HSCScienceExam practice
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Chemistry  ·  Year 12  ·  Module 5  ·  Lesson 16

HSC Exam Practice

Solubility Rules & Precipitation

9 questions / 3 sections / 34 marks total
Section 1

Short answer

1.Short answer

1.1

Define the term precipitate and state the condition (in terms of ion product Q and Ksp) under which precipitation occurs.

2marks Band 3
1.2

Identify the spectator ions in the following reaction and explain why they are described as “spectators”.

2KI(aq) + Pb(NO3)2(aq) → PbI2(s) + 2KNO3(aq)

3marks Band 3–4
1.3

Distinguish between a molecular equation and a net ionic equation for a precipitation reaction, with reference to how each type of species is represented.

3marks Band 3–4
1.4

Explain why BaSO4 is described as insoluble when sulfates are “generally soluble” according to the NAGSAG rules. Include a reference to the specific NAGSAG exception that applies.

3marks Band 4
1.5

Outline the four-step procedure for predicting and writing the equation for a precipitation reaction when two ionic solutions are mixed. Do not use a specific example — describe the general method.

4marks Band 4
1.6

Describe how a water treatment plant uses precipitation chemistry to remove dissolved Pb2+ ions from a contaminated water supply. Name an appropriate precipitant and explain why it is selected.

4marks Band 4–5
Section 2

Data response

2.Data response — CaCO3 formation in Australian water systems

2.1

Hard water in parts of regional NSW contains elevated Ca2+ and HCO3 concentrations. When such water is heated in a kettle, CaCO3 (limescale) deposits on heating elements. The graph below shows the mass of CaCO3 deposited per litre of water boiled at different initial Ca2+ concentrations, for two representative NSW water sources.

0 15 30 45 60 CaCO₃ deposited (mg/L) 0 30 60 90 120 Initial Ca²⁺ concentration (mg/L) Murrumbidgee River water Hawkesbury River water
Figure 2.1. CaCO3 deposited per litre of water boiled versus initial Ca2+ concentration. Illustrative data; after Apell & Bauer (2019), Water Research.

(a) Describe the relationship shown between initial Ca2+ concentration and mass of CaCO3 deposited for both water sources. (2 marks)

(b) Estimate the mass of CaCO3 deposited per litre by Murrumbidgee River water at an initial Ca2+ concentration of 75 mg/L. Show your method. (2 marks)

(c) Write the net ionic equation for CaCO3 precipitation and apply NAGSAG to explain why CaCO3 precipitates. Account for why heating the water promotes this reaction. (3 marks)

7marks Band 4–5

3.Multi-step calculation — gravimetric analysis of chloride

3.1

A 250.0 mL sample of a saline water supply is treated with excess AgNO3(aq) to precipitate all chloride ions as AgCl. The AgCl precipitate is collected, dried, and weighed: mass = 0.7175 g. (Mr: AgCl = 143.32 g/mol; Cl = 35.45 g/mol)

(a) Write the net ionic equation for the reaction. (1 mark)

(b) Calculate the moles of AgCl precipitated and hence the concentration of Cl ions (in mol/L) in the original water sample. Show all working. (3 marks)

(c) The Australian Drinking Water Guidelines recommend a Cl concentration below 250 mg/L for taste. Determine whether this sample complies. (2 marks)

6marks Band 4–5
Section 3

Extended response

4.Extended response

4.1

Analyse how knowledge of solubility rules and net ionic equations allows chemists to design targeted precipitation reactions for water treatment in Australia. In your response, refer to at least two specific Australian water quality contexts and include relevant net ionic equations.

8marks Band 5–6

Chemistry · Year 12 · Module 5 · Lesson 16

Answer Key & Marking Guidelines

1.1

Section 1 · Short answer · 2 marks · Band 3

Sample response. A precipitate is an insoluble solid that forms when two aqueous ionic solutions are mixed and the ion product Q for a particular ionic combination exceeds the solubility product Ksp: precipitation occurs when Q > Ksp.

Marking notes. 1 mark for defining precipitate as an insoluble solid formed in solution; 1 mark for the condition Q > Ksp (or equivalent: when concentration of ions in solution exceeds the saturation limit). Do not penalise if student omits Q notation but correctly states that ion concentrations exceed the solubility limit.

1.2

Section 1 · Short answer · 3 marks · Band 3–4

Sample response. The spectator ions are K+(aq) and NO3(aq). They are described as spectators because they are present in solution on both the left-hand (reactant) and right-hand (product) sides of the full ionic equation in identical form, charge, and state — they do not undergo any change and do not participate in the net chemical reaction. The net event is Pb2+(aq) + 2I(aq) → PbI2(s), from which K+ and NO3 are entirely absent.

Marking notes. 1 mark for correctly identifying both spectator ions (K+ and NO3); 1 mark for explaining that they appear identically on both sides of the full ionic equation; 1 mark for stating they do not participate in the net chemical reaction / are not consumed or produced.

1.3

Section 1 · Short answer · 3 marks · Band 3–4

Sample response. The molecular equation represents all reactants and products as complete formula units (e.g. 2KI(aq) + Pb(NO3)2(aq) → PbI2(s) + 2KNO3(aq)), including spectator ions as part of intact compounds. The net ionic equation shows only the species that actually participate in the reaction: all soluble ionic compounds are split into their constituent aqueous ions, the precipitate remains as its formula unit with state symbol (s), and spectator ions are removed (e.g. Pb2+(aq) + 2I(aq) → PbI2(s)).

Marking notes. 1 mark for distinguishing that molecular equation uses intact formula units for all species including spectator ions; 1 mark for explaining that net ionic equation splits aqueous species into ions; 1 mark for explaining that net ionic equation omits spectator ions. A correct example of each equation earns the relevant mark even without explicit verbal description.

1.4

Section 1 · Short answer · 3 marks · Band 4

Sample response. Within NAGSAG, the “S” rule states that sulfate salts are mostly soluble — not universally so. Ba2+ is one of the named exceptions: BaSO4 (along with PbSO4 and the sparingly soluble CaSO4) is insoluble. The “mostly soluble” language signals that Ba2+, Pb2+, and Ca2+ must be memorised as exceptions. The underlying reason is that the lattice energy of BaSO4 is very high (the large Ba2+ and SO42− ions form a particularly stable lattice), outweighing hydration energy and driving the equilibrium strongly towards the undissolved solid.

Marking notes. 1 mark for identifying that NAGSAG’s S-rule says “mostly soluble” (not all); 1 mark for naming Ba2+ as a specific exception; 1 mark for explanation (high lattice energy, or equivalent: Ksp very low, equilibrium lies far left). Accept “Ba2+, Pb2+, Ca2+ are exceptions” for the second mark.

1.5

Section 1 · Short answer · 4 marks · Band 4

Sample response. Step 1: Identify all four ions present in solution when the two reactant solutions are mixed (two cations and two anions). Step 2: Identify the two possible new ionic combinations — each cation paired with the other solution’s anion. Step 3: Apply NAGSAG to each possible product to determine which (if either) is insoluble; the insoluble product is the precipitate. Step 4: Write the molecular equation (if precipitation occurs), then the full ionic equation (splitting all aqueous species), then cancel spectator ions to obtain the net ionic equation; verify charge balance on both sides of the net ionic equation.

Marking notes. 1 mark per step described correctly. Award 4 marks for all four steps in logical order; 3 marks for three steps; etc. Must include verification of charge balance for full Step 4 mark.

1.6

Section 1 · Short answer · 4 marks · Band 4–5

Sample response. A water treatment plant adds a soluble salt containing an anion that forms an insoluble compound with Pb2+. Sodium carbonate (Na2CO3) is a suitable choice: CO32− combines with Pb2+ to form lead(II) carbonate, an insoluble precipitate (NAGSAG: carbonates are generally insoluble except with Group 1 or NH4+). Net ionic equation: Pb2+(aq) + CO32−(aq) → PbCO3(s). The precipitate settles or is filtered, removing Pb2+ from the treated water. The Na+ counter-ion is a spectator — it remains dissolved and is harmless. The precipitant must also be verified not to remove other essential ions (Ca2+ co-precipitation is a consideration).

Marking notes. 1 mark for naming a correct precipitant (Na2CO3, Na3PO4, or Na2S — all acceptable with correct chemistry); 1 mark for naming the precipitate and stating it is insoluble; 1 mark for a correct net ionic equation (with state symbols); 1 mark for explaining how the precipitate is removed (filter/settle) and/or for explaining why the counter-ion (Na+) does not interfere.

2.1

Section 2 · Data response · 7 marks · Band 4–5

Part (a) — 2 marks. Both sources show a linear (directly proportional) increase in CaCO3 deposited as initial Ca2+ concentration increases. At any given Ca2+ concentration, Murrumbidgee River water deposits a greater mass of CaCO3 per litre than Hawkesbury River water. [1 mark for “linear/directly proportional increase”; 1 mark for the comparative statement with correct direction.]

Part (b) — 2 marks. From the graph, reading between 60 and 90 mg/L Ca2+: at 60 mg/L the Murrumbidgee line gives approximately 30 mg/L CaCO3; at 90 mg/L approximately 45 mg/L. By interpolation at 75 mg/L: (30 + 45)/2 ≈ 37.5 mg/L CaCO3. Accept readings within ±3 mg/L. [1 mark for correct interpolation method; 1 mark for answer in range 34–41 mg/L.]

Part (c) — 3 marks. Net ionic equation: Ca2+(aq) + CO32−(aq) → CaCO3(s). Charge check: +2 + (−2) = 0 = 0 ✓. NAGSAG: carbonates (CO32−) are generally insoluble; Ca2+ is not Group 1 or NH4+, so CaCO3 is insoluble → precipitate forms. Heating promotes reaction because CO2 dissolved in the water is expelled when water is heated (gases are less soluble at higher temperatures), shifting CO2(aq) ⇌ CO2(g) equilibrium to the right. This depletes H+ and CO2 while increasing CO32− concentration, driving the precipitation of CaCO3. [1 mark net ionic equation + charge balance; 1 mark NAGSAG application; 1 mark CO2 expulsion / Le Chatelier explanation.]

3.1

Section 2 · Multi-step calculation · 6 marks · Band 4–5

Part (a) — 1 mark. Ag+(aq) + Cl(aq) → AgCl(s). State symbols required. Charge balance: +1 + (−1) = 0 = 0 ✓.

Part (b) — 3 marks. n(AgCl) = 0.7175 / 143.32 = 5.006×10−3 mol [1 mark]. Since AgCl : Cl = 1:1, n(Cl) = 5.006×10−3 mol [1 mark]. c(Cl) = 5.006×10−3 / 0.2500 = 0.02002 mol/L [1 mark]. Accept 0.0200 mol/L or 2.00×10−2 mol/L.

Part (c) — 2 marks. Convert: c(Cl) = 0.02002 mol/L × 35.45 g/mol × 1000 mg/g = 709.5 mg/L. This exceeds the guideline of 250 mg/L, so the sample does not comply. [1 mark for correct calculation; 1 mark for clear compliance decision with units.]

4.1

Section 3 · Extended response · 8 marks · Band 5–6

Sample response. Solubility rules, codified in the NAGSAG framework, allow chemists to predict whether a specific ionic compound will form an insoluble solid when two solutions are mixed. This predictive power is directly applied in water treatment in two contexts: removal of heavy metals (e.g. dissolved Pb2+ in older Sydney Water distribution systems) and removal of unwanted mineral ions causing water hardness (e.g. CaCO3/CaSO4 in Murray-Darling Basin irrigation systems). In both cases, the chemist selects an anion that forms an insoluble compound with the target cation while remaining soluble with all other ions present. For Pb2+ removal, adding Na2CO3 introduces CO32−: by NAGSAG, carbonates are generally insoluble unless paired with Group 1 or NH4+, so PbCO3(s) precipitates [net ionic: Pb2+(aq) + CO32−(aq) → PbCO3(s)]. The Na+ ions are spectators. The precipitate is then removed by filtration or sedimentation. For water hardness, calcium ions in the Murray-Darling Basin precipitate as CaCO3 when lime (Ca(OH)2) raises pH and shifts the carbonate equilibrium [Ca2+(aq) + CO32−(aq) → CaCO3(s)]. The selectivity of the process depends on the Ksp values of possible products: engineers select the precipitant whose target-ion compound has the lowest Ksp, ensuring precipitation is most complete. Net ionic equations are essential because they isolate the essential chemistry from spectator ions, allowing the same equation to apply regardless of the counter-ions in the source water. Without solubility rules, it would be impossible to design selective treatment steps that remove one ion without disturbing other desirable species in the water.

Marking notes. 1 mark — explains NAGSAG as a framework for predicting solubility/precipitation. 1 mark — states the design principle: choose anion that forms insoluble product with target cation but soluble products with other ions. 1 mark — names at least one Australian context with correct target ion identified (Pb2+ in Sydney pipes; Ca2+/Mg2+ in Murray-Darling; CaCO3 water hardness; accept any other specific Australian water quality context). 1 mark — second distinct Australian context with correct target ion. 1 mark — at least one correct net ionic equation with state symbols and verified charge balance. 1 mark — second correct net ionic equation or correct explanation of spectator ions in one of the contexts. 1 mark — explicit reference to Ksp as the criterion for selecting the most effective precipitant (lower Ksp → more complete precipitation). 1 mark — demonstrates analytical understanding of how the design process works: testing both possible products against NAGSAG, verifying that counter-ions remain dissolved, confirming treatment achieves guideline concentrations.