Chemistry • Year 12 • Module 6 • Lesson 10

Enthalpy of Neutralisation: Comparing Strong & Weak

Lock in the key vocabulary, the ΔHn baseline, and the energy-budget ranking for all four strong/weak combinations.

Build • Vocab & Recall

1. Term–definition match

The definitions below are shuffled. Write the matching term from this list in the right-hand column: enthalpy of neutralisation (ΔHn), net ionic equation, ionisation enthalpy, strong acid, weak acid, spectator ions, Hess’s Law, calorimetry, endothermic, exothermic. 10 marks

#Definition (shuffled)Matching term
1.1The energy change per mole of water formed when an acid and a base react to completion under standard conditions.
1.2An ionic equation that excludes spectator ions, showing only the reacting species: H+(aq) + OH(aq) → H2O(l).
1.3The energy absorbed when a weak acid or base ionises; this is an endothermic process that reduces net heat released during neutralisation.
1.4An acid that completely ionises in dilute aqueous solution; for example, HCl → H+ + Cl.
1.5An acid that partially ionises in dilute aqueous solution; for example, CH3COOH ⇌ H+ + CH3COO.
1.6Ions present in solution that do not participate in the reaction and cancel from both sides of the full ionic equation.
1.7The principle that total enthalpy change is independent of the reaction pathway taken; allows multi-step energy budgets to be summed.
1.8The experimental technique of measuring heat changes in a solution using q = mcΔT.
1.9A reaction or process that releases heat to the surroundings; ΔH is negative.
1.10A reaction or process that absorbs heat from the surroundings; ΔH is positive.
Stuck? Revisit the Key Terms panel and the Formula Panel in the lesson.

2. True or false — with correction

Circle T or F. If false, write the corrected version on the line below. 10 marks (1 T/F, 1 correction each)

2.1 The enthalpy of neutralisation for strong acid + strong base is approximately −57 kJ/mol and represents the energy released solely from the reaction H+(aq) + OH(aq) → H2O(l).   T  /  F

2.2 When a weak acid is neutralised by a strong base, the measured ΔHn is more negative (more exothermic) than −57 kJ/mol because extra energy is released during ionisation.   T  /  F

2.3 The ionisation of a weak acid during neutralisation is an endothermic process that reduces the net heat measured in the calorimeter.   T  /  F

2.4 All strong acids give different values of ΔHn when reacted with NaOH because each acid has different molar mass and Ka.   T  /  F

2.5 A weaker acid (smaller Ka) has a more endothermic ionisation and gives a ΔHn that is further from −57 kJ/mol (more positive) compared to a stronger weak acid.   T  /  F

Stuck? Revisit Cards 1–3 and the Common Error callouts in the lesson.

3. Fill in the blanks — the energy budget for weak acid neutralisation

Use the word bank to complete the paragraph. Each word is used once only. 8 marks

Word bank: endothermic • −57 • intact • ionisation • bond-breaking • Hess’s Law • more positive • weaker

The standard enthalpy of neutralisation for strong acid + strong base is approximately          kJ/mol. This value is also called the “baseline” because strong acids and bases are already fully ionised before mixing — no energy is needed to produce H+ or OH. When a weak acid such as CH3COOH meets NaOH, most acid molecules are          before mixing. During the reaction, OH drives the equilibrium right, forcing the weak acid to         . This step is          because it is a          process — the O–H bond in the carboxyl group must break to release H+. By         , the net heat measured = (heat from H+ + OH → H2O) − (heat absorbed in ionisation). Therefore the measured ΔHn for weak acid + strong base is          than the baseline. A          acid gives a larger positive deviation from −57 kJ/mol because its O–H bond is harder to break.

Stuck? The answer to each blank corresponds to a sentence from Card 2 (Molecular Mechanism) of the lesson.

4. Concept map — connect the key ideas

Draw labelled arrows between the six terms below to show how they relate. Each arrow must carry a linking phrase. Aim for at least 6 labelled arrows. 6 marks

Supplied terms: ΔHn (−57 kJ/mol baseline)ionisation enthalpyweak acidstrong acidH+ + OH → H2Onet heat released

ΔHn baseline (−57 kJ/mol)
H+ + OH → H2O
net heat released
ionisation enthalpy
weak acid
strong acid
Hints: strong acid → zero ionisation enthalpy cost → ΔHn = baseline; weak acid → positive ionisation enthalpy → reduces net heat → ΔHn more positive than baseline.

5. Rank the combinations

Complete the table by filling in the approximate ΔHn value and the ranking (1 = most exothermic, 4 = least exothermic). Explain the cause of the deviation from −57 kJ/mol for each combination. 8 marks

CombinationApprox. ΔHn (kJ/mol)RankCause of deviation from −57 kJ/mol
HCl + NaOH
CH3COOH + NaOH
HCl + NH3
CH3COOH + NH3
Stuck? Approximate values are given in the lesson’s Card 3 comparison table. The cause always involves the ionisation enthalpy of the weak species.
Answers — Do not peek before attempting

Q1 — Term–definition matches

1.1 enthalpy of neutralisation (ΔHn) • 1.2 net ionic equation • 1.3 ionisation enthalpy • 1.4 strong acid • 1.5 weak acid • 1.6 spectator ions • 1.7 Hess’s Law • 1.8 calorimetry • 1.9 exothermic • 1.10 endothermic

Q2 — True / False with corrections

2.1 True. The baseline −57 kJ/mol arises entirely from H+ + OH → H2O; spectator ions contribute nothing.

2.2 False. Correction: when a weak acid is neutralised by a strong base, the measured ΔHn is more positive (less exothermic) than −57 kJ/mol, because the endothermic ionisation of the weak acid consumes part of the exothermic H+ + OH → H2O energy.

2.3 True. The ionisation step (bond-breaking) is endothermic and reduces the temperature rise measured.

2.4 False. Correction: all strong acids give the same ΔHn (approximately −57 kJ/mol) when reacted with a strong base, because the net ionic equation H+ + OH → H2O is the same regardless of which spectator ions are present.

2.5 True. A weaker acid has a stronger, harder-to-break O–H bond — larger ionisation enthalpy — giving a ΔHn further from the baseline.

Q3 — Cloze paragraph

In order: −57intactionisationendothermicbond-breakingHess’s Lawmore positiveweaker

Q4 — Concept map (sample links)

  • strong acidhas zero ionisation enthalpy cost, soΔHn = baseline (−57 kJ/mol)
  • ΔHn baselineis produced byH+ + OH → H2O
  • H+ + OH → H2Oreleasesnet heat released
  • weak acidcontributes a positiveionisation enthalpy
  • ionisation enthalpyis subtracted fromnet heat released
  • net heat releaseddeterminesΔHn baseline (−57 kJ/mol) (or the deviation from it)

Award 1 mark per correctly directed, labelled arrow. Any biologically valid linking phrase is acceptable.

Q5 — Ranking table

CombinationApprox. ΔHn (kJ/mol)RankCause of deviation
HCl + NaOH−57.01stNo deviation — both fully ionised; net ionic equation only.
CH3COOH + NaOH≈ −55.42ndIonisation enthalpy of CH3COOH (+1.6 kJ/mol) consumed during reaction.
HCl + NH3≈ −52.23rdProton-acceptance energy of NH3 (+4.8 kJ/mol) consumed during reaction.
CH3COOH + NH3≈ −49.54thBoth ionisation enthalpy of CH3COOH and proton-acceptance energy of NH3 add to the positive deviation.