Chemistry • Year 12 • Module 7 • Lesson 5

Hydrocarbon Reactions

Apply combustion, substitution, addition and polymerisation to real Australian data, lab observations, and structured scenarios.

Apply · Data & Reasoning

1. Interpret combustion emissions data — Black Summer fire season

During the 2019–20 Black Summer bushfire season, satellite measurements recorded average daily CO (carbon monoxide) and CO2 column concentrations over southeastern Australia. The stylised graph below captures the seasonal trend in CO anomaly (deviation from multi-year baseline) as a proxy for the intensity of incomplete combustion in the landscape. 8 marks

0 50 100 150 200 CO anomaly (ppb above baseline) Jul 19 Aug Sep Oct Nov Dec Jan 20 Feb Mar Month Peak: ~205 ppb CO anomaly, SE Australia

Stylised monthly CO anomaly over southeastern Australia, 2019–20. After Jones et al. (2020), Nature; satellite MOPITT data.

1.1 Describe the trend in CO anomaly from July 2019 to March 2020. Identify the month of peak concentration and give its approximate value. 2 marks

1.2 Using the lesson’s content on combustion products, explain why the December–January peak in CO anomaly indicates incomplete rather than complete combustion was dominant during the fire season. 3 marks

1.3 Predict how the CO2 anomaly for the same period would compare to the CO trend shown. Justify your prediction with reference to combustion chemistry. 3 marks

Stuck? Recall that incomplete combustion produces CO (and soot) while complete combustion produces CO2. Both reactions release heat and contribute to atmospheric warming in different ways.

2. Cause-and-effect chain — free-radical substitution of methane

The cause boxes below describe the key stages of free-radical chlorination of methane. Complete the empty effect boxes and the overall outcome. 5 marks

Cause: UV light is shone onto a mixture of CH4 and Cl2.
Effect (initiation):
Cause: A chlorine free radical Cl• collides with a methane molecule.
Effect (propagation step 1):
Cause: The CH3• radical reacts with a Cl2 molecule.
Effect (propagation step 2):
Cause: Two free radicals collide with each other.
Effect (termination):
Overall outcome (so…): The net reaction is _______________; the reaction type is _______________.
Stuck? The initiation step breaks Cl–Cl; propagation keeps the chain going; termination removes two radicals.

3. Compare substitution and addition reactions

Complete the comparison table. Each cell may require 1–2 short phrases. 8 marks

FeatureSubstitution (alkane + halogen)Addition (alkene + Br2)
Type of hydrocarbon involved
Bond type targeted in the reaction
Condition required
Observation with bromine water
Example equation (with methane or ethene)
Change in molecular formula
By-product (if any)
Named from lesson
Stuck? Review lesson § Card 2 (Substitution) and Card 3 (Addition); compare the two worked examples.

4. Predict-and-justify — Qenos polyethylene plant, Altona VIC

Qenos operates Australia’s only polyethylene manufacturing plant at Altona, Victoria. The process uses ethene gas as the monomer and a catalyst at elevated temperature and pressure to drive addition polymerisation. A process engineer changes the reactor conditions so that the reaction is quenched (stopped) after only a short time. 4 marks

4.1 Predict how this change would affect the chain length (molecular mass) of the polyethylene produced, compared with normal full-reaction conditions. Justify your prediction. 2 marks

4.2 The engineer finds that the short-chain product is more soluble in organic solvents than the full-length polyethylene. Explain this observation using your knowledge of polymer structure and intermolecular forces. 2 marks

Stuck? Connect: fewer addition steps → shorter chain → lower molecular mass → weaker dispersion forces → more soluble.

5. Spot the errors — student’s polymerisation diagram

A student has drawn the diagram below to explain addition polymerisation of ethene. There are three chemical errors in the diagram. Identify each error and write the correction. 6 marks (2 per error: 1 identify, 1 correct)

Spot the errors — student’s polymerisation diagram

5.1 Error 1: What is wrong?

Correction:

5.2 Error 2: What is wrong?

Correction:

5.3 Error 3: What is wrong?

Correction:

Stuck? Compare this diagram to the lesson’s polymerisation SVG (Card 4). Check monomer identity, the repeating unit’s bond structure, and whether any small molecule is lost.
Answers — Do not peek before attempting

Q1.1 — Trend description (2 marks)

CO anomaly is very low (near baseline) from July to September 2019, then rises steadily through October–November, peaks at approximately 205 ppb in January 2020, and drops sharply by February–March 2020. The month of peak concentration is January 2020.

Mark notes: 1 mark for describing the rise and fall pattern; 1 mark for correctly identifying peak month and approximate value (±10 ppb).

Q1.2 — Incomplete vs complete combustion (3 marks)

CO is a product of incomplete combustion, which occurs when oxygen supply is limited [1]. In a large wildfire the interior of fuel masses (dense forest, leaf litter) is oxygen-starved, so carbon atoms in the biomass are only partially oxidised to CO rather than fully oxidised to CO2 [1]. The sharp seasonal peak in CO (not CO2) is therefore consistent with widespread incomplete combustion across a fire front where oxygen cannot reach all burning material uniformly [1].

Q1.3 — CO2 prediction (3 marks)

The CO2 anomaly would also show a seasonal peak during December–January, but it would be broader, larger in absolute magnitude (more carbon is always converted to CO2 than CO in any real fire), and would not drop as sharply [1]. This is because even during incomplete combustion, a large fraction of carbon atoms are still oxidised fully to CO2, and atmospheric CO2 has a much longer atmospheric lifetime than CO (years vs weeks) [1]. The CO2 curve would therefore extend further into the months following the fire season [1]. Accept other well-reasoned predictions.

Q2 — Cause-and-effect chain (5 marks)

Initiation: The UV light provides energy to break the Cl–Cl bond homolytically, generating two chlorine free radicals (Cl•) [1].

Propagation step 1: Cl• abstracts a hydrogen atom from CH4, forming HCl and a methyl free radical CH3• [1].

Propagation step 2: CH3• reacts with Cl2, forming chloromethane (CH3Cl) and regenerating Cl•, which can continue the chain [1].

Termination: Two free radicals combine (e.g. Cl• + Cl• → Cl2, or CH3• + Cl• → CH3Cl), removing radicals from the system and ending the chain [1].

Overall outcome: CH4 + Cl2 → CH3Cl + HCl; reaction type is free-radical substitution [1].

Q3 — Compare substitution and addition (8 marks, 1 per cell)

FeatureSubstitutionAddition
HydrocarbonAlkane (saturated)Alkene (unsaturated)
Bond targetedC–H single bondC=C double bond (pi bond)
ConditionUV lightNo special conditions needed for Br2
Bromine waterNo rapid decolourisationOrange → colourless (decolourises)
Example equationCH4 + Cl2 → CH3Cl + HClC2H4 + Br2 → C2H4Br2
Change in formulaOne H replaced by halogen; formula mass risesBr2 adds; formula mass rises
By-productHCl (or HBr)None
Named exampleChlorination of methaneBromine test for unsaturation

Q4.1 — Chain length prediction (2 marks)

Quenching the reaction early means fewer addition steps occur before the reaction stops, so shorter polymer chains (lower molecular mass) are produced [1]. The number of repeating —CH2—CH2— units in each chain (the value of n) will be smaller than under full-reaction conditions [1].

Q4.2 — Solubility explanation (2 marks)

Shorter chains have lower molecular mass and therefore weaker London dispersion (van der Waals) intermolecular forces between chains [1]. Because the forces between the polymer and the organic solvent molecules can more easily overcome the weaker chain–chain forces, the short-chain polymer dissolves more readily in organic solvents [1].

Q5 — Diagram errors (6 marks)

5.1 Error 1 (monomer drawn as ethane): The monomer for addition polymerisation must contain a C=C double bond; CH3–CH3 is ethane (an alkane, no double bond) and cannot polymerise by addition. Correction: the monomer should be drawn as CH2=CH2 (ethene). [1+1]

5.2 Error 2 (repeating unit retains C=C): During addition polymerisation the double bond opens; the repeating unit must show only single bonds. Writing [–CH2=CH2–]n is wrong. Correction: the repeating unit is [–CH2–CH2–]n. [1+1]

5.3 Error 3 (H2O shown as by-product): Addition polymerisation produces no small molecule by-product; all atoms from the monomer end up in the polymer chain. Condensation polymerisation (not this lesson’s topic) does eliminate water. Correction: remove H2O from the product side. [1+1]