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hscscience Maths Ext 1 · Y11
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Module 1 · L1 of 15 ~30 min ⚡ +90 XP available

Introduction to Extension 1 Functions

You already know what a function is — an input, a rule, an output. But Extension 1 asks a deeper question: what happens when we flip that rule around? What does it mean for two expressions to be constrained by inequality rather than equality? This module unlocks four powerful function tools — inequalities, inverses, graphical transformations, and parametric equations — that will reappear in every calculus and proof topic to come.

Today's hook — If $f(x) = x^2$, what is $f^{-1}(9)$? Is it $3$, or $-3$, or both? This question — which seems simple — hides the most important idea in the module. By the end of this lesson you'll know exactly why the answer depends on the domain, and that will unlock inverse functions forever.
0/5QUESTS
01
Recall — your gut answer first
+5 XP warm-up

What is the difference between a relation and a function? Write down the definition of domain and range, and explain how you would use the vertical line test. Don't look anything up — write what you already know.

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The two moves
+5 XP to read

Everything in Extension 1 Functions flows from two core ideas. First: test whether a relation is a function using the vertical line test. Second: test whether a function is one-to-one using the horizontal line test — because only one-to-one functions have inverses.

The vertical line test asks: does any vertical line cross the graph more than once? If yes, it's not a function. The horizontal line test asks: does any horizontal line cross the graph more than once? If yes, the function is many-to-one and has no inverse function over that domain.

vertical test ✓ horiz. test ✗
$f \text{ one-to-one} \Leftrightarrow f^{-1}$ exists
Vertical line test
One intersection with any vertical line means it's a function. More than one intersection — it's just a relation.
Horizontal line test
One intersection with any horizontal line means one-to-one. Two or more — restrict the domain before finding the inverse.
The four areas
Inequalities · Inverse functions · Graphical relationships · Parametric equations. Every lesson in this module lives in one of these four zones.
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What you'll master
Know

Key facts

  • The four key areas of this module: inequalities, inverse functions, graphical relationships, parametric equations
  • Domain and range of common functions: $x^2$, $\sqrt{x}$, $\frac{1}{x}$, $e^x$, $\ln x$
  • A function has an inverse only when it is one-to-one
Understand

Concepts

  • How Extension 1 extends Advanced function concepts into inequalities and inverses
  • Why the horizontal line test determines whether an inverse function exists
  • How domain restrictions allow non-one-to-one functions to have inverses
Can do

Skills

  • State the domain and range of standard functions
  • Apply vertical and horizontal line tests to graphs
  • Identify appropriate domain restrictions for inverse functions
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Key terms
InequalityA mathematical statement comparing two expressions using $<$, $>$, $\le$ or $\ge$.
Inverse function $f^{-1}$A function that reverses the action of $f$, so $f^{-1}(f(x)) = x$. Exists only when $f$ is one-to-one.
Parametric equationsEquations where $x$ and $y$ are each expressed in terms of a third variable (the parameter $t$).
Graphical relationshipA transformation connecting $y = f(x)$ to a derived graph such as $y = |f(x)|$ or $y = \frac{1}{f(x)}$.
One-to-one functionA function where every output comes from exactly one input. Passes the horizontal line test.
Domain restrictionLimiting the input set of a function so that it becomes one-to-one and an inverse can be defined.
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What is Extension 1 Functions?
core concept

In Mathematics Advanced, you studied functions and their transformations: translations, reflections and dilations. In Extension 1, the module Further Work with Functions goes much deeper into four interconnected areas:

  1. Inequalities — solving linear, quadratic, rational and absolute value inequalities algebraically and graphically.
  2. Inverse functions — finding inverses algebraically, understanding when domains must be restricted, and sketching inverse graphs.
  3. Graphical relationships — sketching $y = |f(x)|$, $y = f(|x|)$, $y = \dfrac{1}{f(x)}$, $y = \sqrt{f(x)}$ and $y = [f(x)]^2$ from the graph of $y = f(x)$.
  4. Parametric equations — describing curves using a parameter, eliminating the parameter, and sketching parametric curves.

All four areas are essential for the HSC Extension 1 examination and form the foundation for calculus and proof in later modules.

Why does this matter? When engineers design robotic arms or satellite trajectories, they use parametric equations to describe motion. When economists model constraint regions (e.g., "spend at most $x$ or $y$"), they need inequalities. The function toolkit you build here underpins every advanced topic from Year 11 onwards.

Four key areas: (1) Inequalities, (2) Inverse functions, (3) Graphical relationships, (4) Parametric equations; A function has an inverse function only if it is one-to-one (passes the horizontal line test)

Pause — copy the four key areas of Module 1 into your book — inequalities, inverse functions, graphical transformations, parametric equations — and the horizontal line test condition for inverse functions.

Quick check: Which of the following is NOT one of the four key areas in the Extension 1 Functions module?

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Function review — the essential toolkit
core concept

We just saw that Module 1 covers four areas: inequalities, inverse functions, graphical transformations, and parametric equations. That raises a question: what prerequisite function knowledge — domains, ranges, function notation — do you need before tackling any of these four areas? This card answers it → by reviewing the essential toolkit: domain, range, the horizontal line test, and the key functions $sqrt{x}$ and $1/x$.

Before diving into new material, recall the essential function concepts from Advanced:

  • A function is a relation where every input ($x$-value) has exactly one output ($y$-value).
  • The domain is the set of all possible inputs.
  • The range is the set of all possible outputs.
  • A function is one-to-one if every output comes from exactly one input (passes the horizontal line test).

Key domains and ranges to memorise:

FunctionDomainRange
$f(x) = x^2$All real $x$$y \ge 0$
$f(x) = \sqrt{x}$$x \ge 0$$y \ge 0$
$f(x) = \dfrac{1}{x}$$x \ne 0$$y \ne 0$
$f(x) = e^x$All real $x$$y > 0$
$f(x) = \ln x$$x > 0$All real $y$

Memory rule for domains: square roots need $\ge 0$ under the root; denominators cannot be zero; logarithms need a positive argument.

Domain: set of allowed inputs. Range: set of possible outputs.; x: domain x 0, range y 0. 1{x}: domain x 0, range y 0.

Pause — copy the domain and range of the key functions into your book: $\sqrt{x}$ has domain $x \ge 0$, range $y \ge 0$; $1/x$ has domain $x \ne 0$, range $y \ne 0$.

Did you get this? True or false: the function $f(x) = x^3$ is one-to-one over all real $x$.

PROBLEM 1 · DOMAIN AND RANGE

State the domain and range of $f(x) = \sqrt{x - 3}$.

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Require $x - 3 \ge 0$, so $x \ge 3$. Domain: $[3, \infty)$.
The square root is only defined for non-negative arguments. Set the expression under the root $\ge 0$ and solve.
PROBLEM 2 · ONE-TO-ONE TEST

Show that $f(x) = x^3$ is one-to-one, but $g(x) = x^2$ is not.

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For $f(x) = x^3$: suppose $f(a) = f(b)$. Then $a^3 = b^3 \Rightarrow a = b$.
Since distinct inputs always give distinct outputs, $f(x) = x^3$ is one-to-one. The horizontal line test confirms this — no horizontal line crosses the cubic more than once.
PROBLEM 3 · MODULE ROADMAP

The 15 lessons in this module are grouped into four areas. Describe each area and the lesson range it covers.

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Lessons 1–4: Inequalities — linear, quadratic, rational, absolute value. Lessons 5–8: Inverse and composite functions — finding inverses, restricting domains, $f(g(x))$.
Inequalities come first because they are algebraically simpler and provide techniques needed for the later topics.

Fill the gap: The domain of $f(x) = \sqrt{x - 5}$ is $x \ge $ .

Trap 01
Every function has an inverse
Wrong — only one-to-one functions have inverses that are also functions. $f(x) = x^2$ over all reals does NOT have an inverse function. You must restrict the domain (e.g., $x \ge 0$) first.
Trap 02
Confusing domain restrictions
Students often forget to apply restrictions for square roots, logarithms and denominators. Remember: $\sqrt{\text{expr}} \Rightarrow \text{expr} \ge 0$; $\ln(\text{expr}) \Rightarrow \text{expr} > 0$; $\frac{1}{\text{expr}} \Rightarrow \text{expr} \ne 0$.
Trap 03
Confusing "relation" and "function"
A circle is a relation but NOT a function — the vertical line test fails. Every function is a relation, but not every relation is a function. Always sketch or apply the vertical line test before assuming something is a function.

Did you get this? True or false: $f(x) = x^2$ over the domain $x \ge 0$ has an inverse function.

Odd one out: Which of the following is the odd one out? Select the function with a different property from the rest.

Work mode · how are you completing this lesson?
1

State the domain and range of $f(x) = \dfrac{1}{x - 2}$.

2

Is $f(x) = \ln x$ one-to-one? Explain your reasoning and state whether it has an inverse.

3

Explain why $f(x) = x^2$ does not have an inverse function over its natural domain. State a restricted domain for which an inverse does exist.

4

List the four key topic areas studied in this module. Which area do you think will be most challenging? Give a reason.

5

Determine whether each of these is a function and, if so, whether it is one-to-one: (a) $y = x^2 - 4$, (b) $x = y^2$, (c) $y = e^x$.

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Revisit your thinking

Earlier you were asked: if $f(x) = x^2$, what is $f^{-1}(9)$?

Over the natural domain (all real $x$), $f(x) = x^2$ is not one-to-one — both $x = 3$ and $x = -3$ give $f(x) = 9$. So $f^{-1}$ does not exist without a domain restriction. If we restrict to $x \ge 0$, then $f^{-1}(9) = 3$. If we restrict to $x \le 0$, then $f^{-1}(9) = -3$. The domain restriction determines which inverse you get.

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Multiple choice
+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

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Short answer
ApplyBand 42 marks

Q1. State the domain and range of $f(x) = \dfrac{1}{x - 2}$. (2 marks)

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UnderstandBand 42 marks

Q2. Explain why $f(x) = x^2$ does not have an inverse function over its natural domain, and state a restricted domain for which an inverse does exist. (2 marks)

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AnalyseBand 54 marks

Q3. List the four key topic areas studied in the Extension 1 Functions module, and briefly describe what is covered in each. (4 marks)

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Comprehensive answers (click to reveal)

Activity answers: 1. Domain $x \ne 2$, range $y \ne 0$. · 2. $\ln x$ is one-to-one (always increasing, horizontal line test passes); inverse is $e^x$. · 3. $x^2$ fails horizontal line test ($g(2) = g(-2) = 4$); restrict to $x \ge 0$ or $x \le 0$. · 4. (1) Inequalities, (2) Inverse functions, (3) Graphical relationships, (4) Parametric equations. · 5. (a) $y = x^2 - 4$: function, not one-to-one. (b) $x = y^2$: not a function (vertical line test fails). (c) $y = e^x$: function, one-to-one.

Q1 (2 marks): Domain: $x \ne 2$ [or $(-\infty, 2) \cup (2, \infty)$] [1 mark]. Range: $y \ne 0$ [or $(-\infty, 0) \cup (0, \infty)$] [1 mark].

Q2 (2 marks): $f(x) = x^2$ fails the horizontal line test — for example $f(2) = f(-2) = 4$, so two inputs give the same output [1 mark]. A restricted domain such as $x \ge 0$ makes $f$ one-to-one and its inverse $f^{-1}(x) = \sqrt{x}$ exists [1 mark].

Q3 (4 marks): (1) Inequalities — solving $<$, $>$, $\le$, $\ge$ statements algebraically and graphically [0.5+0.5]. (2) Inverse functions — finding $f^{-1}$, restricting domains, using $f^{-1}(f(x)) = x$ [0.5+0.5]. (3) Graphical relationships — sketching $|f(x)|$, $f(|x|)$, $1/f(x)$, $\sqrt{f(x)}$, $[f(x)]^2$ [0.5+0.5]. (4) Parametric equations — expressing $x$ and $y$ in terms of parameter $t$, eliminating the parameter [0.5+0.5].

01
Boss battle · The Function Inspector
earn bronze · silver · gold

Five timed questions. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

⚔ Enter the arena
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Science Jump · platform challenge

Climb platforms by answering Extension 1 functions questions. Lighter alternative to the boss.

Mark lesson as complete

Tick when you've finished the practice and review.

🎓
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