Chemistry • Year 12 • Module 7 • Lesson 2

IUPAC Nomenclature II: Functional Group Classes & Isomers

Lock in the structural signatures, suffixes/prefixes, and isomer vocabulary for all eight functional group classes covered in this lesson.

Build · Band 3–4

1. Term–definition match

Match each term in the left column to the correct definition. Write the term in the right-hand column. Terms: aldehyde, ketone, carboxylic acid, ester, amine, amide, haloalkane, structural isomer, chain isomer, position isomer, functional group isomer, primary alcohol. 12 marks

#DefinitionMatching term
1.1A compound with the structural formula R–CHO; the carbonyl carbon is terminal and has a hydrogen directly bonded to it. Suffix: -al.
1.2A compound with R–CO–R′; the carbonyl carbon is internal, flanked by two other carbons. Suffix: -one.
1.3A compound with R–COOH; terminal carbonyl plus a hydroxyl group on the same carbon. Suffix: -oic acid.
1.4Named as alkyl alkanoate; contains a –COO– linkage; the alkyl part (from the alcohol) is written first.
1.5A compound containing nitrogen bonded to one or more alkyl groups; a weak base because the lone pair on N is freely available. Suffix: -amine.
1.6Contains a –CONH2 group; neutral because the N lone pair is delocalised into the adjacent C=O. Suffix: -amide.
1.7Contains a halogen atom (F, Cl, Br, or I) bonded to a carbon chain; named with a prefix (fluoro-, chloro-, bromo-, iodo-) and a locant.
1.8Compounds that share the same molecular formula but have different structural arrangements of atoms.
1.9A pair of structural isomers with the same functional group and same molecular formula, but a different carbon skeleton (degree of branching).
1.10A pair of structural isomers with the same functional group and same carbon skeleton, but the functional group is attached to a different carbon.
1.11A pair of structural isomers with the same molecular formula but entirely different functional groups (e.g. an aldehyde and a ketone).
1.12An alcohol in which the carbon bearing the –OH group is bonded to exactly one other carbon. Classification determined by counting carbon neighbours of C–OH only.
Stuck? Revisit the Key Structural Signatures panel and Cards 1–4 in the lesson.

2. True or false — with correction

Circle T or F for each statement. If false, write the corrected version on the line provided. 10 marks (1 T/F + 1 correction)

2.1 Propanal and propanone are position isomers because the C=O group is at a different position on the same three-carbon chain.    T  /  F

2.2 The IUPAC name for CH3COOC2H5 is ethyl ethanoate (alkyl group written first).    T  /  F

2.3 Amides are weak bases because the nitrogen atom contains a lone pair that accepts H+ from acids, just like amines.    T  /  F

2.4 The suffix –al always indicates an aldehyde, and a locant is never written for the aldehyde carbon because it is always C1.    T  /  F

2.5 Butane (CH3CH2CH2CH3) and 2-methylpropane (CH3CH(CH3)CH3) are functional group isomers because they share the formula C4H10.    T  /  F

Stuck? For 2.1: check the definition of ‘functional group isomers’ vs ‘position isomers’ in Card 4. For 2.3: see the amide callout in Card 3.

3. Fill in the blanks — IUPAC naming rules

Complete the paragraph using the word bank below. Each word is used once. 10 marks

Word bank:

alkyl  •  alkanoate  •  locant  •  terminal  •  internal  •  delocalised  •  lowest  •  primary  •  halogen  •  -oic acid

When naming an alcohol, the chain is numbered from the end that gives the   possible locant for the –OH group. An alcohol whose C–OH carbon is bonded to only one other carbon is classified as a   alcohol. An aldehyde has its C=O group at the   carbon, so no   is needed. A ketone has its C=O group in an   position between two carbon atoms. A carboxylic acid always uses the suffix   and is also always at C1. An ester is named as    +    , with the part derived from the alcohol coming first. An amide is neutral because the lone pair on nitrogen is   into the adjacent C=O group. Haloalkanes are named using the   as a prefix (fluoro-, chloro-, bromo-, or iodo-) with a locant.

Stuck? Review the Key Structural Signatures panel at the top of the lesson.

4. Function recall

Answer each question in 1–2 sentences using precise lesson vocabulary. 8 marks (2 each)

4.1 Explain why a locant is always written for an alcohol but is never written for an aldehyde or carboxylic acid.

4.2 Describe the key structural difference between propan-1-ol and propan-2-ol that makes one a primary alcohol and the other a secondary alcohol.

4.3 State what the terms ‘chain isomers’, ‘position isomers’, and ‘functional group isomers’ all have in common before they differ.

4.4 Explain why amines are weak bases while amides are neutral, referring to the lone pair on nitrogen in each case.

Stuck? See the callout boxes in Cards 1–3 of the lesson.

5. Build a concept map

Draw labelled arrows between the six terms to show how they connect. Each arrow must carry a linking phrase (e.g. “is a type of”, “uses suffix”, “is identified by”). Aim for at least 6 labelled arrows. 6 marks

Terms: functional groupIUPAC suffix/prefixstructural isomersame molecular formulacarbon skeletonlocant.

functional group
IUPAC suffix/prefix
locant
structural isomer
same molecular formula
carbon skeleton
Hint: structural isomers share the same molecular formula; functional groups are identified by their suffix/prefix; locants specify position of a functional group on the carbon skeleton.
Answers — Do not peek before attempting

Q1 — Term–definition match

1.1 aldehyde • 1.2 ketone • 1.3 carboxylic acid • 1.4 ester • 1.5 amine • 1.6 amide • 1.7 haloalkane • 1.8 structural isomer • 1.9 chain isomer • 1.10 position isomer • 1.11 functional group isomer • 1.12 primary alcohol.

Q2 — True / false

2.1 False. Propanal and propanone are functional group isomers. Both have the formula C3H6O but propanal is an aldehyde (terminal C=O with H) and propanone is a ketone (internal C=O between two carbons) — entirely different functional groups, not different positions of the same group.

2.2 True. CH3COOC2H5: ethanoate (from CH3COO–, the acid part) + ethyl (from –OC2H5, the alcohol part). Alkyl first → ethyl ethanoate.

2.3 False. Amides are neutral, not weak bases. The lone pair on the amide nitrogen is delocalised by resonance into the adjacent C=O and is not available to accept a proton. Amines (R–NH2) have an undelocalised lone pair that freely accepts H+ and are weak bases.

2.4 True. The aldehyde C=O is always at C1, so there is only one possible arrangement and no locant is required.

2.5 False. Butane and 2-methylpropane are chain isomers, not functional group isomers. Both are alkanes (same functional group class); only the shape of the carbon skeleton differs (straight vs branched).

Q3 — Cloze answers (in order)

lowest • primary • terminal • locant • internal • -oic acid • alkyl • alkanoate • delocalised • halogen.

Q4.1 — Locants for alcohols vs. aldehydes/acids

Alcohols need a locant because the –OH group can be placed at different positions along the chain (e.g. C1 or C2), giving structurally different compounds with different properties. Aldehydes and carboxylic acids do not need a locant because by definition their functional carbon (C=O + H for aldehyde; C=O + OH for acid) is always C1 at the chain terminus — there is only one possible position.

Q4.2 — Primary vs. secondary alcohol classification

In propan-1-ol, the carbon bearing the –OH group (C1) is bonded to only one other carbon (C2) → primary. In propan-2-ol, the carbon bearing the –OH (C2) is bonded to two other carbons (C1 and C3) → secondary. Classification counts only carbon neighbours of C–OH; H atoms and the O atom are ignored.

Q4.3 — What all structural isomers share

All structural isomers share the same molecular formula (same atoms, same count) but differ in the structural arrangement of those atoms. The difference can be in the carbon skeleton shape (chain isomers), the position of the functional group (position isomers), or the type of functional group itself (functional group isomers).

Q4.4 — Amine (base) vs. amide (neutral)

In an amine (R–NH2), the lone pair on nitrogen is not delocalised and is freely available to accept a proton from an acid → weak base. In an amide (R–CONH2), the lone pair on nitrogen is delocalised by resonance into the adjacent C=O bond — it is spread across the C–N region and cannot accept H+ → neutral.

Q5 — Sample concept map connections

Acceptable arrows include: functional groupis identified byIUPAC suffix/prefix; IUPAC suffix/prefixmay includelocant; locantspecifies position oncarbon skeleton; structural isomerrequiressame molecular formula; structural isomermay differ incarbon skeleton; structural isomermay differ infunctional group. Award 1 mark per biologically/chemically valid labelled arrow (up to 6).