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Module 3 · L2 of 15 ~35 min ⚡ +95 XP available

Reciprocal Trigonometric Functions

The three reciprocal functions — cosecant, secant, and cotangent — are not new trig ratios. They are simply $1/\sin$, $1/\cos$, and $1/\tan$. But they appear constantly in advanced mathematics, proofs, and physics, so fluency with them is essential. In this lesson you'll define them, pin down their domains, evaluate them for exact angles, and understand how to use the Pythagorean identity to find all six trig ratios from a single known value.

Today's hook — If $\sin\theta = \tfrac{3}{5}$, what is $\csc\theta$? That one's easy: $\tfrac{5}{3}$. But what is $\sec\theta$? That requires finding $\cos\theta$ first — and the sign of $\cos\theta$ depends on the quadrant. By the end of this lesson you'll find all six trig ratios from a single given value in under a minute.
0/5QUESTS
01
Recall — your gut answer first
+5 XP warm-up

If $\sin\theta = \dfrac{3}{5}$, what is $\csc\theta$? What about $\cos\theta$ and $\sec\theta$? Write your gut answer — you may not have enough information yet to be certain of the sign.

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02
The two moves
+5 XP to read

There are only two core moves in every reciprocal trig problem. Flip to find the reciprocal, then use the Pythagorean identity to find the missing ratio when only one ratio is given.

Every reciprocal trig question lives on one of two roads: flip the given ratio to get its reciprocal directly, or apply $\sin^2\theta + \cos^2\theta = 1$ to find a missing ratio before flipping.

FLIP csc = 1/sin sec = 1/cos PYTHAGOREAN sin²+cos²=1 find missing ratio first direct flip find missing
$\csc\theta = \dfrac{1}{\sin\theta}$
sec goes with cos
Both secant and cosine start with letters from "sc" — $\sec\theta = 1/\cos\theta$, not $1/\sin\theta$. This is the single most common confusion.
cot as a fraction
$\cot\theta = \dfrac{1}{\tan\theta} = \dfrac{\cos\theta}{\sin\theta}$. The fraction form is more useful in proofs and when simplifying expressions.
Signs are inherited
Each reciprocal function has the same sign as its original. If $\sin\theta > 0$ then $\csc\theta > 0$; if $\cos\theta < 0$ then $\sec\theta < 0$.
03
What you'll master
Know

Key facts

  • The definitions $\csc\theta = 1/\sin\theta$, $\sec\theta = 1/\cos\theta$, $\cot\theta = 1/\tan\theta = \cos\theta/\sin\theta$
  • The domain restrictions for each reciprocal function
  • That reciprocal functions inherit their signs from their parent functions
Understand

Concepts

  • Why $\csc\theta$ and $\cot\theta$ share the same domain restriction (both require $\sin\theta \neq 0$)
  • How the Pythagorean identity links sin and cos to find a missing ratio
  • Why we need to know the quadrant to determine the sign of the missing ratio
Can do

Skills

  • Evaluate exact values of $\csc\theta$, $\sec\theta$, $\cot\theta$ for standard angles
  • Find all six trig ratios given one ratio and the quadrant
  • Identify where each reciprocal function is undefined in $[0, 2\pi)$
04
Key terms
Cosecant $\csc\theta$$\csc\theta = \dfrac{1}{\sin\theta}$; undefined whenever $\sin\theta = 0$, i.e. $\theta = n\pi$.
Secant $\sec\theta$$\sec\theta = \dfrac{1}{\cos\theta}$; undefined whenever $\cos\theta = 0$, i.e. $\theta = \frac{\pi}{2} + n\pi$.
Cotangent $\cot\theta$$\cot\theta = \dfrac{1}{\tan\theta} = \dfrac{\cos\theta}{\sin\theta}$; undefined whenever $\sin\theta = 0$, i.e. $\theta = n\pi$.
Domain restrictionValues of $\theta$ for which the function is undefined (denominator equals zero).
Pythagorean identity$\sin^2\theta + \cos^2\theta = 1$; rearranged: $\cos^2\theta = 1 - \sin^2\theta$.
Inherited signA reciprocal function has the same sign as its parent: $\csc\theta > 0 \Leftrightarrow \sin\theta > 0$.
05
Definitions and domain restrictions
core concept

The three reciprocal trigonometric functions are defined as:

$$\csc\theta = \dfrac{1}{\sin\theta} \qquad \sec\theta = \dfrac{1}{\cos\theta} \qquad \cot\theta = \dfrac{1}{\tan\theta} = \dfrac{\cos\theta}{\sin\theta}$$

Domain restrictions — each function is undefined when its denominator is zero:

  • $\csc\theta$ undefined when $\sin\theta = 0$, i.e. $\theta = n\pi$ for integer $n$ ($\theta = 0°, 180°, 360°, \ldots$)
  • $\sec\theta$ undefined when $\cos\theta = 0$, i.e. $\theta = \dfrac{\pi}{2} + n\pi$ ($\theta = 90°, 270°, \ldots$)
  • $\cot\theta$ undefined when $\sin\theta = 0$, i.e. $\theta = n\pi$ (same as $\csc\theta$)

Sign behaviour: each reciprocal function carries the same ASTC sign as its parent. For example, $\csc\theta$ is positive where $\sin\theta$ is positive (Q1 and Q2), and negative in Q3 and Q4.

Memory hook. secant pairs with cosine (both contain the letter "c" as their first consonant after the initial consonant). cosecant pairs with sine. If you ever confuse them, spell out "cosecant" — it contains "sine" in disguise: cosecant.

= 1/ (undefined at = n); = 1/ (undefined at = /2 + n); = / (undefined at = n); Signs: same sign as (Q1, Q2 positive); same sign as (Q1, Q4 positive); same sign as (Q1, Q3 positive)

Pause — copy all three reciprocal definitions and their domain restrictions into your book: $\csc\theta = 1/\sin\theta$ (undefined at $\theta = n\pi$), $\sec\theta = 1/\cos\theta$ (undefined at $\theta = \pi/2+n\pi$), $\cot\theta = \cos\theta/\sin\theta$ (undefined at $\theta = n\pi$).

Quick check: What is the exact value of $\sec\!\left(\dfrac{\pi}{3}\right)$?

06
Signs of reciprocal functions in each quadrant
core concept

We just saw that $\csc\theta = 1/\sin\theta$, $\sec\theta = 1/\cos\theta$, and $\cot\theta = \cos\theta/\sin\theta$. That raises a question: since each reciprocal function inherits the sign of its parent, do they follow the same ASTC quadrant pattern? This card answers it → $\csc$ is positive wherever $\sin$ is positive, $\sec$ wherever $\cos$ is positive, and $\cot$ wherever $\tan$ is positive — confirmed by the table below.

Because each reciprocal function is just $1 \div (\text{parent function})$, it has exactly the same sign as its parent in every quadrant:

Function Q1 Q2 Q3 Q4
$\sin\theta$ / $\csc\theta$ + +
$\cos\theta$ / $\sec\theta$ + +
$\tan\theta$ / $\cot\theta$ + +

Note that $\csc\theta$ and $\cot\theta$ are undefined at the same angles ($\theta = n\pi$), even though $\cot$ is a "tan" reciprocal and $\csc$ is a "sin" reciprocal. Both require $\sin\theta \neq 0$.

Reciprocal functions have the same sign pattern as their parents — no new quadrant analysis required; positive in Q1 and Q2 (where > 0); positive in Q1 and Q4 (where > 0); positive in Q1 and Q3 (where > 0)

Pause — copy the sign table for $\sin/\csc$, $\cos/\sec$, and $\tan/\cot$ across all four quadrants into your book.

Did you get this? True or false: $\csc\theta$ and $\cot\theta$ are undefined at the same values of $\theta$.

PROBLEM 1 · FIND ALL RATIOS FROM ONE GIVEN VALUE

Given that $\sin\theta = \dfrac{3}{5}$ and $\dfrac{\pi}{2} < \theta < \pi$, find $\csc\theta$ and $\sec\theta$.

1
$\csc\theta = \dfrac{1}{\sin\theta} = \dfrac{1}{\;\frac{3}{5}\;} = \dfrac{5}{3}$
$\csc\theta$ is the direct reciprocal of $\sin\theta$. Since $\sin\theta > 0$ (Q2), $\csc\theta > 0$ too.
PROBLEM 2 · EXACT VALUE OF RECIPROCAL FUNCTION

Find the exact value of $\cot\!\left(\dfrac{\pi}{6}\right)$.

1
$\sin\!\left(\dfrac{\pi}{6}\right) = \dfrac{1}{2}$   and   $\cos\!\left(\dfrac{\pi}{6}\right) = \dfrac{\sqrt{3}}{2}$
Write down the exact values from the standard table.
PROBLEM 3 · DOMAIN & UNDEFINED VALUES

For what values of $\theta$ in $[0, 2\pi)$ is $\sec\theta$ undefined? State and explain the reason.

1
$\sec\theta = \dfrac{1}{\cos\theta}$ is undefined when $\cos\theta = 0$.
A fraction is undefined when its denominator is zero. Identify which values of $\theta$ make $\cos\theta = 0$.

Fill the gap: If $\cos\theta = \dfrac{5}{13}$ and $\sin\theta < 0$, then $\sec\theta = $ .

Trap 01
Swapping sec and csc
The single most common error: writing $\sec\theta = 1/\sin\theta$ (wrong) instead of $\sec\theta = 1/\cos\theta$ (correct). Remember: secant goes with cosine. Both contain the consonant cluster "sc" or begin with "c". Write the three reciprocal definitions at the top of your working every time.
Trap 02
Forgetting the quadrant when using the Pythagorean identity
When $\sin^2\theta + \cos^2\theta = 1$ is used to find $\cos\theta = \pm\sqrt{1 - \sin^2\theta}$, students often drop the $\pm$ and always write the positive root. Always check the quadrant to determine the sign before writing the answer.
Trap 03
Confusing $\csc^2\theta$ with $\csc(2\theta)$
$\csc^2\theta$ means $(\csc\theta)^2$, i.e. the square of the cosecant. It does not mean $\csc(2\theta)$ (cosecant of double the angle). Similarly for $\sec^2\theta$ and $\cot^2\theta$. These notations appear in the Pythagorean reciprocal identities: $1 + \cot^2\theta = \csc^2\theta$.

Did you get this? True or false: if $\theta$ is in Q4 and $\cos\theta = \dfrac{5}{13}$, then $\sec\theta = \dfrac{13}{5}$ (positive).

Work mode · how are you completing this lesson?
1

If $\cos\theta = \dfrac{5}{13}$ and $\sin\theta < 0$, find $\sec\theta$ and $\csc\theta$.

2

Find the exact value of $\cot\!\left(\dfrac{\pi}{6}\right)$.

3

For what values of $\theta$ in $[0, 2\pi)$ is $\sec\theta$ undefined?

4

Find the exact value of $\csc\!\left(\dfrac{5\pi}{6}\right)$.

5

Explain why $\csc\theta$ and $\cot\theta$ share the same domain restrictions, even though $\cot$ is a "tangent" reciprocal.

Odd one out: Three of these statements are correct. Which one is NOT?

11
Revisit your thinking

Earlier you were asked: if $\sin\theta = \dfrac{3}{5}$, what is $\csc\theta$, $\cos\theta$, and $\sec\theta$?

$\csc\theta = \dfrac{5}{3}$ — the direct reciprocal, positive because $\sin\theta > 0$.

For $\cos\theta$: without the quadrant, we cannot determine the sign. If $\theta$ is in Q1, $\cos\theta = +\dfrac{4}{5}$ and $\sec\theta = +\dfrac{5}{4}$. If $\theta$ is in Q2, $\cos\theta = -\dfrac{4}{5}$ and $\sec\theta = -\dfrac{5}{4}$. This is exactly why the quadrant is not optional information — it determines the sign of every missing ratio.

And why do $\csc\theta$ and $\cot\theta$ share domain restrictions? Because $\cot\theta = \cos\theta/\sin\theta$, which has $\sin\theta$ in its denominator — the same denominator as $\csc\theta = 1/\sin\theta$. Both vanish at $\theta = n\pi$.

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01
Multiple choice
+5 XP per correct · +25 XP all-correct

Pick your answer, then rate your confidence — that tells the system what to drill next. Each retry pulls a fresh mix from the bank.

02
Short answer
ApplyBand 43 marks

Q1. If $\cos\theta = \dfrac{5}{13}$ and $\sin\theta < 0$, find $\sec\theta$ and $\csc\theta$. (3 marks)

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ApplyBand 31 mark

Q2. Find the exact value of $\cot\!\left(\dfrac{\pi}{6}\right)$. (1 mark)

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UnderstandBand 42 marks

Q3. For what values of $\theta$ in $[0, 2\pi)$ is $\sec\theta$ undefined? Explain why in terms of the unit circle. (2 marks)

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Comprehensive answers (click to reveal)

Activity 1: 1. $\sec\theta = 13/5$; $\sin\theta = -\sqrt{1-25/169} = -12/13$; $\csc\theta = -13/12$ · 2. $\cot(\pi/6) = (\sqrt{3}/2)/(1/2) = \sqrt{3}$ · 3. $\theta = \pi/2$ and $\theta = 3\pi/2$ · 4. $\sin(5\pi/6) = 1/2$, $\csc(5\pi/6) = 2$ · 5. $\cot\theta = \cos\theta/\sin\theta$ has $\sin\theta$ in the denominator, same as $\csc\theta = 1/\sin\theta$; both undefined when $\sin\theta = 0$, i.e. $\theta = n\pi$.

Odd one out: B is incorrect. $\sec\theta = 1/\cos\theta$ is undefined when $\cos\theta = 0$, which occurs at $\theta = \pi/2$ and $\theta = 3\pi/2$, not at $\theta = 0$ and $\theta = \pi$ (where $\cos\theta = \pm 1 \neq 0$).

Q1 (3 marks): $\sec\theta = 1/\cos\theta = 13/5$ [1]. $\sin\theta < 0$ with $\cos\theta > 0$ means Q4; $\sin\theta = -\sqrt{1-25/169} = -\sqrt{144/169} = -12/13$ [1]. $\csc\theta = 1/\sin\theta = -13/12$ [1].

Q2 (1 mark): $\cot(\pi/6) = \cos(\pi/6)/\sin(\pi/6) = (\sqrt{3}/2)/(1/2) = \sqrt{3}$ [1].

Q3 (2 marks): $\sec\theta$ undefined at $\theta = \pi/2$ and $\theta = 3\pi/2$ [1]. On the unit circle, the x-coordinate (= $\cos\theta$) equals zero at the top ($\pi/2$) and bottom ($3\pi/2$) of the circle, making the denominator of $\sec\theta = 1/\cos\theta$ equal to zero [1].

01
Boss battle · The Reciprocal Master
earn bronze · silver · gold

Five timed questions. Beat the boss to bank a tier — gold (90% + speed), silver (75%), or bronze (50%). Replays welcome.

⚔ Enter the arena
02
Science Jump · platform challenge

Climb platforms by answering reciprocal trig questions. Lighter alternative to the boss.

Mark lesson as complete

Tick when you've finished the practice and review.

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