3: $P(1) = 2 - 3 + k = k - 1 = 4 \Rightarrow k = 5$.

Activity 4: $P(-1) = (-1)^4 - 3(-1)^2 + 2(-1) - 5 = 1 - 3 - 2 - 5 = -9$.

Activity 5: $7 = 7 \cdot x^0$ — it fits the form $a_0 x^0$ with non-negative integer power 0. Degree = 0.

Q1 (2 marks): Degree = 5 [1]; leading coefficient = 3 [1].

Q2 (2 marks): $P(1) = 2(1)^2 - 3(1) + k = 2 - 3 + k = k - 1$ [1]. Set $k - 1 = 4$, so $k = 5$ [1].

Q3 (2 marks): $f(x) = x^{-2} + 3x$ contains the term $x^{-2}$, which has a negative integer exponent $(-2)$. Polynomials require all exponents to be non-negative integers [1]. To make it a polynomial, replace $x^{-2}$ with a term like $x^2$ or any $x^n$ where $n \geq 0$ [1].

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Boss battle · The Polynomial Inspector
earn bronze · silver · gold

Five timed questions. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

⚔ Enter the arena
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Science Jump · platform challenge

Climb platforms by answering polynomial questions. Lighter alternative to the boss.

Mark lesson as complete

Tick when you've finished the practice and review.

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